Saturday

February 28, 2015

February 28, 2015

Total # Posts: 731

**Help - physics**

A block of mass 0.74 kg is suspended by a string which is wrapped so that it is at a radius of 0.060 m from the center of a pulley. The moment of inertia of the pulley is 0.0061 kg·m2. There is friction as the pulley turns. The block starts from rest, and its speed ...
*February 12, 2014*

**Physics Help..**

The surface density of a thin rectangle varies as: σ(x,y)= 14.0 kg/m2 + 9.00 kg/m4(x2+y2) The rectangle has a length L = 0.500 m and a width W = 1.500 m. Calculate Iz, the moment of inertia about the z-axis.
*February 12, 2014*

**physics**

A block of mass 0.74 kg is suspended by a string which is wrapped so that it is at a radius of 0.060 m from the center of a pulley. The moment of inertia of the pulley is 0.0061 kg·m2. There is friction as the pulley turns. The block starts from rest, and its speed ...
*February 12, 2014*

**Algebra 1**

I think I figured out a few of them the fist is given second is distributive third is Commutative and I am not sure about the rest
*January 18, 2014*

**Algebra 1 **

Give the reason (property) for each step in the simplification. 8(a+b)-3a (8a+8b)-3a (8b+8a)-3a 8b+(8a-3a) 8b+5a
*January 18, 2014*

**Physics **

A train traveling at a speed of 110 km/h uniformly decelerates for 20 seconds. During that time it travels 450m. A) What is the acceleration? (m/s^2) B) What is its speed after deceleration? (km/h) A ANS = -.805m/s^2 B ANS = 52km s = 450m t = 20 seconds u = 110km/h*1000m/km /...
*January 11, 2014*

**Kensignton Park**

I have to find two numbers the quotient is between. 393
*January 8, 2014*

**Physics**

A train traveling at a speed of 110km/h uniformly decelerates for 20 seconds. During that time it travels 450m a) what is the acceleration m/s square? b) what is its speed after the deceleration? (km/h) Could really use some help. Thank you.
*January 1, 2014*

**Math**

100 cm = 1 meter Is 172.500 kN correct?
*December 26, 2013*

**Math**

The air pressure in a tire is 150.000 kPa. The internal surface area of the tire is 1150.000 cm^2. Determine the total force applied by the air to the tire. (Round to 3 decimal places) Answer = kN 150.000 kPa x 1000 = 150000 Nm 1150.000 cm / 100 cm = 11.5 m Force = Pressure x ...
*December 26, 2013*

**Math**

The air pressure in a tire is 800.000kPa.The internal surface area of the tire is 550.000cm^2. Determine the total force applied by the air to the tire. (Round to 3 decimal places). ANS = 44.000kN Force = Pressure x Area = 800.000kPa x 550.000 = 440000.000N = 440.000kN I keep ...
*December 26, 2013*

**Math**

Thank you very much.
*December 21, 2013*

**Math**

Where do you get the 1.18 from. Confused a little.
*December 21, 2013*

**Math**

A spring is 25 cm long when stretched. The spring was stretched by 18% of its original length. Determine the original length.
*December 21, 2013*

**calculus**

Imagine making a tent in the shape of a right prism whose cross-section is an equilateral triangle (the door is on one of the triangular ends). Assume we want the volume to be 2.2 m3, to sleep two or three people. The floor of the tent is cheaper material than the rest: assume...
*December 10, 2013*

**physics**

a uniform (in density and shape) stick is balanced by one end on the ground and the other tied to a massless horizontal rope attached to a wall as shown in the figure. The stick's mass is 10kg and its length is 5m. a. Calculate the tension on the rope b. Calculate the ...
*November 21, 2013*

**grammar**

Which part of speech is the capitalized words in this sentence? Four score and seven years ago our fathers brought forth on this continent, a NEW nation, conceived in Liberty, and DEDICATED to the proposition that all men are created equal. Now we are engaged in a great civil ...
*November 17, 2013*

**physics1111**

Rubbing your hands together warms them by converting work into thermal energy. If a woman rubs her hands back and forth for a total of 14 rubs a distance of 7.50 cm each and with a frictional force averaging 30.0 N, what is the temperature increase? The mass of tissue warmed ...
*November 12, 2013*

**Math**

If p^2-q^2=12, and p+q=4 What is the value of p?
*November 2, 2013*

**PHSYICS!**

I solved it and I'm pretty sure it comes around 5.7168.
*October 31, 2013*

**Confused**

Wait, does that mean f to the x power or f * x? An you know your supposed to find what F and G are, right?
*October 31, 2013*

**books Hamlet**

I need to identity three siutaions that Hamlet, Laertes and Fortinbras all share. I have one situation that they all share which is where all of their fathers are dead. I need two more, but I don't see any in the book. if anyone knows any helpful sites or two situations, ...
*October 30, 2013*

**Punctuation Sentence**

Thanks
*October 23, 2013*

**Punctuation Sentence**

Select the correct sentence. 1. Dr. Jones is an excellent surgeon but does not have a good bedside manner. 2. Dr. Jones is an excellent surgeon, but does not have a good bedside manner. 3. Dr. Jones, is an excellent surgeon, but does not have a good bedside manner. Is #2 ...
*October 23, 2013*

**Algebra1**

12"21
*October 3, 2013*

**Algebra1**

12"20
*October 3, 2013*

**Algebra1**

8:12
*October 3, 2013*

**Algebra1**

8/20
*October 3, 2013*

**spanish**

Nosotros siempre _____ la comida. A. comparten B. comparto C. compartimos D. comparte A?
*September 16, 2013*

**Spanish**

_____ las salchichas. Como salchichas todos los días. A. Me gusta mucho B. Me encantan C. No me gustan nada D. Me encanta B?
*September 16, 2013*

**Spanish**

Thank you. :)
*September 16, 2013*

**Spanish**

¿Con quién _____ tú el almuerzo? A. comparto B. compartes C. compartimos D. comparte B?
*September 16, 2013*

**4th grade math**

Thank you
*September 10, 2013*

**4th grade math**

I have to make a table or list to solve these problems. 1. Tina and Bruce are each rolling a 1 to 6 number cube. They are looking for different ways to roll two factors whose product is greater than 14. How many different ways will they find? 2. Trenton has 2 hats and 6 ...
*September 10, 2013*

**Spanish 1**

No Jake, it's C.
*September 10, 2013*

**Physical Science**

Radio waves and then also it could be infrared or microwave cause they are longer than any other type of waves. Radio is used in radio transmission - by taking large wavelengths and conducting them by using antennas to cover large distances. Microwaves are used in all wireless...
*September 5, 2013*

**Physical Science **

The Magnetic field lines of a bar magnet begin near the magnet's _____________. I believe this question is asking where the lines begin (ie leave) the bar magnet...which would be the north pole.
*September 4, 2013*

**Physical Science**

Yes, I found it. :) thanks.
*September 4, 2013*

**Physical Science**

It's A.
*September 4, 2013*

**Physical Science **

The primary colors of pigments A. are cyan, yellow, and magenta. B. are the same as the secondary colors of light. C. combine in equal amounts to produce black. D. all of the above I think it's D.
*September 4, 2013*

**Physical Science **

Energy from the sun reaches Earth mostly by A. conduction. B. convection. C. radiation. D. thermal expansion. I think it's A.
*September 3, 2013*

**Physical Science **

If no friction acts on a diver during a dive, then which of the following statements is true? A. The total mechanical energy of the system increases. B. Potential energy can be converted into kinetic energy but not vice versa. C. (KE+ PE)beginning = (KE + PE)end D. all of the ...
*September 3, 2013*

**Physical Science **

When opposite poles of two magnets are brought together, the poles A. attract each other. B. repel each other. C. cancel each other. D. cause a net force of zero. I think it's B.
*September 3, 2013*

**Physical Science**

Which of the following is a heterogeneous mixture? A. water in a swimming pool B. sugar water C. a jar of mixed nuts D. stainless steel I think it's B.
*August 27, 2013*

**Physics**

A tie bar is made of a material having a tensile strength of 231 MPa and has to carry a load of 255 kN. What is the diameter of the bar if a factor of safety of 7 is applied? ANS = 99.2 mm Cannot figure out how to get the answer. Need help please. Thank you
*August 17, 2013*

**Stress & Strain (Help Please)**

A tie bar is made of a material having a tensile strength of 231 MPa and has to carry a load of 255 kN. What id the diameter of the bar if a factor of safety of 7 is applied? ANS = 99.2 mm Cannot figure out how to get the answer. Need help please. Thank you
*August 10, 2013*

**Physics**

A boiler furnace releases 10000.000kJ of heat for each kg of fuel burned and produces dry saturated steam at 10000.000kPa from feed water at 190.000 degrees Celsius. How many kg of steam will be produced for each kg of fuel burned if the boiler had an efficiency of 69%? ANS = ...
*July 31, 2013*

**Thermodynamics of steam**

A boiler furnace releases 10000.000kJ of heat for each kg of fuel burned and produces dry saturated steam at 10000.000kPa from feed water at 190.000 degrees Celsius. How many kg of steam will be produced for each kg of fuel burned if the boiler had an efficiency of 69%. ANS = ...
*July 22, 2013*

**Physics**

When working with the properties of Saturated Steam. The pressure table supplied states: Pressure kPa = 1100 (P) Temp in Celsius = 184.09 (T) Specific Volume = Sat. Liquid = 1.1330 (Vf) Specific Volume = Sat.Vapor = 177.53 (Vg) Enthalpy = Saturated Liquid = 781.34 (Hf) ...
*July 21, 2013*

**Math (please help steve)**

Brilli the ant randomly placed a token into a square on a 2×100 chessboard according to a probability distribution P. The token is then moved uniformly at random to one of the horizontally, vertically, or diagonally adjacent squares. The probability that the token is in ...
*July 16, 2013*

**Math (please help steve)**

Brilli the ant is considering the complexities of a 5-dimensional universe. She wants to count the number of integer points that are distance n√ away from the origin. Let Tn be the set of ordered 5-tuples of integers (a1,a2,a3,a4,a5) such that a1^2+a2^2+a3^2+a4^2+a5^2=n....
*July 16, 2013*

**Math (help steve)**

Brilli the ant placed the numbers 1,2,…,n in order clockwise around a circle. She can create an infinite sequence A={aj}∞j=0 of integers by letting a0=k∈{1,2,…,n} and constructing ai+1 from ai by taking the integer that is ai positions clockwise in the ...
*July 16, 2013*

**Math (algebra)**

What are the last three digits of the largest perfect square that can be expressed as p^2+pq+q^2, where p and q are (positive) prime numbers?
*July 16, 2013*

**Math (algebra)**

Let x,y be complex numbers satisfying x+y=a xy=b, where a and b are positive integers from 1 to 100 inclusive. What is the sum of all possible distinct values of a such that x^3+y^3 is a positive prime number?
*July 16, 2013*

**Math (number theory)**

For how many positive integers N is ⌊N^2/5⌋(floor of N^2/5) a prime?
*July 16, 2013*

**Physics**

Telephoto lenses allow one to "zoom in" on distant objects, making them bigger. A particular telephoto lens consists of a combination of two thin lenses having focal lengths of f1=20 cm and f2=−8 cm, respectively. The lenses are separated by a distance of d=15 ...
*July 16, 2013*

**Physics Help**

1. The total enthalpy of 15.000kg of steam at 2250.000kPa is 34191.510kJ. Determine the dryness of the steam. ANS = % 2. Determine the quantity of heat required, to raise 11.100kg of water at 80.000 degrees Celsius, to saturated steam at 2250.000kPa and 71.400% dry. ANS = kJ ...
*July 14, 2013*

**Physics (Help)**

1. The total enthalpy of 15.000kg of steam at 2250.000kPa is 34191.510kJ. Determine the dryness of the steam. ANS = % 2. Determine the quantity of heat required, to raise 11.100kg of water at 80.000 degrees Celsius, to saturated steam at 2250.000kPa and 71.400% dry. ANS = kJ ...
*July 14, 2013*

**Thermodynamics **

Posted by Danny on Saturday, July 13, 2013 at 9:42am. 1. The total enthalpy of 15.000kg of steam at 2250.000kPa is 34191.510kJ. Determine the dryness of the steam. ANS = % 2. Determine the quantity of heat required, to raise 11.100kg of water at 80.000 degrees Celsius, to ...
*July 14, 2013*

**Thermodynamics**

1. The total enthalpy of 15.000kg of steam at 2250.000kPa is 34191.510kJ. Determine the dryness of the steam. ANS = % Not sure where to start. I need a little help please. I do have a chart with the properties of saturated steam. Thank you.
*July 13, 2013*

**Thermodynamics**

2. Determine the quantity of heat required, to raise 11.100kg of water at 80.000 degrees Celsius, to saturated steam at 2250.000kPa and 71.400% dry. ANS = kJ Not sure where to start. I need a little help please. I do have a chart with the properties of saturated steam. Thank ...
*July 13, 2013*

**Physics**

2. Determine the quantity of heat required, to raise 11.100kg of water at 80.000 degrees Celsius, to saturated steam at 2250.000kPa and 71.400% dry. ANS = kJ Not sure where to start. I need a little help please. I do have a chart with the properties of saturated steam. Thank ...
*July 13, 2013*

**Physics**

1. The total enthalpy of 15.000kg of steam at 2250.000kPa is 34191.510kJ. Determine the dryness of the steam. ANS = % Not sure where to start. I need a little help please. I do have a chart with the properties of saturated steam. Thank you.
*July 13, 2013*

**Thermodynamics**

1. The total enthalpy of 15.000kg of steam at 2250.000kPa is 34191.510kJ. Determine the dryness of the steam. ANS = % 2. Determine the quantity of heat required, to raise 11.100kg of water at 80.000 degrees Celsius, to saturated steam at 2250.000kPa and 71.400% dry. ANS = kJ ...
*July 13, 2013*

**Thermodynamics**

1. The total enthalpy of 15.000kg of steam at 2250.000kPa is 34191.510kJ. Determine the dryness of the steam. ANS = % 2. Determine the quantity of heat required, to raise 11.100kg of water at 80.000 degrees Celsius, to saturated steam at 2250.000kPa and 71.400% dry. ANS = kJ ...
*July 12, 2013*

**Physics(Thermodynamics)**

1. The total enthalpy of 15.000kg of steam at 2250.000kPa is 34191.510kJ. Determine the dryness of the steam. ANS = % 2. Determine the quantity of heat required, to raise 11.100kg of water at 80.000 degrees Celsius, to saturated steam at 2250.000kPa and 71.400% dry. ANS = kJ ...
*July 12, 2013*

**Thermodynamics **

1. The total enthalpy of 15.000kg of steam at 2250.000kPa is 34191.510kJ. Determine the dryness of the steam. ANS = % 2. Determine the quantity of heat required, to raise 11.100kg of water at 80.000 degrees Celsius, to saturated steam at 2250.000kPa and 71.400% dry. ANS = kJ ...
*July 11, 2013*

**Thermodynamics**

27.300kg of Copper at 35.000 degrees Celsius receives 460.000kJ of heat. Calculate the final temperature of the metal. ANS = degrees Celsius Copper specific heat = 0.39kJ/kg degrees Celsius. Q = mc (t2 - t1) Q = 460.000kJ m = 27.300kg c = 0.39kJ/kg t1 = 35 degrees Celsius t2...
*July 5, 2013*

**Thermodynamics**

Calculate the amount of expansion occurring when a steel rail 920.000 meters in length is heated from -10.000 to 410.000 degrees Celsius. ANS = m Steel = 12 * 10 ^-6 = 0.000012 Change in length = Original length * Coefficient of linear expansion * Temperature rise. = 920m * 0....
*July 4, 2013*

**Physics (Thermodynamics)**

27.300kg of Copper at 35.000 degrees Celsius receives 460.000kJ of heat. Calculate the final temperature of the metal. ANS = degrees Celsius Copper specific heat = 0.39kJ/kg degrees Celsius. Q = mc (t2 - t1) Q = 460.000kJ m = 27.300kg c = 0.39kJ/kg t1 = 35 degrees Celsius t2...
*July 4, 2013*

**Physics**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...
*July 3, 2013*

**Physics**

What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N Ultimate Strength = 630.000MPa...
*July 3, 2013*

**Physics**

Wouldn't you use Allowable Strength and not Ultimate Strength? Factor of Safety = Ultimate Strength/ Allowable Strength Allowable Strength = Ultimate Strength/ Factor of Safety Allowable Strength = Load/ Area= Load= Allowable Strength * Area= = Allowable Strength * (pi*d^2...
*July 3, 2013*

**Physics**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...
*July 3, 2013*

**Physics**

A steel bar has a rectangular cross section measuring 1.000cm by 2.900cm and is 8.700m in length. A load of 189000.00N causes the bar to extend 1.500mm. Calculate the stress and strain produced. ANS 1 = kPa (3 decimal places) ANS 2 = (6 decimal places) 1.000cm = 0.01m 2.900cm...
*July 3, 2013*

**Physics**

The Cross Sectional Area is 10cm^2. Does that mean that the bar would be square in shape? 10cm = 0.10m 10cm^2 = 0.10m * 0.10m * 0.10m * 0.10m = 10 * 10^-4 = 0.001
*July 3, 2013*

**Physics**

A uniform bar 1.000 meters in length and having a cross sectional area of 10.000cm^2 is subjected to a loading of 5750.000 Newtons. This load causes an extension to the bar length of 2.740mm. Calculate the stress and the strain produced. ANS 1 = kPa (Round to 3 decimal places...
*July 3, 2013*

**Physics**

1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN. ANS= MPa (Round to 3 decimal places) Diameter = 33.000mm = 0.033m 30.000kN = 30000N Area = pi*d^2/4 = 3.1416 * 0.033^2/ 4 = 3.1416 *0.001089/ 4 = 0.0034212024/ 4 = 8.553006*10^-4 = 0....
*July 3, 2013*

**Physics**

The ultimate strength of a steel rod is 600.000MPa. if the factor of safety 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 6.000cm? ANS = kN (Round to 3 decimal place) Ultimate strength = 600.000MPa = 600000000Pa = 600 * 10^6 Factor...
*July 3, 2013*

**Physics**

Sorry..ANS = 148440.600kN not kPa. Please Check. Thank you
*July 2, 2013*

**Physics**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...
*July 2, 2013*

**Physics**

A uniform bar 1.000 meters in length and having a cross sectional area of 10.000cm^2 is subjected to a loading of 5750.000 Newtons. This load causes an extension to the bar length of 2.740mm. Calculate the stress and the strain produced. ANS 1 = kPa (Round to 3 decimal places...
*July 2, 2013*

**Physics**

A steel bar has a rectangular cross section measuring 1.000cm by 2.900cm and is 8.700m in length. A load of 189000.00N causes the bar to extend 1.500mm. Calculate the stress and strain produced. ANS 1 = kPa (3 decimal places) ANS 2 = (6 decimal places) 1.000cm = 0.01m 2.900cm...
*July 2, 2013*

**Physics**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...
*July 2, 2013*

**Physics**

What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N ultimate strength = 630.000MPa...
*July 2, 2013*

**Physics**

What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N ultimate strength = 630.000MPa...
*July 1, 2013*

**Physics**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...
*July 1, 2013*

**Physics**

A steel bar has a rectangular cross section measuring 1.000cm by 2.900cm and is 8.700m in length. A load of 189000.00N causes the bar to extend 1.500mm. Calculate the stress and strain produced. ANS 1 = kPa (3 decimal places) ANS 2 = (6 decimal places) 1.000cm = 0.01m 2.900cm...
*July 1, 2013*

**Physics**

A uniform bar 1.000 meters in length and having a cross sectional area of 10.000cm^2 is subjected to a loading of 5750.000 Newtons. This load causes an extension to the bar length of 2.740mm. Calculate the stress and the strain produced. ANS 1 = kPa (Round to 3 decimal places...
*July 1, 2013*

**Physics**

The ultimate strength of a steel rod is 600.000MPa. if the factor of safety 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 6.000cm? ANS = kN (Round to 3 decimal place) Ultimate strength = 600.000MPa = 600000000Pa = 600 * 10^6 Factor...
*July 1, 2013*

**Physics**

1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN. ANS= MPa (Round to 3 decimal places) Diameter = 33.000mm = 0.033m 30.000kN = 30000N Area = pi*d^2/4 = 3.1416 * 0.033^2/ 4 = 3.1416 *0.001089/ 4 = 0.0034212024/ 4 = 8.553006*10^-4 = 0....
*July 1, 2013*

**Pyhsics(Stress&Strain)**

1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN. ANS= MPa (Round to 3 decimal places) Diameter = 33.000mm = 0.033m 30.000kN = 30000N Area = pi*d^2/4 = 3.1416 * 0.033^2/ 4 = 3.1416 *0.001089/ 4 = 0.0034212024/ 4 = 8.553006*10^-4 = 0....
*June 29, 2013*

**Physics(Sress&Strain)**

The ultimate strength of a steel rod is 600.000MPa. if the factor of safety 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 6.000cm? ANS = kN (Round to 3 decimal place) Ultimate strength = 600.000MPa = 600000000Pa = 600 * 10^6 Factor...
*June 29, 2013*

**Physics(Stress&Strain)**

A uniform bar 1.000 meters in length and having a cross sectional area of 10.000cm^2 is subjected to a loading of 5750.000 Newtons. This load causes an extension to the bar length of 2.740mm. Calculate the stress and the strain produced. ANS 1 = kPa (Round to 3 decimal places...
*June 29, 2013*

**Physics(Stress&Strain)**

A steel bar has a rectangular cross section measuring 1.000cm by 2.900cm and is 8.700m in length. A load of 189000.00N causes the bar to extend 1.500mm. Calculate the stress and strain produced. ANS 1 = kPa (3 decimal places) ANS 2 = (6 decimal places) 1.000cm = 0.01m 2.900cm...
*June 29, 2013*

**Physics(Stress&Strain)**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...
*June 29, 2013*

**Physics (Stress & Strain)**

What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N ultimate strength = 630.000MPa...
*June 29, 2013*

**Physics(Stress&Strain)**

What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N ultimate strength = 630.000MPa...
*June 28, 2013*

**Physics (Stress&Strain)**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...
*June 28, 2013*

**Physics (Stress & Strain)**

A steel bar has a rectangular cross section measuring 1.000cm by 2.900cm and is 8.700m in length. A load of 189000.00N causes the bar to extend 1.500mm. Calculate the stress and strain produced. ANS 1 = kPa (3 decimal places) ANS 2 = (6 decimal places) 1.000cm = 0.01m 2.900cm...
*June 28, 2013*

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