If the density of ice is 0.92 g/cm^3, what percent of an ice cubes (or icebergs) mass is above water.
How does the apparent weight loss of the an object compare with the weight of the water displaced by the object?
...I already solved one for you just like this...
And please type the whole equation next time. We do not have ESP.
5+2(x-1) = 12 5+2x-2 = 12 5+2x = 14 2x = 9 x = 9/2 (which is 4.5)
5+2(x-1) = 0 5+2x-2 = 0 5+2x = 2 2x = -3 x = -3/2 (which is -1.5)
Q=cm(Tf-Ti) Q = the heat of an object m = the mass c = the heat capacity of the substance Tf= the final temperature Ti= the initial temperature Q gained by water = Q lost by copper Make sure your units go together.
x = time (independent) y = distance (dependent) horizontal: y isn't changing diagonal: y is increasing at a constant rate
There's also plenty of links on the bottom of the Wikipedia article under "External Links".