Wednesday

July 30, 2014

July 30, 2014

Total # Posts: 1,682

**Math**

2 ( b + 1 ) < - 6 Divide both sides by 2 b + 1 < - 3 Subtract 1 to both sides b + 1 - 1 < - 3 - 1 b < - 4 Answer: a

**math**

yes 16 + 3 = 19 9 * 2 = 18

**math**

8.875 * 10 ^ - 5 = 0.00008875 If 5 / 3.65 * 10 ^ 3 mean 5 / ( 3.65 * 10 ^ 3 ) then 5 / ( 3.65 * 10 ^ 3 ) = 5 / 3.65 * 1000 ) = 5 / 3650 = 0.001369863 8.875 * 10 ^ - 5 - 5 / ( 3.65 * 10 ^ 3 ) = 0.00008875 - 0.001369863 = -0,001281113 = - 1.281113 * 10 ^ - 3

**math**

8.897 * 10 ^ 6 / 3.2 * 10 ^ 4 = ( 8.897 / 3.2 ) * 10 ^ 6 / 10 ^ 4 = ( 8.897 / 3.2 ) * 10 ^ 2 = 2.7803125 * 10 ^ 2

**math-algebra**

64 = 4 ^ 3 64 x ^ 3 = ( 4 x ) ^ 3 27 = 3 ^ 3 64 x ^ 3 - 27 = ( 4 x ) ^ 3 - 3 ^ 3 a ^ 3 - b ^ 3 = ( a - b ) ( a ^ 2 + a b + b ^ 2 ) In this case: 64 x ^ 3 - 27 = ( 4 x ) ^ 3 - 3 ^ 3 = ( 4 x - 3 ) * [ ( 4 x ) ^ 2 + 4 x * 3 + 3 ^ 2 ] = ( 4 x - 3 ) * ( 16 x ^ 2 + 12 x + 9 )

**algr.1**

If your expression mean : ( 1 / 4 ) n + 12 > ( 3 / 4 ) n - 4 then: ( 1 / 4 ) n + 12 > ( 3 / 4 ) n - 4 Multiply both sides by 4 4 * ( 1 / 4 ) n + 4 * 12 > 4 * ( 3 / 4 ) n - 4 * 4 n + 48 > 3 n - 16 Substrac n to both sides n + 48 - n > 3 n - 16 - n 48 > 2 n - 1...

**math**

302.50 / 5 = 60.5

**algebra**

One correction in second line . P > 134 ft

**algebra**

W = 29 ft P = 134 ft P = 2 L + 2 W = 2 ( L + W ) P > 134 ft 2 ( L + 29 ) > 134 2 L + 58 > 134 Substract 58 to both sides 2 L + 58 - 58 > 134 - 58 2 L > 76 Divide both sides by 2 L > 38 ft

**Math- URGENT PLEASE**

9.3 * 10 ^ 3 = 9.3 * 1,000 = 9,300 9.3 * 10 ^ 4 = 9.3 * 10,000 = 93,000 0.011 * 10 ^ 6 = 0.011 * 1,000,000 = 11,000 9.3 * 10 ^ 3 + 9.3 * 10 ^ 4 + 0.011 * 10 ^ 6 = 9,300 + 93,000 + 11,000 = 113,300 = 1.133 * 10 ^ 5

**Trigonometry**

First answer is wrong.

**Trigonometry**

•Trigonometry - Bosnian, Sunday, September 9, 2012 at 1:07am Area of right triangle = 1 / 2 Area of a rectangle In this case: A1 = ( 1 / 2 ) * 8 * 15 = 60 units When each side is doubled: A2 = ( 1 / 2 ) * 2 * 8 * 2 * 15 = 4 * ( 1 / 2 ) * 8 * 15 = 4 A1 A2 = 4 * 60 = 240 un...

**Trigonometry**

Area of right triangle = 1 / 2 Area of a rectangle In this case: A1 = ( 1 / 2 ) * 8 * 15 = 20 units When each side is doubled: A2 = ( 1 / 2 ) * 2 * 8 * 2 * 15 = 4 * ( 1 / 2 ) * 8 * 15 = 4 A1 A2 = 4 * 20 = 80 units

**Trigonometry**

sin theta = H / L = H / 5 H = 5 * sin theta = 5 * sin 50 ° 32 ´ H = 5 * 0.77199 H = 3.85995 m approx. H = 3.86 m

**Trigonometry**

The rule of Pythagoras: c ^ 2 = a ^ 12 + b ^ 2 In this case : c = 34 cm b = a + 14 c = a ^ 2 + ( a + 14 ) ^ 2 34 ^ 2 = a ^ 2 + ( a + 14 ) ^ 2 1156 = a ^ 2 + a ^ 2 + 2 * a * 14 + 14 ^ 2 1156 = 2 a ^ 2 + 28 a + 196 Subtract 196 to both sides 1156 - 196 = 2 a ^ 2 + 28 a + 196 - 1...

**Precalculus**

an = n ^ 2 + 1 n = 1 a1 = 1 ^ 2 + 1 = 1 + 1 = 2 n = 2 a2 = 2 ^ 2 + 1 = 4 + 1 = 5 n = 3 a3 = 3 ^ 2 + 1 = 9 + 1 = 10 n = 4 a4 = 4 ^ 2 + 1 = 16 + 1 = 17

**Cal-Help Please**

When x = 9 9 x − x ^ 2 = 9 * 9 - 9 ^ 2 = 81 - 81 = 0 and 3 - sqt( x ) / ( 9 x − x ^ 2 ) = 3 - sqt( 9 ) / ( 9 x − x ^ 2 ) = 3 - 3 / 0 = 3 - ( + OR - infinity ) So: limit 3 − square root( x ) /(9 x − x ^ 2 ) as x ->9 = + OR - infinity

**geometry**

Two Angles are complementary if they add up to 90 ° (a Right Angle). Or : A + B = 90 ° In this case : A = 16 z - 9 ° B = 4 z + 3 ° A + B = 90 ° 16 z - 9 ° + 4 z + 3 ° = 90 ° 20 z - 6 ° = 90 ° Add 6 ° to both sides 20 z - 6 ° + 6 ...

**geometry**

Two Angles are complementary if they add up to 90 ° (a Right Angle). Or : A + B = 90 ° In this case : A = 16 z - 9 ° B = 4 z + 3 ° A + B = 90 ° 16 z - 9 ° + 4 z + 3 ° = 90 ° 20 z - 6 ° = 90 ° Add 6 ° to both sides 20 z - 6 ° + 6 ...

**Math**

3 x + 2 y = 3 subtract 3 x to both sides 3 x - 3 x + 2 y = 3 - 3 x 2 y = 3 - 3 x Divide both sides by 2 y = 3 / 2 - 3 x / 2 2 x + 10 y = - 5 Subtract 2 x to both sides 2 x - 2 x + 10 y = - 5 - 2 x 10 y = - 5 - 2 x Divide both sides by 10 y = - 5 / 10 - 2 x / 10 y = y 3 / 2 - 3...

**Algebra....HELP!!**

7 a + 6 b = 3 + -7 a + b = 25 ________________ 7 a + ( - 7 a ) + 6 b + b = 3 + 25 7 b = 28 Divide both sides by 7 7 b / 7 = 28 / 7 b = 4 7 a + 6 b = 3 7 a + 6 * 4 = 3 7 a + 24 = 3 Subtract 24 to both sides 7 a + 24 - 24 = 3 - 24 7 a = - 21 Divide both sides by 7 7 a / 7 = - 2...

**Math**

If your expresion mean : ( - 4 ) * ( - x ) ^ 3 * x * ( - 1 / 8 ) then : ( - 4 ) * ( - x ) ^ 3 * x * ( - 1 / 8 ) = - 4 * ( - 1 / 8 ) * ( - x ^ 4 ) = ( 1 / 2 ) * ( - x ^ 4 ) = - x ^ 4 / 2

**math**

If your expression mean : [ ( 2 ^ 5 - 5 ) / 9 ] * 11 then : 2 ^ 5 = 2 * 2 * 2 * 2 * 2 = 32 2 ^ 5 - 5 = 32 - 5 = 27 ( 2 ^ 5 - 5 ) / 9 = 27 / 9 = 3 [ ( 2 ^ 5 - 5 ) / 9 ] * 11 = 3 * 11 = 33

**calculus**

5 = 1 + 4 6 = 2 + 4 7 = 3 + 4 ... 14 = 10 + 4 5 ^ 2 + 6 ^ 2 + 7 ^ 2 + ... + 14 ^ 2 = ( 1 + 4 ) ^ 2 + ( 2 + 4 ) ^ 2 + ( 3 + 4 ) ^ 2 + ... + ( 10 + 4 )^ 2 = E ( k + 4 ) ^ 2 from n = 1 to n = 10 ________________________________________ ( k + 4 ) ^ 2 = k ^ + 2 * k * 4 + 4 ^ 2 = k ...

**Math**

x ^ 2 + y ^ 2 + 6 x - 46 = 0 x ^ 2 + y ^ 2 + 6 x = 46 ( x ^ 2 + 6 x + 9 ) + y ^ 2 = 46 + 9 ( x + 3 ) ^ 2 + y ^ 2 = 55 The circle equation is: (x - a ) ^ 2 + ( y - b ) ^ 2 = r ^ 2 where a and b are the x and y coordinates of the center of the circle. In this case : a = - 3 beco...

**math**

60

**calculus**

Where is your graph?

**math**

If log 7 mean logarithm to base b = 7 then : log 7 ( x ) = log 7 ( 4 ) + log 7 ( 3 ) log ( a ) + log ( b ) = log ( a * b ) log 7 ( 4 ) + log 7 ( 3 ) = log 7 ( 4 * 3 ) = log 7 ( 12 ) log 7 ( x ) = log 7 ( 12 ) x = 12

**Math**

A = sqrt [ s * ( s - a ) * ( s - b ) * ( s - c ) ]

**Math**

The semiperimeter of a triangle is half its perimeter. The formula for the semiperimeter of a triangle with side lengths a, b, and c is: s = ( a + b + c ) / 2 The area of a triangle can also be calculated from its semiperimeter using Heron's formula: A = [ sqrt s * ( s - a...

**Pre-algebra**

2 + 0.35 * 12 = 2 + 4.2 = 6.2

**MATH**

16 - 30 / ( 10 + 5 ) = 16 - 30 / 15 = 16 - 2 = 14

**geometry**

180 ° - x = 3 * ( 90 ° - x ) - 60 ° 180 ° - x = 270 ° - 3 x - 60 ° 180 ° - x = 210 ° - 3 x - x + 3 x = 210 ° - 180 ° 2 x = 30 ° Divide both sides by 2 x = 15 °

**math**

16 ^ 2 = 256 25 / 5 = 5 If 6(3)4 mean 6 * 3 * 4 then . 16^2-25/5+6(3)4= 256 - 5 + 72 = 323

**math**

Go on: wolframalpha dot com When page be open in rectangle type: derivative ln(cos(0.5)+(sin(x^2+3))^1/3) and click option = After few seconds when you see result click option: Show steps On wolfram alpha dot com you can practice any kind of calculus. That is good just for pra...

**Algebra**

When p = 0 1 / p -> Infinity One solution also p < 0 becouse when p < 0 then 1 / 6 p are negative and 1 / 6 p + 14 < 20 So the exact solutions are : p < 0 and p > 1 / 36

**Algebra**

1 / ( 6 p ) + 14 < 20 Subtract 14 to both sides 1 / ( 6 p ) + 14 - 14 < 20 - 14 1 / ( 6 p ) < 6 Multiply both sides by 6p 6 p * 1 / ( 6 p ) < 6 p * 6 1 < 36 p Divide both sides by 36 1 /36 < 36 p / 36 1 / 36 < p that is equivalent of p > 1 / 36

**math**

P = 2 a + 2 b In your case : a = x , b = 2 x + 3 P = 2 a + 2 b = 72 P = 2 x + 2 * ( 2 x + 3 ) = 72 2 x + 4 x + 6 = 72 6x + 6 = 72 Subtract 6 to both sides 6 x + 6 - 6 = 72 - 6 6 x = 66 Divide both sides by 6 x =11 x = a = 11 cm b = 2 x + 3 b = 2 * 11 + 3 = 22 + 3 = 25 cm P = 2...

**Algebra**

1 p = p 1 p + 14 < 20 p + 14 < 20 Subtracrt 14 to both sides p + 14 - 14 < 20 - 14 p < 6

**math**

n = your number a = ones digit b = tenths digin c = hundreds digit d = thousands digit n = a + b / 10 + c / 100 + d / 1000 c = d + 3 b = c - 2 = d + 3 - 2 = d + 1 a = b + c = d + 1 + d + 3 = 2 d + 4 n = a + b / 10 + c / 100 + d / 1000 n = 2 d + 4 + ( d + 1 ) / 10 + ( d + 3 ) /...

**Algebra**

h = the height of the flagpole s = the height of the school h = ( 3 / 4 ) s s - h = 4.5 m s - ( 3 / 4 ) s = 4.5 ( 1 / 4 ) s = 4.5 Multiply both sides by 4 s = 18 The height of the school = 18 m

**math**

Take number 12 and subtract summ of first numbers 2 * 6 = 4 become 12 - ( 2 + 6 ) = 12 - 8 = 4 4 * 1 = 7 become 12 - ( 4 + 1 ) = 12 - 5 = 7 8 * 3 = 1 become 12 - ( 8 + 3 ) = 12 - 11 = 1 So 5 * 5 = x become 12 - ( 5 + 5 ) = 12 - 10 = 2 x = 2 5 * 5 = 2

**Math**

x = first number y = second number x - y = 16 that is equivalent of y = x - 16 x ^ 2 + y ^ 2 = x ^ 2 + ( x - 16 ) ^ 2 = x ^ 2 + x ^ 2 - 2 * x * 16 + 16 ^ 2 = 2 x ^ 2 - 32 x + 256 Quadratic equation a x ^ 2 + b x + c vhen a is positive in point : x = - b / 2 a have MINIMUM x = ...

**Algebra**

1.5 * 17.5 = 26.25 miles

**Algebra2**

1. Eliminate the absoulute value : x ^ 2 - 3 x + 3 = 3 x ^ 2 - 3 x + 3 = - 3 ______________________ x ^ 2 - 3 x + 3 = 3 Subtract 3 to both sides x ^ 2 - 3 x + 3 - 3 = 3 - 3 x ^ 2 - 3 x = 0 x ( x - 3 ) = 0 Solutions : x = 0 and x = 3 x ^ 2 - 3 x + 3 = - 3 Add 3 to both sides x ...

**Algebra2**

1. Eliminate the absoulute value : 7 x + 2 = 10 7 x + 2 = - 10 _________________ 7 x + 2 = 10 7 x = 10 - 2 = 8 x = 8 / 7 7 x + 2 = - 10 7 x = - 10 - 2 = - 12 x = - 12 / 7 Solutions x = 8 / 7 aprox. 1.14 and x = - 12 / 7 aprox. - 1.71 2.Eliminate the absoulute value : Absolute ...

**algebra 2**

x + y = 2 Multiply both sides by 2 2 x + 2 y = 4 2 y = 4 - 2 x 3 x + 2 y = 9 3 x + 4 - 2 x = 9 x + 4 = 9 x = 9 - 4 = 5 x + y = 2 5 + y = 2 y = 2 - 5 = - 3

**math**

á = Greek letter alpha â = Greek letter beta

**math**

One of the most important properties of a straight line is in how it angles away from the horizontal. This concept is reflected in something called the "slope" of the line For straight lines, slope is constant (always the same). You can graph the points and "cou...

**math**

d = your digit d = 100 x + 10 y + z my hundreds digit is three more than my ones x = z + 3 that is equivalent with : z = x - 3 my tens digit is oneless than my hundreds y = x - 1 d = 100 x + 10 y + z d = 100 * x + 10 * ( x - 1 ) + x - 3 d = 100 x + 10 x - 10 + x - 3 = 111 x - ...

**Algebra**

If your expression mean : f ( x ) = 7 / ( x - 1 ) then : x = 0 f ( 0 ) = 7 / ( 0 - 1 ) = 7 / - 1 = - 7 x = 1 f ( 1 ) = 7 / 1 - 1 ) = 7 / 0 = infinity x = 2 f ( 2 ) = 7 / ( 2 - 1 ) = 7 / 1 = 7 x = 3 f ( 3 ) = 7 / ( 3 - 1 ) = 7 / 2 = 3.5 x = 4 f ( 4 ) = 7 / ( 4 - 1 ) = 7 / 3 = 2...

**Math**

Arithmetic mean : ( p1 + p2 + p3 + p4 + p5 ) / 5 = 21 Multiply both sides by 5 p1 + p2 + p3 + p4 + p5 = 21 * 5 = 105 p1 + p2 + p3 + p4 + p5 = Total points of team Total points of team = 105 If 4 other players obtained 1 point greatest score of one player could be : 105 - 4 = 101

**algebra 1**

3 ( 5 y - 5 x ) = 45 3 * 5 * ( y - x ) = 3 * 3 * 5 15 ( y - x ) = 3 * 15 Divide both sides by 15 y - x = 3 Add x to both sides y - x + x = 3 + x y = x + 3 If you must solve y = 0 0 = x + 3 Subtrac 3 to both sides 0 - 3 = x + 3 - 3 - 3 = x x = - 3 OR 3 ( 5 y - 5 x ) = 45 Divide...

**Algebra 1**

P = Perimeter W = Width L = Length P = 2 W + 2 L 36 = 2 * 4 + 2 L 36 = 8 + 2 L Subtract 8 to both sides 36 - 8 = 8 + 2 L - 8 28 = 2 L Divide both sides by 2 28 / 2 = 2 L / 2 14 = L L = 14 in

**algebra**

Vr = Vm * ( 1 - r ^ 2 / R ^ 2 ) Vr = ( 1 / 4 ) Vm ( 1 - r ^ 2 / R ^ 2 ) = 1 / 4 Multiply both sides by 4 4 * ( 1 - r ^ 2 / R ^ 2 )= 1 4 - 4 * r ^ 2 / R ^ 2 = 1 Subtract 4 to both sides 4 - 4 * r ^ 2 / R ^ 2 - 4 = 1 - 4 - 4 * r ^ 2 / R ^ 2 = - 3 Multiply both sides by - 1 4 * r...

**trig**

start-> programs-> Accessories-> Calculator-> View-> Scintific 17 sin

**math**

10 ^ 6 = 10 * 10 * 10 * 10 * 10 * 10 = 1 000 000 = one milion 4.97 * 10 ^ 6 = 4 970 000

**Algebra**

1,760 / 0.04 = 44,000 $

**Algebra 1**

d = r t 48 = r * 16 Divide both sides by 16 48 / 16 = r * 16 / 16 3 = r r = 3

**Algebra**

- 2 ( t - 7 ) - ( t + 8 ) = 8 - 2 * t - 2 * ( - 7 ) - t - 8 = 8 - 2 t + 14 - t - 8 = 8 - 3 t + 6 = 8 Subtrac 6 to both sides - 3 t + 6 - 6 = 8 - 6 - 3 t = 2 divide both sides by - 3 t = - 2 / 3

**algebra**

a + 7b = 17 - a + 2b = 2 __________ ( a - a ) + ( 7b - 2b ) = 17 - 2 5b = 15 Divide both sides by 5 b = 15 / 5 = 3 a + 7b = 17 a + 7 * 3 = 17 a + 21 = 17 Subtract 21 to both sides a + 21 - 21 = 17 - 21 a = - 4

**mathematics**

In point where firs derivative = 0 function have loca minimum or maximum. If second derivative < 0 that is local maxsimum. If second derivative > 0 that is local minimum. If expression 3cos2x mean : 3 cos (2 x ) then first derivative = - 6 sin ( 2 x ) - 6 sin( 2 x ) = 0 ...

**math**

x + 3 y = 7 Subtract 3 y to both sides x + 3 y - 3 y = 7 - 3 y x = 7 - 3 y Put x = 7 - 3 y into equation x + 4 y = 12 7 - 3 y + 4 y = 12 7 + y = 12 Subtract 7 to both sides 7 + y - 7 = 12 - 7 y = 5 Replacing y = 5 into x = 7 - 3 y gives x = 7 - 3 * 5 x = 7 - 15 x = - 8

**math**

Set of known values: x = 1 , y = 280 x = 2 , y = 480 x = 3 , y = 684 x = 4 , y = 913 x = 5 , y = 1205 x = 6 , y = 1615 The interpolating polynomial is : y = ( 17 x ^ 4 - 86 x ^ 3 + 139 x ^ 2 + 4730 x + 1920 ) / 24 For x = 7 , y = 2215 Next term : 2215

**Algebra**

After half hour studen have 9 - 1 = 8 $ x = 8 / 1.25 = 6.4 h A partial hour is charge the same as a full hour so x = 6 h 0.5 + x = 0.5 + 6 = 6.5 h

**Mathematics**

1 h = 60 min 9 h 07 mim = 8 h + 1 h + 7 min = 8 h + 60 min + 7 min = 8 h 67 min 9 h 7 min - 8 h 55 min = 8 h 67 min - 8 h 55 min = 12 min Distance : 1083 km - 957 km = 126 km The average speed : 1 h = 60 min 12 min = 1 / 5 h 126 / ( 1 / 5 ) = 5 * 126 = 630 km / h

**maths**

tan theta = H / L tan theta = 4 / 1.8 = 2.222222 theta = 65 ° 46 ´ 20 "

**math**

4 x + 3 y = 0 16 x + 3 = 8y ______________ Multiply the first equation by 4 16 x + 12 y = 0 16 x + 3 = 8y ______________ Subtract 8 y by second equation 16 x + 12 y = 0 16 x + 3 - 8 y = 8y - 8y = 0 ______________ 16 x + 12 y = 0 16 x + 3 - 8 y = 0 ______________ Subtract 3 by ...

**calculus**

Go on : wolframalpha dot com Whe page be open in rectangle type : derivative tan^4(2x) then click option = After few seconds when you see result click option : Show steps

**Algebra**

Remark: ¡Ý mean greater or equal

**Algebra**

5 ( x + 6 ) = 5 x + 30 12 x - 25 ¡Ý 3 x - 5 ( x + 6 ) 12 x - 25 ¡Ý 3 x - ( 5 / x - 6 ) ) 12 x - 25 3 x - ( 5 x + 30 ) 12 x - 25 ¡Ý 3 x - 5 x - 30 12 x - 25 ¡Ý - 2 x - 30 Add 2 x to both dides 12 x - 25 + 2 x ¡Ý -...

**math**

12 % = 12 / 100 = 0.12 250 / 0.12 = 250 * 100 / ( 0.12 * 100 ) 25,000 / 12 = 2 * 2 * 2 * 5 * 5 * 5 * 5 * 5 / ( 2 * 2 * 3 ) = 2 * 5 * 5 * 5 * 5 * 5 / 3 = 6250/ 3 = 2083.3333...

**Math**

1 kg = 1000 g 2 kg 300 g = 1 kg + 1 kg + 300 g = 1 kg + 1000 g + 300 g = 1 kg 1300 g 2 kg 300 g - 1 kg 700 g = 1 kg 1300 g - 1 kg 700 g = 600 g The mass of the empty basket = 600 g

**Math**

L = 2 + 2 W = 2 ( 1 + W ) A = L * W 24 = 2 * ( 1 + W ) * W 24 = 2 * ( W + W ^ 2 ) Divide both sides by 2 12 = W + W ^ 2 Subtract 12 to both sides 0 = W + W ^ 2 - 12 Now you must solwe equation : W ^ 2 + W - 12 = 0 The exact solutions are 3 and - 4 Width cannot be negative so W...

**math**

The vertex of a parabola: y = a x ^ 2 + b x + c is the point where the parabola crosses its axis. If the coefficient of the x ^ 2 term is positive, the vertex will be the lowest point on the graph, the point at the bottom of the “U”-shape. If the coefficient of the x...

**calculus**

Go on: wolframalpha dot com When page be open in rectangle type: limit x^3-2/x^2+x as x-> - infinity and click option = After few seconds when you see result click option: Show steps On wolfram alpha dot com you can practice any kind of calculus. That is good just for pract...

**calculus**

Go on: wolframalpha dot com When page be open in rectangle type: derivative sin(x^3-5x^2+4x-7) and click option = After few seconds when you see result click option: Show steps On wolfram alpha dot com you can practice any kind of calculus. That is good just for practice. You ...

**math help**

P.S. When you type : derivative (x^2+lnx)(2+e^x) you must click option = in rectangle

**math help**

Go on : wolframalpha dot com When page be open in rectangle type : derivative (x^2+lnx)(2+e^x) After few seconds when you see results click option : Show steps

**math help**

What is your question?

**math**

What is your question?

**Geometry**

tan ( theta ) = 4 / 3 theta = inverse tangent ( 4 / 3 ) theta = 53 ° 7 ´ 48 " theta = 53 ° to the nearest degree

**Math**

¡Ý mean greater or equal

**Math**

- 5 ( 4 x - 14 ) ¡Ý - 25 x + 35 - 20 x + 70 ¡Ý - 25 x + 35 - 20 x + 25 x ¡Ý 35 - 70 5 x ¡Ý - 35 Divide both sides by 5 x ¡Ý - 7 Ansver D

**Algebra**

The graph of any function in the form y = a x ^ 2 + b x + c is a parabola. A quadratic equationhas two solutions. In this case : x 1 = [ - 3 -s qrt ( 29 ) ] / 10 and x 2 = [ - 3 + sqrt ( 29 ) ] / 10 If coefficient a is positive then the graph of parabola is concave up. If coef...

**ALGEBRA**

x = - 6 y = ( 4 / 3 ) * ( - 6 ) + 1 = - 24 / 3 + 1 = - 8 + 1 = - 7 x = - 3 y = ( 4 / 3 ) * ( - 3 ) + 1 = - 12 / 3 + 1 = - 4 + 1 = - 3 x = 6 y = ( 4 / 3 ) * 6 + 1 = 24 / 3 + 1 = 8 + 1 = 9 For plot : In google type : point plotter When you see list of result click on: Graph Indi...

**ALGEBRA**

The x-intercept of a line is the point at which the line crosses the x axis. ( i.e. where the y value equals 0 ) In this case : - 4 x + 9 * 0 = - 36 - 4 x = - 36 Divide both sides by -4 x = - 36 / - 4 = 9 x - intercept point (9,0) The z-intercept of a line is the point at whic...

**algebra**

L = Length W = Width The perimeter of a rectangle P = 2 L + 2 W In this case W = 2 m P = 34 m 34 = 2 L + 2 * 2 34 = 2 L + 4 Subtract 4 for both sides 34 - 4 = 2 L + 4 - 4 30 = 2 L Divide both sides by 2 15 = L L = 15 m

**Calculus**

y = sqrt ( 3 x ) = sqrt ( 3 ) * sqrt ( x ) d y / d x =sqrt ( 3 ) * 1 / 2 sqrt ( x ) d y / d x = ( 1 / 2 ) * sqrt ( 3 / x )

**Integrated Math 1**

If you want to see graph go on: rechneronline.de In blue rectangle type : - x ^ 2 + 25 Set : Range x-axis from - 10 to 10 Range x-axis from - 10 to 40 and click option Draw

**Integrated Math 1**

Answer A.

**Integrated Math 1**

The standard equation of a parabola is : y = a x ^ 2 + bx + c The vertex of a parabola is the point where the parabola crosses its axis. If the coefficient of the x ^ 2 term is positive, the vertex will be the lowest point on the graph, the point at the bottom of the “U&#...

**math**

Rate Sam works : ( 1 job ) / x hrs Rate Denise works : ( 1 job ) / ( x + 2) hrs Rate together : 1 / x + 1 / ( x + 2 ) =

**TRIG**

cos theta = + OR - 1 / sqrt ( 1 + tan ^ 2 theta ) In Quadrant II, cosine are negative so : cos theta = - 1 / sqrt ( 1 + tan ^ 2 theta ) cos theta = - 1 / sqrt [ 1 + ( 3 / 4 ) ^ 2 theta ] cos theta = - 1 / sqrt ( 1 + 9 / 16 ) cos theta = - 1 / sqrt ( 16 / 16 + 9 / 16 ) cos thet...

**algebra**

How can a square table have different length and height?

**Integrated Math 1**

- 1 - 6 x ^ 2 - x ^ 3 - ( - 2 - 4 x ^ 2 ) = - 1 - 6 x ^ 2 - x ^ 3 + 2 + 4 x ^ 2 = - x ^ 3 - 2 x ^ 2 + 1 OR 1 - 2 x ^ 2 - x ^ 3 Answer A.

**Integrated Math 1**

- 16 x ^ 2 - x ^ 3 - ( - 2 - 4 x ^ 2 ) = - 16 x ^ 2 - x ^ 3 + 2 + 4 x ^ 2 = - x ^ 3 - 12 x ^ 2 + 2

**trigonometry**

If a central angle theta = 3 pi / 2 then : Circumference of a circle = 2 * r * pi Ful circle have 360 ° = 2 pi radians. Lenght of arc : L = ( theta / 2 pi ) * 2 * r * pi L = theta * r = 60 ( 3 pi / 2 ) * r = 60 Multiply both sides by 2 3 pi * r = 120 Divide both sides by 3...

**Math**

f = frame = 2.5 cm p = dimension of frame p + f = dimension of one side of square Area of a square painting : A = ( p + f ) ^ 2 = 3600 p + f = sqrt ( 3600 ) p + f = 60 p + 2.5 = 60 p = 60 - 2.5 = 57.5 cm

**Integrated math**

Definite integral 1 to 3 ( 3 x ^ 2 - 2 x + 1 ) dx = ( x ^ 3 - x ^ 2 + x ) from 1 to 3 = ( 3 ^ 3 - 3 ^ 2 + 3 ) - ( 1 ^ 3 - 1 ^ 2 + 1 ) = 27 - 9 + 3 - ( 1 - 1 + 1 ) = 21 - 1 = 20

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