Already answered. math - MathMate, Saturday, May 28, 2011 at 11:00pm Here we have 10 digits, of which the first one cannot be zero. If the three digits are distinct, there are 9 choices for the first digit, still 9 (including zero) for the second, and 8 for the third. So 9*9*8...
Where is the road sign? What does Roseville have to d o with it?
a. If you are only given the value of Æ , you cannot deduce the value of the radius r. b. Æ = pi - 0.213 rad = 2.929 rad csc Æ = 4.739 c. cos Æ = -0.977 d. cot Æ = 1/(tan Æ )= - (8/(ã3)
If T is the half life in days (1.6)/2.0 = (T/156)^(1/2) 0.8 = 0.08006 T^1/2 9.992 = T^1/2 T = 99.8 days The decay constant k is related to the half life by k = ln2/T
Let the unit cube side be a. Its volume is a^3. Its area is 6a^2. The ratio is a/6. The inscribed sphere has a volume of (pi/6)a^3 and an area of pi*(a/2)^2*4 = pi a^2. The ratio is a/6. The inscribed right cylinder has a volume (pi/4)a^2*a = pi*a^3/4 and an area a*pi*a + 2 pi...
N = 2^1 + 2^2! + 2^(1000!)!) The last number has no ending digits as small as 2 or 4 006 would be the last three digits of the complete number.
Let the tension be T and the acceleration be a. Write separate free body diagram equations for the two weights T - 100g*sin37 = 100 a 70 g - T = 70 a 170 a = 9.82 g a = 0.058 m/s^2 Now solve for T
Physics Normal force
Yes. The "normal" force is the perpendicular component. There can be a parallel component as well.
20 kg wt = 200 Newtons Force Component along ground = 200*cos 60 = 100 N Work = 20 * 100 = 200 J
For the speed of the car (V), solve V^2/R = 2 m/s^2 V = sqrt400 = 20 m/s The centripetal force is (acceleration)*(Mass) = 2*2500 = 5000 N Centrifugal acceleration is the opposite of centripetal acceleration