Calc,
Oops, I should have been more specific. I need to solve it using sums, not antiderivates.
Calc,
Find the value of the definite integral: int= integral sign int((x + 2)/(x^(3/2)),x= 16..25)dx I have no idea how to start this... would I get rid of the fraction?
Calculus
A 24 foot ladder is leaning against a building. Let x be the distance between the bottom of the ladder and the building and let theta be the angle between the ladder and the ground. a)Express theta as a function of x. cos theta = x/24 theta = arccos(x/24) correct/incorrect? b)...
Calculus
Could someone please explain this to me? Differentiate. h(u)= 10^(sqrt(u)) h'(u)= 10^(sqrt(u))*log(10)(d/du(sqrt(u))) h'(u)= 10^(sqrt(u))*((1)/(2*sqrt(u)))*log(10)
Calculus
So I get this: = ln Isin(u)I + C = ln Isin(ln x)I + C = ln (sin(ln x)) + C OR = ln (sin(1/x)) + C Is it correct or incorrect?
Calculus
Why is it S (ln u) du = ? What about the sin? And to multiply them are you reciprocating?
Calculus
Evaluate the integral. S= integral sign I= absolute value S ((cos x)/(2 + sin x))dx Not sure if I'm doing this right: u= 2 + sin x du= 0 + cos x dx = S du/u = ln IuI + C = ln I 2 + sin x I + C = ln (2 + sin x) + C Another problem: S ((sin (ln x))/(x)) dx I don't even k...
Calc.
Evaluate the indefinite integral. Please check my work? Not sure if I am doing this correctly. S= integral symbol S x^3*sqrt(x^2 + 1) dx u = x^2+1 x^2= u - 1 du = 2xdx du/2 = xdx 1/2 S x^2 * x sqrt (x^2 + 1) du 1/2 S (u - 1) * sqrt (u) du multiply square root of u and (u - 1) ...
Calc.
But the x is the only thing being squared I thought because it is within parentheses and then multiplied by xcos dx?
Calc.
S is supposed to be the integral symbol and b is the upper bound and a is the lower bound. Yes, xcos(x^2) dx is it.
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