# Posts by Alona

Total # Posts: 12

**Physics II**

Thank you so much!!!! you're a lifesaver!

**Physics II**

A bead with a mass of 0.085 g and a charge of 20 nC is free to slide on a vertical rod. At the base of the rod is a fixed 20 nC charge. In equilibrium, at what height above the fixed charge does the bead rest?

**Alegerbra**

what's the question here?

**Intermediate Algebra**

no problem. good luck with that class

**Intermediate Algebra**

m=2 and n=-7 I solved the second equation for n and got n=-4m+1 then plugged that into the first eqn for n and got m=2. finally i put m into the first eqn and got n=-7 to check, you can see the first eqn: m-2n=16 goes to 2-2(-7)=16 which is correct.

**physics (easy)**

Will a 7.25 kg ball with a diamter of 22 cm float in water? I know that the radius is 11 cm and that the density of water is 1000kg/m^3 and I got that it will float but it just doesn't sound right. Could anyone help please?

**Physics**

A 56kg adult is climbing up a staircase of 67m. By how much would her body temp increase if her lost energy went into increasing her body temperature during this climb (in C)? I calculated the required amount of joules to reach the top to be 37x10^4J but i don't know where...

**economics (game theory)**

There is not an exact square that you could be sure you'd NOT get three in a row but by gaining the knowledge the first move your opponent makes, you have a higher chance of NOT getting three in a row, the closer you mark your variable to your opponents, and the further ...

**3rd grade**

flour- it sounds the same but is spelled differently and means something different

**Science**

If I understand what you're asking, you simply add the forces together 3.0N+2.0N=5.0N.

**8th grade**

So you multiply 21,854,374 x .124 = 2,709,942 for the Korean Vets. Then 21,854,374 x .107 = 2,338,418 for the WWII Vets then subtract those numbers: Korean Vets-WWII Vets = 371,524 Veterans

**Physics**

actually bob, it's 658. You subtract freq E by one harmonic 659-1=658

- Pages:
**1**