Calculus
By recognizing each series below as a Taylor series evaluated at a particular value of x, find the sum of each convergent series. A) 1+5 + (5^2)/(2!)+(5^3)/(3!)+(5^4)/(4!)+...+ (5^k)/(k!)+...= B) 1-(2^2)/(2!)+(2^4)/(4!)-(2^6)/(6!)+...+((-1)^(k)2^(2k))/((2k)!) +...=
Geometery
I figured it out. Thanks.
Geometery
Is the long side one of the parallel sides ? YES Where did the 5 come from? Slanted top.
Geometery
Trapezoid. A = (5+4) x 11/2 = 49.5 Long side is 11 in. bottom base is 4 in Correct? Or you need more info?
Geometery think I got it
I think I figured it out. The triangle. A= 1/2 x bxh A = 1/2 x 19 x 12 = 114cm area of for Triangle. I got the 12 because the paraelel side of 10 is 22 of the rectangle. So the triangle looks like (attached to rect.) it is 12cm.
Geometery
Yes I see what your saying. The bottom of the triangle though is apart of the side of the rectangle. But just a small portion of it. I knew my triangle something was off. A = 1/2 x 10cm???x 19cm The rectangle 10cm is paraelle to 22cm.
Geometery
Sorry I added 374.5 (actual calculation of rectangle area) to 9.5 = 384cm total area of the composite figure is what I meant to type.
Geometery
Composite figure finding area. Rectangle: A=22cm x 17cm = 374 area of rectangle (Long side is 22cm, Width is 17cm.) Triangle: A = 1/2 x b x h A = 1/2 x 19cm ( no height given) A= 9.5 area of Triangle I added 323.5cm + 9.5cm = 333cm area of the composite figure. Is the the righ...
Geometery
Is my answer right? Also, if not is my triangle formula wrong?
Geometery
Composite figure finding area. Is this right my answer I came out with is 323.5 cm? Rectangle: A=22cm x 17cm = 374 (Long side is 22cm, Width is 17cm.) Triangle: A = 1/2 x b x h A = 1/2 x 19cm ( no height given) So then, I added the rectangle and trinagle sum together and came...
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