Wednesday

November 25, 2015
Total # Posts: 22,914

**Algebra(please help ASAP!)**

109/3 = 36 1/3 so 37 in that direction 103 /3 = 34 1/3 so 35 in that direction 37 *35 = 1295 remember you will have some fractional tiles left over, but you need enough to reach the walls after trimming
*November 11, 2015*

**Algebra(please help ASAP!)**

http://www.jiskha.com/display.cgi?id=1447261918
*November 11, 2015*

**Algebra**

2 b (a+c) = 3 2 a b + 2 b c = 3 2 a = (3 -2 b c)/b a = (3 - 2 b c)/ (2 b)
*November 11, 2015*

**Algebra**

y = |x+2| -3 first look at the graph of |x-3| it is zero at x = 3 and goes up both ways from there with slope = 1 like the letter V now move that whole graph down 3
*November 11, 2015*

**Algebra**

6x = -18 -y = -2 so -20
*November 11, 2015*

**AP Physics**

weight force down slope = m g sin 17.5 = 1025 (9.81) sin 17.5 = 3023 N distance = 290 in direction of needed force so Work = 3024 N * 290 m = 876,865 Joules By the way if you do it in 10 minutes which is 600 seconds that is 876,865/600 = 1,461 watts You need about 2 horsepower :)
*November 11, 2015*

**AP Physics**

Force * 2700 meters = 80,000 Joules Force = 80/2.7 Newtons
*November 11, 2015*

**World history**

Mathematics and observation. Start with Copernicus unwinding astronomy. Perhaps close with Newton.
*November 10, 2015*

**Math**

distance = 8 * .75 = 6 km time down = 6/24 = 1/4 hour total time = 3/4 + 1/4 = 1 hour total distance = 12 km so average speed = 12 km/hour
*November 10, 2015*

** Huh??**

It is a little hard to compute anything with the information given.
*November 10, 2015*

**Algebra 2**

3. -4x^2 + x + 5 + 2 = -4 x^2 + x + 7
*November 10, 2015*

**Algebra 2**

=21x-36^2-1 You mean -36 x^2 + 21 x - 1
*November 10, 2015*

**Algebra 2**

1. agree 2. agree 3. agree 4. agree
*November 10, 2015*

**Jake**

please read my reply above !
*November 10, 2015*

**Unit 1**

no, only if you multiply or divide by negative do you reverse direction 3 h + 1 > -26 3 h > -27 h > -9 check, for example if h = 0 1 is > -26 yes
*November 10, 2015*

**Unit 1**

| p - 4 | < 9 (p - 4) < 9 or (4 - p) < 9 p < 13 or -p < 5 p < 13 or p > -5 so -5 < p < 13
*November 10, 2015*

**Algebra**

No, retired professor of engineering
*November 10, 2015*

**Algebra**

yes S = 50 x - x^2 dS/dx = 0 = 50 - 2x so x = 25 S = 50(25) -625 = 625 sure enough
*November 10, 2015*

**Math**

2^(x+2) - 2^x = 24 2^2 * 2^x - 2^x = 24 (2^x) (4-1) = 24 2^x = 8 well x = 3 works :) ======================= check : 2^5 - 2^3 32 -8 24 sure enough
*November 10, 2015*

**Unit 1**

F = 55 + 4 y S = 95 - 6 y so when does F = S ? 55 + 4 y = 95 - 6 y I bet you can do it now.
*November 10, 2015*

**Physics**

Ac = v^2/R = 3.70 v^2 = 3.7 * 0.64 solve for v F = m Ac = 0.78 * .70
*November 10, 2015*

**Unit 1**

distance between = 90 t if t is in hours and d is in miles
*November 10, 2015*

**Math**

n = 3 h - 100 n + h = 300 so 3 h - 100 + h = 300 4 h = 400 h = 100
*November 10, 2015*

**algebra**

n = 2 q 5 n + 25 q = 175 so 5 (2 q) + 25 q = 175 35 q = 175 q = 5 so n = 10
*November 10, 2015*

**Physics**

ok, I will do it all out beginning Ke = (1/2)(77)(1.44)= = 55.44 Joules final Ke = (1/2)(77) (8.5)^2 = 2782 Joules gain in Ke = 2782 - 55.4 = 2726 Joules drop in Potential energy U = 77*9.8*1.6 1207 Joules so 2726 -1207 = 1519 Joules came from something else non-conservative, ...
*November 10, 2015*

**Maths**

4/7 + 2/5 + s = 1 20/35 + 14/35 + x = 35/35 x = 1/35
*November 10, 2015*

**Geometry**

yes
*November 10, 2015*

**Algebra**

4:00 is 120 degrees on the hour hand (4/12)*360 35/60 * 360 = 210 210 - 120 = 90 of course the hour hand has moved about 35/60 * 360/12 = 17.5 degrees so 90 - 17.5 = 72.5 agree
*November 10, 2015*

**Algebra**

bottom is square x by x h x^2 = 4 x^8 + 3 x^6 so h = 4 x^6 + 3 x^4
*November 10, 2015*

**Math**

http://www.jiskha.com/display.cgi?id=1447186689
*November 10, 2015*

**Physics**

1.2^2 = 1.44 sorry energy gained = (1/2)(77)(8.5^2-1.44)
*November 10, 2015*

**Physics**

initial Ke = (1/2) 77 * 1.44 final Ke = (1/2) 77 (8.5)^2 energy gained = (1/2)(77)(8.5^2-1.44^2) energy that should have been gained = m g (1.6) = 77 * 9.81 * 1.6 non conservative work = final energy gained - what it should have been
*November 10, 2015*

**math101**

I can not help you train jazzy :)
*November 10, 2015*

**math101**

ok, good luck, study what you have worked on here.
*November 10, 2015*

**math101**

nope 1/14 is the end. One / anything can not be reduced
*November 10, 2015*

**math101**

oh well, better learn prime factors and least common denominator.
*November 10, 2015*

**math101**

Go back over those. The last one looks like the next chapter :)
*November 10, 2015*

**math101**

factor 7 = 1 and 7 factor 2 = 1 and 2 so LCD = 2*7 = 14 4/7 = 8/14 1/2 = 7/14 ----------- subtract answer 1/14
*November 10, 2015*

**math101**

yes .125 = 1/8 but .125 * 100 = 12.5 % not 125 %
*November 10, 2015*

**math101**

1/8 is smaller than 1 125% is bigger than 1 no way the same :) percent to decimal divide by 100 decimal to percent, multiply by 100 100/8 = 12.5
*November 10, 2015*

**math101**

1/8 = 0.125 =times 100 = 12.5 % be more careful
*November 10, 2015*

**math101**

(4/3) [ x / (4/3) ] = (7/8 )(4/3) x = (7/2)(1/3) x = 7/6 or 1 1/6 ========================== check (7/6)/(4/3) = (7/6)(3/4) = 21/24 = 7/8 right check
*November 10, 2015*

**math101**

I think that means x / (4/3) = 7/8 multiply both sides by (4/3)
*November 10, 2015*

**math101**

LOL getting tired ?
*November 10, 2015*

**math101**

good dividing by 6/5 is multiplying by 5/6
*November 10, 2015*

**math101**

check : (6/5) (1/12) = 6/60 = 1/10 check :)
*November 10, 2015*

**math101**

(5/6) (6/5) x = (5/6)(1/10) 1 x = 5/60 but 5/60 = 1/12
*November 10, 2015*

**math101**

well, same as multiply by 5/6
*November 10, 2015*

**math101**

which is 2/3
*November 10, 2015*

**math101**

x + 2/3 - 2/3 = 4/3 - 2/3
*November 10, 2015*

**math101**

NO SUBTRACT 2/3
*November 10, 2015*

**math101**

multiply both sides by 21
*November 10, 2015*

**math101**

which is 13 :)
*November 10, 2015*

**math101**

52 x / 52 = 676 / 52 or x = 676 / 52
*November 10, 2015*

**math101**

yes, divide both sides by 52
*November 10, 2015*

**math101**

x-3.5=18.7 x - 3.5 + 3.5 = 18.7 + 3.5 x + 0 = 22.2
*November 10, 2015*

**math101**

18.7 + 3.5 = 22.2 you have a typo
*November 10, 2015*

**math101**

I do not know what undoing means but try adding 3.5 to both sides
*November 10, 2015*

**math101**

by the way 4/3 is 1 1/3
*November 10, 2015*

**math101**

yes, good
*November 10, 2015*

**math101**

Ms. Sue - we have been at this for quite a while, just working it out :)
*November 10, 2015*

**math101**

150/100 = 1.5 just follow the recipe
*November 10, 2015*

**math101**

yes?
*November 10, 2015*

**math**

(n/-3) >-1 ? multiply both sides by -3, that changes direction of arrow n < 3 check if n = 0 5>4 yes if n = 3 -1 + 5 = 4 yes
*November 10, 2015*

**Math (algebra)**

9 x^2 -15 x -21 x + 15 which is 9 x^2 - 36 x + 15
*November 10, 2015*

**Physics**

You are welcome.
*November 10, 2015*

**Physics**

once you have Va and Vb Ke before = (1/2) m Via^2 Ke after = (1/2) m Va^2 + (1/2) m Vb^2 note m cancels everywhere in this problem I think you can do the lost over the initial
*November 10, 2015*

**Physics**

Va is the speed of A after collision
*November 10, 2015*

**Physics**

so you can solve for Va, the speed of A after then for Vb the speed of B after
*November 10, 2015*

**Physics**

so Via = 40 You did not say that use it
*November 10, 2015*

**Physics**

Vb = Va sin 30/sin 45 then Via = Va cos 30 + (Va sin 30/sin 45)cos 45
*November 10, 2015*

**Physics**

You have to use the two equations I derived to get Va and Vb in terms of Via, the initial speed of A then you can do the x and y components
*November 10, 2015*

**Physics**

momentum x = m Via momentum y = 0 after m Via = m Va cos 30 + m Vb cos 45 0 = m Va sin 30 - m Vb sin 45
*November 10, 2015*

**Math**

80=<(82+88+n)/3=<85 80*3 = 240 82 + 88 = 170 240</= = 170+n n>/= 70 85*3 = 255 n + 170 </= 255 n </= 85 so d
*November 10, 2015*

**Math**

hey, I think you can solve those two equations !
*November 10, 2015*

**Math**

d = 130 - 25 t or d = -(130 -25 t) = -130 + 25 t
*November 10, 2015*

**math**

3 a - 4 </= 5 3 a </= 9 a </= 3
*November 10, 2015*

**Math**

assume your symbol is upside down U or intersection, in both where circles overlap 2 in both 4 6 8 even numbers up to 8 looks like d
*November 10, 2015*

**math**

****** + ****** = ****** ****** which is 12 count them
*November 10, 2015*

**Math**

whew, great !
*November 10, 2015*

**Math**

all but the 70 who downloaded CD only That is 340
*November 10, 2015*

**Math**

220 = both 290 -220 = 70 = CD only 410 - 70 = download = 340
*November 10, 2015*

**Math**

1.25 x >/= 150 x >/= 120 a
*November 10, 2015*

**Math**

x + (x+5) = 70 2 x = 65 x = 32.50 x+5 = 37.50
*November 10, 2015*

**Math**

Just do it 1 2 3 4 6 8 12 24
*November 10, 2015*

**Math**

No has to be greater than, not equal to so d
*November 10, 2015*

**Math**

12 < 8 y - y^2 or 8 y - y^2 > 12 now is 8*2 - 4 > 12 I think not but 8*3 - 9 = 24 - 9 = 15 which is
*November 10, 2015*

**Math**

c >/= 325 - 135 - 89 c >/= 101 so 101 or more
*November 10, 2015*

**pre algebra**

12.25 % = 0.1225 yes
*November 10, 2015*

**pre algebra**

better start a new question. This scrolling is getting a bit much.
*November 10, 2015*

**pre algebra**

to get decimal from percent divide percent by 100
*November 10, 2015*

**pre algebra**

divide by 100 8% = 8/100 = 0.08
*November 10, 2015*

**pre algebra**

I would go with only 0.03 x
*November 10, 2015*

**pre algebra**

I guess so, but I would never write x0.03
*November 10, 2015*

**pre algebra**

I think so although I would have written x * 0.03 0.03x is clear x0.03 is confusing
*November 10, 2015*

**pre algebra**

Yes they are equivalent
*November 10, 2015*

**pre algebra**

the one with the / is right :)
*November 10, 2015*

**pre algebra**

I know what you mean, but it is not used in algebra I was a college professor, engineering.
*November 10, 2015*

**pre algebra**

oic, there is none, / is always used but division symbol not normally used in algebra x/3 would be normal or x --- 3 maybe :)
*November 10, 2015*