physics
1. The apparent frequecy should be 20kHz i.e.lower than the actual freq. of 21kHz. Therefore the sound source should move away from you. If the rider speed is U - F' = v*F/(v+U) 20*10^3= 330*21*10^3/(330+U) 330+U= 330*21/20 U = 330*[21/20 -1]= 330*1/20 = 16.5m/s (min.ridin...
dynamic
How much is the acceleration? Not stated in the problem! anyway, you can use the formula: V^2 = U^2 + 2*a*s here a = accleration, U=0 and s = 2-1= 1m
Physics
Solution to a similar problem has been posted earlier which please check. B) The total mechanical energy = KE + PE of the object at the surface of Eris will remain constant and will be equal to PE at the max. height h (above the surface). The object's KE will be zero at th...
Physics
Can't be solved without the diagram showing the incline gradient
Physics
use T^2 = 4*pi^2*r^2/GM T and r are given, G -Universal constant of gravitation. Compute M - mass of star
Physics
use the law: T^2 proportional to r^3
Physics
Since the box is moving through sea water at a constant speed, the net force on it must be zero. The forces are: i) W= mg its weight downwards ii) Fb - buoyant force upwards iii) Ff - frictional force offered by water acting upwards. now W = mg = V*Db*g (Db-density of box) and...
Physics
tension in the string = m*V^2/r max tension is 70N so Vmax = sqrt(70*r/m)
physics
I suppose you have to find time for the bomb to strike the ground. h = (1/2)*g*t^2 h = 3000ft g = 32 ft/s^2 find out t The data - jet's horizontal velocity and mass of the bomb - is irrelevant for the above computation of time
Physics
a) s1= vt - for motorist s2= (1/2)*a*t^2 - for police officer when the cop cathes up the motorist: s1 = s2 So vt = (1/2)*a*t^2 15*t= (1/2)*3*t^2 t = 15*2/3 = 10 sec b) v = u + a*t = 0 + 3*10 = 30 m/s c) distance s1=s2= 15*10 = 150m
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