math ALG 2!
x+(x-14)=300 2x-14=300 2x=314 x=157
math ALG 2!
4x=x+78 4(20)=20+78 80=98 no i did guess and check 4(26)=26+78 104=104
Calc
f(x)=2ln(x^2+3)-x Domain [-3,5] how do i find the absolute maximum value of this?
algebra
3(x-2/3)=-10 (x-2/3)=-10/3 x=-8/3
Math
60 degrees
algebra
-.1x-1>.4 -.1x>1.4 x<14 dividing/multiplying negatives switches the sign
Calc
f(x)=2ln(x^2+3)-x Domain [-3,5] how do i find the absolute maximum value of this?
never mind! figured it out
never mind i figured it out
Calc
range of f(x)= 5^(2x^2-1)^(1/2) i know that the domain of the inverse would be the range of this and i've found the inverse but it has natural logs in it and i don't know how to find the domain with that.. i feel like i'm missing something simple
math
the pie is 360 degrees divide that by 10 peices it gives you 36 degrees per slice 3 slices left times 36 degrees is 108 degrees
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