Algebra
the smallest of those numbers is(2) (3) 135 has one bigger and one smaller so it is the median the biggest is (1)
physics
initial speed up Vi = 1000 sin 45 = 707 m/s v = Vi - 9.81 t when v = 0, we go no higher t = 707/9.81 = 72 seconds upward h = Vi t - (1/2) 9.81 t^2 h = 707 (72) - 4.9 * 5184 = 50904-25427 25,000 m u = horizontal speed = 1000cos 45 = 707 u t = 707 * 2*72 = 102,000 m
calculus
-5 e^(-5x) - 3 sin x cos^2 x 3 (x^2 - x + 1 )^2 (2x - 1)
mathematics
m^2 - 8 m + k (m-x)(m-x) = m^2 -2 x m + x^2 so 2 x = -8 x = -4 x^2 = 16 = k so m^2 - 8 m + 16 in general to complete the square 1 x^2 + b x + c if that is to be a perfect square c = (b/2)^2
mathematics
change = +2 so -3 + 7(2) = -3 + 14 = 11
physics
weight = 700 + 400 = 1,100 x is distance from the strong person 1100 x = 400(2) x = 8/11 meters from the person lifting with 700 N
Physics
assume boom weighs 2450 Newtons HAVE to Know Length of boom (I will call it L) clockwise moments about base of boom 5000 L cos 60 + 2450 (39) cos 60 counterclockwise moments T L sin 60 so T = (5000 L + 2450(39) )cos 60/(L sin 60)
Algebra 2/ Trigonometry
(1-sin^2)/sin + sin 1/sin - sin + sin 1/sin = csc
Algebra 2/ Trigonometry
cos^2 = c I suspect typo 1 - sin^2 = c sin^2 = 1 - c sin^2 /2 = (1-c)/2 not 1 - c/2 I am not a mind reader. Please check what you type to make sure it makes sense.
Algebra 2/ Trigonometry
4 - (1-sin^2 A) so suspect another typo 4 + cos^2 A 4 + (1-sin^2 A) 5 - sin^2 A
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