Wednesday
September 2, 2015

Posts by Damon


Total # Posts: 21,865

physics
Ke = .5 m v^2 .5 (7)(2.15)^2 = .5 (.0024) v^2 v^2 = (7)(2.15)^2/.0024
February 17, 2015

physics
(a) 150 * 5.5 Joules (b) no acceleration so work done by friction = 150 * 5.5 mu m g *5.5 = 150 * 5.5 mu = 150/(45*9.81)
February 17, 2015

physics
east distance = x = 4 + 2 cos 50 south distance = y = -2 sin 50 d = sqrt ( x^2 + y^2 )
February 17, 2015

Math
.015(500) + .01 (241.23)
February 17, 2015

math
S(5) = 125 -125 + 4 = 4 v = 3 t^2 - 10 t v(5) = 75 - 50 when is v = 0? 3 t^2 - 10 t = 0 = t(3 t - 10) t = 0 or t - 10/3 a = 6 t - 10 a(2) = 12 - 10 = 2
February 17, 2015

Calculus
he said at (0,0) the slope is 2 That is a line through the origin with slope = 2 y = 2 x + 0
February 17, 2015

Business Math
paid 5.50 dollars for 100 dollars that is 100(5.50/100) = 5.5 percent in two weeks or 2.75 percent per week 2.75 * 52 = 143 percent per year. Which is huge!
February 16, 2015

Algebra typo ???
b a^2 This question means nothing to me, sorry.
February 16, 2015

phyic
G = 6.67 * 10^-11 N m^2/Kg^2 Sun mass = 1.99 * 10^30 Kg Jupiter mass = 1.89 * 10^27 Kg d= 7.78 * 10^11 m F = G Msun Mjup / d^2 =[6.67*1.99*1.89/60.5]10^[-11+30+27-22] = .141 * 10^24 = 1.41 * 10^23 Newtons
February 16, 2015

math
You fixed the speed at 5 d = 5 t distance, d, depends on how long you walk ,t We are assuming that the number of credits earned is a function of (dependent on) age age is independent credits is dependent There is no function implied here, in fact there might be multiple values...
February 16, 2015

math
51 = 3 m
February 13, 2015

Physics
work = charge * voltage work in Joules charge in Coulombs voltage in Volts 133/3 = 44 1/3 Volts
February 13, 2015

Physics
Do not understand your notation. Do you mean 2.13 * 10^8 Volts ???? anyway energy in Joules = potential in Volts * charge in Coulombs
February 13, 2015

kayli
molecules
February 13, 2015

math
All three of us got the same answer.
February 13, 2015

math
10 ft/min (60 min/1h)(1 mi /5280 ft) = 600/5280 mi/h = 0.1136 mi/h
February 13, 2015

pre cal 11
You are welcome.
February 13, 2015

pre cal 11
If tn = -4 + (n-1)6 then tn = -4 + 6 n - 6 or tn = 6 n - 4 -6 which is 6 n - 10 sure enough
February 13, 2015

pre cal 11
There are 7 posts including the two end ones. That means six equal spaces between posts 42/6 = 7 meters (note, number of spaces = number of posts - 1)
February 13, 2015

Physics
28.5 cm/s * 2.88 cm^2 = 82.1 cm^3/s volume flow rate so mass flow rate is 82.1 cm^3/s * 1.03 g/cm^3 = 84.5 g/s
February 13, 2015

maths
A work/day = 1/16 B work/day = 1/12 2(1/16) + x(1/16 +1/12) = 1
February 13, 2015

Physics Dynamics
work done against friction = Initial PE - final Ke = Force of friction * distance down slide = mu * normal force * distance Now where is your work?
February 12, 2015

Math
ds/dt = v = -4 (2t) /t^4 = -8/t^3 if t = a v = -8/a^3 if t = 1 v = -8/1 = -8 if t = 2 v = -8/8 = -1 if t = 3 v = -8/27
February 12, 2015

Algebra 1
6 a + 2 s = 40 5 a + 12 s = 85 multiply first one by 6 36 a + 12 s = 240 5 a + 12 s = 85 ------------------ subtract 31 a = 155 a = $5 now find s
February 12, 2015

Physics
so the magnitude is 3.31 kg m/s
February 12, 2015

Physics
-29 m/s - (+29 m/s) = -58 m/s velocity change change in momentum = -.057(58) kg m/s
February 12, 2015

Physics
Ac = v^2/R = 100/20 = 5 m/s^2 so F = m g + 5 m = (9.81+5)m = 14.81 m so F = 14.81*85 = 1258 Newtons f = change in momentum / time change in momentum = 85*10 = 850 kg m/s time = distance/average speed = 1.5/5 = .3 seconds so f = 850 kg m/s / .3 s = 2833 kg m/s^2 = 2833 Newtons
February 12, 2015

math
(1/2) x = 3 x = 6
February 12, 2015

Math
HE HAD 280 dollars. That is the answer. It is not a fraction.
February 12, 2015

Math
he started with x he spent 3/7 of x then he had 4/7 of x left he then gave his sister 1/4 of 4/7 of x so he was left with 3/4 of 4/7 of x that is 120 so 3/4 * 4/7 * x = 120 3/7 * x = 120 x = 40*7 = 280 =========================== NOW spend 3/7 * 280 = 120 280 - 120 = 160 left ...
February 12, 2015

Math
Look at this simpler problem: http://www.jiskha.com/display.cgi?id=1423783632
February 12, 2015

Math
He spent 3/7 which left him with 4/7 !!! 7/7 - 3/7 = 4/7 then he gave away 1/4 of his 4/7 1 - 1/4 = 3/4 so he is left with 4/7 * 3/4
February 12, 2015

math
HUH ? 120.25 + (7/28)^(3/7) ??? but 7/28 = 1/4 = .25 120.25 + .25^.42857 ??? 120.25 + 0.55 = 120.80
February 12, 2015

Physics
You have to tell us the angles from vertical or horizontal or what. if from horizontal T1 cos 45 = T2 cos 30 .707 T1 = .866 T2 T2 = .816 T1, so T1 is the one that will break m g = T1 sin 45 + T2 cos 30 m g = .866 T1 + .866 (.816) T1 m g = .866 T1 + .707 T1 = 1.57 T1 m g = 1.57...
February 12, 2015

Math
I am getting a bit bored with this question as well.
February 12, 2015

Math
he was left with 4/7 he gave 1/4 of the 4/7 to his sister so he was left with 3/4 of the 4/7 so (3/4)(4/7)x = 120 (3/7) x = 120 x/7 = 40 x = 280
February 12, 2015

math
1 - 3/7 = 4/7 is remainder (4/7) x - 3 = 120
February 12, 2015

TYPO ???
5 seconds up, 5 seconds down do vertical problem first with Vi = initial velocity component up v = Vi - g t at top v = 0 0 = Vi - 10 t but t = 5 seconds so Vi = 50 m/s IF YOU LAUNCH AT 10 m/s, YOU CAN NOT STAY IN THE AIR TEN SECONDS!
February 12, 2015

Science
If there are no mutations, there are no changes with generations, no adaptation of beak lengths or anything.
February 12, 2015

Science
You are welcome.
February 12, 2015

Science
n = 2 , 3, 4, 5, 6 ,7 ..... n^2 = 4 , 9 , 16, 25,...... 1/n^2 = 1/4 , 1/9 , 1/16 .....
February 12, 2015

Science
so did I :)
February 12, 2015

Science
1/n^2
February 12, 2015

math
100(3/4) = 300/4 = 75
February 12, 2015

math
sorry, slope intercept form is y = -(1/2) x + 1/2
February 12, 2015

math
2 y = -x + 8 y = -(1/2) x + 4 so slope = -1/2 -2 = -(1/2) 5 + b -2 = -2.5 + b b = .5 = 1/2 so y = -(1/2) x + 1/2 2 y + x = 1
February 12, 2015

Math
x in 1900 y in 2015 x = .64 y so y = 1.56 x so y now is 156 percent of x which is an increase of 56 percent
February 12, 2015

Math
(4/7)(3/4) x = 120
February 12, 2015

Physics
d = (1/2) g t^2 6.9 = 4.9 t^2
February 12, 2015

Physics
horizontal x = 100 + 35 cos 35 vertical y = 35 sin 35 or sqrt(x^2+y^2) at tan^-1(y/x) above x axis
February 12, 2015

Physics
There is no force on the ball after it its release so it continues at 4,000 km/s while the ship accelerates away from it. Therefore: -6 m/s^2 Think, how does your head move when you accelerate a car as opposed to driving straight at constant speed.
February 12, 2015

math
3/2 is bigger than 1 4/9 = 13/9
February 12, 2015

linear algebra
well, we agree this time :)
February 12, 2015

linear algebra
I am going to call c1 = a c2 = b c2 = c +3a + 1b -11c = 0 +3a + 2b -13c = 0 -1a - 3b + 9c = 0 -b+2c = 0 from first 2 so b = 2 c +3a + 2b -13c = 0 -3a - 9b +27c = 0 from second 2 ---> -7 b + 14 c = 0 so -7(2c) = -14 c c = anything at all In your linear algebra using Cramer&#...
February 12, 2015

Physics
You must know the acceleration A of the shuttle F = m A + m g
February 12, 2015

physics
work = change in potential energy = m g h No work is done in the horizontal motion because the force, gravity, is perpendicular to the direction of motion during horizontal displacement.
February 12, 2015

math
A = x y cost = 75 x + 60 y = 1750 60 A = x (1750 - 75 x) maximize 60 A = z z = 1750 x -75 x^2 75 x^2 -1750 x = -z complete square to find vertex o parabola x^2 - 23.3 x = -z/75 x^2 - 23.3 x + 11.7^2 = - z/75 + 136 (x -11.7)^2 = -(1/75)(z-10,200) x = length = 11.7 A = z/60 = ...
February 12, 2015

Physical sciences
v = 0 + a t 12 = a (5) a = 12/5 Is that the whole question? Surely they ask about the deceleration as well? d = Vi t + (1/2) a t^2 so 24 = 12 t + (1/2) a t^2 v = Vi + a t so 0 = 12 + a t
February 12, 2015

algebra
if b is base 8 b + b = 36 9 b = 36 b = 4 then 4 b = 16 so 16 , 16 and 4
February 12, 2015

physics
(1/2) m v^2 = m g h v = sqrt (2 g h) = sqrt(2*9.81*4.03) average speed = v/2 5.00 = (v/2) t t = 10/v
February 12, 2015

Physics
tension - T inward force = T cos 30 so T cos 30 = m v^2/.6 downward force = mg = T sin 30 = T/2 T = 2 m g so 2 m g = m v^2/.6 v^2 = 1.2 g if you want angular velocity v = omega r omega = v/.6
February 12, 2015

Physics
power = V^2/Req = 9.8 = 26^2/Req so Req = 69 ohms so R = 2 Req = 138 Ohms new Req: 1/Req = 1/138 + 1/276 Req = 92 Ohms power = 26^2/92 = 7.35 Watts
February 12, 2015

physics
correct
February 12, 2015

GEO
7.5 * 5*10^4 cm (1 km/10^5 cm) = 37.5 * 10^-1 = 3.75 km
February 11, 2015

Physics
If there were a potential difference current would flow. i = V/R where V is the potential difference and R is the resistance In a perfect conductor the resistance is zero and and V ( potential difference) would lead to infinite current to wipe out the potential difference. ...
February 11, 2015

math(5th grade)
.375 = 3/8 (3/8)120 = 3*15 = 45
February 11, 2015

physics
m1 = 3 m2 = 4 F = m1 a1 = 3 a1 F = m2 a2 = 4 a2 so 3 a1 = 4 a2 3 * 6 = 4 * a2 a2 = 18/4 = 9/2 = 4.5 m/s^2
February 11, 2015

physics
40 = (1/2)(9.81) t^2 t = 2.86 seconds v = g t = 9.81 * 2.86
February 11, 2015

physics
13400 cm (1.72*10^-6) ohm cm /2.07*10^-2 cm^2 = [(1.34)(1.72)/(2.07)] * 10^(4-6+2) = 1.11 Ohms
February 11, 2015

physics
multiply
February 11, 2015

MATH
18 qt * 1 gal/4 qt = 2.5 gal 7 half gal * 1 gal/2 half gal = 3.5 gal 2.5 + 3.5 = 6 gal
February 5, 2015

Math Ms Sue please help me
We can not see your picture so have no idea how to help.
February 5, 2015

physic
420 rev/min = 420 * 2 pi /60 = 44 radians/second 120 rpm = 12.6 rad/s alpha = (12.6 - 44 ) /4 = -7.86 radians/s^2 (part A) angle = initial omega t + (1/2) alpha t^2 angle = 44 (4) - (1/2)(7.86)(16) = 113 radians 113/2pi = 18 revolutions 18 * 2 pi r =18 *2 pi * .2 = 22.6 cm but...
February 5, 2015

physics
d = u t for car d = 20.1 t d = (1/2) a t^2 for cruiser d = (1/2) 2.65 t^2 = 1.325 t^2 so 1.325 t^2 - 20.1 t = 0 t (1.325 t - 20.1) = 0 they are together at t = 0 and again at t = 20.1/1.325 = 15.2 seconds
February 5, 2015

physics
v = Vi - 9.81 t at top v = 0 t = Vi/9.81 at top Vi = 20.1 sin 33.4 = 11.1 so t = 11.1/9.81 = 1.13 seconds at top how far horizontal in 1.13 seconds? u = 20.1 cos 33.4 = 16.8 m/s 16.8 m/s * 1.13 s = 19 meters
February 5, 2015

algebra
2.5 pounds/month is a constant slope of weight as a function of age. Therefore we are dealing with a straight line, linear function. (eventually it will hopefully turn exponential as it approaches full grown weight but that is a later problem :) six weeks = 1.5 months weight...
February 5, 2015

chemistry
They are liquid.
February 5, 2015

Math
You are welcome.
February 5, 2015

Math
7/8 = .875 14/14 = 1 1 4/9 = 1.444444444...... 3.2 = 1.5 which is the winner
February 5, 2015

math
Hey, you are supposed to know how to solve simultaneous linear equations or would not have been given this problem: http://www.jiskha.com/display.cgi?id=1423159248#1423159248.1423161824
February 5, 2015

math
2.4 * 2.8 * 3 = 20.16 m^3 1 m^3 = 1000 liters so V tank = 20,160 liters we have 3,600 liters so must deliver 16,560 liters 16,560 liters / .5 liters/s = 33,120 seconds /3600 = 9.2 hours 9 hours and 12 minutes
February 5, 2015

math
p = 1040 - c L = c - 880 but p = 3 L 3 L = 1040 - c so 3 (c-880) = 1040 - c 3 c - 2640 = 1040 - c 4 c = 3680 c = 920
February 5, 2015

Latin I
Well, I took Latin in 1951 and 1952 but your work looks ok to me for what that is worth.
February 5, 2015

statistic
This might help: http://davidmlane.com/hyperstat/z_table.html
February 5, 2015

chemistry
Mg ion +2 Cl ion - 1 so I suspect MgCl2
February 5, 2015

math/algebra
s = a + 70 s+a=770 so (a+70) + a = 770 2 a + 70 = 770 2 a = 700 a = 350
February 5, 2015

physics
v = Vi - 9.81 t if it came down at 28 m/s, it started up at 28 m/s (symmetry) v = 28 - 9.81 t at the top, v = 0 0 = 28-9.81 t so t = 28/9.81 at the top, same time falling h = (1/2)(9.81) t^2 h = (4.9)(28/9.81)^2 h = 4.9
February 5, 2015

math - We do not do magic
If you do not give some sort of distribution of customer arrival times I have no idea when Tony's staff should be there.
February 5, 2015

math Huh ?
I do not have the slightest idea what you are talking about. Arithmetic sequences or series maybe ?
February 5, 2015

physics
Now you should be able to do them.
February 5, 2015

physics
in general if speed is s at A degrees above horizontal u = s cos A Vi = s sin A
February 5, 2015

physics
Now divide your problems up into vertical problems and horizontal problems if horizontal speed is u at start it is u to the finish so x = u t if initial vertical speed is Vi then v = Vi - 9.81 t (remember v=0 at top) h = Hi + Vi t - 4.9 t^2
February 5, 2015

physics
just a vertical problem Vi = 17.9 sin 36.0 h = 0 + Vi t - 4.9 t^2 0 = 0 + t (Vi - 4.9 t) so it is at ground level at t = 0 of course and at t = Vi/4.9
February 5, 2015

Algebra typo ???
a (b+c) = db a (b+c) = dc If you did not make a mistake than of course b = c but CHECK FOR TYPOS
February 5, 2015

physics
first do the horizontal problem with constant horizontal speed of 13 for 21.4 m to get time in air distance = speed * time t = 21.4 /13.0 now we know it fell for time t h = (1/2) g t^2 h = (1/2) (9.81) (21.4/13.0)^2 meters
February 5, 2015

Math
Not that I know of.
February 5, 2015

Math
(5/12) s = 10 c + 20 (7/12) s = 15 c well we have two linear equations with two unknowns. We can do it. 7 s = 180 c so c = (7/180) s (5/12) s = (7/18)s + 20 (5/4) s = (7/6) s + 60 (15/12)s = (14/12) s + 60 s/12 = 60 s = 720 kg
February 5, 2015

physics
speed east = 1.65 cos 18.8 t = 21.0 / ( 1.65 cos 18.8 )
February 5, 2015

Maths
5 f + 10 t = 500 f + t = 90 f + 2 t = 100 f + 1 t = 90 ------------- subtract t = 10 then f = 80 check 400 +100 = 500 80 + 10 = 90 ok
February 5, 2015

chm
water is 1 g/mL so we have 0.105 g of H2SO4 per mL How many mols is that H2 = 2 g/mol S = 32 g/mol 4 O = 64 g/mol total = 98 g/mol .105/98 = .0011 mol /mL which is 1.1 mol/Liter
February 2, 2015

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