Sunday
May 26, 2013

# Posts by Collin

Total # Posts: 45

Health
That's right and thanks for answering my question.

Math - 4th grade
It could be a line because a line segment.

physics
Runner A is initially 6.0 mi west of a flagpole and is running with a constant velocity of 4.0 mi/h due east. Runner B is initially 4.0 mi east of the flagpole and is running with a constant velocity of 5.0 mi/h due west. How far are the runners from the flagpole when they meet?

Math
Circle O is centered at the origin and has a radius of 5. Circle O' is the image of circle O after a translation of T1,2. What is the center of circle O'? What is the radius of circle O'?

Math
What single rotation is equivalent to Rotate 40 degrees circle, Rotate 60 degrees circle, rotate -10 degrees

calculus
Use the chain rule d/dx[f(x)^(n)]= (n(f(x))^(n-1))*(f'(x)).

calculus
y'=[(1/2)*(arctan(x))^(-1/2)]*(1/(1+x^(2)))

calculus
Note that f'(x) can be rewritten algebraically a f'(x)= x -(1/x). Now, take the integral (anti-drivitive) of f'(x) with respect to 'x' to obtain f(x). So, Int(x-(1/x),x)=((x^(2))/2)-ln(abs(x))+C To understand this you must first look at the rules of integra...

Calculus
You are almost right but since u=-t^(2) the limits are [0,-25] then put them into e^(u) and you get, e^(-25)-e^(0)= e^(-25)-1 Then divide that answer by 5 thus the answer is, (e^(-25)-1)/5

calculus
sqrt(-16)=sqrt(-1)sqrt(16)=i sqrt(16)=4i sqrt(-25)=sqrt(-1)sqrt(25)=i sqrt(25)=5i I think you can see it now. Just remember i=sqrt(-1). And don't forget your properties of sq-roots.

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