Monday

March 30, 2015

March 30, 2015

Total # Posts: 20,743

**Is this right**

as far as I know
*November 11, 2014*

**Is this right**

sin (cos - sin) + cos (sin + cos) -sin^2+cos^2 + 2 sin cos I have cos^2 You have cos
*November 11, 2014*

**math**

8*6 = 48 slices total 48/24 = 2 slices each person 2/6 = 1/3 of a pie each to check 24 people * 1/3 pies/person = 8 pies sure enough :)
*November 11, 2014*

**Financing and Budget**

Yes, C
*November 11, 2014*

**Chemistry**

hard to argue with any of those
*November 11, 2014*

**Algebra Help URGENT Please?**

380/.2 = 3800/2 = 1900
*November 11, 2014*

**Algebra Help URGENT Please?**

95 + .2 s = 475 .2 s = 380 s = 380/.2
*November 11, 2014*

**Math**

yes side , side , side
*November 11, 2014*

**World History Answer Check**

That is more complete. Of course it does not cover the average dead French citizen.
*November 11, 2014*

**Algebra help URGENT Please?**

Oh, sorry, thought there were five eaters, there are 6 25/6 = about 4
*November 11, 2014*

**Algebra help URGENT Please?**

.1*124 =12.4 so.2*124 is about 25 25/5 = $5
*November 11, 2014*

**math**

what does the comma mean in F(x, y) = y cos x − xy sin x, xy + x cos x ? are we to integrate F around the perimeter of the triangle by integrating the divergence over the area or what ? Look at earlier questions below.
*November 11, 2014*

**Math**

the three sides of triangle 1 are the same length as the tree sides of triangle 2
*November 11, 2014*

**Math**

side EF = sqrt (4+4) = sqrt (8) side FD = sqrt (1+4) = sqrt 5
*November 11, 2014*

**Math**

hey if all three sides are the same it is congruent by side,side,
*November 11, 2014*

**Math**

side AB = sqrt (16+1) = sqrt 17 side BC = sqrt (4+4) = sqrt 8 side CA = sqrt (1+4) = sqrt 5 side DE = sqrt (16+1) = sqrt 17 LOL I guess you get the SSS idea
*November 11, 2014*

**Calculus**

Look at that link. It gives you the series expansion about zero explicitly.
*November 11, 2014*

**physics**

the charge on a proton is equal in magnitude and opposite in sign to the charge on a electron. Therefore if an atom has the same number of electrons as it has protons, it is neutral. Otherwise it is called an "ion".
*November 11, 2014*

**Physics**

c) (1/2) m v^2 = answer to b d) The reason they want is that the person would have reached terminal velocity where air drag up = weight down before falling 5000 meters. The reason they forgot about is that the diver also has the constant horizontal velocity of the airplane the...
*November 11, 2014*

**Did I get this right?**

yes, correct but perhaps you better multiply out and collect like terms for example 3x^2 + x^2 = 4 x^2
*November 11, 2014*

**physics**

weight = .010*9.8 = .098 Newtons x = .05 m k = 1.96 N/m omega = sqrt (k/m) = 2 pi f so f = 2.23 T = 1/f = .45 seconds
*November 11, 2014*

**Derivatives**

for starters x^3[ 4(5x-1)^3 (5) ] + 3 x^2 (5x-1)^4
*November 11, 2014*

**Square Roots**

11^2 = 121 12^2 = 144
*November 11, 2014*

**math**

yes, that makes sense. Did she get 26 ( 50/2 + 2/2 = 25+1 = 26 or did she come up with something else entirely?
*November 11, 2014*

**World History Answer Check (Ms. Sue)**

I like your other answers.
*November 11, 2014*

**World History Answer Check (Ms. Sue)**

2. What was the effect of total war on ordinary citizens during World War I? A: Because of total war, ordinary citizens underwent rationing of goods. =================================== True in the world outside the war zone, such as in the US. However ordinary French or ...
*November 11, 2014*

**Math**

I do not know what power you are raising twelve to if you mean 2 + (12)^2 then 2 + 144 = 146
*November 11, 2014*

**physics**

I need to know how far the center of mass of a blade is from the axis. If we assume the blade is a uniform rod with cg at its center (unlikely) then the moment of inertia about its end is: I = (1/3) m L^2 so for 3 we have just I = 1 m L^2 = 159 * 3.69^2 = 2165 kg m^2
*November 11, 2014*

**Math**

200 n = 3000 2 n = 30 n = 15
*November 11, 2014*

**Physics**

u = horizontal velocity = 3.2 cos 40 forever Vi = initial up velocity component = 3.2 sin 40 v = Vi - 9.8 t h = 1.175 + Vi t - 4.9 t^2 at ground, h = 0 so 4.9 t^2 - Vi t - 1.175 = 0 solve quadratic for t, use positive solution then range = u t
*November 11, 2014*

**Statistics**

well, just using what iss given and assuming it is true probability that woman uses computer at work = .72 so probability not = 1-.72 = .28 Binomial distribution prob 5/5 yes = C(5,5) .72^5 *.28^0 = 1 * .72^5 * 1 = .72^5 = .193 (second answer) so prob that someone does not = 1...
*November 11, 2014*

**physics**

seesaw :) 1 x = 35.5(1.27*10^-10 - x) 36.5 x = 45.1 * 10^-10 x = 1.24 * 10^-10 in other words right beside the Cl atom
*November 11, 2014*

**physics**

find the well depth in meters. I doubt if it is really just 10 cm deep but if really true then 0.10 meter multiply mass in kilograms by g, about 9.8 meters/second^2 to get weight force multiply that force by the depth to get work done.
*November 11, 2014*

**question**

I believe so.
*November 10, 2014*

**Math**

d = 4 t d + t = 20 5 t = 20 t = 4 d = 16 16-4 = 12
*November 10, 2014*

**Math help please!!!!!**

24/10 = 30/x 24 x = 300 x = 12.5 I am assuming that x and 10 are along the wall and not the ground.
*November 10, 2014*

**PHYSICS**

dW = p A dr dW = p 4 pi r^2 dr integrate W = p (4/3) pi (r final^3 - r initial^3) W = p (final volume - initial volume)
*November 10, 2014*

**Trigonometry**

sin^-1 (1.2 /4.4 )
*November 9, 2014*

**Physics**

F = m a 150 lbs = 68 kg Fscale up - m g down = m a Fscale up = m g + m a = 150 pounds + 68* 10 newtons = 150 pounds + 680 Newtons 680 Newtons = 153 pounds so 150 + 153 is about 300 pounds
*November 9, 2014*

**math**

65/60 is to the right of 1 on a number line. The result is positive. +
*November 9, 2014*

**Physics**

Thanks, I just went and looked, might do that but I am pretty busy here when I am not coaching our sailing team or whatever.
*November 9, 2014*

**Physics**

I will go look though.
*November 9, 2014*

**Physics**

I am a retired professor, do this for fun.
*November 9, 2014*

**Physics**

You are welcome.
*November 9, 2014*

**Physics**

Ah, here: http://earthsky.org/earth/tides-and-the-pull-of-the-moon-and-sun ( former clammer and lobsterman here :)
*November 9, 2014*

**Physics**

maximum high and low tides occur when the earth, moon and sun are co-linear. That is at full moon and new moon. Such tides are called "spring tides" and occur about twice a month.
*November 9, 2014*

**Physics**

Yes 0 free falling weightless :)
*November 9, 2014*

**Physics**

Backup link :) http://www.jiskha.com/display.cgi?id=1282164495
*November 9, 2014*

**Physics**

Like - "weightless" :)
*November 9, 2014*

**Physics**

No !!! ZERO no force on scale - in free fall, accelerating downward at 9.81 m/s^2
*November 9, 2014*

**Physics**

Total force on person = m g = m a in free fall. No external force on person from scale
*November 9, 2014*

**physics**

ke = .5 m v^2 + .5 I w^2 I = m r^2 w = v/r so ke = .5 m v^2 + .5 m r^2 v^2/r^2 ke = m v^2 v = 2.1 * 3.8 = 8.0 m/s so ke = 5.6 *64 Joules = m g h = 5.6 g h so 64 = g h h = 64/9.8 sin 17.7 = h/distance up ramp so distance up ramp = h.sin 17.7
*November 9, 2014*

**Physics**

see this similar reply http://www.jiskha.com/display.cgi?id=1415568126
*November 9, 2014*

**Chemistry**

How do you find the amount of water that reacted 2 mol of phenylmagesium bromine?
*November 9, 2014*

**Chemistry **

If there are 25 mg of water in a typical drop of water, how many drops of water would react completely with 2 mmol of phenylmagnesium bromide? How do I set up the problem?
*November 9, 2014*

**Physics**

sum of vectors, not product Pa =3.2[ 2.3 i + 4.2 j] = 7.36 i +13.44 j Pb =2.9[ -1.8 i +2.7 j] =-5.22 i +7.83 j P = (7.36-5.22) i +(13.44+7.83) j
*November 9, 2014*

**Physics**

initially p1 = 4 i + 2 j p2 = -3i + 3 j total p = 1 i + 5 j final p must be the same final p1 = px i + py j p2 = 6 i - 3 j px + 6 = 1 px = -5 vx = -5/2 = -2.5 py -3 = 5 vy = 5/2 = 2.5 so v = -2.5 i + 2.5 j
*November 9, 2014*

**physics**

no question was asked
*November 9, 2014*

**Physics**

m g h + (1/2)m v^2 = total energy = constant h is height above hanging straight down mg(2-2 cos 30)+.5m*9 = total energy = m g (2 -cos max angle when v = 0) notice m has nothing to do with this problem, cancels = mg(2-cos45) +.5 m v^2
*November 9, 2014*

**Physics**

Ke - work done against friction = (1/2)kx^2 (1/2)mv^2 - .3 m g (.2+x) = (1/2)(800)x^2 (1/2)*2*9 -.3*2*9.8(.2+x) = 400 x^2 solve quadratic for x why are you talking about m g h ??? it fell on horizontal plane?
*November 9, 2014*

**Math**

b did both draw Venn diagram fri---both- weekend |20-b | b |29-b| 20-b + b + 29-b = 40 49 - b = 40 b = 9 11 fri , 9 both , 20 weekend
*November 9, 2014*

**Calculus**

You are welcome.
*November 9, 2014*

**Calculus**

Do you mean? y= (x^3+8)/(x+2) ???? or what you typed? If my guess is correct then (bottom dtop/dx -top d bottom/dx)/bottom^2 =[(x+2)(3x^2)-(x^3+3)(1)]/(x+2)^2 =[3x^3+6x^2-x^3-3]/(x+2)^2 = (2x^3+6x^2-3)/(x+2)^2
*November 9, 2014*

**calc**

x y = 50 2 x + y = p 100/y + y = p dp/dy = 0 for min = -100/y^2 + 1 y = 10 x = 5 p = 20 feet of fence
*November 9, 2014*

**Algebra**

if x = 6 then f(x/2) = f(3) = 4 y = 4/2 = 2 (6,2)
*November 9, 2014*

**Algebra**

if x = 3 then f(x) = 4 so y = 4 + 4 = 8
*November 9, 2014*

**Physics, please!**

I used g = -10, you do it with your g
*November 8, 2014*

**Physics, please!**

I guess he kicked it horizontally? Hi = 22 0 = Hi - (1/2)(10) t^2 4.4 = t^2 t = 2.1 seconds goes 17 meters horizontal in 2.1 seconds u = 17/2.1 = 8.1 m/s
*November 8, 2014*

**Physics**

F = mu m g work = F d = mu m g d Ke lost = (1/2) m Vo^2 Vo^2 = 2 mu g d mu = Vo^2/(2gd)
*November 8, 2014*

**Algebra 2**

4x(x-6)-x(x-2)=-24 4 x^2 - 24 x - x^2 + 2 x + 24 = 0 3 x^2 -22 x + 24 = 0 18 and 4 I bet (3x - 4)(x - 6) ??? yes x = 4/3 or 6
*November 8, 2014*

**Algebra 2**

6 x^2 - 13 x + 6 = 0 we want 6 * 2 and a 1 to get 13 or 9 and 4 (3 x - 2)( 2x - 3 ) ah, 9 and 4 x = 2/3 or 3/2
*November 8, 2014*

**Algebra**

speed up = u -c speed down = u+c d = speed * time 3 = (u-c)1.5 3 = (u+c)1 1.5 u - 1.5 c = 3 1.5 u + 1.5 c = 4.5 --------------------- add 3 u = 7.5 u = 7.5/3 3 = 7.5/3 + c c = (9-7.5)/3 = 2.5/3 = .83333333333333333333333333
*November 8, 2014*

**S.S.**

Civil Rights Act of 1964? People are still discriminating against black people, particularly in the South
*November 8, 2014*

**Algebra 2**

we know that 7*7 = 49 and 49+1 = 50 so we know what to do 7 p^2 - 50 p + 7 = 0 (7 p - 1) ( p - 7) = 0
*November 8, 2014*

**Calculus (math)**

I tried method 2 but gave up about an hour ago. I do not think there is any trick, just plug and chug.
*November 8, 2014*

**Calculus**

if you were supposed to use feet instead of meters as your other problem that I just saw, use 32 ft/s^2 for g not 9.81 m/s^2
*November 8, 2014*

**Calculus**

a = g = -9.81 m/s^2 v = -gt = -9.81 t h = Hi - (1/2) g t^2 = Hi - 4.9 t^2 b) h at t = 0 = Hi h at t = 3 = Hi-4.9 t^2 = Hi - 44.1 m/s average = (-44.1)/3 = - 14.7 m/s c) at 0 v = 0 at 3 v = -9.81*3 = -29.4 m/s at 6 v = -9.81*6 = -58.9 m/s d) well I am not about to Google Hi Hi...
*November 8, 2014*

**calculus**

I mean e^x as x --> big negative is 1/e^big positive
*November 8, 2014*

**calculus**

e^-a = 1/e^a
*November 8, 2014*

**calculus**

e^x as x --> big negative is 1/e^big negative
*November 8, 2014*

**calculus**

Thought I answered this -x/e^x e^x >> x for large x
*November 8, 2014*

**Math**

C --> y S --> 3 y J --> 3 y + 50 y + 3 y + 3 y + 50 = 7 y + 50
*November 8, 2014*

**Calculus**

Oh good grief, feet :( old text had initial speed 16 ft/s up ? I guess ? h = 32 + 16 t - 16 t^2 0 = 32 + 16 t - 16 t^2 solve quadratic t = [ -16 +/- sqrt ( 256+2048) ] /-32 t = 2 seconds v = dh/dt = 16 - 32 t = 16 - 64 = -48 ft/s
*November 8, 2014*

**Algebra 2**

4 x^2 + 2 x - 2 = 0 2 ( 2 x^2 + x - 1) = 0 (2x-1)(x+1) = 0 x = 1/2 or -1 5 x^2 + 34 x - 7 = 0 (5x-1)(x+7) = 0 etc
*November 8, 2014*

**Algebra 2**

http://www.gregthatcher.com/Mathematics/GaussJordan.aspx x= 1, y=2, z = 3
*November 8, 2014*

**Calculus**

x --> + oo of -x/e^x
*November 8, 2014*

**Physics**

sqrt (251^2 + 80^2)
*November 7, 2014*

**Physics**

How long to fall 10 meters? 10 = (1/2)(10) t^2 solve for t, time in air then 4 meters = u t solve foe u
*November 7, 2014*

**Science Help!!!!**

Yes, first it is burned in the engine to make CO2 The CO2 is used in photosynthesis to make wood and leaves and stuff, releasing the O2 for us to breathe.
*November 7, 2014*

**physics**

Problem entirely vertical assuming your straight line is horizontal Vi = 10 sin 46 v = Vi - g t delta h = Vi t - (1/2) g t^2
*November 7, 2014*

**CAL**

f'(x) or d f(x)/dx y' or dy/dx maybe?
*November 6, 2014*

**Calculus**

-4 cos^3 x^4 sin x^4 (4 x^3) = - 16 x^3 cos^3 x^4 sin x^4 how that is tan x2 whatever that is I can not imagine
*November 6, 2014*

**Math**

log 9 - log 300 2 log 4 + 4 log 3
*November 6, 2014*

**Science**

F2 + F1 = .450 (.750) F2 - F1 = .240 (.750) -------------------------- 2 F2 = .690(.750) etc
*November 6, 2014*

**Physics**

force down = 9.81*12 max friction force = 9.81 * 12 * mu forward force - friction force = m a 15 - 9.81*12 * mu = 12 (.2)
*November 6, 2014*

**Math**

I do not think so I think h = 300 - 16 t^2 she is accelerating DOWN 100 = 300 - 16 t^2 t^2 = 200/16 t = 10 sqrt 2 / 4 = 2.5 sqrt 2
*November 6, 2014*

**Physics easier**

http://outreach.phas.ubc.ca/phys420/p420_04/sean/
*November 6, 2014*

**Hurricane Project for Physics Class**

Physics (hard) http://www.psfc.mit.edu/library1/catalog/online_pubs/iap/iap2013/emanuel.pdf
*November 6, 2014*

**Hurricane Project for Physics Class**

Physics (hard) http://www.psfc.mit.edu/library1/catalog/online_pubs/iap/iap2013/emanuel.pdf
*November 6, 2014*

**Hurricane Project for Physics Class**

Click on hurricane in the upper right corner
*November 6, 2014*

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