You ended up with a quadratic? 0.8mol/2L = 0.4 M ..........2NOCl2 ==> 2NO + Cl2 I.........0.40........0.....0 C..........-2x........2x....x E.......0.40-2x.......2x....x I ended up with a cubic equation but I found a cubic calculator on the web and it returned 0.00395 for C...
Those look right to me.
Not having seen the video I have no idea what you're talking about.
0.2 mol x (6.02E23 atoms/mol) x 0.75 = ?
Neither equation you have written is a redox equation. Check them out. Nothing changes oxidation state (at least I don't think so unless you can point them out to me).
Use PV = nRT You have n.Substitute the new T and P. Remember T must be in kelvin and P in atmospheres. P of 700 mm = 700/760 atm
This is a limiting reagent problem. I now that because amounts are given for BOTH reactants. Write a balanced equation. 2Al + 3H2SO4 ==> Al2(SO4)3 + 3H2 Convert mols of each reactant to mols H2. Al first. 15.0 mols Al x [3 mols H2/2 mols Al) = 15.0 x 3/2 = 22.5 mols H2 gas....
4.3E5 x 9.2E7 = 3.96E13 which I would round to 4.0E13 since you are allowed only two significant figures.
Si + 2l2 ==> SiCl4 mols Si = grams/atomic mass = ? mols Cl2 = grams/molar mass. Convert mols Si to mols SiCl4 using the coefficients in the balanced equation. Convert mols Cl2 to mols SiCl4 the same way. It is likely these two numbers will not be the same which means one of...
preparation of Ag? determination? Ag can be used as the primary standard for analytical determination of Ag.
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