Thursday

October 27, 2016
Total # Posts: 27,573

**Physics**

I guess you mean north of east and east of north east = 1000 cos 40 + 500 sin 20 north = 1000 sin 40 + 500 cos 20 east = 937 north = 1113 distance = sqrt(937^2+1113^2) tan angle north of east = 1113/937

*April 27, 2016*

**Math**

width = 1.5 1.5 * 3 * 6 = 18+9 = 27 ft^3 which is one cubic yard

*April 26, 2016*

**Science**

calibrate it. Mark points on it that are he same temp as the real thermometer shows, say in cold water and hot.

*April 26, 2016*

**Math**

7 * 2.5 * h = 175 h = 10

*April 26, 2016*

**math**

Can not, sorry, rules.

*April 26, 2016*

**math**

Note above that she answered a question at 6:41 EDT

*April 26, 2016*

**math**

Your guess is as good as mine.

*April 26, 2016*

**math**

1, 89 , 67 , 89 , 7, 5 , 45 , 7

*April 26, 2016*

**math**

What do you mean? They all are except 0.

*April 26, 2016*

**math**

I suppose

*April 26, 2016*

**math**

Hi neighbor

*April 26, 2016*

**math**

1*1*5/(2*2*6) = 5/24

*April 26, 2016*

**Math**

I said 280 + 4 w = 420 so 4 w = 140 w = 35 mph wind speed now go back and get v

*April 26, 2016*

**Math**

v = 140 + w (140+2w)2 = (140 +w -w )3 = 420 280 + 4 w = 420 etc

*April 26, 2016*

**math**

we need something else with y = 16 and with x = 4 so (4,16) DRAW IT !!!!!!!!

*April 26, 2016*

**Calculus**

how far apart are they ? t in hours sqrt (x^2 + y^2) =sqrt [(50t)^2 + (60 t)^2] so d = (2500 + 3600)^.5 t d = 78.1 t so separation speed is 78.1 mph all the time

*April 26, 2016*

**math**

well they have to add up to one and there are 6 sides p(1) = n prime p(2) = 2n prime p(3) = n prime p(4) = 2n p(5) = n prime p(6) = 2n sum of p s is one 9 n = 1 n = 1/9 primes are 5n or 5/9

*April 26, 2016*

**physics**

Angular momentum after = angular momentum before angular momentum before = I w = 1.4*10^-3 * .33 = .462 * 10^-3 angular momentum after = (1.4*10^-3 + 4.2*10^-3) w so w = .462/5.6 = .0835 rad/s

*April 26, 2016*

**History**

Actually I think the historical advantage of rivers is that you can float down them easily and if the wind happens to blow up river commonly, you can get up the river easily as well. (the Nile :)

*April 26, 2016*

**History**

In fact, more often than not, rivers are more like highways than barriers. Of curse as you know I feel the same way about oceans, but that is because I use them.

*April 26, 2016*

**math**

c(27)= 10 * 27 + 26 = 270+26 = 296 so (27 , 296) c(39) = 10*39 + 26 = 390+26 etc

*April 26, 2016*

**math**

just use 27 for n and do the arithmetic then do the others.

*April 26, 2016*

**History**

Yes, agree with Astral.

*April 26, 2016*

**History**

Not on my map. I also have charts of the South China Sea and Straits of Malacca and Indian Ocean that hint at serious ancient interactions. Your text was not written by a seafarer.

*April 26, 2016*

**math**

up two in x, down one in y slope = -1/2 so y = -x/2 + b 1 = -2/2 + b b = 2 so y = -x/2 + 2

*April 26, 2016*

**maths**

total time = 45 min .75 hour 72 t + 48(.75-t) = 48 etc

*April 26, 2016*

**math**

v = Vi - 32 t 0 = 96 - 32 t t = 3 s h = Vi t - 16 t^2 h = 96(3) - 16(3)^2 h = 288 - 144 = 144 ft

*April 26, 2016*

**American history**

yes

*April 26, 2016*

**American history**

Agree

*April 26, 2016*

**Physics**

Of course there is a more basic way to look at this. F = m a = -mg so a = - g = -10 so v = -gt = -10 t so+- initial speed * t - (1/2)(10) t^2 0 = 3 + 0 - 5 t^2 t = sqrt(3/5) so v = -10 sqrt(3/5) = -sqrt(60) = -2 sqrt 15 = -7.75 which we knew

*April 26, 2016*

**Physics**

sure, as it drops it picks up speed. The loss in height potential energy, m g h, turns into kinetic energy, (1/2) m v^2 In other words: (1/2) m v^2 = m g h v^2 = 2 g h v = sqrt(2gh) which is something a lot of us remember. Note that the mass does not matter. In a vacuum, a ...

*April 26, 2016*

**Mathematics**

neither 8 + 2 n = 32 2 n = 24 n = 12

*April 26, 2016*

**Math**

w+2a = 18 h+2a = 11 w h = 60 so w = 60/h (60/h) + 2 a = 18 but a = (11-h)/2 60/h + 11 - h = 18 60 + 11 h - h^2 = 18 h h^2 + 7 h - 60 = 0 check my arithmetic and solve quadratic

*April 26, 2016*

**Mathematics**

still 12

*April 26, 2016*

**Economic**

google supply and demand

*April 25, 2016*

**Algebra**

http://www.jiskha.com/display.cgi?id=1461567386#1461567386.1461580442

*April 25, 2016*

**physics**

http://www.jiskha.com/display.cgi?id=1461575534

*April 25, 2016*

**Physcis**

How many Joules are needed? power = Vi = 110*7 = 770 watts energy = power*time = 770*600seconds 462,000 JOULES needed = m g h = m (9.81)(10) so m = 4709 Kilograms of water there are 1000 kg of water/meter^2 so 4.709 cubic meters of water

*April 25, 2016*

**Algebra I DONT KNOW HOW TO DO 3 VARIABLES**

x = 2 - y - 5z 4(2 - y - 5z) -3y + 5z = 3 3(2 - y - 5z) -2y + 5z = 1 8 - 4y - 20z - 3y + 5z = 3 6 - 3y - 15z - 2y + 5z = 1 -7y - 15z = -5 -5y - 20z = -5 or y = 1 - 4z -7(1-4z) - 15z = -5 7 + 28z -15 z = -5 13 z = 2 SO I get: z = 2/13 y = 13/13 - 8/13 = 5/13 x = 26/13 - 5/13 -...

*April 25, 2016*

**Physics help**

Is this the same set of waves? Do you have a box where you store leftover waves? If waves go by you in deep water with high speed and long wavelength for example, they will slow down and become shorter as they approach a shallow beach. However the same number hit the beach per...

*April 24, 2016*

**Math**

m = k n/p^2 3 = k (2/1) k = 3/2 m = (3/2) n/p^2

*April 24, 2016*

**Math, algebra 2**

arithmetic sequence first term is one so a = 1 d = -1 sum =120 see http://www.mathsisfun.com/algebra/sequences-sums-arithmetic.html

*April 24, 2016*

**math**

5/4 inch * 4 miles/inch = 5 miles (ignoring the change in altitude :)

*April 24, 2016*

**math**

4 + 5 + 4 = 13 unless you mean (x+20) / (x+4) which is 24/8 = 3 watch your mathematical grammar.

*April 24, 2016*

**life orientation ?**

Is it a violation of my human rights to be asked the same question time after time, day after day, week after week until I am ready to scream?

*April 24, 2016*

**maths**

a, ar ar^2 ar^3 ar^4 a r^2 + a r^3 = -4/3 a r^3 + a r^4 = -4/9 a r^2 (1 + r) = -4/3 a r^3 (1 + r) = -4/9 -4/(3 a r^2) = -4/(9 a r^3) so r = 1/3 a(1/9)(4/3) = -4/3 a = -9 so: -9 -3 -1 -1/3 -1/9 and -1/27

*April 24, 2016*

**maths**

to get -1 + 0 i z^5 = 1 cos 180 + i sin 180 That should get you started

*April 24, 2016*

**math**

9+3 8+4 7+5 6+6 and reverse

*April 24, 2016*

**precalc**

θ = 180 + cos^-1 (1/3) = 180 + 70.5 = 250.5 ϕ = 180 - sin^-1 (1/4) = 165.5 so we want tan (416) = 1.48

*April 24, 2016*

**Calculus**

I get d^2s/dt^2 = 4 sin 3 t ds/dt = v = -(4/3)cos 3 t + c when t = 0 , v = 1 1 = -4/3 + c c = 7/3 v = -(4/3)cos 3 t + 7/3 s = -(4/9) sin 3 t + 7 t/3 + k 6 = k s = (1/9)(21 t - 4 sin 3 t +54)

*April 24, 2016*

**algebra**

1/R = 1/R1 + 1/R2 or R = R1 R2 /(R1+R2) = 8*12/(20) = 4.8 Ohms

*April 24, 2016*

**math**

L = k m^(1/3) 15 = k (125)^(1/3) = k (5) k = 3

*April 23, 2016*

**converting parabolic equations**

huh? multiply x + 15= 8(y^2 - 2y + 1) 8 y^2 - 16 y + 8 = x +15 x = 8 y^2 - 16 y -7

*April 23, 2016*

**Mathematics**

maybe something like let z = ln x dz /dx = 1/x dx = x dz ∫ 1/[x(1+lnx)^2] dx ∫ dz/[ 1+z]^2

*April 23, 2016*

**World History**

Even without an invasion or nuclear bombs Japan was all done. Between the American submarine fleet and surface/air fleets, they were being strangled. Japan does not have oil or many other vital supplies. Without merchant ships to and from Southeast Asia and elsewhere, they ...

*April 22, 2016*

**Math**

Oval? If it were circular, the fence would be 2 pi R long where R is radius (in feet, three times radius in yards) If it is an ellipse, then a = half length of long axis b = half length of short axis Perimeter = 4 a E(k) where k^2 = 1 - (b/a)^2 and E(k) is an elliptic integral...

*April 22, 2016*

**Complex number cartesian form**

Well, that was entertaining :)

*April 22, 2016*

**Complex number cartesian form**

yes r^2 = 4 + 4 = 8 so r = sqrt 8 = 2 sqrt 2 - 2 - 2 i is in quadrant 3, 45 degrees below -x axis Theta = pi + pi/4 = 5 pi/4 or 180 + 45 = 225 degress so x = 8^.5 e^(5 pi i/4) now raise to power five raise (8^.5)^5 = 8^2.5 multiply angle by 5 25 pi/4 = 24 pi/4 + pi/4 which is ...

*April 22, 2016*

**Math**

-4 = x^2 - 4 x = 0 then y = -4 A

*April 22, 2016*

**Physics**

1. U = (1/2) k x^2 =(1/2)(3.792*10^2) (1.42^2)(10^-2) = 3.82 Joules 2. same 3.82 Joules 3. 3.82 + m g h = 3.82 + .294(9.81)(0.960) = 6.59 Joules 4. How long does it take to fall .96 meters? .96 = (1/2)(9.81)(t^2)

*April 22, 2016*

**algebra!!!!**

do you mean y = x^2 - 2 x - 6 ???? if so then 4 x + 10 = x^2 - 2 x - 6 x^2 - 6 x - 16 = 0 (x-8)(x+2) = 0 x = +8 or x = -2 C is looking good but check it if x = -2 does y = +2 work? yes if x = +8 does 42 work? looks good so C

*April 22, 2016*

**Technology**

Hard to say. If you tried to copy and paste, that does not work here.

*April 22, 2016*

**Precal**

log x + log (x-3) = 1 log (x^2 -3x) = 1 10^log (x^2 -3x) = 10^1 = 10 x^2 -3 x -10 = 0 (x-5)(x+2) = 0 x = +5 or - 2

*April 22, 2016*

**Physics**

a) m g h = 110 * 9.81 * 200 Joules (you left the mass out) b) m g h = (1/2) m v^2 c) The work done by gravity is the same, force of gravity times distance down. The work done by friction makes the kinetic energy (speed) less at the bottom. It does not change the change in ...

*April 22, 2016*

**already know how**

I see a long string of what seem to be standard end of semester questions and I am being asked to do them despite having done so half a century ago. I see no attempt by the student or students to do the problems or any indication of what the difficulty is. All I see is an ...

*April 22, 2016*

**College Algebra**

v = Vi c^t .692 = c^3 c = .692^(1/3) c = .884 every year the car loses (1-.884) = .116 or 11.6% of its value value = initial value * .884^t

*April 21, 2016*

**Math**

9:45 do you not have a clock?

*April 21, 2016*

**math**

a lot of different things for example 6 (4+4) = 24 + 24 = 48 (2+2+2)(8) = 16 + 16 + 16 = 48 (1 + 5)(2 + 6) = 1(2+6) + 5(2+6) = 8 + 5*8 = 8 + 40 = 48 etc etc etc etc .......

*April 21, 2016*

**Geometry**

so divide your 85,403 by 9 9,489

*April 21, 2016*

**Math**

(1/2)(4/3)pi r^3 a little bigger than (2)(4^3) 2 * 64 128 a

*April 21, 2016*

**english**

Both are correct. The first means she has it now. The second means she had one in the past.

*April 21, 2016*

**english**

The police on the street and even the courts seem to employ different interpretations of the "innocent until found guilty" principle depending on the race of the suspect.

*April 21, 2016*

**math- pre calc**

x is negative in Q 2 (n/13)^2 + (5/13)^2^2 = (13/13)^2 12=n so x = 12/13

*April 21, 2016*

**HELP PHYSICS PLS :)**

In an elastic collision energy is conserved. NOT if it is inelastic. What is conserved in both cases is momentum. The total kinetic energy at the bottom = (1/2) m v^2 where m = 2.1 + .015 = 2.12 kg so your PE at top = (1/2)(2.12)v^2 solver for that v at the bottom. Then use ...

*April 20, 2016*

**Physics**

constant speed means no acceleration F = m g = 608 N W = force * distance = 608*4*5 = 12,164 Joules same but force opposite to motion for gravity -12,164 signs reverse if going down

*April 20, 2016*

**math**

3 x^3 (x-2)

*April 20, 2016*

**math**

if a circle of radius r then pi r^2

*April 20, 2016*

**Physics**

total R = 28 so i = EMF/28 = 1.5 so EMF = 1.5*28 = 42 volts voltage drop internal = 1.5*3 = 4.5 volts so terminal V = 42 -4.5 = 37.5 volts power waste = i^2R = (1.5)^2 * (3) = 6.75 Watts

*April 20, 2016*

**Math**

a + (3a+12) = 90 4 a = 78 a = 19.5 degrees 90 - 19.5 = 70.5 check 3(19.5) + 12 = 70.5 ok

*April 20, 2016*

**math help pls pls pls**

at x = 4 h = -16 +32 + 2 = 18 ft at x = 1 h = -1 +8 + 2 = 9 ft so from x = 1 to x = 4, the water went up 9 feet the average speed = 9/3 = 3 feet/second so yes c

*April 20, 2016*

**ethics**

My cat pretty much decides what he is going to do next.

*April 20, 2016*

**Physics**

if speed o sound = V meters per second then 2 V

*April 20, 2016*

**science help PLS**

Yes, the first choice is most likely.

*April 20, 2016*

**Maths**

conditional: If a cow, then a mammal Draw a small circle with a cow in it completely inside a big circle with other mammals in it. Alligators and dinosaurs are way outside even the big circle converse: If a mammal, then a cow (maybe, false) In big circle, maybe not in little ...

*April 20, 2016*

**nah**

0.00

*April 20, 2016*

**Analytic Geometry**

http://www.youtube.com/watch?v=8A1BsHbXWBE latus rectum: http://www.emathzone.com/tutorials/geometry/length-of-latus-rectum-of-ellipse.html

*April 20, 2016*

**Physics**

A) (1/2) m v^2 B) m g h Potential

*April 20, 2016*

**Algebra**

for heavens sake it says to subtract, so subtract 9-5 = 4 2 - 0 = 2 -5 - -7 = 2 4-4 = 0 so 4 x^3 + 2 x^2 + 2 x 2x(2x^2 + x + 1)

*April 20, 2016*

**Math**

You are welcome.

*April 20, 2016*

**Math**

yes, 2 pi r is a bit more than 6*12

*April 20, 2016*

**Math**

You want me to find the mean then the difference of each from the mean then square that then add them all and divide by 3 or 4 depending on your class' definition then take the square root. No way - You do it.

*April 20, 2016*

**good grief !**

Where? Silk road? European river routes? Indian Ocean? Baltic - Volga - Caspian - Black Sea? South China Sea? Mediterranean Sea?

*April 20, 2016*

**Maths**

e^iT = cos T + i sin T = for z^5 = -1 z^5 = 1cos pi + i sin pi that pi angle gives you real pat of -1 and imaginary part of 0 |z|= r = 1^(1/5) = 1 T = pi pi + 2pi/5 pi + 4pi/5 pi + 6 pi/5 pi + 8 pi/5 subtract 2 pi if they are over to get angles the first one is at 180 deg the ...

*April 20, 2016*

**Math**

60 = 5 * 2 * 3 * 2 60 = 2^2 * 5^1 * 3^1 log3(60)=log3(3)+log3(5)+2log3(2) we know log3(3) = 1 so log3(60) = 1 + x + 2y

*April 20, 2016*

**missed - sign**

5 a *c + 5 a *2b - 5 a *5d = 5 a ( c + 2b - 5d )

*April 20, 2016*

**Mathematics grade 9**

8m-24mn m is common and 24 = 8 * 3 so 8 m * 1 - 8 m * 3n = 8m ( 1-3n) 30gh+15fg-5fh 5 again and I see nothing else common to all three terms 5 ( 6gh + 3fg - 1fh )

*April 20, 2016*

**Mathematics grade 9**

5 a *c + 5 a *2b + 5 a *5d = 5 a ( c + 2b + 5d ) by distributive property of multiplication

*April 20, 2016*

**Pre-Cal**

by the way surely they ask the range, x x = u * t in air = 131 * 3.07 = 402 ft That is a serious throw

*April 20, 2016*

**Pre-Cal**

typo you mean y=h+v(o)tsin(o)-16t^2 Vi = initial speed up = 139 sin 20 = 47.54 ft/s u = horizontal speed = 139 cos 20 = 131 ft/s x = 131 t y = 5 + 47.54 t - 16 t^2 when is y = 0? 16 t^2 - 47.54 t - 5 = 0 t = [ 47.54 +/- sqrt(2260+320)]/32 use positive time t = 3.07 seconds in ...

*April 20, 2016*

**Math**

2 D correct 3 B correct despite the name being radiator the warm air will rise on the hot wall and sink on the cold wall. 4. D correct

*April 20, 2016*