Thursday

October 23, 2014

October 23, 2014

Total # Posts: 649

**Physics**

A uniform bar 1.000 meters in length and having a cross sectional area of 10.000cm^2 is subjected to a loading of 5750.000 Newtons. This load causes an extension to the bar length of 2.740mm. Calculate the stress and the strain produced. ANS 1 = kPa (Round to 3 decimal places...
*July 2, 2013*

**Physics**

A steel bar has a rectangular cross section measuring 1.000cm by 2.900cm and is 8.700m in length. A load of 189000.00N causes the bar to extend 1.500mm. Calculate the stress and strain produced. ANS 1 = kPa (3 decimal places) ANS 2 = (6 decimal places) 1.000cm = 0.01m 2.900cm...
*July 2, 2013*

**Physics**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...
*July 2, 2013*

**Physics**

What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N ultimate strength = 630.000MPa...
*July 2, 2013*

**Physics**

What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N ultimate strength = 630.000MPa...
*July 1, 2013*

**Physics**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...
*July 1, 2013*

**Physics**

A steel bar has a rectangular cross section measuring 1.000cm by 2.900cm and is 8.700m in length. A load of 189000.00N causes the bar to extend 1.500mm. Calculate the stress and strain produced. ANS 1 = kPa (3 decimal places) ANS 2 = (6 decimal places) 1.000cm = 0.01m 2.900cm...
*July 1, 2013*

**Physics**

A uniform bar 1.000 meters in length and having a cross sectional area of 10.000cm^2 is subjected to a loading of 5750.000 Newtons. This load causes an extension to the bar length of 2.740mm. Calculate the stress and the strain produced. ANS 1 = kPa (Round to 3 decimal places...
*July 1, 2013*

**Physics**

The ultimate strength of a steel rod is 600.000MPa. if the factor of safety 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 6.000cm? ANS = kN (Round to 3 decimal place) Ultimate strength = 600.000MPa = 600000000Pa = 600 * 10^6 Factor...
*July 1, 2013*

**Physics**

1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN. ANS= MPa (Round to 3 decimal places) Diameter = 33.000mm = 0.033m 30.000kN = 30000N Area = pi*d^2/4 = 3.1416 * 0.033^2/ 4 = 3.1416 *0.001089/ 4 = 0.0034212024/ 4 = 8.553006*10^-4 = 0....
*July 1, 2013*

**Pyhsics(Stress&Strain)**

1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN. ANS= MPa (Round to 3 decimal places) Diameter = 33.000mm = 0.033m 30.000kN = 30000N Area = pi*d^2/4 = 3.1416 * 0.033^2/ 4 = 3.1416 *0.001089/ 4 = 0.0034212024/ 4 = 8.553006*10^-4 = 0....
*June 29, 2013*

**Physics(Sress&Strain)**

The ultimate strength of a steel rod is 600.000MPa. if the factor of safety 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 6.000cm? ANS = kN (Round to 3 decimal place) Ultimate strength = 600.000MPa = 600000000Pa = 600 * 10^6 Factor...
*June 29, 2013*

**Physics(Stress&Strain)**

A uniform bar 1.000 meters in length and having a cross sectional area of 10.000cm^2 is subjected to a loading of 5750.000 Newtons. This load causes an extension to the bar length of 2.740mm. Calculate the stress and the strain produced. ANS 1 = kPa (Round to 3 decimal places...
*June 29, 2013*

**Physics(Stress&Strain)**

A steel bar has a rectangular cross section measuring 1.000cm by 2.900cm and is 8.700m in length. A load of 189000.00N causes the bar to extend 1.500mm. Calculate the stress and strain produced. ANS 1 = kPa (3 decimal places) ANS 2 = (6 decimal places) 1.000cm = 0.01m 2.900cm...
*June 29, 2013*

**Physics(Stress&Strain)**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...
*June 29, 2013*

**Physics (Stress & Strain)**

What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N ultimate strength = 630.000MPa...
*June 29, 2013*

**Physics(Stress&Strain)**

What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N ultimate strength = 630.000MPa...
*June 28, 2013*

**Physics (Stress&Strain)**

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter = 3.000cm = 0.03m Ultimate ...
*June 28, 2013*

**Physics (Stress & Strain)**

A steel bar has a rectangular cross section measuring 1.000cm by 2.900cm and is 8.700m in length. A load of 189000.00N causes the bar to extend 1.500mm. Calculate the stress and strain produced. ANS 1 = kPa (3 decimal places) ANS 2 = (6 decimal places) 1.000cm = 0.01m 2.900cm...
*June 28, 2013*

**Physics (Stress&Strain)**

A uniform bar 1.000 meters in length and having a cross sectional area of 10.000cm^2 is subjected to a loading of 5750.000 Newtons. This load causes an extension to the bar length of 2.740mm. Calculate the stress and the strain produced. ANS 1 = kPa (Round to 3 decimal places...
*June 28, 2013*

**Physics(Stress & Strain)**

1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN. ANS= MPa (Round to 3 decimal places) Diameter = 33.000mm = 0.033m 30.000kN = 30000N Area = pi*d^2/4 = 3.1416 * 0.033^2/ 4 = 3.1416 *0.001089/ 4 = 0.0034212024/ 4 = 8.553006*10^-4 = 0....
*June 28, 2013*

**Physics (Stress & Stain)**

Load = Allowable Strength * Area = Allowable Strength * (pi*d^2/4) =200*10^6*pi*.06^2/4 =200000000*3.1416*.0036/4 =2261952/4 =565488N =565.488kN Please check. Thank you.
*June 28, 2013*

**Physics (Stress & Stain)**

The ultimate strength of a steel rod is 600.000MPa. if the factor of safety 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 6.000cm? ANS = kN (Round to 3 decimal place) Ultimate strength = 600.000MPa = 600000000Pa = 600 * 10^6 Factor...
*June 28, 2013*

**Physics (Stress & Strain)**

The ultimate strength of a steel rod is 550.000MPa. If the factor of safety of 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 4.100cm? ANS = kN (Round to 3 decimal places) ultimate strength = 550.000MPa Factor of safety = 3.000 Rod ...
*June 28, 2013*

**Physics (Stress & Strain)**

What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 79000.000N. The steel hanger in question has a cross sectional area of 7.000cm^2. ANS = (Round to 3 decimal places) ultimate strength = 550.000MPa load = 79000....
*June 28, 2013*

**Physics (Stress & Strain)**

What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 79000.000N. The steel hanger in question has a cross sectional area of 7.000cm^2. ANS = (Round to 3 decimal places) ultimate strength = 550.000MPa load = 79000....
*June 27, 2013*

**Physics (Stress & Strain)**

The ultimate strength of a steel rod is 550.000MPa. If the factor of safety of 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 4.100cm? ANS = kN (Round to 3 decimal places) ultimate strength = 550.000MPa Factor of safety = 3.000 Rod ...
*June 27, 2013*

**Physics (Stress & Strain)**

A hole 3cm in diameter is to be punched out of a steel plate 8cm thick. The shear stress of the material is 670GPa. What load is required on the punch? 3cm = 0.03m 8cm = 0.08m Lateral surface area (As) = pi*D*h = 3.1416 * .03m * .08m = 3.1416 * .0024m = .007539m Force = Stress...
*June 26, 2013*

**Physics (Stress & Strain)**

A uniform bar 1.900 meters in length and having a cross sectional area of 11.000cm^2 is subject to a loading of 5450.000 Newtons. this load causes an extension to the bar length of 2.420mm. Calculate the stress and strain produced. 11cm = .11m 2.420mm = .02420m length = 1.9m ...
*June 26, 2013*

**Physics (Stress & Strain)**

A hole 3cm in diameter is to be punched out of a steel plate 8cm thick. The shear stress of the material is 670GPa. What load is required on the punch? 3cm = 0.03m 8cm = 0.08m Lateral surface area (As) = pi*D*h = 3.1416 * .03m * .08m = 3.1416 * .0024m = .007539m Force = Stress...
*June 26, 2013*

**Physics (Stress & Strain)**

A steel bar has a rectangular cross section measuring 1.000cm by 2.500cm and is 8.100m in length. A load of 150000.000N causes the bar to extend 2.000mm. Calculate the stress and strain. Area = l*w = 1.000cm*2.500cm = 2.500cm = 0.025m = 0.025m*8.100m = 0.2025m Stress = Load/ ...
*June 24, 2013*

**Physic (Stress & Strain)**

A uniform bar 1.900m in length and having a cross sectional area of 11.000cm^2 is subject to a loading of 5450.000N. this load causes an extension to the bar length of 2.420mm. Calculate the stress and the strain produced. Area = 11.000cm^2 = 11*10^-3m Load = 5450.000N Stress...
*June 24, 2013*

**Physics (Stress & Strain)**

Stress = force/ area = 87500N/ 5cm^2 = 17500 = 70000/ 17500 ANS = 4 Is that correct?
*June 24, 2013*

**Physics (Stress & Strain)**

What is the factor of safety for a steel hanger having an ultimate strength of 70000N per cm^2 and supporting a load of 87500N. The hanger has a cross sectional area of 5cm^2. Factor of safety = ultimate stress/ allowable stress = 70000/87500 = 0.8 Have I done this correctly?
*June 24, 2013*

**Physics (Stress & Strain)**

A hole 3cm in diameter is to be punched out of a steel plate 8cm thick. The shear stress of the material is 670GPa. What load is required on the punch? First find the area: A = pi*d^2/ 2 = 3.1416 * 3cm^2/ 2 = 3.1416 * 9/ 2 = 28.2744/ 2 = 7.0686cm Stress = 670GPa Second, covert...
*June 24, 2013*

**Math-algebra-Steve**

148
*June 24, 2013*

**Physics (Stress & Strain)**

1) Calculate the tension stress in a 21.00mm diameter rod subjected to a pull of 30.000kN. 21mm =0.021m 30.000kN = 30000N A = pi*d^2/4 = 3.1416 * (0.021)^2m^2/ 4 = 3.1416 * 0.000441/ 4 = 0.0013854456/ 4 = 0.0003463614 Stress = Load/ Area = 30000/ 0.0003463614 = 86614732.47N = ...
*June 23, 2013*

**Physics (Stress & Strain)**

What is the factory of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 61000.000N. The steel hanger in question has a cross sectional area of 6.500cm^2. ANS = (Round to 3 decimal places) 6.500cm = 0.065m Load = 61000.000N Ultimate ...
*June 23, 2013*

**Physic (Stress & Strain)**

1) Calculate the tension stress in a 21.00mm diameter rod subjected to a pull of 30.000kN. 21mm =0.021m 30.000kN = 30000N A = pi*d^2/4 = 3.1416 * (0.021)^2m^2/ 4 = 3.1416 * 0.000441/ 4 = 0.0013854456/ 4 = 0.0003463614 Stress = Load/ Area = 30000/ 0.0003463614 = 86614732.47N = ...
*June 23, 2013*

**Physics (Stress & Strain)**

A uniform bar 1.900m in length and having a cross sectional area of 10.500cm^2 is subject to a loading of 5550.000N. This load causes an extension of the bar length of 1.100mm. Calculate the stress and strain produced. Stress = Load/ Area Strain = Change in length/ length ...
*June 23, 2013*

**Physics**

What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 64000.000N. The steel hanger in question has a cross sectional area of 7.600cm^2 ANS= Round to 3 decimal places Safety factor = design load/ load = 550.000MPa = ...
*June 22, 2013*

**Physics**

What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 64000.000N. The steel hanger in question has a cross sectional area of 7.600cm^2 ANS= Round to 3 decimal places Safety factor = design load/ load = 550.000MPa = ...
*June 22, 2013*

**Physics**

A tie bar is made of a material having a tensile strength of 231MPa and has to carry a load of 225kN. What is the diameter of the bar if a factor of safety of 7 is applied? Where do I begin?
*June 22, 2013*

**Physics**

Safety factor = design load/ load = 550.000MPa = 550000000Pa = 550000000/ 64000 = 8593.75 tension design = 550MPa * 0.076M^2 = 18.000 Have I messed thing up?
*June 21, 2013*

**Physics**

Sorry i missed this part of the question: The steel hanger in question has a cross sectional area of 7.600cm^2
*June 21, 2013*

**Physics**

What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 64000.000N. ANS= Round to 3 decimal places Where do I begin?
*June 21, 2013*

**Physics**

A tie bar is made of a material having a tensile strength of 231MPa and has to carry a load of 225kN. What is the diameter of the bar if a factor of safety of 7 is applied? Where do I begin?
*June 21, 2013*

**math**

634
*June 21, 2013*

**Physics**

What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 64000.000N. The steel hanger in question has a cross sectional area of 7.600cm^2. Answer = (Round to 3 decimal places)
*June 8, 2013*

**Physics**

1. A train traveling at a speed of 110km/h decelerates for 20 seconds. During that time it travels 450 meters. A) What is the acceleration? = m/s^2 B) What is its speed after deceleration? = km/h Initial velocity (u) = 110km/h Time (t) = 20s Distance = 450m Using this formula ...
*June 7, 2013*

**Physics**

1. A train traveling at a speed of 110km/h decelerates for 20 seconds. During that time it travels 450 meters. A) What is the acceleration? = m/s^2 B) What is its speed after deceleration? = km/h I need help with which formula to use and how to use it to find the correct ...
*June 6, 2013*

**Physics**

1. A train traveling at a speed of 150km/h decelerates for 15 seconds. During that time it travels 400 meters. A) What is the acceleration? = m/s^2 B) What is its speed after deceleration? = km/h I need help with which formula to use and how to use it to find the correct ...
*June 6, 2013*

**Physics**

1. A train traveling at a speed of 110km/h decelerates for 20 seconds. During that time it travels 450 meters. A) What is the acceleration? = m/s^2 B) What is its speed after deceleration? = km/h I need help with which formula to use and how to use it to find the correct ...
*June 6, 2013*

**Physics**

1. A train traveling at a speed of 150km/h decelerates for 15 seconds. During that time it travels 400 meters. A) What is the acceleration? = m/s^2 B) What is its speed after deceleration? = km/h I need help with which formula to use and how to use it to find the correct ...
*June 6, 2013*

**Physics**

1. A train traveling at a speed of 150km/h decelerates for 15 seconds. During that time it travels 400 meters. A) What is the acceleration? = m/s^2 B) What is its speed after deceleration? = km/h I need help with which formula to use and how to use it to find the correct ...
*June 5, 2013*

**Physics**

1. A car is traveling at 85km/h, find the following: A) Its speed in m/s u = 85km/h = 85km/h * 1000m/km/ 60s/min * 60min/m/h = 85000/ 3600 = 23.61 ANS = 23.61m/s B) How many meters will it travel in 8 seconds = 23.61m/s * 8s ANS = 188.88m C) How long (in seconds) will it take ...
*June 5, 2013*

**Velocity**

An object is thrown directly downwards from a height of 60m with an initial velocity of 11m/s. What will be its velocity on impact? v^2 = U^2 + 2as a= 9.81m/s^2 u = 11m/s s = 60m v^2 = 11m/s + 2 * 9.81m/s^2 * 60 = 1188.2m^2/s^2 = square root of 1188.2m^2/s^2 = 34.47m/s Is this...
*June 3, 2013*

**Acceleration**

Which of the following statements about acceleration is true. Acceleration is: A) time/ velocity B) force/ time C) the rate of change of displacement D) time/ force E) the result of an unbalanced force exerted on a body. ANS = E Is this correct??
*June 3, 2013*

**Acceleration**

Which of the following statements about acceleration is true. Acceleration is: A) time/ velocity B) force/ time C) the rate of change of displacement D) time/ force E) the result of an unbalanced force exerted on a body. ANS = E Is this correct??
*June 3, 2013*

**Linear velocity/ acceleration**

A body moves 180 degrees from point A to point B in a semi circle. The diameter of the semi circle is 2m. Calculate the distance traveled between point A and point B. C = pi * d = 3.1416 * 2m = 6.283 = 6.283/ 2 = 3.141 ANS = 3.141 Is this done correctly??
*June 3, 2013*

**Physics**

Camera lenses are described in terms of their focal length. A 50.0 mm lens has a focal length of 50.0 mm (a) A camera with a 50 mm lens is focused on an object 4.0 m away. Locate the image. (b) A 980 mm lens is focused on an object 125 m away. Locate the image.
*May 21, 2013*

**Physics**

A wheel and axle arrangement has an axle with a diameter of 25cm. A rope is wrapped around the axle and is supporting a load of 2 tonnes. 1)If the mechanical advantage of the system is 30, determine the diameter of the wheel. ANSWER = m 2)Determine the effort required to ...
*May 20, 2013*

**Physics- Simple machines**

A wheel and axle arrangement has an axle with a diameter of 25cm. A rope is wrapped around the axle and is supporting a load of 2 tonnes. 1) If the mechanical advantage of the system is 30, determine the diameter of the wheel___________m. 2)Determine the effort required to ...
*May 12, 2013*

**Physics**

Simple Machines A simple wheel and axle has a wheel diameter of 2.3m and an axle diameter of 92mm. If an effort of 26N is required to raise a mass of 16 kg what is the efficiency of the machine? A- 2.46% B- 95.3% C- 24.1% D- 20.1% E- 65.5% I am having a problem determining ...
*May 11, 2013*

**MATH**

the area of a certain rectangle is 288yd squared. the perimeter is 68yd. if you double the length and width,what will be the area and perimeter of the new rectangle?
*May 9, 2013*

**Physics**

300N 200N ? |- 8m -|- 5m - |_____________________________________| R2 10M | 10m R1 A beam having a length of 20 metres is pivoted at its mid point. A 200 newton load is located at a point 5 metres from the right hand end of the beam. A 300 newton load is located at a point 8 ...
*May 4, 2013*

**Physics**

A beam having a length of 20 metres is pivoted at its mid point. A 200 newton load is located at a point 5 metres from the right hand end of the beam. A 300 newton load is located at a point 8 metres from the right hand end. In order to be in equilibrium, what load is required...
*May 4, 2013*

**physics**

A body of 150kg is located at a height of 45m. If allowed to fall freely to the ground. What will be its velocity on impact?
*April 29, 2013*

**Physics**

A body is moving north at 12m/s and 5 seconds later it has a velocity of 30m/s in the same direction. What was the acceleration of the body?
*April 27, 2013*

**Physics**

A Body with a mass of 150kg is located at a height of 45 m. If allowed to fell freely to the ground. What will be its velocity on impact? KE= 1/2*m*v^2 PE= m*g*h 1/2*m*v^2= m*g*h 1/2*150kg*45m*v^2= 150kg*9.81*45m 3375* v^2= 66217.5 3375*v^2/3375= 66217.5/3375 v^2= 19.62m/s Is ...
*April 27, 2013*

**Physics**

1/2* 75kg* v^2= 75kg* 9.81* 20-0 37.5* v^2= 14715 37.5* v^2/ 37.5= 14715/37.5 v^2= 14715/37.5 v^2= 392.4 m/s
*April 27, 2013*

**Physics**

A body with a mass of 75 kg is located at a height of 20 m. If it is allowed to free fall to the ground. What will be its velocity on impact?
*April 27, 2013*

**Math**

Find the total surface area of a closed cylinder having a diameter of 1.000 m and 15.000 mm and a length of 12.000 m and 55.000 mm. (Round the answer to 3 decimal places) 1 m = 1000 mm Total surface area= pi*D*h+2*(0.7854*D^2)
*April 19, 2013*

**Math**

Calculate the mass of water in kg and tonne contained in a rectangular tank with the following dimensions: width of 3.2000 metres height of 2.000 metres length of 8.000 metres. (Round answers to 3 decimal places) Answers: l= 8.000 1 tonne= 1000 kg w= 3.200 h= 2.000 V= l*w*h V...
*April 19, 2013*

**math**

a steel tube has an outside diameter of 15 cm, an inside diameter of 13 cm, and is 3.7 m long. The volume of the steel contained in the tube in cubic cm is ? V= pi*r^2*h V= pi*7.5cm^2*370cm V= pi*56.25cm*370cm V= 65384.397 V= pi*r^2*h V= pi*6.5cm^2*370cm V= pi*42.25cm*370cm V...
*April 19, 2013*

**math**

A steel tube has an outside diameter of 15 cm, an inside diameter of 13 cm,and is 3.7 m long. What is the volume of the steel contained in the tube in cubic cm is?
*April 19, 2013*

**Math**

358
*April 19, 2013*

**Math**

PLEASEEE Help. I need the answer and explanation please.
*April 7, 2013*

**Math**

How do you convert 7 to the square root of 2 into a decimal? Also, how do you convert 3 to the square root of 8 into a decimal? Thanks
*April 7, 2013*

**Math**

Radio stations use three or four letters for their call letters(name). The first letter must be a W or K. How many different call letters are possible if repeated letters are allowed? And not allowed?
*March 29, 2013*

**Math**

Frank has 3 nickels, 5 dimes, and 2 quarters. What is the range, mean, median, and mode of the values of Frank's coins?
*March 18, 2013*

**science**

Zinc chloride solution is poured into a solution of ammonium carbonate. need conventional, ionic and net ionic equations thanks
*March 12, 2013*

**do ur work**

idk u look it up and find it and u need to do ur work
*March 1, 2013*

**Physics**

One of the most powerful cranes in the world, operating in Switzerland, can slowly raise a load of 6000 tonne to a height of 12 m. (1 tonne = 1000 kg) The acceleration of gravity is 9.81 m/s2 . How much work is done by the crane? Answer in units of MJ I found it by using Work...
*February 26, 2013*

**spainsh 2 help please**

1. Si yo Tuviera Hambre, YO VOLVERIA A COMER 2. Si el bebe TUVIERA sueï¿½o, EL ESTARIA DORMIDO. 3. ï¿½Que te necesito to (gustar) pedir? I'm not sure but here are some options: Que te gustaria pedir? te gustaria pedir algo? 4.MEGUSTAN ...
*February 26, 2013*

**Math**

If a train traveled at 480 kilometers per hour for 1/4 hour,what distance would the train travel?
*February 12, 2013*

**Physics **

The condensing pressure is 260psig and the metering device inlet temperature is 100 degrees for R-22 what is the total subcooling in the system?
*February 8, 2013*

**chemistry**

I wasn't given any densities...except to assume that water has a density of 1.00 g/cm^3 in previous problems.
*February 7, 2013*

**chemistry**

I know the molecular weights of the acids: HCl -- 36.5 H2SO4 -- 98.0 H3PO4 -- 98.0
*February 7, 2013*

**chemistry**

I have no idea how to begin solving these problems... Calculate the normality of a 1.0 molal solution of each of the following acids: a. HCl b. H2SO4 c. H3PO4 Calculate the molality of a 1.0 normal solution of each of the following acids: a. HCl b. H2SO4 c. H3PO4
*February 7, 2013*

**Math**

take the square of the 1st number & the square root of 2nd number 09+36=75 (81-6=75) 05+04=23 (25-2=23) 08+01=63 (64-1=63) 06+16=32 (36-4) 09+09=78 (81-3) 03+09=6 (9-3=6) 03+81=?? (9-9=0)
*February 7, 2013*

**Physics **

If the specific volume of red brass is 0.001865 ft/3lb. What would be the density? Thanks!
*February 1, 2013*

**Calc**

Line L is tangent to the graph of y= x- (x^2/500) at the point Q a) find the x coordinate of point Q B) right an equation for line L C) suppose the graph above were a hill (measured in feet). There is a 50 foot tree growing vertically at the top of the hill. Does a spot light...
*January 25, 2013*

**Math**

Which is a molecule of phosphoric acid contains 3 atoms of hydrogen to every 4 atoms of oxygen. Could a compound containing 16 atoms of oxygen and 12 atoms of hydrogen be phosphoric acid? Explain. Mr.Lee has 3/10 of his gross salary deducted for taxes. If Mr.Lee makes $900 a ...
*January 6, 2013*

**algebra**

y=2x+1 yes 2x
*January 4, 2013*

**physics**

A 2561-kg van runs into the back of a 823-kg compact car at rest. They move off together at 8.5 m/s. Assuming the friction with the road is negligible, calculate the initial speed of the van.
*December 18, 2012*

**physics**

A hockey player makes a slap shot, exerting a constant force of 31.4 N on the hockey puck for 0.13 s. What is the magnitude of the impulse given to the puck?
*December 18, 2012*

**physics**

Haloke does 179 J of work lifting himself 0.296 m. What is Haloke's mass?
*December 12, 2012*

**physics**

Early skeptics of the idea of a rotating Earth said that the fast spin of Earth would throw people at the equator into space. The radius of Earth is about 6400 km. Show why this objection is wrong by determining the following information. (a) Calculate the speed of a 94-kg ...
*December 6, 2012*

**physics**

An airplane flies due south at 185 km/h relative to the air. There is a wind blowing at 68 km/h to the east relative to the ground. What are the plane's speed and direction relative to the ground?
*December 6, 2012*

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