Physics
The object located between F and 2F => the image will be located beyond the 2F point on the other side of the lens. It is real, inverted and its dimension is larger than the object demension. d₀ - object distance d₁ - image distance f- focal lenth 1/d₀ +1/...
Physics *Electrical Scientist* please help me!!!
http://www.tutorvista.com/science/jj-thomson-atomic-theory-0 http://en.wikipedia.org/wiki/Cathode_ray_tube
calculus
t=∛x =x^(1/3) => y=3x^5 = 3x^(5/3). dy/dx =3•(5/3)•x^(2/3) = =5 •125^(2/3)=525=125
Physics
d₀ - object distance d₁ - image distance f- focal lenth 1/d₀ +1/d₁ =1/f, 1/d₁ =1/f - 1/d₀ = = (d₀-f)/ d₀•f, d₁=d₀•f/(d₀-f)= =0.4•0.15/(0.4-0.15)=0.24 m, 0.03/0.4 =h/ d₁ , h= d₁•0....
Physics
mgsinα=F(fr) = μN= μmgcosα sinα= μcosα μ=tanα
calculus
s= 189t- t³ v=ds/dt = 189-3t² t=0 = > v=189 m/s. 189-3t² = 0 t=√(189/3) =√63 = 7.94 s. s=189 t- t³= =189(7.94) -7.94³=1000.1 m a=dv/dt =d(189-3t²)/dt= - 6t t=8 => a= - 6•8 = - 48 m/s²
physics
I=2mR²/5 ω=2π/T KE= Iω²/2
Physics
m₁gh= m₁v₁₀²/2 => v₁₀=sqrt(2gh) m₂gh= m₂v₂₀²/2 => v₂₀ =sqrt(2gh) m₁v₁₀ - m₂v₂₀= - m₁v₁ + m₂v₂ v₁= {-2m₂v₂₀...
Physics
C)λ, ν, and 100E
calculus (gr 12)
f(x) = 2x³+4x²-5x+8 f′(x) =6x²+8x-5 f′(-2) = 2(-4) ² +8(-2) -5 = 11
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