Wednesday

November 26, 2014

November 26, 2014

Total # Posts: 19

**physics**

a body travels 200 cm in the first two second and 220 cm in the next 4 seconds.what will be the velocity at the seventh second from the start.
*July 14, 2013*

**chemistry**

What will be value of molarity and strength %w/v respectively 30V H2O2 solution
*August 23, 2011*

**math 12**

the answer is 60 degrees
*March 19, 2010*

**Advanced Math**

4cos(theta)+3sin(theta)=(10/r)
*August 6, 2009*

**Advanced Math**

The general equation of such cosine function is:y=acos(x-phasedifference), y=displacement a=amplitude x=angular displacement =(angular velocity)*time =(2pi/time period)*time Therefore, the equation can be written as: y=2cos[x-(pi/4)]..........(a) or,y=2cos[(2pi/pi)*t-(pi/4)] ...
*August 6, 2009*

**mathhhhhhhhhhh,**

x^6+3x^3+2=0 It can also be written as: (x^3)^2+3(x^3)+2=0...........(1) Let a=(x^3), then we may rewrite equation (1) as: a^2+3a+2=0 or,a^2+a+2a+2=0 or,a(a+1)+2(a+1)=0 or,(a+1)(a+2)=0 either,a=-1 or,a=-2 that is (x^3)=-1 or (x^3)=-2 Therefore, x=-1 or x=cube root of -2 this ...
*August 6, 2009*

**Math**

Thanks that was really helpful. But the solution to the limit problem is still not clear to me.
*August 5, 2009*

**Math**

a)in how many different ways can 8 exam papers be arranged in a line so that the best and worst papers are not together? b)in how many ways can 9 balls be divided equally among 3 students? c)There are 10 true-false questions. By how many ways can they be answered? d)lim(x ...
*August 5, 2009*

**math**

=-12y+40+4y+10 =-8y+50
*August 5, 2009*

**physics**

If R1 and R2 be the two resistances connected in (a)series, then equivalent resistance=R1+R2 (b)parallel, then equivalent resistance=(R1*R2)/(R1+R2)
*August 5, 2009*

**trigonometry**

if sin2x=3sin2y, prove that: 2tan(x-y)=tan(x+y) ( here, in sin2x, 2x is an angle., like there's a formula:sin2x=2sinxcosx and sin2y=2sinycosy; ....)
*January 25, 2008*

**physics**

metals are the good conductor of heat. hence, metals can gain heat by contact. so, the cup with the metal spoon will cool faster.
*January 24, 2008*

**physics**

cause the air comes in thermal equlibrium with your body... and it depends upon the heat that your body looses...i guess so.
*January 24, 2008*

**Physics(last line:correction)**

q=(n*e).....(i) where, q= charge, n=number, e= charge of an electron n=q/e....(i) (from equation i) given,q= +2.8mc= +2.8*10^-6 c we know, charge of an electron(e)=1.6*10^-19 c hence n= (2.8*10^-6)/(1.6*10^-19) = 1.75*10^13 so, 1.75*10^13number of charges should be removed.
*January 24, 2008*

**Physics**

q=(n*e).....(i) where, q= charge, n=number, e= charge of an electron n=q/e....(i) (from equation i) given,q= +2.8mc= +2.8*10^-6 c we know, charge of an electron(e)=1.6*10^-19 c hence n= (2.8*10^-6)/(1.6*10^-19) = 1.75*10^13 so, 1.75*10^13number of charges should ne removed.
*January 24, 2008*

**trig**

if sin2x=3sin2y, prove that: 2tan(x-y)=tan(x+y) ( here, in sin2x, 2x is an angle., like there's a formula:sin2x=2sinxcosx and sin2y=2sinycosy; ....)
*January 23, 2008*

**trig**

if sin2x=3sin2y, prove that: 2tan(x-y)=tan(x+y)
*January 23, 2008*

**Antiderivatives**

Integration of 1/x with respect to x is natural logarithm of x
*January 22, 2008*

**physics**

find the force exerted by these two equal charges by using f=(1/4*pi*epsilon)*(q1*q2)/r^2 if f1 is the force exerted by one charge q1 and f2 be the force exerted by another charge q2 which are equal in their magnitude(as you've mentioned) then f1=f2=f. i.e, f1 and f2 are ...
*January 21, 2008*

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