chem word problem
(V1/T1) = (V2/T2)
molar mass HI = ? molar mas NH3 = ? The smaller molar mass diffuses faster. Are you calling velocity the same as rate? rate ratio NH3/HI = sqrt(MM HI/MMNH3)
2 M CaCl2 = 2 mols CaCl2/L soln. 2 mol = 111 x 2 = 222 g (but that's an estimate--you recalculate it). Use density to calculate mass of 1L soln. That will be 1145grams. mass solvent = 1145g-222g = ?g and convert to kg. Then mols Cl in CaCl2 = 4 (2*2) mols Cl in MgCl2 = 10 ...
CONFUSING QUESTION PLEASE HELP
The strongest reducing agent is the easiest to oxidize. The activity series is Li (not Li^+). Zn Sn H2 So Zn is at the top of the list of the elements/ions you have. Zn is the strong reducing agent.
If that is 5.88E-8 M, no. If you had shown your work I could tell you where you went wrong. The answer is closer to 1.2 or so x 10^-4.
CH3CH2CH2CH2CH3 is n-pentane. CH3CH2CHCHCH3 is 2-pentene. You have a pentavalent C on C #2 from the right end. Counting from the left it is 3-pentene but counting from the right it is 2-pentene. Which end do you start counting? The one that gives the smaller numbers.
1. mols HCl = M x L = ? mols NaOH = mols HCl mols NaOH = grams/molar mass. You know molar mass and mols, solve for grams. 2.mols NaOH = grams/molar mass = estimated 0.01 mols HCl = grams/molar mass = estimated 0.02. NaOH + HCl ==> NaCl + H2O 0.02 mols HCl - 0.01 mols NaOH =...
.......Ca^2+ + 2HCO3^- ==> Ca(HCO3)2 I.......1.0.....1.5..........0 Which is the limiting reagent? 1 mmol Ca^2+ will form 1 mmols Ca(HCO3)2 1.5 mmol HCO3^- will form 0.75 mmols Ca(HCO3)2; therefore, 0.75 mmols Ca(HCO3)2 will be formed. Then Ca(HCO3)2 ==> CaCO3 + H2O + CO...
PV = nRT
PV = nRT Remember V in L, P in atm, T in kelvin. R is 0.08206 L*atm/mol*K
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