Physics Classical Mechanics
remember that the sum of the torques is equal to I*alpha so sigma(t) = r1xF1 + r2xF2 +... +rnxFn = I*alpha where I is the moment of inertia through the axis of rotation. look for I in a table, easily found on google. notice the similarity to the application of Newtons second l...
notice that the rocket described in the problem is *not* under any gravitational interaction. So really the only problem with your equation is the "-g*burn time" part. the equation you want to solve is just v_f = -v_ex*ln(m_final/m_initial)
Hi, What point is a solution to the system of inequalities y >4x and y >-2x-3 (1/2,2)?
Do ur HW of 8.02x yourself,or else.......
Why i mean
And can u explain way they all equal 5^11
Would another way be 5^6?
I already know 48828125 is one way please help
What are three ways to write 5^11 as a product of two powers