Math question
ah d = 2 * r
Logarithms
b = a^(1/48) logb(b) = 1 = logb (a^(1/48)) = (1/48)logb(a) so logb(a) = 48 2 logb(a) = 96 so logb(a^2) = 96
physics 52
down slip problem: forces along slope pointed down slope: m g sin 10 - .1 m g cos 10 = m (v^2/r)cos 10 up slip problem, reverse direction of friction m g sin 10 +.1 m g cos 10 = m (v^2/r) cos 10 note m cancels everywhere
physics 70
m g down Tension of string toward center At top m g + T = m v^2/r T = m (v^2/r-9.81 T = .275(5.2^2/.85 -9.81) = 6.05 N At bottom T - m g = m v^2/r 22.5 = .275 (v^2/.85 + 9.81)
Physics (G and g)
Hey, look for answers already posted.
Physics (G and g)
Posted by Kathy on Sunday, April 21, 2013 at 6:37pm. Could anyone please help me with this problem? I would really appreciate it. The top of Mt. Everest is 8850 m above sea level. Assume that sea level is at the average Earth radius of 6.38×106 m. What is the magnitude o...
Physics (G and g)
I just did this for someone a few minutes ago.
Electric fields and Coulomb's law
E = k (e) /r^2 r^2 = k e/E r = sqrt ( k e/E )
Electric fields and Coulomb's law
dies off as k/r^2 three times as far is 9 times as weak 27.5/9
pre calc
Hey, Steve already answered that for you.
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