Saturday

October 10, 2015
Total # Posts: 22,103

**Physics C**

force = E q force * distance = work done = Ke = Eqd so .880 = 64.0 * q * 0.500 solve for q
*January 14, 2015*

**Math**

Any time :)
*January 14, 2015*

**Math**

4 x = -12 x = -3 indeed
*January 14, 2015*

**Math**

Yes, that is correct
*January 14, 2015*

**Math**

3 (p - .35) = 3.45
*January 14, 2015*

**physics**

How far up from earth surface? 6.92 sin theta where theta is the angle up from horizontal mg opposite to up motion so g does negative work so - m g sin theta * (6.92)
*January 14, 2015*

**Algebra 1**

(2.5*10^-9)(1.5*10^3) = 3.75*10^-6 yes
*January 14, 2015*

**math**

7 (41/10) = $28.70
*January 14, 2015*

**Math**

t = 2h-4 h = 6 so t = 12-4 = 8 legs
*January 14, 2015*

**Math**

J + S + D = 5416 J = 1615 S = 6 D so 1615 + 6 D + D = 5416 7 D = 3801 D = 543 so S = 6 D = 3258
*January 14, 2015*

**Math**

.4 is bigger than .3
*January 14, 2015*

**Math equation**

No problem :)
*January 14, 2015*

**Math equation**

4 n = 6-5 = 1 n = 1/4
*January 14, 2015*

**Math equation**

I do not know for question 1. It could be + or -. My guess is that you are right. question 2 is 4 n - 6 = -5
*January 14, 2015*

**math**

(115 words/3 min)(7 min ) = 268
*January 14, 2015*

**math**

You are welcome ;)
*January 14, 2015*

**math**

elevation angle A = 45 degrees = pi/4 radians tan A = h/25 d tan A/dA = sec^2 A = (1/25) dh/dA so 25 sec^2 A * dA/dt= dh/dt = 5 dA/dt = (1/5) cos^2 A but cos^2 A = 1/2 dA/dt = .1 radians/second So I agrees but maybe you want degrees? .1 Rad/s( 180 deg/rad) = 18 degrees/second
*January 14, 2015*

**Math**

You are welcome.
*January 14, 2015*

**Math**

$20 per thousand ? 20*80 = 1,600
*January 14, 2015*

**Algebra 2 ( I doubt it)**

I bet you mean 9 x^2 - 100 (3x-10)(3x+10)
*January 14, 2015*

**trigonometry**

[sin T/cos T + cos T/sin T] /( sin T/cos T) = [ sin T + cos^2 T/sin T ]/ sin T = [ sin^2 T + cos^2 T ] /sin^2 T = 1/sin^2 T = csc^2 T
*January 14, 2015*

**algebra 1**

You are welcome.
*January 14, 2015*

**algebra 1**

If it is all under that square root sign then divide all the exponents by 2 25 x^2 z^4 y
*January 14, 2015*

**Math.**

You are welcome.
*January 14, 2015*

**Math.**

w = .5 x .5 * 120 = 60 grams
*January 14, 2015*

**math**

Mars 100 * 56.55/150 = 37.7% Moon 100 * 24.9/150 = 16.6% (about 1/6, remember that) Mars .377 x Moon .166 x .166 * 180 = 29.9 pounds (note 180/6 =30) 180 * 2.364
*January 14, 2015*

**math**

A. (x^1/2)^4√x^6 x^2 x^3 = x^5 B. I do not know if you mean (x^4)^.5 y^12 or (x^4 y^12)^.5 if the second then x^2 y^6 C if you mean (a^6 b^3)^1/3 then indeed a^2 b I am at a loss with your notation
*January 14, 2015*

**Physics 10 (helppp please) thannnks**

delta L/L = w /(E A) .008/120 = w/(E*6) w = 6 E * .008/120
*January 14, 2015*

**physica science**

When they are both in the same direction and therefore add. |R| = |A| |B| cos theta |cos theta| </= 1 for all theta and is max of 1 when theta = 0 5+7 = 12 If theta is the angle between vectors.
*January 14, 2015*

**algebra**

(-25/10)(1/A^2)( B^4) -25 B^4/(10 A^2)
*January 14, 2015*

**Physic**

https://iit.edu/arc/workshops/pdfs/Magnetic_Field.pdf
*January 14, 2015*

**mathematics**

L=(5x^2-4x-3) w=(x^2-x+1) h=(3x^2-5) use distributive property for multipication Lw: 5 x^2(x^2-x+1) = 5x^4-5x^3+5x^2 -4x(x^2-x+1)= -4x^3+4x^2-4x -3(x^2-x+1)= -3x^2 +3 x -3 add Lw = 5 x^4 - 9 x^3 + 6 x^2 -x - 3 for side areas 2 Lw = 10x^4-18x^3+12x^2-2x-6 do the same for top ...
*January 14, 2015*

**Algebra**

x - 9 = 6 x + 21 5 x = 30 x = 6
*January 13, 2015*

**Math**

85/100 = 17/20
*January 13, 2015*

**Science**

work = force * distanced moved in direction of force W = 10 * 1.5 = 15 Joules
*January 13, 2015*

**MATH**

Yes, it is D
*January 13, 2015*

**MATH**

NO! hey sketch both graphs for x = -1, x=+1, x = 0
*January 13, 2015*

**MATH**

Please sketch a graph. It is two V shapes identical except that one is 15 below the other.
*January 13, 2015*

**Math**

1/4 went 1/4 * 496 = 124
*January 13, 2015*

**math**

dimensions are length = 8+4 = 12 width = 4 +4 = 8 2 L + 2 w = 24 + 16 = 40
*January 13, 2015*

**algebra 2**

x = 0.04 t 25 = 0.04 t t = 25/.04 = 625 seconds which is about ten and a half minutes
*January 13, 2015*

**math**

You are welcome
*January 13, 2015*

**math**

yes 2.5 * 15 = 37.5 and 2.5 hours per day * 22 days = 55 hours
*January 13, 2015*

**physics**

It is going away so you hear a longer wavelength so LOWER frequency
*January 13, 2015*

**algebra 2 help typo?**

x+4 = 8/3 x = 8/3 - 12/3 = -4/3 or -x-4 = 8/3 x+4 = -8/3 x = -20/3
*January 12, 2015*

**alegebra 2 Help**

(x+h)^2 = x^2 + 2 h x + h^2 x(x^2 + 2 h x + h^2)=x^3 +2 hx^2+ xh^2 h(x^2 + 2 h x + h^2)=hx^2+2h^2x+h^3 sum=x^3 +3hx^2 +3h^2x+ h^3 etc
*January 12, 2015*

**alegebra 2 Help**

so continue [ x^3 -(x+h)^3 ] / [h x^3(x+h)^3]
*January 12, 2015*

**alegebra 2 Help**

[1/(x+h)^3 - 1/x^3 ]/h
*January 12, 2015*

**physics**

reaches top in 1.5 seconds v = Vi - g t 0 = 5 - 1.5 g g = 5/1.5 = 3.33 m/s^2 v = 15 - 3.33 t 8 = 15 - 3.33 t t = 2.1 seconds h = 15 t - (3.33/2) t^2
*January 12, 2015*

**Legal research**

Would you believe it says a digest is an index ? :)
*January 11, 2015*

**Legal research**

http://lawlibguides.byu.edu/content.php?pid=225319&sid=1961818
*January 11, 2015*

**Legal research**

I believe you are correct.
*January 11, 2015*

**math**

You are welcome.
*January 11, 2015*

**math**

M = 2 P- 4 so P + 2P-4 = 32 3 P = 36 P = 12 then Marc has 24 - 4 = 20
*January 11, 2015*

**legal research writings**

Then I suppose go with the dictionary. I do not think law dictionaries have pockets with updates, but I am not a legal scholar.
*January 11, 2015*

**legal research writings**

Well, I agree that a treatise might not be typically updated.
*January 11, 2015*

**legal research writings**

but I think you might just publish a new edition of a dictionary.
*January 11, 2015*

**legal research writings**

I think you might: http://en.wikipedia.org/wiki/Legal_treatise
*January 11, 2015*

**legal research writings**

Would you update treatises?
*January 11, 2015*

**Legal research**

Yes, Lucina is right http://www.acronymfinder.com/LexisNexis-%28online-legal-research-tool%29-%28LN%29.html
*January 11, 2015*

**Legal research**

go with Lucina, I just Googled it.
*January 11, 2015*

**Legal research**

sorry, Google shows: Lex-Nex
*January 11, 2015*

**chemistry**

mol of Na O H = 23+16 + 1 = 40 grams so 1 gram is 1/40 mol = .025 mol .025 mol = .2 mol/liter * x liters so x = .025/.2 = .125 liters or 1/8 liter
*January 11, 2015*

**Algebra Help Please**

here, for any old x x^0 * x^1 = x^(1+0) = x^1 so x^0 was 1
*January 11, 2015*

**Algebra Help Please**

ANYTHING^0 = 1 no more steps needed
*January 11, 2015*

**algebra**

HEY, you were almost there! -4 1/x^2 x * y^4 y^7/1 -4 *1/(x^2*x) * y^(4+7) = -4 y^11/x^3
*January 11, 2015*

**algebra**

12 x^-2 y^4 /{ -3 x (y^-7) } ?? is -4 x^-3 y^11 = -4 y^11/x^3
*January 11, 2015*

**Math**

maybe average = (7.6+10.4)/2 = 9 9 +/- |1.4|
*January 11, 2015*

**physics**

we must find the change of momentum during contact, in other words Vi and u Vi = w sin 61.8 u = w cos 61.8 if w is the initial speed 176 = u t where t is total time in air v = w sin 61.8 - g t h = Hi + Vi t - 4.9 t^2 0 = 0 + Vi t - 4.9 t^2 = t(Vi - 4.9 t) so it is at the ...
*January 11, 2015*

**Math**

10/(100+20) = 10/120 = 1/12
*January 11, 2015*

**Algebra 2**

z = k x y^2/ (r s) where k is a constant
*January 11, 2015*

**Physics**

average force = change of momentum/time instantaneous force if m is constant = m A so average force = 97.7 / .368 Newtons
*January 11, 2015*

**Algebra II**

(f+g)(x) = 8 x^2 + 1/x^2 (f-g)(x) = 8 x^2 - 1/x^2 f [g(x)] = f (1/x^2) = 8(1/x^4) = 8/x^4 f [1/g(x)] = f (x^2) = 8 x^4
*January 11, 2015*

**Algebra 2**

Intersection of a hyperbola with an ellipse, cool 2 x^2 - 5 y^2 = 1 2 x^2 + 10y^2 = 136 --------------------subtract -15 y^2 = -135 y^2 = 9 so y = +/-3 x^2 = 68-45 = 23 so x = +/-sqrt(23) (sqrt 23 , 3) (sqrt 23 , -3) (-sqrt 23 , 3 ) (-sqrt 23 , -3)
*January 11, 2015*

**math**

The trick is: Out of every four bagels one is sesame and three are plain so that sesame/plain = 1/3 sesame/all = 1/4 = .25 = 25% plain/all = 3/4 = .75 = 75% (1/4) 24 = 6 sesame (3/4) 24 = 18 plain
*January 11, 2015*

**Calculus**

f' = 1/x^2 at x = -3, f = 1/3 at x = -1/2, f = 2 slope = (2 - 1/3)/(-1/2 + 3) = (5/3)/(5/2) = 2/3 where is the derivative = 2/3 ? 1/x^2 = 2/3 x^2 = 3/2 x = +/- sqrt (3/2) yes B
*January 11, 2015*

**Math**

first equation y - x/2 = 5 2 y - x = 10 second equation -x + y/5 = -13 y - 5x = -65 2 y - 10 x = -130 so two equations 2 y - x = 10 2 y - 10 x = -130 --------------------subtract 9 x = 140 x = 15.56 y = 5 + x/2 = 12.78
*January 11, 2015*

**Calculus**

yes, v = 6 t - 3 t^2 dv/dt = 0 at max or min = 6 - 6 t so max or min at t = 1 max or min? d^2v/dt^2 = -6 so max what is that max v at t = 1 v(1) = 6-3 = 3 so C.
*January 11, 2015*

**MATH**

I think you will have to try various interest rates and graph that function if i = .1 or 10% 6.25 = 5.76 if i = .08 6.25 = 6.24 close to 8%
*January 10, 2015*

**Math**

scroll down a bit. I just did that not a good idea to use your real name
*January 10, 2015*

**Polynomials**

it is asking if the left is the same as the right look at a (a-b)(a-b) = a^2 -2ab + b^2 Always then b (a+b)(a+b) = a^2 + 2ab + b^2 NOT a^2+b^2 and is ONLY true if a or b is zero same problem with c You have a typo in d but if that is a + sign then true (a+b)(a+b)=a^2+2ab+b^2
*January 10, 2015*

**Math**

(4x-1)/[(x+3)(x+4)] * (x+4)(x-3)/(2x-1) when you divide fractions, invert the denominator and multiply (x+4) cancels (4x-1)(x-3) /[ (x+3)(2x-1)]
*January 10, 2015*

**Math**

yours (x^2-2x)/(x+1)x (x^2-1)/(x^2+x-6) My work on simplifying the expressions x(x-2)/(x+1) * (x+1)(x-1)/[(x+3)(x-2)] note your sign error in second denominator (x+1) and (x-2) cancel x(x-1) / (x+3)
*January 10, 2015*

**Calculus**

2^1 +2^1 *2^1 + 2^1* 2^2 ..... 2^1*2^(n-1) is 2 + 2*2 + 2 *2^2 .... note 2^1 * 2^(n-1) = 2^n 2^1 =2 = a 2 = r sum from i = 1 to n = 2 ( 1-2^n)/(1-2) = -2 (1-2^n) =2^(n+1) - 2
*January 10, 2015*

**calculus**

Do you mean from 0 to 5 and from 0 to 6 ? if so 2 (x^2 -3 x) at 5 - at 0 = 2 (25 - 15) - 0 = 20 at6 it is 2 (36-18) = 2*18 = 36
*January 10, 2015*

**calculus**

what is the derivative of (5/7)x^7 ? what is the derivative of -x^(-2) ?
*January 10, 2015*

**Physics**

period = T = 60 seconds/26 = 30/13 f = 1/T = 13/30 A = 3.9 cm y = -3.9 cos (2 pi t/T) because y = -3.9 when t = 0 y = - 3.9 cos (26 pi t/30)
*January 10, 2015*

**Math**

I can not simplify it but f(x) = -3(x^2+4x+4) -x-1 = -3 x^3 -12 x -12 - x - 1 = -3x^2 - 13 x -13 sure enough f(x) = [(x-2)(x+1)] / [ (3x+1)(x+1) ] = (x-2)/(3x+1) we win again
*January 10, 2015*

**Math**

(x-2)(x+1)/(x+1) = x-2 = g(x) (x-4)(x+3)/(x+3) = x-4 g(x) = (x-2)(x-4)/(x-2) = x-4 also
*January 10, 2015*

**math**

13,000 = 6,000 +.05(x-20,000)
*January 10, 2015*

**maths**

took me 40 http://www.jiskha.com/display.cgi?id=1420913304
*January 10, 2015*

**maths-6th grade**

sorry I took so long, had a grandson's hockey game in the middle of that.
*January 10, 2015*

**maths-6th grade**

t x 0 0 1 20 2 10 3 30 4 20 5 40 6 30 7 50 8 40 9 60 10 50 11 70 12 60 13 80 14 70 15 90 16 80 17 100 18 90 19 110 20 100 21 120 22 110 23 130 . . . 40 200 averages 5 meters/min
*January 10, 2015*

**maths algebra**

x/2 red x/d blue x - x/2 - x/d = x(1/2 - 1/d) yellow
*January 10, 2015*

**math**

-2 -2*-3 = 6 6*-3 = -18 -18*-3 = 54 54*-3 = -162 etc
*January 9, 2015*

**math**

oh 486 + 440
*January 9, 2015*

**math**

area of cube = 6*49 subtract pi (3.5^2) so cube area painted = 294 - pi(3.5)^2 side area of cylinder = 20 ( 7 pi) end areas = 2 pi(3.5^2) but delete one so total cylinder area =140 pi+pi(3.5^2) total = 294-pi(3.5)^2+140pi+pi(3.5)^2 = 294 + 140 pi = 294 + 20(22) = 294+440 = 734
*January 9, 2015*

**math**

a + 12 d = 159 a + 19 d = 264 --------------- 7 d = 105 d = 15 a = 159-12(15) = -21
*January 9, 2015*

**Math**

[5(x+1) +2(x-1)]/(x^2-1) = -6 5x+5 +2x-2 = -6x^2 + 6 6 x^2 + 7 x - 3 = 0 (2x+3)(3x-1) = 0 x = 1/3 or -3/2
*January 9, 2015*

**Math**

(3x+1)/[2(x+1)(x-1)]+2(x+1)/[2(x-3)(x-1)] [(3x+1)(x-3)+(x+1)^2 ]/[(x^2-1)(x-3)] [ 3x^2-8x-3 +x^2+2x+1 ]/[(x^2-1)(x-3)] [4x^2-6x-2]/[(x^2-1)(x-3)] 2[2x^2-3x-1] / [(x^2-1)(x-3)]
*January 9, 2015*