Monday

April 27, 2015

April 27, 2015

Total # Posts: 20,993

**Physics**

56.1 mi/h = 25.1 m/s v = Vi - a t 0 = 25.1 - a t so t = 25.1/a d = (1/2) a t^2 206 = a t^2 206 = a(630/a^2) = 630/a a = 3.06 m/s^2 (negative of course)
*January 19, 2015*

**Physics**

h = (1/2) g t^2 = 4.9 (3.12)^2
*January 19, 2015*

**Physics**

d = (1/2) a t^2 194 = 6.60 t^2 solve for t then v = Vi - 6.60 t = 0 at end Vi = 6.60 t
*January 19, 2015*

**Physics**

v = Vi + a t 104/3.6 = 74/3.6 + 1.52 t
*January 19, 2015*

**ap calc**

d/dx (2x+7)) = 2 so the 1/2 gets rid of the 2
*January 19, 2015*

**Physics**

but you forgot the work done against gravity m g * 500 = .05 * 9.81 * 500 = 245 J 1450 - 245 = 1204 J so 1204 = .05 * a * 500 =============================== The second one looks ok
*January 18, 2015*

**physics**

Aaaarrrgghhhhh !!!!! Joey is right. At the top v = 0, no velocity except that of mother earth spinning on her axis and making her way around the sun. The acceleration is constant, -9.81 m/s^2 the whole time. Charlie could not possibly, any way, be more wrong. Send him to his ...
*January 18, 2015*

**Physics**

t = 4.2 T = 8 a = 5 I guess it started from a dead stop. x = (1/2) a t^2 during acceleration Vi = speed at end of acceleration = a t X = Vi T during constant speed so distance = (1/2) a t^2 + Vi T
*January 17, 2015*

**Math**

32 = 8 * 4 56 = 8 * 7 so 32 + 56 = 8 (4+7)
*January 15, 2015*

**MATH**

how much of the 40 hours he works at each job
*January 15, 2015*

**Torque**

Huh? 30 * 1.5 = 45 BUT 60 * 1 = 60
*January 15, 2015*

**physicsss**

You are welcome.
*January 15, 2015*

**physicsss**

If the velocity is constant you are correct.
*January 15, 2015*

**Physics**

work done in stopping = brake force * 75 meters (1/2) m v^2 = work done by brakes (1/2) m (93)^2 = F * 75 F = m (57.66) but F = ma so a = 57.66 that is the acceleration the tires can give you. Use it for centripetal acceleration a = 57.66 = v^2/r r = (93)^2/57.66
*January 15, 2015*

**Physics**

mu m g = m v^2/r = m omega^2 r mu g = omega^2 r omega = 2 *2pi radians/s = 4 pi rad/s mu = .4 g = 9.81 so r = .4 * 9.81 /16 pi^2 = .0248 meters = 2.5 cm
*January 15, 2015*

**Physics**

m v2/r
*January 15, 2015*

**No picture**

If you drew a picture, we can not see it.
*January 15, 2015*

**Alegebra**

Huh? how can it be even and 9 ????
*January 15, 2015*

**physics**

Without friction, the angular velocity will not change. In real fife of course it will. Even in the vacuum there is loss of kinetic energy to the bearings. However as far as the information given here, the answer is constant angular velocity forever. or at least for a very ...
*January 15, 2015*

**Physics**

Vi = 15 sin 30 = 7.5 v = Vi - gt v = 0 at top so g t = 7.5 t = 7.5/9.8 = about .77 s
*January 15, 2015*

**Calculus POwer RUle**

dy/dx = -3 k x^2 3 = -3 k (4) k = -1/4
*January 14, 2015*

**Math**

b = 2 r b - r = 24 2 r - r = 24 r = 24 b = 48
*January 14, 2015*

**math**

16 x = x^2 x^2 -16 x = 0 x(x-16) = 0 x = 0 or x = 16 y = 0 or y = 256 (0,0) and (16 , 256)
*January 14, 2015*

**calculus**

If 5x2 + y4 = -9 then evaluate d^2y/dx^2 when x = 2 and y = 1 5 x^2 + y^4 = -9 10 x + 4 y^3 dy/dx = 0 so dy/dx = -2.5 x/y^3 d^2y/dx^2=-2.5[ y^3 - 3 x y^2 dy/dx]/y^6 at (2,1) dy/dx = -2.5(2/1) = -5 so d^2y/dx^2=-2.5[1-6(-5)]/1 = -2.5 [ 31] = - 77.5
*January 14, 2015*

**calculus**

Find the slope of the graph of the relation x2y + 4y = 8 at the point (2, 1) (x^2+4)y = 8 (x^2+4)dy/dx + y (2x) = 0 8 dy/dx + 4 = 0 dy/dx = -1/2
*January 14, 2015*

**calculus**

f(x)=(x+1)^2x d/dx u^v = v u^(v-1)du/dx + u^v lnu dv/dx so f'=2x(x+1)^(2x-1) + 2(x+1)^2x ln(x+1)
*January 14, 2015*

**calculus**

x^2 + y^2 = 2 x y 2 x + 2 y dy/dx = 2 x dy/dx + 2 y dy/dx (y-x) = y-x dy/dx = 1 easier way without using calculus: x^2-2xy+y^2 = 0 (x-y)(x-y) = 0 x = y slope = 1
*January 14, 2015*

**calculus**

y = 7 x^6 cos^-1 x f' = 7[ x^6 (1/(1-x^2)) + 6x^5 cos^-1 x ] = 7 x^6/(1-x^2) + 42x^5 cos^-1 x
*January 14, 2015*

**history**

LOL - well, to start with which ? TR or FDR ? You better Google which ever president you mean because it would take all night to summarize.
*January 14, 2015*

**science**

NaCl = 23 + 35 = 58 g/mol 22/58 = .379 mol .379 mol/ .2 liter = 1.9 M
*January 14, 2015*

**Math**

Get it now. When you subtract you reverse the sign of the bottom one and add.
*January 14, 2015*

**Math**

y=-x+4 y=-2x-4 ------------- SUBTRACT these two equations 0 = -x -(-2x) + 4 - (-4) 0 = -x + 2x + 4 + 4 0 = x + 8 x = -8
*January 14, 2015*

**Math**

y = -x + 4 y = -(-8) + 4
*January 14, 2015*

**Math**

for elimination subtract as is y=-x+4 y=-2x-4 ------------- 0 = 1 x + 8 so x = -8 then get y = 8+4 = 12
*January 14, 2015*

**Math**

I did the earlier ones with elimination here is substitution y = (-x+4) so (-x+4) = -2x - 4 x = -8 then go back and get y y = -x + 4 = 8+4 = 12
*January 14, 2015*

**Math**

You are welcome.
*January 14, 2015*

**Math**

10 x - 8 y = 20 -10 x + 2 y = -20 ----------------- add 6 y = 0 y = 0 if y = 0 5 x = 10 x = 2 so the two lines intersect at (2 , 0)
*January 14, 2015*

**calculus**

1. If f(x) = ln(1 - 2x), then find f '(x) f' = [ 1/(1-2x) ]( -2) = -2/(1-2x) = 2/(2x-1) I do not understand your second function
*January 14, 2015*

**Math**

check it then 2 (9) - 5 (-7) = 53 ? yes -9 +5(-7) = -44 ? yes so it is right, why ask ? :)
*January 14, 2015*

**Calculus**

x = 15 t h = 5 t + 5 = 5(t+1) y^2=x^2+h^2 = 225t^2 + 25t^2 + 50 t + 25 y^2 = 250 t^2 + 50 t + 25 2 y dy/dt = 500 t + 50 now at t = 3 y^2 = 250(9)+150 +25 = 2425 y = 49.2 so 2(49.2) dy/dt = 1500 + 50 = 1550 dy/dt = 15.8 m/s
*January 14, 2015*

**Math**

add the two equations as is x = -10 5 y = 50 y = 10
*January 14, 2015*

**physics**

easier way work done = final (1/2) m v^2 4310 = (1/2)2520 v^2 v = 1.85 m/s ;)
*January 14, 2015*

**physics**

change of momentum = 2520 v average force = change of momentum/time F = 2520 v/t work = force * distance 4310 = 2520 v/t * 22.4 or v/t = .0764 or t = v/.0764 now if force were constant d = (1/2) a t^2 44.8 = a t^2 v = a t so a = v/t so 44.8 = v t = v^2/.0764 v^2 = 3.42 v = 1....
*January 14, 2015*

**Sixth Grade Math**

m = p - 3 = 51 - 3 = 48 yes, you did it right. Either the question was meant to be confusing or the person who wrote the question never asked the more complicated question he/she had in mind :)
*January 14, 2015*

**Socal Studies**

sorry: http://science.kqed.org/quest/2007/12/12/snakes-are-not-poisonous/
*January 14, 2015*

**physics**

mass has nothing to do with this work = force * distance in direction of force = 4.67 * 10^5 * 528 Joules
*January 14, 2015*

**Math**

multiply the second equation by 2 5 x - 4 y = 10 -20x +4 y = -40 ------------------ mow add -15 x = -30 x = 2 etc
*January 14, 2015*

**history**

You are welcome.
*January 14, 2015*

**history**

here: http://en.wikipedia.org/wiki/Iron_Brigade and Texas was very, very important to the Confederacy.
*January 14, 2015*

**history**

Oh my, oh my, you better Google Minnesota and Michigan Gettysburg
*January 14, 2015*

**Math**

24.8 / 0.6 = 41.3
*January 14, 2015*

**Math**

100 * 1382.5/27650 = 5 %
*January 14, 2015*

**english**

http://www.jiskha.com/display.cgi?id=1421282361
*January 14, 2015*

**english**

I did, scroll down to where you first posted this question.
*January 14, 2015*

**english**

( It is a real marine biology subject )
*January 14, 2015*

**english**

I gave you a reference for the lobster and the cod. Try. Read the article and see if you can come up with something.
*January 14, 2015*

**us history**

http://www.bostonmassacre.net/timeline.htm
*January 14, 2015*

**English**

might help: http://www.gma.org/lobsters/allaboutlobsters/society.html
*January 14, 2015*

**English**

Do cod eat baby lobsters? Do lobsters eat cod fingerlings? Are populations of both species likely to peak at the same time? ( I am more into math than English. )
*January 14, 2015*

**chemistry**

P1 V1 = P2 V2 P2 = 3 P1 P1 V1 = 3 P1 V2 so V2 = V1/3 = 5/3 liters
*January 14, 2015*

**Math**

(25/1000)(112000 = 2,800
*January 14, 2015*

**math**

1.325/.304 = 4.4
*January 14, 2015*

**math**

1.333 *1000 feet * (1 mile/5280 feet) = 1333/5280 = 0.2525 miles = 0.25 a little over a thousand feet is a little over a quarter of a mile by the way the Marianas Trench is more like 30,000 feet deep or over five miles
*January 14, 2015*

**algebra**

s = 2 k s-10 + k-10 = 23 s + k = 43 2 k + k = 43 3 k = 43 k = 43/3 = 14 1/3 s = 28 2/3
*January 14, 2015*

**science**

1. charged 2. pull 3. motion, work, potential energy(voltage), kinetic energy - beats me what they want her to say
*January 14, 2015*

**Hist**

It is not d.
*January 14, 2015*

**Physics**

A has a lower specific heat (heat capacity) Q = m C (T2-T1) for the same Q, lower C means bigger temp change
*January 14, 2015*

**Engineer**

You are welcome of course. Google water clock by the way.
*January 14, 2015*

**Engineer**

Water flows down because of gravity.
*January 14, 2015*

**Physics C**

force = E q force * distance = work done = Ke = Eqd so .880 = 64.0 * q * 0.500 solve for q
*January 14, 2015*

**Math**

Any time :)
*January 14, 2015*

**Math**

4 x = -12 x = -3 indeed
*January 14, 2015*

**Math**

Yes, that is correct
*January 14, 2015*

**Math**

3 (p - .35) = 3.45
*January 14, 2015*

**physics**

How far up from earth surface? 6.92 sin theta where theta is the angle up from horizontal mg opposite to up motion so g does negative work so - m g sin theta * (6.92)
*January 14, 2015*

**Algebra 1**

(2.5*10^-9)(1.5*10^3) = 3.75*10^-6 yes
*January 14, 2015*

**math**

7 (41/10) = $28.70
*January 14, 2015*

**Math**

t = 2h-4 h = 6 so t = 12-4 = 8 legs
*January 14, 2015*

**Math**

J + S + D = 5416 J = 1615 S = 6 D so 1615 + 6 D + D = 5416 7 D = 3801 D = 543 so S = 6 D = 3258
*January 14, 2015*

**Math**

.4 is bigger than .3
*January 14, 2015*

**Math equation**

No problem :)
*January 14, 2015*

**Math equation**

4 n = 6-5 = 1 n = 1/4
*January 14, 2015*

**Math equation**

I do not know for question 1. It could be + or -. My guess is that you are right. question 2 is 4 n - 6 = -5
*January 14, 2015*

**math**

(115 words/3 min)(7 min ) = 268
*January 14, 2015*

**math**

You are welcome ;)
*January 14, 2015*

**math**

elevation angle A = 45 degrees = pi/4 radians tan A = h/25 d tan A/dA = sec^2 A = (1/25) dh/dA so 25 sec^2 A * dA/dt= dh/dt = 5 dA/dt = (1/5) cos^2 A but cos^2 A = 1/2 dA/dt = .1 radians/second So I agrees but maybe you want degrees? .1 Rad/s( 180 deg/rad) = 18 degrees/second
*January 14, 2015*

**Math**

You are welcome.
*January 14, 2015*

**Math**

$20 per thousand ? 20*80 = 1,600
*January 14, 2015*

**Algebra 2 ( I doubt it)**

I bet you mean 9 x^2 - 100 (3x-10)(3x+10)
*January 14, 2015*

**trigonometry**

[sin T/cos T + cos T/sin T] /( sin T/cos T) = [ sin T + cos^2 T/sin T ]/ sin T = [ sin^2 T + cos^2 T ] /sin^2 T = 1/sin^2 T = csc^2 T
*January 14, 2015*

**algebra 1**

You are welcome.
*January 14, 2015*

**algebra 1**

If it is all under that square root sign then divide all the exponents by 2 25 x^2 z^4 y
*January 14, 2015*

**Math.**

You are welcome.
*January 14, 2015*

**Math.**

w = .5 x .5 * 120 = 60 grams
*January 14, 2015*

**math**

Mars 100 * 56.55/150 = 37.7% Moon 100 * 24.9/150 = 16.6% (about 1/6, remember that) Mars .377 x Moon .166 x .166 * 180 = 29.9 pounds (note 180/6 =30) 180 * 2.364
*January 14, 2015*

**math**

A. (x^1/2)^4√x^6 x^2 x^3 = x^5 B. I do not know if you mean (x^4)^.5 y^12 or (x^4 y^12)^.5 if the second then x^2 y^6 C if you mean (a^6 b^3)^1/3 then indeed a^2 b I am at a loss with your notation
*January 14, 2015*

**Physics 10 (helppp please) thannnks**

delta L/L = w /(E A) .008/120 = w/(E*6) w = 6 E * .008/120
*January 14, 2015*

**physica science**

When they are both in the same direction and therefore add. |R| = |A| |B| cos theta |cos theta| </= 1 for all theta and is max of 1 when theta = 0 5+7 = 12 If theta is the angle between vectors.
*January 14, 2015*

**algebra**

(-25/10)(1/A^2)( B^4) -25 B^4/(10 A^2)
*January 14, 2015*

**Physic**

https://iit.edu/arc/workshops/pdfs/Magnetic_Field.pdf
*January 14, 2015*