If the external force on the satellite is zero, the linear momentum will be conserved. This would be the case for a satellite out in the space where the gravitational pull of earth is nearly zero. In such a situation the fragments will fly off in all the directions obeying the...
The larger contact time means longer duration of the impulse imparted to the golf ball. (Impulse I = F*t) Largere impulse causes larger change in the momentum of the ball. And the distance covered is directly proportional to the momentum imparted.
Since momentum in each case is the same, the damage will be identical. Both the options are equally bad.
correct option - (C)
1) r = m*v/(q*B) r(a)= m(a)*2v/(q(a)*B).....(1) r(p)= m(p)*v/(q(p)*B).....(2) r(a)/r(p)= m(a)*2v*q(p)/[m(p)*v*q(a)] = 4m(p)*2*q(p)/[m(p)*2q(p)] = 4*2/2 = 4 2) Ma*Va/[Qa*B] = Mp*Vp/[Qp*B] So, Va = 4.4*2/4 = 2.2m/s
a)As the acceleration is zero, the force exerted by the man equal the comp. of gravitational force on the body along the incline. F = mg*Sin22 b)Wm = F.d = - 3.8*F ( -ve because F and d are in opposite directions) c) Wg = +3.8*mg*Sin22 d) Net force on piano = 0. So Wnet = 0
What is the unit of work given in the problem? Is it Joules? W = mgh should give you the height h.
The moments of the gravitational forces should balance each other to prevent plank's rotation(about the wedge). a)Taking moments about the wedge position: 40g*X = 60g*10 X = 15m from the wedge b) You can't balance with a 10Kg mass. 40g*10 = 10g*X X= 40m - beyond the le...
kx = mg k = mg/x = 2*10/0.25 = 80 N/m
Try G*Ms*Mu/R^2 = Mu*Vu^2/R here Ms = mass of Sun Mu = mass of Uranus Vu = Speed of Uranus R =Orbital radius Also 2*pi*R = Vu*T will give value of Vu which when plugged in the first equation will give R.
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