Have you tried 0.510 + 0.510*(6/3) + 0.510*(5/3) =? This is the longer way of working it. Your 3/14(0.510) is on the right track but conceptually not quite right. Actually, Pdiatomic = 0.510 = (3/14)Ptotal And Ptotal = ? You should get about 2.4 atm either way but that 2.4 is ...
All of that looks good EXCEPT for using 0.026M for concentration of the propanoate ion. That is not 0.026 because it has been diluted by the addition of the NaOH. You started with 100 mL of 0.026M acid, when you've added 200 mL of NaOH the salt concn is now 0.026 x (100/30...
Some elements are soft Others are not Dazzling sometimes In bright sunlight Unlike others such as a gas Metallic, of course, free at last I'll leave the punctuation up to you. I like poems that rhyme. I'd give myself an "F" on something like this.
No reaction given. 1. Write and balance the equation. 2. Convert 34.2g P to mols. mol = grams/molar mass. 3. Using the coefficients in the balanced equation, convert mols P to mols Cl2 gas. 4. Using PV = nRT, convert mols Cl2 gas (n) to volume. Remember T must be in kelvin.
K = (products)/(reactants) = 10^21 How do you get such a large number? With products high and reactants low. So E is the only answer that makes sense. Right?
Ya gotta complete it if you want help.
A = abc; slope = 0.433 which is a. Then 0.345 = 0.433*c. solve for c in mg/mL.
The first numeber is the atomic number followed by the element symbol followed by the mass number; thus 26Co60 is Co 60 (Co is element 26). 92U235 + 0n1 ==> 38Sr94 + yXz + 3 0n1 Atomic numbers must add up. Mass numbers must add up. Therefore, 92 + 0 = 38 + y + 0. Solve for ...
rate = 1/5 dBr^-/dt rate = dBrO3^-/dt(I assume you meant BrO3^- and not BrO)