Monday
December 9, 2013

# Posts by Ajayb

Total # Posts: 117

physics
W2^2 = W1^2 + 2*alpha*theta 13.5^2 = 22.0^2 +2*alpha*13.8 alpha = (13.5^2 - 22.0^2)/2*13.8 = - 10.9 rad/s^2 So, magnitude of angular acceleration = 10.9 rad/s^2

Physics
A) Escape vel. = Ue = sqrt(2GM/R) ...(1) also g = GM/R^2 So GM/R = gR .....(2) From(1) & (2) Ue = sqrt(2gR) = sqrt(2*0.77*1200,000) = 1360 m/s B) u = Ue/2 = (1/2)*sqrt(2GM/R) Now KEi+PEi = PEf+KEf (conservation of mechanical energy) or (1/2)mu^2 - GMm/R = -GMm/(R+h)+0 or GM/4R...

Physics
The total load is 980+230 = 1210N but how it shall be shared by the supporting poles would depend on the location of the painter on the board. The question can not be answered in absence of this information/diagram.

Physics
F= m*a = m*(v-u)/t v is the velocity after time t(5.5s) u is the initial velocity = 0 Plug in the values to find the av. net force F

Physics
F = dP/dt = 0.70(6.9-0)/0.15 = 32.2 N

physics
Resultant force=160-40-60=60 N to the left.

Physics
g(n) = G*Mn/Rn^2 & g(e)= G*Me/Re^2 Mn=d*(4/3)*pi*Rn^3 (Mn->new planet's mass) Me=d*(4/3)*pi*Re^3 (Me-> Earth's mass) So, g(n)/g(e) = Rn/Re .....(1) Now, Mn/Me = 2 (given) So Rn^3/Re^3 = 2 or Rn/Re = 2^1/3 ......(2) From (1) & (2) g(n)/g(e)= Rn/Re = 2^1/3 So, if t...

physics
use the formula: S = ut +(1/2)*a*t^2 S - distance covered =1.25m u - initial velocity = 75m/s^2 a - acceleration = 25m/s^2 t - time taken to cover the distance

Physics.
Try E = mc^2 Take mass of electron and positron to be 9.1x10^-31Kg and 3x10^8m/s as speed of light.

physics
A) position: x(2)= (2*2-3)^2= 1m v = dx/dt = 2(2t-3)*2 so v(2)= 4 m/s a = dv/dt = 8 m/s^2 B) v at origin: x=0=(2t-3)^2 so t=3/2 at t=3/2, v = 4(2*3/2-3)= 0

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