Sunday
May 19, 2013

# Posts by Ajayb

Total # Posts: 117

physics
You have been given the linear expansion coefficient - find increase in radius R and then find the disk's MI.

physics
1.You apply a force F on the book in horizontal direction towards the wall. 2. The normal reaction of the wall on the book will be (say) N. For equilibrium in horizontal direction => F = N 3. The weight of the book M*g will act on the book in downward direction. 4. The fric...

Physica
Work done by the man = F*d = 10*5 = 50 J work done by frictional force = mu*mg*d = - 0.2*5*9.8*5 = - 49 J Net work done on the box = 50-49= 1 J

Physics
You can consider the surface area of the sphere (4*pi*r^2) as the surface area of the steel plate. Multiply it with the thickness i.e. 0.5in to get volume of the steel material.

Physics
In the case of completely elastic collision, not only momentum is conserved but KE is also conserved. Considering these two principles, you get two equations from which you can find V1 and V2 in terms m1,m2 and U1.

Physics
E=V/d = 60/.03 = 2000 v/m W = qV = 5*12.45 = 62.25 J

Physics
during the slide down the hill: use a=gSin9.8-mu*gCos9.8 to find vel. at the base of the incline. For the horizontal part accleration is -mu*g - to find the distance covered. Figure it out based on the above hint

physics
That is correct. This is a case of inelastic collision where linear momentum is conserved because there is no external force. So, Pi = Pf

physics
1. Max. compression is 20cm - so the amplitude A is 0.2m. 2.(1/2)mV^2 = (1/2)kA^2 V^2 = kA^2/m = 5.2*0.04/0.7 V=0.54m/s 3.Speed at X = sqrt(k/m)sqrt(A^2-X^2) =2.72sqrt(.04-0.0144) = 2.72*0.16= 0.43m/s Acc. at X= (k/m)x= (5.2/0.7)*0.12 =0.89 m/s^2

Physics
h+g*t^2/2 t=sqrt(2h/g) =sqrt(2*51/9.8) = 3.2 sec

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