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October 20, 2014

Posts by Akle


Total # Posts: 21

Chemistry hw
What is the answer for Tb and Tf??????? please help.
February 19, 2012

Chemistry hw
Assuming 100% dissociation, calculate the freezing point and boiling point of 3.13 m SnCl4(aq). Tf=? Tb=? My work: SnCl4 with 100% dissociation gives a van't hoff factor of 5, 1Sn 4+ ion and 4 Cl- ions deltaT = i x Kf x m for freezing point = 5 x 0.51C/m x 3.13m = deltaTf ...
February 19, 2012

CHEMISTRY
Thanks so much! :] I understand my mistake!
February 18, 2012

CHEMISTRY
A solution of H2SO4(aq) with a molal concentration of 1.94m has a density of 1.119g/mL. What is the molar concentration of this solution? I got an answer of 2.17 M and it is incorrect..please help. My work: So Molar concentration = molal concentration * density = 1.94 mol/kg...
February 18, 2012

Chem
Thank you! It did and i found my error a minute before you posted this. Once again, I always appreciate your help DrBob222 :)
February 10, 2012

Chem
DrBob222, I got an answer of 33 and 24.23 as the temperature but it is incorrect. I looked at your response to David and unfortunately it did not help me. Would you please take a look at this question and help me out. Thanks. If the heat from burning 5.800 g of C6H6 is added ...
February 10, 2012

CHEM
yeah i converted it. It was suppossed to be kj :]
February 10, 2012

CHEM
I got an answer of 56.976. The answer is negative though since the reaction is exothermic. Other than that great explanation. Thank you so much. You are the best!!!! :]
February 10, 2012

CHEM
This is my work..... (18g) (4.184 J)(28.70-24.07) I get 350.95 then i divide it by 0.0340 and get 10322.17. Then I divide it by a 1000 and get 10.322... It is wrong. Can you take a look at my work and tell me what i did wrong and confirm the right answer for me thanks!
February 10, 2012

CHEM
I know I posted this question again but no one is really helping me. Can someone please help me as soon as possible. In a constant-pressure calorimeter, 60.0 mL of 0.340 M Ba(OH)2 was added to 60.0 mL of 0.680 M HCl. The reaction caused the temperature of the solution to rise ...
February 10, 2012

CHEM
Yes! It is right. Thank you for your help. I really appreciate it.
February 10, 2012

CHEM
You can select more than one answer and I can't seem to figure it out.
February 10, 2012

CHEM
sorry i meant the second one. I put the second one and it marked me wrong. As well, I put the last two and it marked me wrong also.
February 10, 2012

CHEM
I think it is only the first one, but it marked me wrong.
February 10, 2012

CHEM
At constant pressure, which of these systems do work on the surroundings? Check all that apply. 2A (g) + B(s) --> 3C(g) 2A (g) +2B (g) -->5C(g) A(g)+ B(g) --> C(g) A (s) +2B(g)--> C(g)
February 10, 2012

CHEM
This is my work..... (18g) (4.184 J)(28.70-24.07) I get 350.95 then i divide it by 0.0340 and get 10322.17. Then I divide it by a 1000 and get 10.322... It is wrong. Can you take a look at my work and tell me what i did wrong and confirm the right answer for me thanks!
February 10, 2012

CHEM
Also can you look it up as well thanks. I really appreciate it!
February 10, 2012

CHEM
I solved it numerous times and it says I am getting the wrong answer. Could you help explain how to solve it and see what I am doing wrong please.
February 10, 2012

CHEM
In a constant-pressure calorimeter, 60.0 mL of 0.340 M Ba(OH)2 was added to 60.0 mL of 0.680 M HCl. The reaction caused the temperature of the solution to rise from 24.07 °C to 28.70 °C. If the solution has the same density and specific heat as water, what is ΔH ...
February 10, 2012

CHEM
I got an answer of 24.23 degrees celsius and it marked me wrong? Can someone please explain and tell me what they get.
February 10, 2012

CHEM
If the heat from burning 5.800 g of C6H6 is added to 5691 g of water at 21 °C, what is the final temperature of the water? 2C6H6(l) +15O2 (g)----> 12CO2(g)+6H2O(l) +6542
February 10, 2012

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