Wednesday

March 1, 2017
Total # Posts: 29,472

**Math**

24 x^2 = 3*4.5 = 13.5 x^2 =13.5/24 so x^2 = .5625 feet^2 *144 in^2/ft^2 = 81 inches^2 so 9 inches on a side

*February 6, 2017*

**Algebra**

sketch graph at x = -oo it goes to -oo at x = -1 it is +6 at x = 0 it is-2 at x = +oo it is +oo SO it crosses the x axis three times, three real roots

*February 6, 2017*

**Math PROBABILITY part 1**

3/36 = 1/12 are less than 4 1,1 1,2 2,1 ================== IF you mean < or = 4 THEN 6/36 = 1/6

*February 6, 2017*

**Math PROBABILITY part 1**

1 though 6 horizontal and 1 - 6 verrtical chat 36 possible rools 9 have up two odd 9/36 = 1/4 so I bet B

*February 6, 2017*

**Math PROBABILITY part 1**

4/9 + 7/18 + x = 18/18 15/18 + x = 18/18 x = 3/18 = 1/6 which is a

*February 6, 2017*

**Math PROBABILITY part 1**

yes, 5/8 yes 4/9 next, problems

*February 6, 2017*

**PHYSICS**

1.3*.4 = .52 .7*.4 = .28 total distance = .8 total time = 1.1 av speed = .8/1.1 = .73 m/s

*February 6, 2017*

**math plzzz help quick**

You are welcome.

*February 6, 2017*

**math plzzz help quick**

2x = y-14 so -4x = -2(y-14) = -2y + 28 use that for -4x in equation 2 (-2y+28) - y = 4 -3 y = -24

*February 6, 2017*

**physics**

Vi = 14 a = -3.3 v = Vi + a t at stop, v = 0 0 = 14 - 3.3 t 3.3 t = 14 for half time if t = 7/3.3 v = 14 - 3.3 (7/3.3) v = 14 - 7 = 7 on the nose then

*February 6, 2017*

**math plzzz help quick**

yes

*February 6, 2017*

**math plzzz help quick**

rewrite first one x = y -11 use that for x in the second one y + 7 = -2(y-11) y + 7 = -2 y + 22 3 y = 15 y = 5

*February 6, 2017*

**Algebra**

divide by factor (x+2) (x^3 – 3x^2 – 6x + 8)/(x+2) = x^2-5x+4 which is (x-4)(x-1) so 4 and 1

*February 6, 2017*

**electricity**

15 = 60R/(60+R) 900 + 15 R = 60 R 45 R = 900

*February 6, 2017*

**Physics**

m v^2/R = 600 0.8 v^2/0.9 = 600

*February 6, 2017*

**modern worl studies connexus**

6 NO WAY!!! 9 Canada has its own monarch ??? First I heard of it, and I row against them up there in Nova Scotia.

*February 6, 2017*

**math**

4 works for 1, 4 or 4 people 6 works for 1, 2 , 3 or 6 people

*February 5, 2017*

**math**

READ That was the CHECK James is 48

*February 5, 2017*

**math**

Jo + 5 = Ja/3 Jo - 3 = Ja/6 -------------- subtract 0 + 8 = Ja(1/3 - 1/6) Ja (2/6-1/6) = 8 Ja = 6*8 = 48 =========================== check Ja = 48 Jo = 3 + Ja/6 = 3 + 8 = 11 then 11+5 = ??? 48/3 16 = 16 sure enough

*February 5, 2017*

**need info**

Please type entire problem. Without knowing the density of the logs or the mass of you and your friend, no way. call log density rho call g = 9.81 m/s^2 water density = 1000 kg/m^2 mass of passengers = m n = number of logs n * .13^2 *2.2 = V, needed volume of logs 1000 g V = B...

*February 5, 2017*

**mechanics**

F1 = f in x direction F2 = f cos 60 in x and f sin 60 in y total x = f +f cos 60 = 1.5 f total y = f sin 60 = [sqrt3/2]f magnitude of resultant = sqrt [ 1.5^2 f^2 + 3/4 f^2 ] = f sqrt [2.25 +.75 ] = f sqrt 3

*February 5, 2017*

**Phycis**

(1/2 )m v^2 + m g h = 1470 so Ke = 1470 - m(9.81)25 to get a numerical answer you need to know m

*February 5, 2017*

**Physics**

with constant acceleration a: v = Vi + a t x = Xi + Vi t + (1/2) a t^2 here Vi = Xi = 0 so x = (1/2)at^2

*February 4, 2017*

**math**

Fid = Fif + 26 Fif = R-12 so R = Fif+12 Fid + Fif + R = 71 Fif+26 + Fif + Fif+12 = 71

*February 4, 2017*

**physics**

2.2*10^4 = mg + ma =2150(9.81+a)

*February 4, 2017*

**Calculus**

http://www.jiskha.com/display.cgi?id=1486194050

*February 4, 2017*

**value**

75/3 = 25

*February 4, 2017*

**distance ?**

You have to know some distance in the problem. Otherwise you just have similar triangles of arbitrary size.

*February 4, 2017*

**maths**

well, go ahead. 30, 60, 90 triangle side opposite 30 = 5.6 sin 30 side opposite 60 = 5.6 sin 60

*February 4, 2017*

**Calculus**

tangent of angle above x axis = 35/42 magnitude = sqrt (42^2+35^2)

*February 4, 2017*

**Math**

0 to 9

*February 4, 2017*

**Physics**

F = G Mm m /Rm^2 F/m = G Mm/Rm^2 = 6.67×10-11 m^3 kg-1 s-2 * 1.08*10^16kg/[1.35*10^4]^2m^2

*February 4, 2017*

**history**

No way !

*February 4, 2017*

**Math**

4/-2 = -2 -2/-2 = 1 1/-2 = -1/2 (-1/2)/-2 = 1/4

*February 4, 2017*

**math**

(35/64)a = 2450 a = 2450*64 /35

*February 3, 2017*

**Math : ratio and proportion**

(2 L/80km) 1 km = 1/40 liter

*February 3, 2017*

**Geometry**

north wind due to boat speed at 16 kn west wind at 10.4 kn magnitude = sqrt(16^2+10.4^2) tan angle west of north = 10.4/16 compass angle= 360 - that angle

*February 3, 2017*

**Math**

5 * .0625 * 7150 = interest due total = interest due + 7150

*February 3, 2017*

**Mathmaybe something like:s**

7 , 8, 9 , 11 , 11, 11

*February 3, 2017*

**MS. SUE! World History (Absolutism and Revolution)**

The second one, Peter the Great's accomplishments,is correct. Do not forget he established a Russian port, called St. Petersburg, on the Baltic. I do not know much about Maria T. However from what little I know I would vote for #3.

*February 3, 2017*

**History**

http://www.britannica.com/event/United-States-presidential-election-of-1860

*February 3, 2017*

**History**

10 a is correct 3 see http://www.carolana.com/SC/1800s/antebellum/educational_opportunities.html 7. D is correct 8. http://www.geni.com/projects/Southern-Fire-Eaters/4715 9. Good grief, no slavery did not become legal in Massachusetts. However in theory after that decision, a ...

*February 3, 2017*

**Maths**

two years at 3% = .03*2 = .06 so .06 times original deposit = 72 so 72/.06 which is 1200

*February 2, 2017*

**Maths**

.06 v = £72

*February 2, 2017*

**C**

Sometimes: "Code of Ethics"

*February 2, 2017*

**dynamics**

v = -k ln x + c 15 = -k ln .6 + c 9 = -k ln 1.2+ c -----------------subtract 6 = -k ln(.6/1.2) etc

*February 2, 2017*

**Math m1**

600 = 400 a so a = 600/400 total force = 400 a + 1000 a = 1400 a

*February 2, 2017*

**physics**

and add heat of vaporization to steam

*February 2, 2017*

**Geologic Time and Earth's History Unit Te**

I would be happy to do it but need WhiteRain's text book.

*February 2, 2017*

**ah --**

hey - only the component in the k direction passes through your loop :)

*February 2, 2017*

**set maths**

You have to do this with a Venn diagram, which I can not really draw here but using that you should be able to figure it out.

*February 2, 2017*

**So where is your work?**

So where is your attempt to do this? There are two common ways, I do not even know which you are using since I see no work.

*February 2, 2017*

**History**

1. agree 2. agree 3. agree 4. agree Hey, you know the answers perfectly well :)

*February 2, 2017*

**Math--Matrix**

http://matrixcalc.org/en/vectors.html

*February 2, 2017*

**Math--Matrix**

http://www.sosmath.com/matrix/eigen1/eigen1.html

*February 2, 2017*

**physics**

Newtonian Gravity, objects of mass M and n: F = force of attraction on each F = G m M/r^2 if M is earth mass, call it Me and r is earth radius, call it Re then G Me/Re^2 = 9.81 m/s^2 approximately so F = 9.81 m F/m we call acceleration of gravity on earth, g = about 9.81 If ...

*February 2, 2017*

**physics**

now F = m g work done against gravity = integral F*dr or m g dr or m * integral g dr m 9.8 Re^2 integral dr/r^2 from Re to 4 Re integral dx/x^2 = -1/x so here 1/6,400,000 - 1/25,600,000 = 1.17 * 10^-7 so work done in Joules - m 9.8 Re^2 * 1.17* 10^-7 = m (47,040,000) Joules ...

*February 2, 2017*

**trick question**

Although g may be about 9.8 m/s^2 at the surface of earth, it is not 9.8 at 4 Re and therefore you can not assume it is constant g = 9.8 (Re^2/r^2)

*February 2, 2017*

**backwards**

sorry P(0 broke) = 1* 1 * .82^11 P(1 broke) = C(11,1).18^1 .82^10 P(2 broke) =C(11,2).18^2 .82^9

*February 1, 2017*

**stats**

p yes broke = .18 p not broke = .82 P(0 broke) = 1*.18^11 * 1 P(1 broke) = C(11,1).18^10 .82^1 P(2 broke) =C(11,2).18^9 .82^2 C(11,1) = 11 C(11,2) = 55

*February 1, 2017*

**physics**

Once again you have not given the moment arms Torque or moment is force * distance from axis

*February 1, 2017*

**algebra**

(6-4)/(2-3) = 2/-1 = -2

*February 1, 2017*

**dumb error**

4(-4)+7 = k(-4) + 10 -19 = -4k k = 19/4

*February 1, 2017*

**Math Cal 1**

4(-4) + 7 = k(-4) - 4 -4k = -5 k = +5/4

*February 1, 2017*

**magic difficult**

I have no idea about directions or moment arms. The force furthers from the axis exerts the greatest moment, if and only if they are normal to the door.

*February 1, 2017*

**Physics**

mass = 2166 * (4/3)pi r^3 weight = 9.81 (2166)(4/3)pi r^3 balance weight with Stokes force weight = 6 pi ? r v so 6pi? r v=9.81 (2166)(4/3)pi r^3 9 ? v=9.81 (2166)(2)(9*10^-6)^2 9 ? v=9.81 (2166)(2)(9*10^-6)^2 v = 382472 *10^-12/? have to know ? to estimate v, see part b v =...

*February 1, 2017*

**physics**

ah come on 2 pi rad/22.8 s so what is the circumference? C = 2 pi R = 22.8s * 37.3m/s = 850 meters around the track so R = 850/(2 pi)

*February 1, 2017*

**MATH PLEASE CHECK AND HELPPP**

Always draw a picture !

*February 1, 2017*

**M1-math**

Nope, say F = ma a = 400/t so t = 400/a d = Vi t -(1/2)a t^2 d = 400 t - (1/2)(400/t)t^2 d = 400 t - 200 t = 200 t t = d/200 = .01/200 = 5*10^-5 s again a = 400/t = 8*10^6 F = m a = .02*8*10^6 = 160,000 N again :)

*February 1, 2017*

**M1-math**

momentum = m v = .020*400 = 8 kg m/s stops in 1 cm = .01 meter average speed during stop = 200m/s so time to stop t = .01/200 = 5*10^-5 seconds Average force = change of momentum/time = (8/5)10^5 = 160,000 Newtons

*February 1, 2017*

**physics**

Well, if you get a few million miles above the north pole and look down, the earth spins counterclockwise about its axis and also orbits counterclockwise around the sun, so take that as positive,clockwise looking up :) (sun rises in the east :) so daily spin: 2 pi rad/24 h * 1...

*February 1, 2017*

**Social studies**

:)

*February 1, 2017*

**Social studies**

Bethlehem Steel gave me an engraved watch at the launching. It is here in my desk drawer.

*February 1, 2017*

**Social studies**

My mother and I flew to California on China Clipper seaplane after bombing. Father went to sea.

*February 1, 2017*

**Social studies**

Yes, on bridge of Cruiser San Francisco off Guadalcanal Nov 12-13 1942, Iron bottom Sound

*February 1, 2017*

**Social studies**

Google Destroyer Escort 643

*February 1, 2017*

**Social studies**

Yes, scary then. Long story.

*February 1, 2017*

**Social studies**

( I lived there until January 1942.)

*February 1, 2017*

**Social studies**

Hawaii annexation was before the Spanish American war, agree

*February 1, 2017*

**math**

120 sin 8 degrees

*February 1, 2017*

**physics**

(1/4) as far because 25 cm/100 cm = 1/4

*February 1, 2017*

**physics, science!**

Oh my, I just noticed the Bob Pursley answered an almost identical question for you. note w^2 r = v^2/r and READ THE CHAPTER in your text on centripetal acceleration !

*February 1, 2017*

**physics, science!**

circumference = 2 pi r = 2 pi(.2) speed = v = distance/time = 2 pi (.2)/36 Ac = v^2/r F = m Ac = 37 v^2/r

*February 1, 2017*

**No idea**

If it is in a triangle, 72+113+x=180 otherwise I have no idea what sort of drawing you are talking about.

*February 1, 2017*

**PHYSICS**

fall 45 m: (1/2) m v^2 = m g h so v = sqrt(2 g h) = sqrt(90*9.81) = 29.7 m/s Vi = 29.7 average speed during stop = 14.9 so stopping time = 4.10/14.9 = .279 seconds a = dv/dt = 29.7/.279 = 106 m/s^2 looks like E, what are you using for g I wonder

*February 1, 2017*

**science**

I would guess pretty much constant thrust. So pretty much constant acceleration. a = F/m v = a t x = (1/2) a t^2

*February 1, 2017*

**science**

2^n bacteria where n is the number of periods You did not say how long a period was or how many is half full or how many is full.

*February 1, 2017*

**Maths: Surds**

Oh, did no. notice the "in half"

*February 1, 2017*

**Maths: Surds**

a(a+b) = 100 but b = 2a/(1+sqrt5) a [ a + 2a/(1+sqrt5) ]=100 a^2 [ 1 +2/(1+sqrt5) ] = 100 etc

*February 1, 2017*

**Maths: Surds**

I do not see your picture but suspect you are talking about what is often called the "golden ratio". http://en.wikipedia.org/wiki/Golden_ratio

*February 1, 2017*

**Chemistry**

if you have 2 moles of B you need 6 moles of A In other words you do not have enough A I guess I just said 2) :)

*February 1, 2017*

**algebra**

conversion factor is (14 gal/340 mi) (14 gal/340 mi)(544 mi) = 22.4 needed for whole trip so 22.4-14 = 8.4 more needed ============================= with proportions (I do physics not math so not my thing) 14/340 = x/544 so x = (14/340)544 again

*February 1, 2017*

**Physics**

a = change in velocity/time = 105/1.2*10^-3 = (105/1.2)10^3 x = 40(1.2)10^-3 - (1/2)at^2 = 40*1.2*10^-3 -(105/2.4)10^3 (1.2)^2 10^-6

*February 1, 2017*

**physics**

u = 42 cos 36 horizontal speed so t = 27/(42 cos 36) Vi = 42 sin 36 initial speed up h = Vi t - 4.9 t^2

*January 31, 2017*

**Physics**

0.5 m^3 * 2.70 * 10^3 kg/m^3 = 1.35 *10^3 kg = 1350 kg

*January 31, 2017*

**Calculus**

I do not see how it could be otherwise. If there were a singularity at infinity resulting in an undefined limit, then how could the domain include plus and minus infinity?

*January 31, 2017*

**math**

2.2222 + 4.375 = 6.6 so p = 13.2

*January 31, 2017*

**math**

4 3/8 * w = 9 13/18 35/8 * w = 175/18 9/9 (35/8) * w = 4/4 (175/18) 315 w = 700 w = 140/63 = 2.222...

*January 31, 2017*

**Technology HURRY**

It is not B

*January 31, 2017*