Monday

February 20, 2017
Total # Posts: 40

**physics**

A ball is thrown straight up at 20.0 m/s. How fast is the ball moving after 2.00 s?

*January 23, 2016*

**chemical science**

what is the van't Hoff factor for MgSo4.7H2O and ZnSo4.7H2O?

*January 23, 2014*

**physics**

so... no ideas for this problem???

*December 7, 2013*

**Physics Classical Mechanics**

answers depend on the values we have so, for A F = dp/dt -> dp = Fdt ∫dp = ∫Fdt p_f - p_i = ∫βt²dt p_f - 0 = (β/3)(t_f)^3 - (β/3)(t_i)^3 for b: F - fk = m.a F - fk = m.dv/dt (F - fk)dt = m.dv ∫(F - f_k)dt = ∫m.dv m.vf - m.vi...

*December 7, 2013*

**Physics Classical Mechanics**

so, no more suggestions for b and c of initial question? and Mets, check the videos from week 13.

*December 7, 2013*

**Physics Classical Mechanics**

have you check your data, because for a got a green mark, so A is ok, but b and c were not. There might be some where m = 3 and beta=1.2

*December 7, 2013*

**Physics Classical Mechanics**

for b: F - f_k = ma F - f_k = mdv/dt (F - f_k)dt = mdv ∫(F - f_k)dt = ∫mdv mv_f - mv_i = (β/3)(t_f)^3 - (f_k)t_f - [(β/3)(t_i)^3 - (f_k)t_i] [Note: v_i = 0 and t_i = 0] mv_f = (β/3)(t_f)^3 - (f_k)t_f v_f ≅ 10.83, but that's not the answer, ...

*December 7, 2013*

**Physics Classical Mechanics**

for a: 41.67

*December 7, 2013*

**Classical Mechanics Physics**

my values were right, just had to write the value of f without the -. Now, anyone has checked the falling ruler???

*December 6, 2013*

**Classical Mechanics Physics**

error, so we'll have: F-ff=m.a -> ff=F-m.a (1) I.alpha=F.r+ff.R (2) alpha=a/R then: a=F.(R+r)/(I/R+m.R) a=positive ff=negative, and for a got green mark, but not for f, should I write ff with "-" or just the value? I got a=16.3 f=-4.6

*December 6, 2013*

**Classical Mechanics Physics**

It might be better to indicate the equation rather than answers, because the data changes. So, we have: F-ff=ma (1) I.alpha=F.R-ff.r (2) and we have two equation ant variables. but alpha is a/R or a/r

*December 6, 2013*

**physic**

so I risked one chance and got: a) N=f.d/Vs b) dN/dt=f.Vobs/Vs c) f'=f(1-Vobs/Vs) and I thought for d: f'=f.Vs/(Vs-Vwind) but it's not right, I'll assume f' have to be bigger since, Vwind goes from source to observer.. but well, any suggestions?

*December 6, 2013*

**physic**

but, how did you do with D)???

*December 6, 2013*

**physic**

from a we have: N=f.d/Vs for b: N=f.(d+v.t)/Vs dN/dt=f.v/Vs

*December 6, 2013*

**ALGEBRA HELP**

B- spoe!!!

*October 21, 2013*

**physics what am i doing wrong?**

did you ever figure it out?

*November 16, 2012*

**Calc**

f(x)=x^3-3x^2-3x-8/(-3x^2-4x-6) Find the equation of the non-vertical asymptote. What is the smallest value of x at which f(x) intersects its non-vertical asymptote?

*March 11, 2012*

**math**

what percent of the total population believed saying to be true?

*January 3, 2012*

**Precalculus**

The Downhill Ski club is organizing a ski trip. Group tickets for the ski trip are priced at $20 for the first 100 skiers and a discount of $5.00 per ticket for each of the skiers over 100. a) write a formula to find the cost of x skiers. Answer: c(x)=2000+15(x-100), if x>...

*December 22, 2011*

**Precalculus**

@ Luckylin and Reiny, yes, no brackets

*December 22, 2011*

**Precalculus**

Would someone kindly verify these answers~ Thank you! --------------------------------------- 1.where does the reciprocal function of f(x)=3-x increase? a){XER|x>3} b){XER|x<3} c){XER|x≠3} d){XER} Answer: C ---------------------------------------- 2. What is the ...

*December 22, 2011*

**Math**

I have to rely on youtube and jiksha >.<

*December 21, 2011*

**Math**

I am in pre-calculus, and my teacher barely explains the content... As for question 1, there is no brackets in 2x-3 or x-2, I am not sure if it will make a difference to it

*December 21, 2011*

**Math**

Can someone help me with these. 1.Name any intervals on which f(x)=2x-3/x-2 is increasing or decreasing. 2. Find any horizontal asymptotes of f(x)=10/x+3.

*December 21, 2011*

**Math~Reinyyy**

Could someone help me with these questions, I don't know question c) and d) Consider the function f(x) = (0.1x-1)(x+2)^2. a) Determine the function's average rate of change on -2<x<6. Answer; Avg rate of change is -3.2 b) Estimate the instantaneous rate of change...

*December 20, 2011*

**Math**

Could someone help me with these questions, I don't know question c) and d) Consider the function f(x) = (0.1x-1)(x+2)^2. a) Determine the function's average rate of change on -2<x<6. Answer; Avg rate of change is -3.2 b) Estimate the instantaneous rate of change...

*December 19, 2011*

**Math**

So, question a is correct right? The answer is 0? As for question b, the question is wrong? there is no way to predict the average rate of change unless you calculate inside the bracketS?

*December 19, 2011*

**Math**

Verify if question a is correct I calcuated twice now and I am getting 0 as an answer. I don't understand question b a) Examine the function f9x) =2(0.5x-1)^2(x+2)^2. Determine the function's average of change from -2<x<2. I got answer: =0-0/-2-2 =0 Avg rate of ...

*December 19, 2011*

**Math**

Nevermind Thank you for clarifications!

*December 19, 2011*

**Math**

I did factoring and got this: f(x)=15x^2 -195x +950 500 = 15x^2 -195x + 950 0=15x^2 -195x + 950 - 500 0=15x^2 - 195x + 450 0=15(x^2 - 13x + 30) 0=15(x-10)(x-3) x=10 and x=3 It doesn't seem right~

*December 19, 2011*

**Math**

So do I have factor out the 15x^2 - 195x + 450, which will give me (x-?)(x-?)

*December 19, 2011*

**Math**

A stunt pilot is testing a new plane. The equation that models his height over time is f(x)=15x^2 -195x +950, where x is his the time in seconds and (fx) is his height in metres. Determine when the pilot is below 500 metres. I subbed in 500 for f(x) f(x)=15x^2 -195x +950 500...

*December 19, 2011*

**Math**

A stunt pilot is testing a new plane. The equation that models his height over time is f(x)=15x^2 -195x +950, where x is his the time in seconds and (fx) is his height in metres. Determine when the pilot is below 500 metres. Do i sub in 500 metres for f(x)?

*December 18, 2011*

**Math**

A stunt pilot is testing a new plane. The equation that models his height over time is f(x)=15x^2 -195x +950, where x is his the time in seconds and (fx) is his height in metres. Determine when the pilot is below 500 metres. Do i sub in 500 metres for f(x)?

*December 18, 2011*

**marketing**

What is a marketing plan? What does it provide? Briefly discuss strategy and tactics associated with a marketing plan.

*July 31, 2011*

**Marketing**

Consider any product or service you are familiar with and briefly discuss the four Ps. What initial strategy and tactic is used in each of the Ps.

*July 31, 2011*

**math**

differentiate y=e^x/(x)^(1/2).i need the calculation work.[ans: e^x/x^(1/2) - e^x/2x^(3/2)]

*July 20, 2011*

**home economics**

what are the advantages and disadvantages of a butcher and a fish monger

*October 1, 2010*

**English**

1. Her mother gave her hot soup. "a" is unnecessary because we are talking about SOME hot soup, not a specific container. You could, however, say "a bowl of hot soup" 3. A mouse is generally smaller than a rat. 4. Technically, you should pronounce every &...

*December 19, 2008*

**Physics**

A ball and a barrel roll down a 16m-long incline of height "h." Assume I equals 2/5mr^2 for the ball I equals 1/2mr^2 for the barrel. Prove that the ball reaches the bottom first.

*December 19, 2008*

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