I think the answer is this: The change of momentum of a system is equal to the net impulse applied to it. Therefore, delta p=Fnet*deltat=Impulse In our case, p initial=mv=28kg*13m/s=364 kg*m/s p final=0 ( the object stops, v=o, p final 0) delta p = p final- p initial = 0- 364 ...
A moving electron passes near the nucleus of a gold atom, which contains 79 protons and 118 neutrons. At a particular moment the electron is a distance of 4.5 × 10−9 m from the gold nucleus.
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