Chemistry
C + O2 ==> CO2 mols C = grams/molar mass 1 mol C forms 1 mol CO2 Then grams CO2 = mols CO2 x molar mass CO2. This is the theoretical yield. %yield = (actual yield/theo yield)*100 = ?
Chemistry
6C12 is 1s2 2s2 2p2 so it has four outer shell electrons.
Chemistry
You should edit your post. I don't know what a bromited bromide ion is.
Chemistry
M x 2 = N; therefore, 3M = 6N Then 6N x mL = 12N x 20 mL Sole for mL.
chemistry
You check the numbers and number of significant figures. ......HCOOH ==> H^+ + HCOO^- Equil..0.00400...x.....x Ka = (H^+)(HCOO^-)/(HCOOH) Ka = (x)(x)/(0.004) Solve for x.
Chemistry
mols ethylene glycol = grams/molar mass, then m = mols/kg solvent. Freezing point depression is delta T = kf*m
Chemistry
You need to re-read the problem and see how impossible it is; however, I think I know what you are asking. You want a 15% solution of CaCl2 but you must use CaCl2.2H2O to make the solution. If that's what you're asking, do it this way. And I'm assuming that is 15 m...
CHEMISTRY
First, calculate the molarity of the concentrated solution of HCl. 1.18 g/mL x 1000 mL x 0.37 x (1/36.5) = approximately 12 M. Then mL1 x M1 = mL2 x M2 mL x 12 = 5000 x 0.25
CHEMISTRY
See your other post.
chemistry
Doesn't that depend upon how much it cost?
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