Thursday
July 28, 2016

Posts by Damon

Total # Posts: 26,566

Math
Matt had x May had 3x 4 x - 50 = 70 4 x = 120 x = 30 ======================= check Matt 30 May 3*30 = 90 sum = 120 120 = 50+70
January 27, 2016

math
tan 30 = h/a tan T = h/2a tan T = (1/2) tan 30 T = 8.21 degrees
January 27, 2016

W Hist
semiconductors sitting around staring at screens no horse messes stinking up the city streets
January 26, 2016

Math
6 * 3 * 2 = 6 * 6 = 36 ft^3
January 26, 2016

math
2*2*2*2*2*2
January 26, 2016

Physics
vertical problem: Vi = 68 sin 25 = 28.7 m/s h = Vi t -4.9 t^2 h = 28.7 t - 4.9 t^2 horizontal problem: u = 68 cos 25 = 61.6 m/s t = 50/61.6 = .811 s so h = 28.7(.811) - 4.9(.811^2)
January 26, 2016

Pre Algebra
-1 11/16 + 4 1/6 = - 27/16 + 25/6 sure enough = -81/48 + 200/48 agree = 119/48 = 2 23/48 yes ============================ NO! -1 33/48 + 4 8/48 = 3 -25/48 = 2 + 48/48 -25/48 = 2 + 23/48
January 26, 2016

?
Please proof read initially at rest maybe? 12 what? /s^2 meters, feet ? 205 what? seconds, meters ? feet? miles? after 205 what again? 12 m/s^2 for how long ? Is this after the first question using that final for this initial velocity?
January 26, 2016

math
Yours is much better. I got off on that both queens tack :)
January 26, 2016

math
Go with jolly rancher !
January 26, 2016

whoops
what I gave you was for a specific rank, like two queens multiply by 13 because there are 13 ranks
January 26, 2016

math
4/52 * 3/51
January 26, 2016

Science
storage space, closet ?
January 26, 2016

typo?
You need to specify a time before the encounter
January 26, 2016

History
Well, I suppose D, but I do not think communes were that large as a rule.
January 26, 2016

math
No, you can not copy and paste to this site.
January 26, 2016

Math
3 times as many cookies takes 3 times as many cups of sugar so 6 cups 2 cups/ 2 dozen = 6 cups/6 dozen
January 26, 2016

physics
m v^2/r 2500 (25)/50 = 1250 Newtons
January 26, 2016

Physics
dw/dt = -10 - 4.42 t so w = -10 t - 2.21 t^2 + constant find constant at t = 0 71.6 = -10(0) - 2.21(0)^2 + c so c = 71.6 w = 71.6 - 10 t - 2.21 t^2 put in t = 2.73 Now the angle dTheta/dt = w = 71.6-10 t -2.21 t^2 so Theta = 71.6 t - 5 t^2 - (2.21/3)t^3
January 26, 2016

Physical sciences
Fx = 30 cos 60 - 40 cos 60 Fy = 30 sin 60 + 40 sin 60 F = sqrt (Fx^2 + Fy^2) Tan theta = Fy/Fx Note - Theta is in quadrant 2 because 40>30 Use 180 - the magnitude of the angle
January 26, 2016

Physics
from the plus plate toward the negative plate Remember that if you integrate along them you get the voltage difference.
January 26, 2016

Physics
You do not say what the moment of inertia of the Merry Go Round is. I will call it I 39.4 revs/min (2 pi rad/rev)(1 min/60s) = 4.13 radians /s = W1 omega of John = v/r = 6.36/3.21 = 1.98 rad/s Initial angular momentum = I (4.13) + 48.4(3.21)^2 (1.98) Final I = I + 48.4(3.21)^2...
January 26, 2016

Physics
You need how far it rolled down the hill to get initial speed v = w r where w is omega, the angular velocity kinetic energy = m g h = (1/2)I w^2 + (1/2) mv^2 = (1/2)(2/3)mr^2v^2/r^2 + (1/2)mv^2 =(mv^2/2)[2/3 + 1] = (5/3) (mv^2/2) so g h = (5/3)(v^2/2) solve for v, initial ...
January 26, 2016

math
If those are matrices, no they do not necessarily commute
January 26, 2016

Physics
Your equations seem to indicate that the 70 degrees is with the FLOOR, not the Wall, which makes more sense) First, force up = force down so force up at floor = 160 Call friction force at floor Fw It is equal and opposite to horizontal force at top Now moments about ladder at ...
January 26, 2016

physics
How amusing - you happened upon a Naval Architect. increased volume of ship in the water = Area * .025 meters mass of water displaced = density of seawater * that volume density of seawater is about 1029 kg/m^3 so mass of water displaced = 1029 * .025 * A Buoyancy force due to...
January 25, 2016

physics
You mean (4/3) pi r^3 r = 0.25 meter V = .0654 meters^2 mass of water displaced-mass of foam = (1000-300)(.0654) = 45.8 kg
January 25, 2016

physics
rho fresh = 1000 kg/m^2 rho salt = 1029 kg/m^3 approx submerged draft = d vol of block = .1*.1*.1 = .001 m^3 mass of block = 700*.001 = .7 kg volume of fresh water displaced must have mass = .7 kg so .1 * .1 * d * 1000 = .7 kg d = .07 m = 7 cm so freeboard above water = 3 cm ...
January 25, 2016

Physical Science
h = 4.9 t^2 h= 4.9(1.16)^2 h = 6.19 m
January 25, 2016

physics
assume salt water density = 1029 kg/m^3 and g = 9.81 m/s^2 mass in salt water = 1029*.8*60 = 1000 * d * 60 d = .8 (1029/1000) = .8232 m
January 25, 2016

History
Knowing nothing of the subject all I can do is give you a link: http://www.geocities.ws/krysstravel/writing_kanarda.html
January 25, 2016

math
7 = 1+6 2+5 3+4 if greater than 40 and less than 50, has to start with 4 impossible to be an even number 43
January 25, 2016

math
but if being strict about significant figures you only have two 5.1 * 10^6
January 25, 2016

Calc help!
What you typed does not make sense. Perhaps you mean: [ x(x+3) - (x+1)(x-3)] / (x^2-9) ??? [ x^2 + 3x - x^2 +2 x + 3 ] /(x^2-9) (5x+3)/(x^2-9)
January 25, 2016

physics
None, no motion in the direction of the force.
January 25, 2016

I did this already
http://www.jiskha.com/display.cgi?id=1453734257
January 25, 2016

Math
7 in ( 5 miles/1 in) = 35 miles
January 25, 2016

Math
same way as the one above (15 mi)
January 25, 2016

Math
yes
January 25, 2016

Math
24 + 36 + 24 + 36
January 25, 2016

Physics
99.5-.7 = 98.8 so Reading C = Cr = .7 +(98.8/100) C if Cr = 30 30 = .7 + .988 C C = 29.7 if the same C = .7 + .988 C .012 C = .7 C = 58.3 degrees C or Cr
January 25, 2016

Math
I assume you mean a = 6.25 m/s^2 Please proof read what you type. v = a t = 6.25 m/s^2 * 7 s = 43.75 m/s Now parachute, a = - 2.5 m/s^2 and Vi = 43.75 m/s v = Vi + a t 0 = 43.75 - 2.5 t t = 17.5 seconds
January 25, 2016

math
30 km (1 hour/225 km) = .1333333... = (.1 + 1/30) hours .1 hours = .1*60 minutes = 6 minutes (1/30) hours (60 min/hour) =2 minutes 6 + 2 = 8 minutes
January 25, 2016

math
70 km/h * 1000 m/km * 1 h/3600 s = 19.44 m/s so 50 km/h = 13.89 m/s a = change in v/change in t = (13.89 - 19.44)/5 = - 1.11 m/s^2
January 25, 2016

Algebra
well, halfway between x axis intercepts is x = 12/2 = 6 so that is where the vertex must be y - b = (x-6)^2 -5 - b = (-7)^2 = 49 b = -54 y = (x-6)^2 - 54 y = x^2 - 12 x + 36 - 54 y = x^2 - 12 x - 18 ===================== check: x^2 - 12 x = y+18 x^2 - 12 x + 36 = y+ 54 (x-6)^2...
January 25, 2016

math
The top seems to be an arithmetic sequence and the bottom a geometric sequence, but I can not get that ratio to converge as i --->oo
January 25, 2016

maths
6 n + 4/n = 14 ??? 6 n^2 + 4 = 14 n 6 n^2 - 14 n + 4 = 0 3 n^2 - 7 n + 2 = 0 (3n-1)(n-2)= 0 n = 1/3 or 2 which do you think? Hint - try 2 then try 1/3 :)
January 25, 2016

Physics
work accomplished = 300*30 = 9,000 J applied work = 9,000 + 2,000 = 11,000 Joules efficiency = 100 * work accomplished/work applied = (9/11)100 = 81.8 % force applied = (300/6)/.818 = 61.1 N assuming that the 6 in your question refers to mechanical advantage
January 24, 2016

Algebra
Yes, sure :) BUT you did not need to ask because to be sure just put it back in 2 (3) + 3 (2) = ??? maybe 12 6 + 6 = YES
January 24, 2016

algebra
if + k is to the right, it is everything left of but not including -1 if k is up, it is everything below -1
January 24, 2016

Algebra
well, pick any old x, like for example x = 0 find y 0 - y = 9 y = -9 so (0 , - 9) now pick another x, like x = 1 3 - y = 9 y = 3-9 = -6 so ( 1 , - 6 ) and on and on until bored
January 24, 2016

math
I assume you mean compounded r = interest rate specified usually per year /4 because compounding every quarter year 18.5 years * 4 = 74 periods 3 = x^74 log 3 = 74 log x log x = .00644758 x =1.015 so 1.5 percent per period or r = 4*1.5 = 6%
January 24, 2016

math
Yes, I think that is the intent of the fuzzy phrasing :)
January 24, 2016

Pre-Calculus
50 72 45 (the 72 is 60+12) 32 45 12 ----------subtract 18 27 33 now being a navigator, I happen to know that a minute of latitude is a nautical mile so I would say 18*60 + 27 + 33/60 = 1107.5 NAUTICAL miles However do not tell you math teacher that :) we have 1107.5 Minutes of...
January 24, 2016

trig
one goes 60 km one goes 20 km the third side is 50 km divide them all by ten (similar triangle then law of cosines 5^2 = 6^2 + 2^2 - 2*6*2 * cos A 25 = 36 + 4 - 24 cos A -15 = -24 cos A cos A = .625 A = 51.3
January 24, 2016

English I guess
Specify subject so you do not get a physicist.
January 24, 2016

Physics
2 * 6.41 = 12.82 :)
January 24, 2016

Physics- HELP PLEASE!
F = k q1 q2 /r^2 all on 6 F = (k q6) q/r^2 let d = .15 meter due to 3 Fx = - (k q6) 3/d^2 negative direction because +and - Fy = 0 due to -2.4 repelling Fx = +(kq6) 2.4 /[ 2*(d)^2](sqrt2/2) Fy = same up due to -1 only up Fy = (kq6)9/ d^2 so Fx = -c 3/d^2 + c 2.4 *sqrt 2/4d^2 ...
January 24, 2016

math
26 miles ( 1 hour/175 miles) = .14897 hours .14897 hours * (60 minutes/1 hour) = 8.915 minutes .915 minutes ( 60 seconds/1 minute) = 55 seconds so 8 minutes and 55 seconds approximately.
January 24, 2016

Algebra
x and 83-x x - (83-x) = 24 2 x - 83 = 24 2 x = 107 x = 53.5 83.0 - 53.5 = 29.5
January 24, 2016

Grade 11 Functions
parabola, complete square -x^2/100 + 3x - 50 = p x^2 - 300 x + 5000 = -100 p x^2 - 300 x = - 100 p - 5000 x^2 - 600 x + (150)^2 = -100p+22,500 (x-150)^2 = -100 (p-225) vertex at x = 150, p = 225 so once again, 150
January 24, 2016

typo at start 150 is right
profit = 6x - x^2/100 - 50 - 3x p = -x^2/100 + 3 x - 50 dp/dx = 0 at max = -x/50 + 3 x = 50 * 3 = 150
January 24, 2016

Grade 11 Functions
whooops, you have not have derivatives parabola, complete square -x^2/100 + 6x - 50 = p x^2 - 600 x + 5000 = -100 p x^2 - 600 x = - 100 p - 5000 x^2 - 600 x + (300)^2 = -100p+85,000 (x-300)^2 = -100 (p-850) vertex at x = 300, p = 850 so once again, 300
January 24, 2016

Grade 11 Functions
profit = 6x - x^2/100 - 50 - 3x p = -x^2/100 + 6 x - 50 dp/dx = 0 at max = -x/50 + 6 x = 50 * 6 = 300
January 24, 2016

math
1.5 * 8/5 = .3*8 = 2.4 2.5 * 8/5 = .5*8 = 4.0
January 24, 2016

Calculus
1/3 - 1/sqrt 2 = (sqrt 2 -3)/3 sqrt 2 divide that by 2-9 = -7 (sqrt 2 -3)/-21
January 24, 2016

Physics II
m = mass of electron q = electron charge F = m a q E = m a a = q E/m v = Vi - a t v = 0 at stop so t = 5 * 10^5/a d = Vi t - .5 a t^2 .09 = 5*10^5 t - .5 a t^2 now the easy way :) if acceleration is constant the average speed during this stop is 2.5 *10^5 m/s it stops in .09 m...
January 24, 2016

Math
He works two and then four more for a total of six ? 2 + 4*4 = 18
January 24, 2016

math
a + ar + ar^2 ...+ ar^(n-1) a = 3 a r+ a r^2 = 60 r + r^2 = 20 r^2 + r - 20 = 0 (r-4)(r+5) = 0 r = 4 3 + 12 + 48 .... 3 * 4^(n-1)
January 24, 2016

physics
m (g - v^2/r)
January 24, 2016

physic
change of momentum = Force * time = 200 * s If you really mean for s seconds.
January 24, 2016

phy 231
horizontal problem: u = 338 cos 40.5 = 257 m/s x = u t = 257 * 8.09 h = Vi t - 4.9 t^2 where Vi = 338 sin 40.5 = 220 m/s h = 220(8.09) - 4.9 (8.09)^2
January 24, 2016

Been there - use d = v t
http://www.jiskha.com/display.cgi?id=1453604915 Yes, it is composite, so use d = v t which was part B and please use one name so I do not have to search all over for your earlier attempt.
January 24, 2016

Physics
initial momentum east = 3 * 1 - 5 * 2 = -7 so final momentum east = -7 I guess left is west, negative -7 = 3 * -1 + 5 * u 5 u = -4 u = 4/5 west
January 24, 2016

physics
Vertical problem: v = a t x = Xi + Vi t + .5 a t^2 here x = 0 Xi = 49.1 Vi = 0 a = -9.8 0 = 49.1 + 0 t - 4.9 t^2 so a) t = sqrt ( 49.1 m/4.9 m/s^2 ) b) v = -9.8 t c) u = 12.6 v = -9.8 t tan(angle from horizontal) =(v/u)
January 24, 2016

Physics
a = 710/275 v = a t t = 20 * 275 / 710 seconds
January 24, 2016

physics
assuming the weight is evenly distributed radius = .04 meters pi r^2 * P = 400 P = 400/.00503 = 79577 Pascals or about .8 atmospheres
January 23, 2016

Math
Area = 2400 ft^2 2400 (2/12) = 400 cubic feet(7.48 gal/ft^3 = 2992 gallons
January 23, 2016

Math
for P sin T is -1 when T = (3/4)(2pi) = 3 pi /2 for Q sin T then becomes +1 when sin T = 2 pi + pi/2 = 5 pi/2 ------------------------ now x for P 6 pi x = 3 pi/2 x = 1/4 and y is -2 now x for Q 6 pi x = 5 pi/2 x = (5/12) and y is +2 slope = 4/(5/12 - 1/4) = 4 / (5/12 - 3/12...
January 23, 2016

physics
F = 800 - 300 = 500 N a = F/m = 500/400 = 1.25 m/s^2
January 23, 2016

Math
so d = v t
January 23, 2016

Math
what is that x about? d is distance traveled k is hypotenuse 10 , not (10+x) is original distance leg k = sqrt (d^2 + 100) d = v t Is c) the dot product of k and d? I do not understand your notation If it is k dot d then that is |k| |d| cos angle between path direction and ...
January 23, 2016

Physics
m = mass of proton q = charge of proton During first E1 F = q E1 north a = q E1/m north vfinal = (q/m) E1 (14.8) x final = 0 + 0 +.5 (q/m)E1 (14.8)^2 = (q/m)E1 (110) Now during E2 x initial = 110 (q/m)E1 Vinitial = (q/m)E1 (14.8) x final = 0 so 0 = 110(q/m)E1 + 14.8(q/m)E1(8....
January 23, 2016

Math
Well, anyway, the Physics was easy :)
January 23, 2016

Physics
cool :)
January 23, 2016

Physics
By the way, of course they had the same momentum at rest.
January 23, 2016

Physics
That was intended to be a trick, confusing question, but you did not fall for it :)
January 23, 2016

Physics
work done = F * distance in this case the work done goes straight into increasing the kinetic energy F * d = increase in Ke same for both one to one the end.
January 23, 2016

Physics 30
To start: Potential energy of 3 kg box up .5 = m g h = 3*9.81*.5 14.72 Joules 3 kg hit floor point: Potential energy of 2 kg box now = 2 * 9.81 * .5 = 9.81 Joules SO 14.72 - 9.81 = 4.92 Joules is in the kinetic energy of the two moving blocks, m = 3+3=5 kg (1/2)(5)v^2 = 5 v = ...
January 23, 2016

physics
I bet her class uses g = -10 m/s^2 so it came out zero.
January 23, 2016

physics
And that one with the truck and the car bothered you ?
January 23, 2016

Calculus
W = (1/2) k x^2 where x is the stretch or compress length here x = .36 - .28 = .08 meter so 5 = .5 k (.0064) k = 1563 N/m so (1/2) k = 781 a) work to .34 - work to .32 subtract the .28 from both .06 and .04 = 781 (.06^2-.04^2) =1.562 J b) F = k x 15 = 1563 * x x = .00960 m = ....
January 23, 2016

Calc 1
The sin function range is between -1 and +1 1.7321 is not the sin of any angle.
January 23, 2016

Chemistry
6 g of M is 6/27 mol 23.66 g of Cl is 2/3 mol 2/3 = 14/27 so there are 14 Cl atoms for every 6 atoms of M ratio is 3/7 M/Cl M3Cl7
January 23, 2016

Math
there are 2 cups in a pint so 5 pints = 10 cups 4 cups/10 cups = 2/5
January 23, 2016

math
s = 3 c - 20 s = 180 - a c = 90 - a -------------subtract s - c = 90 so s = c+90 c+90 = 3 c - 20 2 c = 110 c = 55 then s = 145 s/c = 145/55 = 29/11 ================= check ================= 3(55)= 20 = 165 - 20 = 145 yes a = 90 -c = 35 180 - 35 = 145 yes
January 23, 2016

maths
4 c + 8 a = 380 c = a - 10 ==================== substitute (a-10) for c 4 (a -10) + 8 a = 380 12 a - 40 = 380 12 a = 420 a = 35
January 23, 2016

Physics
v = Vi - 9.81 t at top v = 0 so t = Vi/9.81 at top 34 = 0 + Vi t - (9.81/2) t^2 34 = Vi^2/9.81 - Vi^2 /(2*9.81) 34 = Vi^2/(2*9.81) Vi = 25.8 m/s
January 22, 2016

physics
momentum = m v = 1200 * 30 kg m/s Ke = (1/2) m v^2 = 600 * 900 Joules 30/2 = 15 v^2 = (1/2)30^2 = 900/2 = 450 so v = sqrt (450) = sqrt (9*50) = sqrt(3*3*5*5*2) = 15 sqrt 2 v = 21.2 m/s
January 22, 2016

Ms sue or damon pls help me with mathhhhhhhhhhhhh
9/12 = 3/4 foot 6/12 = 1/2 foot so Volume = 7 * 1/2 * 3/4 = 21/8 ft^3 (21/8) / 2.625 = 2.625/2.625 = 1 bag. I guess he built the box to hold one bag :)
January 22, 2016

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