8x-3y=-6, 5x+6y=75 multiply the top one by 2 16x-6y=-12, 5x+6y=75 add the two together 21x=63 can you take it from here?
I have a 40 ml solution of pH 4.36. I need to make this solution at pH 8.5 by adding extra 10 ml of HCl and NaOH. Not sure that this question entirley makes sense. However, if pH is 4.36 then pOH is 9.74 and [OH-] is 1.82 x 10^-10 M if target pOH is 5.5 then [OH-] is 3.16 x 10...
0n1 + 88X232 ---->ZYA element 88 is radium Ra 0n1 + 88Ra232 ---->88Ra233 There is either infromation missing in the question or is it Ra223 you are starting with? If so the question makes more sense 0n1 + 88Ra223 ---->88Ra224 and Ra 224 under goes alpha decay to 88Ra2...
I guess your college/school is using an automated response system like the Open Universitiy's iCMA system based on the response. It is difficult to guess what is missing as the formatting is different. My guess would be 2OH^-(aq)--> O_2(g)+2H^+(aq)+4e^-(aq)
I don't know your experiment, but the usual reason for diluting the titrating solution is so that there is a sensible volume. Looking at your question it looks as though the NaOH at 6M is 20x too concentrated, which means that if you are using 0.3M you will need 20x the vo...
The atomic nucleus has a + charge. A proton and an alpha particle (He nucleus) also have + charges, so what will happen if you sent one of these two towards a nucleus? The neutron has no charge.
It will depend on the gas. In some cases it is temperature and pressure. Others that react with water like CO2, these are also pH dependent.
Try here as well rpharms(dot)com/home/home(dot)asp and click on the link to 'about pharmacy'
Thionyl chloride first reacts with the alcohol to form an alkyl chloro sulfite, actually forming an intimate ion pair. The second step is the concerted loss of a sulfur dioxide molecule and its replacement by the chloride, which was attached to the sulfite group. SO not A) and...
Integrated Physics and Chemistry
Have a go at answering these and you might get a response. We are not here to do the homework for you.
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