Thursday
December 5, 2013

# Posts by DANNY

Total # Posts: 610

Physics (Stress & Strain)
A uniform bar 1.900 meters in length and having a cross sectional area of 11.000cm^2 is subject to a loading of 5450.000 Newtons. this load causes an extension to the bar length of 2.420mm. Calculate the stress and strain produced. 11cm = .11m 2.420mm = .02420m length = 1.9m A...

Physics (Stress & Strain)
A hole 3cm in diameter is to be punched out of a steel plate 8cm thick. The shear stress of the material is 670GPa. What load is required on the punch? 3cm = 0.03m 8cm = 0.08m Lateral surface area (As) = pi*D*h = 3.1416 * .03m * .08m = 3.1416 * .0024m = .007539m Force = Stress...

Physics (Stress & Strain)
A steel bar has a rectangular cross section measuring 1.000cm by 2.500cm and is 8.100m in length. A load of 150000.000N causes the bar to extend 2.000mm. Calculate the stress and strain. Area = l*w = 1.000cm*2.500cm = 2.500cm = 0.025m = 0.025m*8.100m = 0.2025m Stress = Load/ A...

Physic (Stress & Strain)
A uniform bar 1.900m in length and having a cross sectional area of 11.000cm^2 is subject to a loading of 5450.000N. this load causes an extension to the bar length of 2.420mm. Calculate the stress and the strain produced. Area = 11.000cm^2 = 11*10^-3m Load = 5450.000N Stress ...

Physics (Stress & Strain)
Stress = force/ area = 87500N/ 5cm^2 = 17500 = 70000/ 17500 ANS = 4 Is that correct?

Physics (Stress & Strain)
What is the factor of safety for a steel hanger having an ultimate strength of 70000N per cm^2 and supporting a load of 87500N. The hanger has a cross sectional area of 5cm^2. Factor of safety = ultimate stress/ allowable stress = 70000/87500 = 0.8 Have I done this correctly?

Physics (Stress & Strain)
A hole 3cm in diameter is to be punched out of a steel plate 8cm thick. The shear stress of the material is 670GPa. What load is required on the punch? First find the area: A = pi*d^2/ 2 = 3.1416 * 3cm^2/ 2 = 3.1416 * 9/ 2 = 28.2744/ 2 = 7.0686cm Stress = 670GPa Second, covert...

Physics (Stress & Strain)
1) Calculate the tension stress in a 21.00mm diameter rod subjected to a pull of 30.000kN. 21mm =0.021m 30.000kN = 30000N A = pi*d^2/4 = 3.1416 * (0.021)^2m^2/ 4 = 3.1416 * 0.000441/ 4 = 0.0013854456/ 4 = 0.0003463614 Stress = Load/ Area = 30000/ 0.0003463614 = 86614732.47N = ...

Physics (Stress & Strain)
What is the factory of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 61000.000N. The steel hanger in question has a cross sectional area of 6.500cm^2. ANS = (Round to 3 decimal places) 6.500cm = 0.065m Load = 61000.000N Ultimate st...

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