Not a very well worded question but here is how you do it. .........HA ==> H^+ + A^- I.......0.5.....0......0 C.......-x......x......x E......0.5-x....x......x (H^+) = x The problem tells you OH^- = 3.9 E-9. Use (H^+)(OH^-) = Kw = 1E-14, substitute OH and Kw and solve for H...
I gave you a link to this earlier.
By calculating it using Hess' Law.
In general, no. In whatever sense you're talking about, perhaps. I'm trying not to buy a pig in a poke here.
The first sentence ending with the question mark makes sense. The rest does not. The answer to the first sentence is No, serial dilution may start at any concn one chooses.
I would do this but you should confirm. I looked up the C-Cl bond energy in a text I have and it lists 330 kJ/mol. C + 4Cl ==> CCl4 dHrxn = (dHf products) - (n*dHf reactants) dHrxn = (-95.7) - (716.7 + 4*121.3) = about -1300 and that divided by 4 = about -325 or so. Then yo...
chem - instrumental analysis
Let x = #2 web and 2x = #1 web and 2x+3 = #3 web. Then x + 2x + 2x+3 = 18 and solve for x, 2x and 2x+3.
If solids are mixed together there is no reaction. If solutions are mixed the following occurs. AgNO3(aq) + KBr(aq) ==> AgBr(s) + KNO3 The addition of HBr to the solutions will have no additional effect; if HBr is added to the solids the liquid allows the solid salts to for...