Saturday

August 1, 2015

August 1, 2015

Total # Posts: 21,591

**Math**

85/100 = 17/20
*January 13, 2015*

**Science**

work = force * distanced moved in direction of force W = 10 * 1.5 = 15 Joules
*January 13, 2015*

**MATH**

Yes, it is D
*January 13, 2015*

**MATH**

NO! hey sketch both graphs for x = -1, x=+1, x = 0
*January 13, 2015*

**MATH**

Please sketch a graph. It is two V shapes identical except that one is 15 below the other.
*January 13, 2015*

**Math**

1/4 went 1/4 * 496 = 124
*January 13, 2015*

**math**

dimensions are length = 8+4 = 12 width = 4 +4 = 8 2 L + 2 w = 24 + 16 = 40
*January 13, 2015*

**algebra 2**

x = 0.04 t 25 = 0.04 t t = 25/.04 = 625 seconds which is about ten and a half minutes
*January 13, 2015*

**math**

You are welcome
*January 13, 2015*

**math**

yes 2.5 * 15 = 37.5 and 2.5 hours per day * 22 days = 55 hours
*January 13, 2015*

**physics**

It is going away so you hear a longer wavelength so LOWER frequency
*January 13, 2015*

**algebra 2 help typo?**

x+4 = 8/3 x = 8/3 - 12/3 = -4/3 or -x-4 = 8/3 x+4 = -8/3 x = -20/3
*January 12, 2015*

**alegebra 2 Help**

(x+h)^2 = x^2 + 2 h x + h^2 x(x^2 + 2 h x + h^2)=x^3 +2 hx^2+ xh^2 h(x^2 + 2 h x + h^2)=hx^2+2h^2x+h^3 sum=x^3 +3hx^2 +3h^2x+ h^3 etc
*January 12, 2015*

**alegebra 2 Help**

so continue [ x^3 -(x+h)^3 ] / [h x^3(x+h)^3]
*January 12, 2015*

**alegebra 2 Help**

[1/(x+h)^3 - 1/x^3 ]/h
*January 12, 2015*

**physics**

reaches top in 1.5 seconds v = Vi - g t 0 = 5 - 1.5 g g = 5/1.5 = 3.33 m/s^2 v = 15 - 3.33 t 8 = 15 - 3.33 t t = 2.1 seconds h = 15 t - (3.33/2) t^2
*January 12, 2015*

**Legal research**

Would you believe it says a digest is an index ? :)
*January 11, 2015*

**Legal research**

http://lawlibguides.byu.edu/content.php?pid=225319&sid=1961818
*January 11, 2015*

**Legal research**

I believe you are correct.
*January 11, 2015*

**math**

You are welcome.
*January 11, 2015*

**math**

M = 2 P- 4 so P + 2P-4 = 32 3 P = 36 P = 12 then Marc has 24 - 4 = 20
*January 11, 2015*

**legal research writings**

Then I suppose go with the dictionary. I do not think law dictionaries have pockets with updates, but I am not a legal scholar.
*January 11, 2015*

**legal research writings**

Well, I agree that a treatise might not be typically updated.
*January 11, 2015*

**legal research writings**

but I think you might just publish a new edition of a dictionary.
*January 11, 2015*

**legal research writings**

I think you might: http://en.wikipedia.org/wiki/Legal_treatise
*January 11, 2015*

**legal research writings**

Would you update treatises?
*January 11, 2015*

**Legal research**

Yes, Lucina is right http://www.acronymfinder.com/LexisNexis-%28online-legal-research-tool%29-%28LN%29.html
*January 11, 2015*

**Legal research**

go with Lucina, I just Googled it.
*January 11, 2015*

**Legal research**

sorry, Google shows: Lex-Nex
*January 11, 2015*

**chemistry**

mol of Na O H = 23+16 + 1 = 40 grams so 1 gram is 1/40 mol = .025 mol .025 mol = .2 mol/liter * x liters so x = .025/.2 = .125 liters or 1/8 liter
*January 11, 2015*

**Algebra Help Please**

here, for any old x x^0 * x^1 = x^(1+0) = x^1 so x^0 was 1
*January 11, 2015*

**Algebra Help Please**

ANYTHING^0 = 1 no more steps needed
*January 11, 2015*

**algebra**

HEY, you were almost there! -4 1/x^2 x * y^4 y^7/1 -4 *1/(x^2*x) * y^(4+7) = -4 y^11/x^3
*January 11, 2015*

**algebra**

12 x^-2 y^4 /{ -3 x (y^-7) } ?? is -4 x^-3 y^11 = -4 y^11/x^3
*January 11, 2015*

**Math**

maybe average = (7.6+10.4)/2 = 9 9 +/- |1.4|
*January 11, 2015*

**physics**

we must find the change of momentum during contact, in other words Vi and u Vi = w sin 61.8 u = w cos 61.8 if w is the initial speed 176 = u t where t is total time in air v = w sin 61.8 - g t h = Hi + Vi t - 4.9 t^2 0 = 0 + Vi t - 4.9 t^2 = t(Vi - 4.9 t) so it is at the ...
*January 11, 2015*

**Math**

10/(100+20) = 10/120 = 1/12
*January 11, 2015*

**Algebra 2**

z = k x y^2/ (r s) where k is a constant
*January 11, 2015*

**Physics**

average force = change of momentum/time instantaneous force if m is constant = m A so average force = 97.7 / .368 Newtons
*January 11, 2015*

**Algebra II**

(f+g)(x) = 8 x^2 + 1/x^2 (f-g)(x) = 8 x^2 - 1/x^2 f [g(x)] = f (1/x^2) = 8(1/x^4) = 8/x^4 f [1/g(x)] = f (x^2) = 8 x^4
*January 11, 2015*

**Algebra 2**

Intersection of a hyperbola with an ellipse, cool 2 x^2 - 5 y^2 = 1 2 x^2 + 10y^2 = 136 --------------------subtract -15 y^2 = -135 y^2 = 9 so y = +/-3 x^2 = 68-45 = 23 so x = +/-sqrt(23) (sqrt 23 , 3) (sqrt 23 , -3) (-sqrt 23 , 3 ) (-sqrt 23 , -3)
*January 11, 2015*

**math**

The trick is: Out of every four bagels one is sesame and three are plain so that sesame/plain = 1/3 sesame/all = 1/4 = .25 = 25% plain/all = 3/4 = .75 = 75% (1/4) 24 = 6 sesame (3/4) 24 = 18 plain
*January 11, 2015*

**Calculus**

f' = 1/x^2 at x = -3, f = 1/3 at x = -1/2, f = 2 slope = (2 - 1/3)/(-1/2 + 3) = (5/3)/(5/2) = 2/3 where is the derivative = 2/3 ? 1/x^2 = 2/3 x^2 = 3/2 x = +/- sqrt (3/2) yes B
*January 11, 2015*

**Math**

first equation y - x/2 = 5 2 y - x = 10 second equation -x + y/5 = -13 y - 5x = -65 2 y - 10 x = -130 so two equations 2 y - x = 10 2 y - 10 x = -130 --------------------subtract 9 x = 140 x = 15.56 y = 5 + x/2 = 12.78
*January 11, 2015*

**Calculus**

yes, v = 6 t - 3 t^2 dv/dt = 0 at max or min = 6 - 6 t so max or min at t = 1 max or min? d^2v/dt^2 = -6 so max what is that max v at t = 1 v(1) = 6-3 = 3 so C.
*January 11, 2015*

**MATH**

I think you will have to try various interest rates and graph that function if i = .1 or 10% 6.25 = 5.76 if i = .08 6.25 = 6.24 close to 8%
*January 10, 2015*

**Math**

scroll down a bit. I just did that not a good idea to use your real name
*January 10, 2015*

**Polynomials**

it is asking if the left is the same as the right look at a (a-b)(a-b) = a^2 -2ab + b^2 Always then b (a+b)(a+b) = a^2 + 2ab + b^2 NOT a^2+b^2 and is ONLY true if a or b is zero same problem with c You have a typo in d but if that is a + sign then true (a+b)(a+b)=a^2+2ab+b^2
*January 10, 2015*

**Math**

(4x-1)/[(x+3)(x+4)] * (x+4)(x-3)/(2x-1) when you divide fractions, invert the denominator and multiply (x+4) cancels (4x-1)(x-3) /[ (x+3)(2x-1)]
*January 10, 2015*

**Math**

yours (x^2-2x)/(x+1)x (x^2-1)/(x^2+x-6) My work on simplifying the expressions x(x-2)/(x+1) * (x+1)(x-1)/[(x+3)(x-2)] note your sign error in second denominator (x+1) and (x-2) cancel x(x-1) / (x+3)
*January 10, 2015*

**Calculus**

2^1 +2^1 *2^1 + 2^1* 2^2 ..... 2^1*2^(n-1) is 2 + 2*2 + 2 *2^2 .... note 2^1 * 2^(n-1) = 2^n 2^1 =2 = a 2 = r sum from i = 1 to n = 2 ( 1-2^n)/(1-2) = -2 (1-2^n) =2^(n+1) - 2
*January 10, 2015*

**calculus**

Do you mean from 0 to 5 and from 0 to 6 ? if so 2 (x^2 -3 x) at 5 - at 0 = 2 (25 - 15) - 0 = 20 at6 it is 2 (36-18) = 2*18 = 36
*January 10, 2015*

**calculus**

what is the derivative of (5/7)x^7 ? what is the derivative of -x^(-2) ?
*January 10, 2015*

**Physics**

period = T = 60 seconds/26 = 30/13 f = 1/T = 13/30 A = 3.9 cm y = -3.9 cos (2 pi t/T) because y = -3.9 when t = 0 y = - 3.9 cos (26 pi t/30)
*January 10, 2015*

**Math**

I can not simplify it but f(x) = -3(x^2+4x+4) -x-1 = -3 x^3 -12 x -12 - x - 1 = -3x^2 - 13 x -13 sure enough f(x) = [(x-2)(x+1)] / [ (3x+1)(x+1) ] = (x-2)/(3x+1) we win again
*January 10, 2015*

**Math**

(x-2)(x+1)/(x+1) = x-2 = g(x) (x-4)(x+3)/(x+3) = x-4 g(x) = (x-2)(x-4)/(x-2) = x-4 also
*January 10, 2015*

**math**

13,000 = 6,000 +.05(x-20,000)
*January 10, 2015*

**maths**

took me 40 http://www.jiskha.com/display.cgi?id=1420913304
*January 10, 2015*

**maths-6th grade**

sorry I took so long, had a grandson's hockey game in the middle of that.
*January 10, 2015*

**maths-6th grade**

t x 0 0 1 20 2 10 3 30 4 20 5 40 6 30 7 50 8 40 9 60 10 50 11 70 12 60 13 80 14 70 15 90 16 80 17 100 18 90 19 110 20 100 21 120 22 110 23 130 . . . 40 200 averages 5 meters/min
*January 10, 2015*

**maths algebra**

x/2 red x/d blue x - x/2 - x/d = x(1/2 - 1/d) yellow
*January 10, 2015*

**math**

-2 -2*-3 = 6 6*-3 = -18 -18*-3 = 54 54*-3 = -162 etc
*January 9, 2015*

**math**

oh 486 + 440
*January 9, 2015*

**math**

area of cube = 6*49 subtract pi (3.5^2) so cube area painted = 294 - pi(3.5)^2 side area of cylinder = 20 ( 7 pi) end areas = 2 pi(3.5^2) but delete one so total cylinder area =140 pi+pi(3.5^2) total = 294-pi(3.5)^2+140pi+pi(3.5)^2 = 294 + 140 pi = 294 + 20(22) = 294+440 = 734
*January 9, 2015*

**math**

a + 12 d = 159 a + 19 d = 264 --------------- 7 d = 105 d = 15 a = 159-12(15) = -21
*January 9, 2015*

**Math**

[5(x+1) +2(x-1)]/(x^2-1) = -6 5x+5 +2x-2 = -6x^2 + 6 6 x^2 + 7 x - 3 = 0 (2x+3)(3x-1) = 0 x = 1/3 or -3/2
*January 9, 2015*

**Math**

(3x+1)/[2(x+1)(x-1)]+2(x+1)/[2(x-3)(x-1)] [(3x+1)(x-3)+(x+1)^2 ]/[(x^2-1)(x-3)] [ 3x^2-8x-3 +x^2+2x+1 ]/[(x^2-1)(x-3)] [4x^2-6x-2]/[(x^2-1)(x-3)] 2[2x^2-3x-1] / [(x^2-1)(x-3)]
*January 9, 2015*

**math**

along diameter 28/4 + 1 = 8 around semicircle pi D/2 = 14 pi = 14(22/7) = 44 meters or 11 spaces none at ends, already there, so 11-1 = 10 total of 18
*January 9, 2015*

**History**

... and it was Turkey, Greece and Iran in the Middle East by the way. ... and what about Eastern Europe - Poland, Hungary, etc
*January 9, 2015*

**math**

p pencil p - 15 = rulers 3(p-15) = books total = p + p - 15 + 3 p - 45 = 5 p - 60
*January 9, 2015*

**math**

yes 12+3 = 15 :)
*January 9, 2015*

**U.S History**

Google history of US presidential cabinet
*January 9, 2015*

**Science - Please answer as soon as possible**

I would pick b.
*January 9, 2015*

**physics**

weight down = mass times centripetal A down mass cancels, does not matter g = v^2/R
*January 9, 2015*

**incomplete**

You need to know the magnitude of the pulling force. If mass and coef of friction are given and the velocity is constant then it is horizontal force = F cos 30 = m g (mu-sin 30) W = F cos 30 * 20*10^3 J
*January 9, 2015*

**LA - 1 question**

1.
*January 9, 2015*

**Geometry**

A is your statement of the problem B subtract two from both sides C multiply both sides by 6
*January 9, 2015*

**Social Studies help**

If you look at the products on that tree, it looks like we all use coal in one way or another :)
*January 9, 2015*

**Social Studies help**

http://www.coaleducation.org/lessons/twe/bytree.htm
*January 9, 2015*

**Math**

29500 + .041*128500
*January 9, 2015*

**Math**

Yes cos = 0 sin = 1
*January 9, 2015*

**physics**

882 *3.8/9.8
*January 9, 2015*

**Physics and Math**

ball rolls distance 1 + x loss of height = (1+x)sin 30 = .5(1+x) loss of potential energy = 1*9.8*.5(1+x) gain of potential energy = .5 k x^2 = .5 x^2 so 9.8(1+x) = x^2 x^2 - 9.8 x - 9.8 = 0 x = [ 9.8 +/-sqrt(96+39.2)]/2 x = (9.8+/-11.6)/2 x = 10.7
*January 8, 2015*

**Incomplete**

So what is the question ?
*January 8, 2015*

**MNHS_HELP**

I drew 6 8*8 5*5 3*3 2*2 two 1*1
*January 8, 2015*

**English**

I suppose you could say the social context was very lonely, just the nut case and the poor old man. In other words isolated.
*January 7, 2015*

**Physics**

m g sin theta 4 * 9.81 * (1/2) about 19.6 N
*January 7, 2015*

**Science**

Yes, in fact it was Thorium.
*January 7, 2015*

**Science**

it depends on what medium to what medium. Fastest in a vacuum
*January 7, 2015*

**Math**

yes, with some left over.
*January 7, 2015*

**math**

1260 miles (6 gallons/180 miles) = ?
*January 7, 2015*

**Math**

there are more 81 s than anything else
*January 7, 2015*

**Math**

I assume you mean: -x^2/4 + 9 x/5 + 2 = y complete the square first multiply by -4 x^2 - 36 x/5 - 8 = y x^2 - 36 x/5 = y+8 x^2 - 36 x/5 + (18/5)^2 = y + 8 + 12.96 (x-18/5)^2 = y + 20.96 so vertex at ( 3.6 , -20.96)
*January 7, 2015*

**adding and subtracting rational**

(11*8)/(15*8) + (1*15)/(8*15) = 88/120 + 15/120 = 103/120
*January 7, 2015*

**Physics**

infinitely fast, constant acceleration forever m a = m * 9.81 * sin 10.3 so a = g sin 10.3 = 9.81 sin 10.3 so v = (9.81 sin 10.3) t v is proportional to time, forever
*January 7, 2015*

**physics**

(T-30)(10 kg) (heat capacity of water) = 5000
*January 7, 2015*

**physics**

m v^2/r = m g so m cancels of course, has to be the same no matter how many in the car :) v= sqrt (r g)
*January 7, 2015*

**Physical Science HELP**

Zn + I2 ---> ZnI2 the end
*January 7, 2015*

**Math**

I assume x/(x^2-3x-4) - 4/(x+1) ????? x/[(x+1)(x-4)] - 4(x-4)/[(x+1)(x-4)] -3x+4 /[(x+1)(x-4)] blows up if x = -1 or x = 4
*January 7, 2015*

**algebra 2**

(x+4)(x-1) = 0 y = x^2 + 3 x - 4
*January 7, 2015*