Saturday

November 28, 2015
Total # Posts: 785

**Thermodynamics of steam**

A boiler furnace releases 10000.000kJ of heat for each kg of fuel burned and produces dry saturated steam at 10000.000kPa from feed water at 190.000 degrees Celsius. How many kg of steam will be produced for each kg of fuel burned if the boiler had an efficiency of 69%. ANS = ...
*July 22, 2013*

**Physics**

When working with the properties of Saturated Steam. The pressure table supplied states: Pressure kPa = 1100 (P) Temp in Celsius = 184.09 (T) Specific Volume = Sat. Liquid = 1.1330 (Vf) Specific Volume = Sat.Vapor = 177.53 (Vg) Enthalpy = Saturated Liquid = 781.34 (Hf) ...
*July 21, 2013*

**Math (please help steve)**

Brilli the ant randomly placed a token into a square on a 2×100 chessboard according to a probability distribution P. The token is then moved uniformly at random to one of the horizontally, vertically, or diagonally adjacent squares. The probability that the token is in ...
*July 16, 2013*

**Math (please help steve)**

Brilli the ant is considering the complexities of a 5-dimensional universe. She wants to count the number of integer points that are distance n√ away from the origin. Let Tn be the set of ordered 5-tuples of integers (a1,a2,a3,a4,a5) such that a1^2+a2^2+a3^2+a4^2+a5^2=n....
*July 16, 2013*

**Math (help steve)**

Brilli the ant placed the numbers 1,2,…,n in order clockwise around a circle. She can create an infinite sequence A={aj}∞j=0 of integers by letting a0=k∈{1,2,…,n} and constructing ai+1 from ai by taking the integer that is ai positions clockwise in the ...
*July 16, 2013*

**Math (algebra)**

What are the last three digits of the largest perfect square that can be expressed as p^2+pq+q^2, where p and q are (positive) prime numbers?
*July 16, 2013*

**Math (algebra)**

Let x,y be complex numbers satisfying x+y=a xy=b, where a and b are positive integers from 1 to 100 inclusive. What is the sum of all possible distinct values of a such that x^3+y^3 is a positive prime number?
*July 16, 2013*

**Math (number theory)**

For how many positive integers N is ⌊N^2/5⌋(floor of N^2/5) a prime?
*July 16, 2013*

**Physics**

Telephoto lenses allow one to "zoom in" on distant objects, making them bigger. A particular telephoto lens consists of a combination of two thin lenses having focal lengths of f1=20 cm and f2=−8 cm, respectively. The lenses are separated by a distance of d=15 ...
*July 16, 2013*

**Physics Help**

1. The total enthalpy of 15.000kg of steam at 2250.000kPa is 34191.510kJ. Determine the dryness of the steam. ANS = % 2. Determine the quantity of heat required, to raise 11.100kg of water at 80.000 degrees Celsius, to saturated steam at 2250.000kPa and 71.400% dry. ANS = kJ ...
*July 14, 2013*

**Physics (Help)**

1. The total enthalpy of 15.000kg of steam at 2250.000kPa is 34191.510kJ. Determine the dryness of the steam. ANS = % 2. Determine the quantity of heat required, to raise 11.100kg of water at 80.000 degrees Celsius, to saturated steam at 2250.000kPa and 71.400% dry. ANS = kJ ...
*July 14, 2013*

**Thermodynamics **

Posted by Danny on Saturday, July 13, 2013 at 9:42am. 1. The total enthalpy of 15.000kg of steam at 2250.000kPa is 34191.510kJ. Determine the dryness of the steam. ANS = % 2. Determine the quantity of heat required, to raise 11.100kg of water at 80.000 degrees Celsius, to ...
*July 14, 2013*

**Thermodynamics**

1. The total enthalpy of 15.000kg of steam at 2250.000kPa is 34191.510kJ. Determine the dryness of the steam. ANS = % Not sure where to start. I need a little help please. I do have a chart with the properties of saturated steam. Thank you.
*July 13, 2013*

**Thermodynamics**

2. Determine the quantity of heat required, to raise 11.100kg of water at 80.000 degrees Celsius, to saturated steam at 2250.000kPa and 71.400% dry. ANS = kJ Not sure where to start. I need a little help please. I do have a chart with the properties of saturated steam. Thank ...
*July 13, 2013*

**Physics**

2. Determine the quantity of heat required, to raise 11.100kg of water at 80.000 degrees Celsius, to saturated steam at 2250.000kPa and 71.400% dry. ANS = kJ Not sure where to start. I need a little help please. I do have a chart with the properties of saturated steam. Thank ...
*July 13, 2013*

**Physics**

1. The total enthalpy of 15.000kg of steam at 2250.000kPa is 34191.510kJ. Determine the dryness of the steam. ANS = % Not sure where to start. I need a little help please. I do have a chart with the properties of saturated steam. Thank you.
*July 13, 2013*

**Thermodynamics**

1. The total enthalpy of 15.000kg of steam at 2250.000kPa is 34191.510kJ. Determine the dryness of the steam. ANS = % 2. Determine the quantity of heat required, to raise 11.100kg of water at 80.000 degrees Celsius, to saturated steam at 2250.000kPa and 71.400% dry. ANS = kJ ...
*July 13, 2013*

**Thermodynamics**

1. The total enthalpy of 15.000kg of steam at 2250.000kPa is 34191.510kJ. Determine the dryness of the steam. ANS = % 2. Determine the quantity of heat required, to raise 11.100kg of water at 80.000 degrees Celsius, to saturated steam at 2250.000kPa and 71.400% dry. ANS = kJ ...
*July 12, 2013*

**Physics(Thermodynamics)**

1. The total enthalpy of 15.000kg of steam at 2250.000kPa is 34191.510kJ. Determine the dryness of the steam. ANS = % 2. Determine the quantity of heat required, to raise 11.100kg of water at 80.000 degrees Celsius, to saturated steam at 2250.000kPa and 71.400% dry. ANS = kJ ...
*July 12, 2013*

**Thermodynamics **

1. The total enthalpy of 15.000kg of steam at 2250.000kPa is 34191.510kJ. Determine the dryness of the steam. ANS = % 2. Determine the quantity of heat required, to raise 11.100kg of water at 80.000 degrees Celsius, to saturated steam at 2250.000kPa and 71.400% dry. ANS = kJ ...
*July 11, 2013*

**Thermodynamics**

27.300kg of Copper at 35.000 degrees Celsius receives 460.000kJ of heat. Calculate the final temperature of the metal. ANS = degrees Celsius Copper specific heat = 0.39kJ/kg degrees Celsius. Q = mc (t2 - t1) Q = 460.000kJ m = 27.300kg c = 0.39kJ/kg t1 = 35 degrees Celsius t2...
*July 5, 2013*

**Thermodynamics**

Calculate the amount of expansion occurring when a steel rail 920.000 meters in length is heated from -10.000 to 410.000 degrees Celsius. ANS = m Steel = 12 * 10 ^-6 = 0.000012 Change in length = Original length * Coefficient of linear expansion * Temperature rise. = 920m * 0....
*July 4, 2013*

**Physics (Thermodynamics)**

27.300kg of Copper at 35.000 degrees Celsius receives 460.000kJ of heat. Calculate the final temperature of the metal. ANS = degrees Celsius Copper specific heat = 0.39kJ/kg degrees Celsius. Q = mc (t2 - t1) Q = 460.000kJ m = 27.300kg c = 0.39kJ/kg t1 = 35 degrees Celsius t2...
*July 4, 2013*

**Physics**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...
*July 3, 2013*

**Physics**

What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N Ultimate Strength = 630.000MPa...
*July 3, 2013*

**Physics**

Wouldn't you use Allowable Strength and not Ultimate Strength? Factor of Safety = Ultimate Strength/ Allowable Strength Allowable Strength = Ultimate Strength/ Factor of Safety Allowable Strength = Load/ Area= Load= Allowable Strength * Area= = Allowable Strength * (pi*d^2...
*July 3, 2013*

**Physics**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...
*July 3, 2013*

**Physics**

A steel bar has a rectangular cross section measuring 1.000cm by 2.900cm and is 8.700m in length. A load of 189000.00N causes the bar to extend 1.500mm. Calculate the stress and strain produced. ANS 1 = kPa (3 decimal places) ANS 2 = (6 decimal places) 1.000cm = 0.01m 2.900cm...
*July 3, 2013*

**Physics**

The Cross Sectional Area is 10cm^2. Does that mean that the bar would be square in shape? 10cm = 0.10m 10cm^2 = 0.10m * 0.10m * 0.10m * 0.10m = 10 * 10^-4 = 0.001
*July 3, 2013*

**Physics**

A uniform bar 1.000 meters in length and having a cross sectional area of 10.000cm^2 is subjected to a loading of 5750.000 Newtons. This load causes an extension to the bar length of 2.740mm. Calculate the stress and the strain produced. ANS 1 = kPa (Round to 3 decimal places...
*July 3, 2013*

**Physics**

1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN. ANS= MPa (Round to 3 decimal places) Diameter = 33.000mm = 0.033m 30.000kN = 30000N Area = pi*d^2/4 = 3.1416 * 0.033^2/ 4 = 3.1416 *0.001089/ 4 = 0.0034212024/ 4 = 8.553006*10^-4 = 0....
*July 3, 2013*

**Physics**

The ultimate strength of a steel rod is 600.000MPa. if the factor of safety 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 6.000cm? ANS = kN (Round to 3 decimal place) Ultimate strength = 600.000MPa = 600000000Pa = 600 * 10^6 Factor...
*July 3, 2013*

**Physics**

Sorry..ANS = 148440.600kN not kPa. Please Check. Thank you
*July 2, 2013*

**Physics**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...
*July 2, 2013*

**Physics**

A uniform bar 1.000 meters in length and having a cross sectional area of 10.000cm^2 is subjected to a loading of 5750.000 Newtons. This load causes an extension to the bar length of 2.740mm. Calculate the stress and the strain produced. ANS 1 = kPa (Round to 3 decimal places...
*July 2, 2013*

**Physics**

A steel bar has a rectangular cross section measuring 1.000cm by 2.900cm and is 8.700m in length. A load of 189000.00N causes the bar to extend 1.500mm. Calculate the stress and strain produced. ANS 1 = kPa (3 decimal places) ANS 2 = (6 decimal places) 1.000cm = 0.01m 2.900cm...
*July 2, 2013*

**Physics**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...
*July 2, 2013*

**Physics**

What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N ultimate strength = 630.000MPa...
*July 2, 2013*

**Physics**

What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N ultimate strength = 630.000MPa...
*July 1, 2013*

**Physics**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...
*July 1, 2013*

**Physics**

A steel bar has a rectangular cross section measuring 1.000cm by 2.900cm and is 8.700m in length. A load of 189000.00N causes the bar to extend 1.500mm. Calculate the stress and strain produced. ANS 1 = kPa (3 decimal places) ANS 2 = (6 decimal places) 1.000cm = 0.01m 2.900cm...
*July 1, 2013*

**Physics**

A uniform bar 1.000 meters in length and having a cross sectional area of 10.000cm^2 is subjected to a loading of 5750.000 Newtons. This load causes an extension to the bar length of 2.740mm. Calculate the stress and the strain produced. ANS 1 = kPa (Round to 3 decimal places...
*July 1, 2013*

**Physics**

The ultimate strength of a steel rod is 600.000MPa. if the factor of safety 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 6.000cm? ANS = kN (Round to 3 decimal place) Ultimate strength = 600.000MPa = 600000000Pa = 600 * 10^6 Factor...
*July 1, 2013*

**Physics**

1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN. ANS= MPa (Round to 3 decimal places) Diameter = 33.000mm = 0.033m 30.000kN = 30000N Area = pi*d^2/4 = 3.1416 * 0.033^2/ 4 = 3.1416 *0.001089/ 4 = 0.0034212024/ 4 = 8.553006*10^-4 = 0....
*July 1, 2013*

**Pyhsics(Stress&Strain)**

1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN. ANS= MPa (Round to 3 decimal places) Diameter = 33.000mm = 0.033m 30.000kN = 30000N Area = pi*d^2/4 = 3.1416 * 0.033^2/ 4 = 3.1416 *0.001089/ 4 = 0.0034212024/ 4 = 8.553006*10^-4 = 0....
*June 29, 2013*

**Physics(Sress&Strain)**

The ultimate strength of a steel rod is 600.000MPa. if the factor of safety 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 6.000cm? ANS = kN (Round to 3 decimal place) Ultimate strength = 600.000MPa = 600000000Pa = 600 * 10^6 Factor...
*June 29, 2013*

**Physics(Stress&Strain)**

A uniform bar 1.000 meters in length and having a cross sectional area of 10.000cm^2 is subjected to a loading of 5750.000 Newtons. This load causes an extension to the bar length of 2.740mm. Calculate the stress and the strain produced. ANS 1 = kPa (Round to 3 decimal places...
*June 29, 2013*

**Physics(Stress&Strain)**

A steel bar has a rectangular cross section measuring 1.000cm by 2.900cm and is 8.700m in length. A load of 189000.00N causes the bar to extend 1.500mm. Calculate the stress and strain produced. ANS 1 = kPa (3 decimal places) ANS 2 = (6 decimal places) 1.000cm = 0.01m 2.900cm...
*June 29, 2013*

**Physics(Stress&Strain)**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...
*June 29, 2013*

**Physics (Stress & Strain)**

What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N ultimate strength = 630.000MPa...
*June 29, 2013*

**Physics(Stress&Strain)**

What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N ultimate strength = 630.000MPa...
*June 28, 2013*

**Physics (Stress&Strain)**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...
*June 28, 2013*

**Physics (Stress & Strain)**

A steel bar has a rectangular cross section measuring 1.000cm by 2.900cm and is 8.700m in length. A load of 189000.00N causes the bar to extend 1.500mm. Calculate the stress and strain produced. ANS 1 = kPa (3 decimal places) ANS 2 = (6 decimal places) 1.000cm = 0.01m 2.900cm...
*June 28, 2013*

**Physics (Stress&Strain)**

A uniform bar 1.000 meters in length and having a cross sectional area of 10.000cm^2 is subjected to a loading of 5750.000 Newtons. This load causes an extension to the bar length of 2.740mm. Calculate the stress and the strain produced. ANS 1 = kPa (Round to 3 decimal places...
*June 28, 2013*

**Physics(Stress & Strain)**

1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN. ANS= MPa (Round to 3 decimal places) Diameter = 33.000mm = 0.033m 30.000kN = 30000N Area = pi*d^2/4 = 3.1416 * 0.033^2/ 4 = 3.1416 *0.001089/ 4 = 0.0034212024/ 4 = 8.553006*10^-4 = 0....
*June 28, 2013*

**Physics (Stress & Stain)**

Load = Allowable Strength * Area = Allowable Strength * (pi*d^2/4) =200*10^6*pi*.06^2/4 =200000000*3.1416*.0036/4 =2261952/4 =565488N =565.488kN Please check. Thank you.
*June 28, 2013*

**Physics (Stress & Stain)**

The ultimate strength of a steel rod is 600.000MPa. if the factor of safety 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 6.000cm? ANS = kN (Round to 3 decimal place) Ultimate strength = 600.000MPa = 600000000Pa = 600 * 10^6 Factor...
*June 28, 2013*

**Physics (Stress & Strain)**

The ultimate strength of a steel rod is 550.000MPa. If the factor of safety of 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 4.100cm? ANS = kN (Round to 3 decimal places) ultimate strength = 550.000MPa Factor of safety = 3.000 Rod ...
*June 28, 2013*

**Physics (Stress & Strain)**

What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 79000.000N. The steel hanger in question has a cross sectional area of 7.000cm^2. ANS = (Round to 3 decimal places) ultimate strength = 550.000MPa load = 79000....
*June 28, 2013*

**Physics (Stress & Strain)**

What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 79000.000N. The steel hanger in question has a cross sectional area of 7.000cm^2. ANS = (Round to 3 decimal places) ultimate strength = 550.000MPa load = 79000....
*June 27, 2013*

**Physics (Stress & Strain)**

The ultimate strength of a steel rod is 550.000MPa. If the factor of safety of 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 4.100cm? ANS = kN (Round to 3 decimal places) ultimate strength = 550.000MPa Factor of safety = 3.000 Rod ...
*June 27, 2013*

**Physics (Stress & Strain)**

A hole 3cm in diameter is to be punched out of a steel plate 8cm thick. The shear stress of the material is 670GPa. What load is required on the punch? 3cm = 0.03m 8cm = 0.08m Lateral surface area (As) = pi*D*h = 3.1416 * .03m * .08m = 3.1416 * .0024m = .007539m Force = Stress...
*June 26, 2013*

**Physics (Stress & Strain)**

A uniform bar 1.900 meters in length and having a cross sectional area of 11.000cm^2 is subject to a loading of 5450.000 Newtons. this load causes an extension to the bar length of 2.420mm. Calculate the stress and strain produced. 11cm = .11m 2.420mm = .02420m length = 1.9m ...
*June 26, 2013*

**Physics (Stress & Strain)**

A hole 3cm in diameter is to be punched out of a steel plate 8cm thick. The shear stress of the material is 670GPa. What load is required on the punch? 3cm = 0.03m 8cm = 0.08m Lateral surface area (As) = pi*D*h = 3.1416 * .03m * .08m = 3.1416 * .0024m = .007539m Force = Stress...
*June 26, 2013*

**Physics (Stress & Strain)**

A steel bar has a rectangular cross section measuring 1.000cm by 2.500cm and is 8.100m in length. A load of 150000.000N causes the bar to extend 2.000mm. Calculate the stress and strain. Area = l*w = 1.000cm*2.500cm = 2.500cm = 0.025m = 0.025m*8.100m = 0.2025m Stress = Load/ ...
*June 24, 2013*

**Physic (Stress & Strain)**

A uniform bar 1.900m in length and having a cross sectional area of 11.000cm^2 is subject to a loading of 5450.000N. this load causes an extension to the bar length of 2.420mm. Calculate the stress and the strain produced. Area = 11.000cm^2 = 11*10^-3m Load = 5450.000N Stress...
*June 24, 2013*

**Physics (Stress & Strain)**

Stress = force/ area = 87500N/ 5cm^2 = 17500 = 70000/ 17500 ANS = 4 Is that correct?
*June 24, 2013*

**Physics (Stress & Strain)**

What is the factor of safety for a steel hanger having an ultimate strength of 70000N per cm^2 and supporting a load of 87500N. The hanger has a cross sectional area of 5cm^2. Factor of safety = ultimate stress/ allowable stress = 70000/87500 = 0.8 Have I done this correctly?
*June 24, 2013*

**Physics (Stress & Strain)**

A hole 3cm in diameter is to be punched out of a steel plate 8cm thick. The shear stress of the material is 670GPa. What load is required on the punch? First find the area: A = pi*d^2/ 2 = 3.1416 * 3cm^2/ 2 = 3.1416 * 9/ 2 = 28.2744/ 2 = 7.0686cm Stress = 670GPa Second, covert...
*June 24, 2013*

**Math-algebra-Steve**

148
*June 24, 2013*

**Physics (Stress & Strain)**

1) Calculate the tension stress in a 21.00mm diameter rod subjected to a pull of 30.000kN. 21mm =0.021m 30.000kN = 30000N A = pi*d^2/4 = 3.1416 * (0.021)^2m^2/ 4 = 3.1416 * 0.000441/ 4 = 0.0013854456/ 4 = 0.0003463614 Stress = Load/ Area = 30000/ 0.0003463614 = 86614732.47N = ...
*June 23, 2013*

**Physics (Stress & Strain)**

What is the factory of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 61000.000N. The steel hanger in question has a cross sectional area of 6.500cm^2. ANS = (Round to 3 decimal places) 6.500cm = 0.065m Load = 61000.000N Ultimate ...
*June 23, 2013*

**Physic (Stress & Strain)**

1) Calculate the tension stress in a 21.00mm diameter rod subjected to a pull of 30.000kN. 21mm =0.021m 30.000kN = 30000N A = pi*d^2/4 = 3.1416 * (0.021)^2m^2/ 4 = 3.1416 * 0.000441/ 4 = 0.0013854456/ 4 = 0.0003463614 Stress = Load/ Area = 30000/ 0.0003463614 = 86614732.47N = ...
*June 23, 2013*

**Physics (Stress & Strain)**

A uniform bar 1.900m in length and having a cross sectional area of 10.500cm^2 is subject to a loading of 5550.000N. This load causes an extension of the bar length of 1.100mm. Calculate the stress and strain produced. Stress = Load/ Area Strain = Change in length/ length ...
*June 23, 2013*

**Physics**

What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 64000.000N. The steel hanger in question has a cross sectional area of 7.600cm^2 ANS= Round to 3 decimal places Safety factor = design load/ load = 550.000MPa = ...
*June 22, 2013*

**Physics**

What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 64000.000N. The steel hanger in question has a cross sectional area of 7.600cm^2 ANS= Round to 3 decimal places Safety factor = design load/ load = 550.000MPa = ...
*June 22, 2013*

**Physics**

A tie bar is made of a material having a tensile strength of 231MPa and has to carry a load of 225kN. What is the diameter of the bar if a factor of safety of 7 is applied? Where do I begin?
*June 22, 2013*

**Physics**

Safety factor = design load/ load = 550.000MPa = 550000000Pa = 550000000/ 64000 = 8593.75 tension design = 550MPa * 0.076M^2 = 18.000 Have I messed thing up?
*June 21, 2013*

**Physics**

Sorry i missed this part of the question: The steel hanger in question has a cross sectional area of 7.600cm^2
*June 21, 2013*

**Physics**

What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 64000.000N. ANS= Round to 3 decimal places Where do I begin?
*June 21, 2013*

**Physics**

A tie bar is made of a material having a tensile strength of 231MPa and has to carry a load of 225kN. What is the diameter of the bar if a factor of safety of 7 is applied? Where do I begin?
*June 21, 2013*

**math**

634
*June 21, 2013*

**Physics**

What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 64000.000N. The steel hanger in question has a cross sectional area of 7.600cm^2. Answer = (Round to 3 decimal places)
*June 8, 2013*

**Physics**

1. A train traveling at a speed of 110km/h decelerates for 20 seconds. During that time it travels 450 meters. A) What is the acceleration? = m/s^2 B) What is its speed after deceleration? = km/h Initial velocity (u) = 110km/h Time (t) = 20s Distance = 450m Using this formula ...
*June 7, 2013*

**Physics**

1. A train traveling at a speed of 110km/h decelerates for 20 seconds. During that time it travels 450 meters. A) What is the acceleration? = m/s^2 B) What is its speed after deceleration? = km/h I need help with which formula to use and how to use it to find the correct ...
*June 6, 2013*

**Physics**

1. A train traveling at a speed of 150km/h decelerates for 15 seconds. During that time it travels 400 meters. A) What is the acceleration? = m/s^2 B) What is its speed after deceleration? = km/h I need help with which formula to use and how to use it to find the correct ...
*June 6, 2013*

**Physics**

1. A train traveling at a speed of 110km/h decelerates for 20 seconds. During that time it travels 450 meters. A) What is the acceleration? = m/s^2 B) What is its speed after deceleration? = km/h I need help with which formula to use and how to use it to find the correct ...
*June 6, 2013*

**Physics**

1. A train traveling at a speed of 150km/h decelerates for 15 seconds. During that time it travels 400 meters. A) What is the acceleration? = m/s^2 B) What is its speed after deceleration? = km/h I need help with which formula to use and how to use it to find the correct ...
*June 6, 2013*

**Physics**

1. A train traveling at a speed of 150km/h decelerates for 15 seconds. During that time it travels 400 meters. A) What is the acceleration? = m/s^2 B) What is its speed after deceleration? = km/h I need help with which formula to use and how to use it to find the correct ...
*June 5, 2013*

**Physics**

1. A car is traveling at 85km/h, find the following: A) Its speed in m/s u = 85km/h = 85km/h * 1000m/km/ 60s/min * 60min/m/h = 85000/ 3600 = 23.61 ANS = 23.61m/s B) How many meters will it travel in 8 seconds = 23.61m/s * 8s ANS = 188.88m C) How long (in seconds) will it take ...
*June 5, 2013*

**Velocity**

An object is thrown directly downwards from a height of 60m with an initial velocity of 11m/s. What will be its velocity on impact? v^2 = U^2 + 2as a= 9.81m/s^2 u = 11m/s s = 60m v^2 = 11m/s + 2 * 9.81m/s^2 * 60 = 1188.2m^2/s^2 = square root of 1188.2m^2/s^2 = 34.47m/s Is this...
*June 3, 2013*

**Acceleration**

Which of the following statements about acceleration is true. Acceleration is: A) time/ velocity B) force/ time C) the rate of change of displacement D) time/ force E) the result of an unbalanced force exerted on a body. ANS = E Is this correct??
*June 3, 2013*

**Acceleration**

Which of the following statements about acceleration is true. Acceleration is: A) time/ velocity B) force/ time C) the rate of change of displacement D) time/ force E) the result of an unbalanced force exerted on a body. ANS = E Is this correct??
*June 3, 2013*

**Linear velocity/ acceleration**

A body moves 180 degrees from point A to point B in a semi circle. The diameter of the semi circle is 2m. Calculate the distance traveled between point A and point B. C = pi * d = 3.1416 * 2m = 6.283 = 6.283/ 2 = 3.141 ANS = 3.141 Is this done correctly??
*June 3, 2013*

**Physics**

Camera lenses are described in terms of their focal length. A 50.0 mm lens has a focal length of 50.0 mm (a) A camera with a 50 mm lens is focused on an object 4.0 m away. Locate the image. (b) A 980 mm lens is focused on an object 125 m away. Locate the image.
*May 21, 2013*

**Physics**

A wheel and axle arrangement has an axle with a diameter of 25cm. A rope is wrapped around the axle and is supporting a load of 2 tonnes. 1)If the mechanical advantage of the system is 30, determine the diameter of the wheel. ANSWER = m 2)Determine the effort required to ...
*May 20, 2013*

**Physics- Simple machines**

A wheel and axle arrangement has an axle with a diameter of 25cm. A rope is wrapped around the axle and is supporting a load of 2 tonnes. 1) If the mechanical advantage of the system is 30, determine the diameter of the wheel___________m. 2)Determine the effort required to ...
*May 12, 2013*

**Physics**

Simple Machines A simple wheel and axle has a wheel diameter of 2.3m and an axle diameter of 92mm. If an effort of 26N is required to raise a mass of 16 kg what is the efficiency of the machine? A- 2.46% B- 95.3% C- 24.1% D- 20.1% E- 65.5% I am having a problem determining ...
*May 11, 2013*

**MATH**

the area of a certain rectangle is 288yd squared. the perimeter is 68yd. if you double the length and width,what will be the area and perimeter of the new rectangle?
*May 9, 2013*

**Physics**

300N 200N ? |- 8m -|- 5m - |_____________________________________| R2 10M | 10m R1 A beam having a length of 20 metres is pivoted at its mid point. A 200 newton load is located at a point 5 metres from the right hand end of the beam. A 300 newton load is located at a point 8 ...
*May 4, 2013*