Calculate the coulomb force on q. They are all in a straight line q1, q2,q3. Q1:1.05 micro coulombs Q2:5.51 micro coulombs Q3:-2.15 micro coulombs The distance, r1, between q1 and q2 is 20.1cm. The distance, r2, between q2 and q3 is 15.3 cm. Also, calculate e coulomb force on q2
What is the electric field at a point midway between a -7.34 micro coulombs and a +4.49 micro coulombs charge apart 31.5m apart?
we have a test coming up and I cannot figure out the practice question. Can somebody please help? Aaron throws a 7.5 kg bowling ball by applying a 45 N force for a time of 0.90seconds. What is the impulse Aaron applies to the ball? What is the ball's speed at the end of th...
How do I set up the quadratic equation for this problem? 4.0= (2x)^2 / (1.0-x)(1.0-x) I know how to use the formula, but I have a hard time setting those equation to zero. Please explain step by step. Thank you
A Cu/Cu^2+concentration cell has a voltage of 0.22v at 25 C. The concentration of Cu^2+ in one of the half cells is 1.5x10^-3 M. What is the concentrate of Cu^2+ in the other half cell? I think I will have to use Nernst equation, but I am so stuck! please help. Thank you so much.
Find the critical point(s) of the function. Then use the second derivative test to classify the nature of each point, if possible. Finally, determine the relative extrema of the function f(x,y)= 3x^2 - 3e^5y^2
Find the critical point(s) of the function. Then use the second derivative test to classify the nature of each point, if possible. Finally, determine the relative extrema of the function. f(x,y)=3x^2 - 3xy + 3y^2 +5
0+3 on the bottom Sorry
The slope formula is Y2-Y1 over X2-X1 Therefore, it would be 6+8 on top, and 0-3 on the bottom.
Mercury, with a freezing point of -38.8°C, is the only metal that is liquid at room temperature. How much heat energy (in joules) must be released by mercury if 1.30 mL of the metal is cooled from room temperature (18.0°C) to -38.8°C and then frozen to a solid? (Th...