Friday
April 18, 2014

Posts by AwesomeGuy


Total # Posts: 39

Pre-Calculus
Find the inverse of the following quadratic equation. Hint: Complete the square first. y= 2x²+16x-5

Pre-Calculus
Find the inverse of the following quadratic equation. Hint: Complete the square first. y= x²+14x+50

Trigonometry
Solve the equation for all values of x. 2sin(2x)-√3=0, on the interval [0,2π).

Trigonometry
Solve the equation for all values of x. -2cos²x-sin x+1=0, on the interval [0,2π).

Trigonometry
1.) Apply the following method you used in #2! You should notably understand this already! Goodness grief! 2.) let A = arctan x let B = arccos x then we are looking for sin(A + B) . now, tan A = x , sin A = x/√(x^2+1) cos A = 1/√(x^2+1) ... create a right triangle ...

Trigonometry
Write the trigonometric expression as an algebraic expression. 1.) SIN(ARCSIN X+ARCCOS X) ANSWER: 1 2.) SIN(ARCTAN 2X-ARCCOS X) ANSWER: 2x²-SquareRoot of 1-x²/Square Root of 4x²+1.

Trigonometry
AWESOME! SUPERB! I had it right when you provided support. THANKS!

Trigonometry
Verify the identities please. 1.) TAN(X+π)-TAN(π-X)= 2 TAN X 2.) SIN(X+Y)+SIN(X-Y)= 2 SIN X COS Y

Trigonometry
Directions: Use a graphing utility to approximate the solutions of the equation in the interval [0,2π) by setting the equation equal to zero, graphing the new equation, and using the ZERO or ROOT feature to approximate the x-intercepts of the graph. (Note: These problems ...

Trigonometry
Verify the identities algebraically. 1.) TAN^5 X= TAN³X SEC²X-TAN³X 2.) COS³X SIN²X= (SIN²X-SIN^4X)COS X

Trigonometry
Verify the identity algebraically. This problem is very intriguing and awesome at the same time. It's wonderfully amazing! 1.) TAN³α-1/TAN α-1= TAN²α + TAN α + 1

Trigonometry
State the quadrant in which θ lies. 1.) CSC θ is greater than 0 and TAN θ is less than 0. 2.) SEC θ is greater than 0 and SIN θ is less than 0.

Trigonometry
2.) SEC X COS X= 1 1/COS X*COS X/1= 1 BINGO! 3.) CSC²X-CSC X SIN X+SIN X/SINX-TAN X+ COS X/SIN X 1/SIN²X-1/SIN X*SIN X/1-TAN X+COS X/ SIN X 1/SIN²X-1-SIN X/COS X+COS X/SIN X 1/SIN²X-1-TAN X*1/TAN X= CSC²X COOL! Need help on #6 and 7 please. Thank you!

Trigonometry
Verify the identities. 1.) √1-COSθ/1+COSθ= 1+SINθ/SINθ 2.) SEC X SIN(π/2-X)= 1 3.) CSC X(CSC X-SIN X)+SIN X-COS X/SIN X + COT X= CSC²X 4.) CSC^4 X-2 CSC²X+1= COT^4 X 5.) CSC^4 θ-COT^4 θ= 2 CSC²θ-1 6.) TAN^5 X= TAN&su...

Trigonometry
Verify the identity algebraically. TAN X + COT Y/TAN X COT Y= TAN Y + COT X

Trigonometry
1.) 1/TAN[(π/2)-X]=COT X BINGO! SOLVED! 2.) SEC X/-CSC X 1/COS X ÷ -1/COS X 1/COS X * -SIN X/1 -TAN X YES BINGO! WOW!

Trigonometry
Verify the identities. 1.) SIN[(π/2)-X]/COS[(π/2)-X]=COT X 2.) SEC(-X)/CSC(-X)= -TAN X 3.) (1 + SIN Y)[1 + SIN(-Y)]= COS²Y 4.) 1 + CSC(-θ)/COS(-θ) + COT(-θ)= SEC θ (Note: Just relax through verifying/solving these nice fun looking math proble...

Trigonometry
Verify/Solve the identities. 1.) SIN^1/2 X COS X-SIN^5/2 X COS X 2.) Long problem, but it's fun to solve! SEC^6 X(SEC X TAN X)-SEC^4 X(SEC X TAN X)

Trigonometry
Solve the equation. 1.) COS X CSC X

Trigonometry
Google this: 5.1 using fundamental identities Comcast Click and open the first result that appears on your search (Result= PDF Document). Textbook pages will appear and go to page 383 on problem #129. The directions will mention "Solve the right triangle shown in the figu...

Trigonometry
Let's solve this fun trigonometric fun math problem! 1.) SEC²X-1/SIN²X

Trigonometry
Solve the trigonometric equations. 1.) SIN²x(CSC²x-1) 2.) COT x SEC X 3.) COS²[(π/2)-x]/COS X (Note: These mathematical problems are somewhat tricky, but useful for students as of learning how to their fundamental identities. Let's enjoy solving these p...

Trigonometry
A ship is 50 miles east and 35 miles south of port. If the captain wants to sail directly to port, what bearing should be taken?

Trigonometry
Two fire towers are 30 km apart, tower A being due west of tower B. A fire is spotted from the towers, and the bearings from A and B are E 14° N and W 34° N, respectively. Find the distance d of the fire from the line segment AB.

Trigonometry
Since I have also forgot to label the conversion for the solution, it is ultimately measured in FEET.

Trigonometry
BP= 3091.79 AB/sin 2.5° = 3091.79/sin 4° 3091.785015 sin 2.5° = 134.8617682 134.8617682/sin 4° = 1933.33 Awesome! Thanks for the help!

Trigonometry
An observer in a lighthouse 350 feet above sea level observes two ships directly offshore. The angles of depression to the ships are 4° and 6.5°. How far apart are the ships?

Trigonometry
A plane is 160 miles north and 85 miles east of an airport. If the pilot wants to fly directly to the airport, what bearing would be taken?

Trigonometry
Reiny thanks a lot for the help! I welcome you with a nice smile! Here is the website where I can show how the problems look/appear like... Google this: 4.8 applications and models Comcast Click the first result that appears on the web search page. Go to page 8 in the PDF docu...

Trigonometry
Surveying A surveyor wishes to find the distance across a swamp. The bearing from A to B (Segment AB is opposite side of triangle) is N 32° W. The surveyor walks 50 meters from A to C, and at the point C the bearing to B is N 68° W. (Segment AC is adjacent side of tria...

Trigonometry
Wave Motion A buoy oscillates in simple harmonic motion as waves go past. At a given time it is noted that the buoy moves a total of 3.5 feet from its low point to its high point, and that it returns to its high point every 10 seconds. Write an equation that describes the moti...

Trigonometry
Mountain Descent A road sign at the top of a mountain indicates that for the next 4 miles the grade is 12%. Find the angle of the grade and the change in elevation for a car descending the mountain.

Trigonometry
Height of a Kite A 100-foot line is attached to a kite. When the kite has pulled the line taut, the angle of elevation to the kite is approximately 50°. Now everybody lets approximate the height of the kite!

Trigonometry
Angle of Depression Find the angle of depression from the top of the lighthouse 250 feet above water level to the water line of a ship 2.5 miles offshore.

Trigonometry
Navigation A ship leaves port at noon and has a bearing of S 29° W. If the ship sails at 20 knots, how many nautical miles south and how many nautical miles west will the ship have traveled by 6:00 P.M.?

Trigonometry
Height of a mountain While traveling across flat land, you notice a mountain directly in front of you. The angle of elevation to the peak is 2.5°. After you drive 18 miles closer to the mountain, the angle of elevation is 10°. Approximate the height of the mountain.

Trigonometry
A passenger in an airplane flying at an altitude of 10 kilometers sees two towns directly to the left of the plane. The angles of depression to the towns are 28° and 55°. How far apart are the towns?

Trigonometry
The length of a shadow of a tree is 130 feet when the angle of elevation of the sun is θ°. a) Write the height h of the tree as a function of θ. b) θ=10° What's height? θ=15° Height? θ=20° How tall is the height? θ=25° What...

mathematics
Stop cheating on Gauss you loser

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