Friday
April 18, 2014

Posts by DrPhysics


Total # Posts: 2

Quantum mechanics, eigenfunctions!
You are absolutely right. To be an eigenfunction, the operator has to reproduce the function with some multiplicative constant. Even without doing a lot of work, you can see for the special case of a=0 it doesn't work because you need to take four derivatives of sine to ge...

(expi)^i
This question is not well defined. By 'expi' do you mean exp(i)? In other words, is the expression [exp(i)]^i ? If so, then the answer is undoubtedly exp(-1). You can use Euler's equation to show this, but it is much easier to use this fact about exponents: (a^b)^c...

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