I would like to understand my calc homework:/
B) at (1 , 1) dy/dx = slope = 1*1/2 = .5 so y = .5 x + b is tangent for some b put in (1 , 1 ) 1 = .5 + b b = .5 so tangent at (1,1) is y = .5 x + .5 at x = 1.2 y = .5(1.2) + .5 = 1.1 ========================== C) dy/y = (1/2) x dx ln y = (1/4) x^2 + C y = k e^(x^2/4) 1 = k e^...
Form a polynomial
must have complex conjugates of complex zeros given: (x+8)(x+i)(x-i)(x+8-i)(x+8+i) Multiply out. Have fun.
Physics Oasis!! Help!!
By the way, this means that for a glider: Drag/Lift = tangent of steady glide angle
Physics Oasis!! Help!!
Lift does not act perpendicular to the wings but to the oncoming air flow. The two angles differ by the angle of attack. speed = 129*10^3/3600 = 35.8 m/s weight = 1250 * 9.81 = 12,263 N Path at angle T down from Horizontal Vertical forces: weight down = 12,263 N Lift component...
MATH
24 (3/4) = 6*3 = 18
MATH
4*4 = 16 or 4 * 4 1/4 = 16 + 1 = 17 exact is 17.015625
MATH
11/16 is about 12/16 which is 3/4 as any carpenter knows :)
MATH
Under estimate. Add (3/10)*2*5 to get exact distance 4 3/10 = (4 + 3/10) (4 + 3/10) * 2 * 5 = 4 * 10 + 3 by distributive property = 43
MATH
3 * 2 = 6 3/5 * 10 - 1/2 * 1/2 = 6-1/4 = 5 3/4 30/5 = 6
We do not do magic
I have no idea what the configuration of these boxes is. Is the big one on a table and the little one hanging or something? Where and how is this force acting?
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