Saturday

December 3, 2016
Total # Posts: 2,546

**Calculus 12th grade.**

1. A body is moving along a straight line with a velocity which varies according to the equation v=9t^2+2t, where v is in feet per second and t is in seconds. Find the expression for the distance as a function of time. A. 3t^3+t^2+C B. 3t^3+2t^2+C C. 18t+C D. 20t+C My answer ...

*March 5, 2011*

**Calculus 12th grade.**

Find the area lying above the x axis and below the parabolic curve y= 4x -x^2 a.8 b. 8 1/3 c. 10 2/3 d. 16 B or C not sure??

*March 5, 2011*

**12th grade Trigonometry **

Solve this trigonometric equation.give all positive values of the angle between 0deg and 360deg that will satisfy. Give any approximate value to the nearest minute only. 3 sin theta - 4 cos theta = 2

*March 4, 2011*

**Trigonometry(please Clarify)**

Thank you and yes I'm.

*March 4, 2011*

**Trigonometry(please Clarify)**

I posted before ; Write equivalent equations in the form of inverse functions for a.)x=y+cos theta b.)cosy=x^2 my answers were a.) x= y+ cos theta cos theta = x-y theta = cos^-1(x-y) b.) cosy=x^2 cos(y) = x^2 y = Cos^-1(x^2) your post confused me a little. Can you clarify if ...

*March 4, 2011*

**Trigonometry(correction)**

3 sin theta - 4 cos theta = 2

*March 3, 2011*

**Trigonometry**

Solve the following trig equations. Give all positive values of the angle between 0 degrees and 360 degrees that will satisfy each. Give any approximate value to the nearest minute only. 3 sin è - 4 cos è = 2 Can you please help me with this one.

*March 3, 2011*

**Trigonometry (repost Reiny)**

at 1:35am I posted ; Write equivalent equations in the form of inverse functions for a.)x=y+cos theta b.)cosy=x^2 my answers were a.) x= y+ cos theta cos theta = x-y theta = cos^-1(x-y) b.) cosy=x^2 cos(y) = x^2 y = Cos^-1(x^2) your post confused me a little. Can you clarify ...

*March 3, 2011*

**trigonometry (please double check this)**

Answer for b. 29deg 5',239deg 5',38deg 40',218deg 40'. can you plz check if i messed anything.

*March 3, 2011*

**trigonometry (please double check this)**

Solve the following trig equations. give all the positive values of the angle between 0 degrees and 360 degrees that will satisfy each. give any approximate value to the nearest minute only. a.) ( I got confused doing this 1 can you help me with it.) 3 sin theta - 4 cos theta...

*March 3, 2011*

**trigonometry (please double check this)**

""ƒÆ "" is supposed to be theta.

*March 3, 2011*

**trigonometry (please double check this)**

Solve the following trig equations. give all the positive values of the angle between 0 degrees and 360 degrees that will satisfy each. give any approximate value to the nearest minute only. 1. sin2ƒÆ = (sqrt 3)/2 2. sin^2ƒÆ = cos^2ƒÆ + 1/2 3. ...

*March 3, 2011*

**Trigonometry**

Write equivalent equations in the form of inverse functions for a.)x=y+cos è b.)cosy=x^2 (can you show how you would solve) a.) x= y+ cos è cos è = x-y theta = cos^-1(x-y) b.) cosy=x^2 cos(y) = x^2 y = Cos^-1(x^2)

*March 3, 2011*

**geometry **

what are the polar coordinates of the point k(-1,-sqrt3)? a.(2,60deg) b.(2,240deg) << right?

*March 2, 2011*

**geometry **

correct me if I'm wrong please. 7. what is the equation of the line which passes through c(2,3) and has a slope m =1/2? a.)x-2y=-4 <<<<< my choice b.)2x-y =1 c.)2x+y=7 d.)x+2y=8 what is the equation of the line which passes through point d(-4,2) and has ...

*March 2, 2011*

**trigonometry repost .**

This is an outline that i have to use to find the solution of the question. It involves logarithms and half-angle formulas.I have worked though it but got stuck on some parts. I'd like if you look over my work. solve the triangle for which given parts are a=27 ,b=21 ,c=24 ...

*March 1, 2011*

**trigonometry**

that was a typo its 15.5 which makes the log entry correct. =3.22875 log s =1.56229 subtract. -------- 2)1.66646 <<.. then divide by 2 = -------- log r =0.83323 the reason why i posted the out line was because they did not match. and i didn't understand how you got ...

*February 28, 2011*

**trigonometry**

This is an outline that i have to use to find the solution of the question. It involves logarithms and half-angle formulas.I have worked though it but got stuck on some parts. I'd like if you look over my work. solve the triangle for which given parts are a=27 ,b=21 ,c=24 ...

*February 28, 2011*

**Physics**

when a .187 kg mass is attached to a vertical spring it causes the spring to stretch distance d. if the mass is now displaced slightly from equilibrium, it is found to make 223 oscillations in 157s. Find the stretch distance d.

*February 28, 2011*

**Trigonometry /Logarithms (brace yourself)**

This is an outline that i have to use to find the solution of the question. It involves logarithms and half-angle formulas.I have worked though it but got stuck on some parts. I'd like if you look over my work. solve the triangle for which given parts are a=27 ,b=21 ,c=24 ...

*February 28, 2011*

**trigonometry **

an example problem showed the following log tan A/2 = 9.54435 - 10 A= 38 deg 36' 12" Now i want to do the same. log tan A/2 = 9.85551 - 10 A= ?? I don't know how to convert tan into degrees can you help me.

*February 27, 2011*

**Writing **

okay i have this writing assignment on how drunk driving can be stopped .. i have like three sentences to complete it and these three sentences are to explain how/what harsher penalties can help in stopping drunk driving.. I'm stuck because the following are already the ...

*February 27, 2011*

**cosines**

I don't know how to reverse cosine decimals into angles. Can you please explain and help me solve these . cos A= 0.28571428571 A= cos B= 0.66666666667 B= cos C= 0.5238089523

*February 27, 2011*

**trigonometry (repost) Mathmate**

Use logarithms and the law of tangents to solve the triangle ABC, given that a=21.46 ft, b=46.28 ft, and C=32°28'30" Using the previous values, a=21.46 b=46.28 C=32-28-30=32.475 We have A+B=180-32.475=147.525 a+b=67.74 a-b=-24.82 tan((A+B)/2)=3.433633 tan((A-B)/2...

*February 27, 2011*

**trigonometry **

Use logarithms and the law of tangents to solve the triangle ABC, given that a=21.46 ft, b=46.28 ft, and C=32°28'30" I have to use logarithms and law of tangents . and then provide the check. which says law of sine or mollweids equation. I can't us the cosine ...

*February 26, 2011*

**trigonometry (repost) Mathmate**

I want to start by saying thank you . You have no idea how much u have helped me understand logarithms, even better then the books i have (it poorly explains the subject of trigonometry let alone logarithms and antilog). Your last explanation was very clear and i even ...

*February 26, 2011*

**trigonometry **

Use logarithms and the law of tangents to solve the triangle ABC, given that a=21.46 ft, b=46.28 ft, and C=32°28'30" Also Give checks. I know the use of logarithms is unnecessary but i have to show my solution by using logarithms and that's the only reason I&#...

*February 24, 2011*

**Algebra 2**

In Kentucky, where i am from, we do algebra and algebra two before pre-cal and calculus. I didn't realize that the problem could be solved in multiple ways and i apologise. But the solution should be done without calculus.

*February 24, 2011*

**Algebra 2**

I already looked over what you had posted. Unfortunatly, i didn't quite understand what you had said.

*February 24, 2011*

**Algebra 2**

A company charges 16$ for a subscription. It has 30,000 subscribers. It looses 1,000 subscribers for every 1$ they raise the price. 1.Find the quadratic quation. (Can you tell me how to pull the numbers out of the question and put it into the equation?) Find the rate at 16$. (...

*February 24, 2011*

**Science**

Sand is silicon dioxide, or SiO2, therefore you must be Silcon or Si.

*February 24, 2011*

**Trigonometry (Logarthims) **

Give checks to the following two questions Use logarithms and the law of tangents to solve the triangle ABC, given that a=21.46 ft, b=46.28 ft, and C=32°28'30" without logarithms i can do this problem easily and i have. but when i try solving it with logarithms i...

*February 24, 2011*

**trigonometry**

Can you please show me the steps: Derive the identity for sin 3x in terms of sin x.

*February 24, 2011*

**trigonometry**

255 i guess that makes the first 1 wrong.

*February 23, 2011*

**trigonometry**

or sin (255°) = sin (180° + 75°) = - sin 75° [The terminal side of the angle lies in quadrant III, so the sine function is negative.] = - sin (45° + 30°) = - (sin 45°cos 30° + cos 45°sin 30°) [Use sin (A + B) = sin A cos B + cos A sin B...

*February 23, 2011*

**trigonometry**

is this correct? sin 255degrees 225 = 180 + 45 sin(225) = sin(180 + 45) = sin(180)cos(45) + cos(180)sin(45) sin(225) = 0 + (-1)(sqrt2/2) sin(225) = -(sqrt2)/2

*February 23, 2011*

**please please i need more ideas in the answer**

write a single paragraph which answers this question, “Who is responsible for program planning, the academic advisor or the student? Explain why.”

*February 22, 2011*

**trigonometry**

how can i find the anti-logarithm of this number. 5.07843058944 it should be 59477.5 can show me how.

*February 21, 2011*

**trigonometry (MathMate)**

okay i was able to get c*sin(A)= 1.8555387 but i was lost after that. I couldn't reproduce the same answers u have. value logarithm c 2.6294096 sin(A) 1̅.8555387 2.4849483 [ADD] sin(C) 1̅.9809493 a 2.5039990 [SUBTRACT] Anti-log 319.1530 (length of c)

*February 21, 2011*

**trigonometry (MathMate)**

MathMate i would really appreciate if you can show me where the logarithms can be used.I know they are unnecessary and I already found the answer without them but i still have to show my work using logarithms and they just confuse me. I also have most trouble woth the anti-...

*February 21, 2011*

**trigonometry**

1. Finde the area of the following tringles: (use Logarithms) A) a=12.7, b=21.5, c=28.6. i'm not of the answer i got. i got 127.6 if you got something different can you show me how you did while using logarithms.

*February 21, 2011*

**trigonometry**

is there anyway i can use logarthims in this problem?

*February 20, 2011*

**trigonometry**

i used cosin and got that answer .. I'm i wrong .

*February 20, 2011*

**trigonometry**

anyways the area would be 312,918.8

*February 20, 2011*

**trigonometry**

i don't know why its asking the url

*February 20, 2011*

**trigonometry**

C = 180 - A - B = 180 - 45° 48' 36" - 61° 2' 13" = 73° 9' 11" Law of sines: a/sinA = c/sinC a = c.(sinA/sinC) = 426.(sin(45° 48' 36"))/sin(73° 9' 11")) a = 426*0.749186 a = 319.153

*February 20, 2011*

**trigonometry**

okay so i have this trigonometry problem were i HAVE to use logarithms. Now this is my work but can u help me solve it using logarithms. Find the area of the following triangles:(use logarithms) 1) c=426, A=45degrees 48' 36",and B=61degrees 2' 13"

*February 20, 2011*

**trigomometry**

Thank you !

*February 20, 2011*

**trigomometry**

I don't think its right . can you correct me please . A.log sin A = 9.91655 - 10 sinA = 0.82537 A = 55.626° = 55° 34' 35" B.log cot A = 0.11975 cot(A) = 1.317498... A = 37.199 degs A = 37º 11' 56"

*February 20, 2011*

**trigomometry**

I don't think its right . can you correct me please . A.log sin A = 9.91655 - 10 sinA = 0.82537 A = 55.626° = 55° 34' 35" B.log cot A = 0.11975 cot(A) = 1.317498... A = 37.199 degs A = 37º 11' 56"

*February 20, 2011*

**sciencce**

Mrs. Scheib was riding her bike and leaves home and rides due east for a distance of 45 km. she returns home on the same bike path. if the entire bike path takes 4 hrs what is her average speed? Is it 11.25?

*February 17, 2011*

**list some harmful effects of plagiarism.**

please ineed answer for this question by his or her own word list some harmful effects of plagiarism. In other words, explain what is morally wrong with plagiarism. How does plagiarism harm the perpetrator? thank you

*February 16, 2011*

**program planning**

write a single paragraph which answers this question, “Who is responsible for program planning, the academic advisor or the student? Explain why.”

*February 15, 2011*

**trigonometry**

can you correct the rest for me please? Express each as a function of theta: a. sin (270deg + theta)= cos theta b. cos (pi + theta)= -cos theta c. tan (810 + theta)= ????? d. sin (theta - 180)= -sin theta

*February 11, 2011*

**gr.10 math**

could you please show me the steps to solve this equation?I looked at the answer in the back of our textbook but i keep getting the wrong answer. 5(2y+1)-(5y-2) answer=5y+7. thanks so much!

*February 11, 2011*

**Math**

R(p) = p - 0.08p - 1200

*February 9, 2011*

**Math**

Add the two equations to form one equation.

*February 9, 2011*

**Algebra**

Area = pi * r^2 diameter = 2r, r = d/2 d = 10x, r = 10x/2 = 5x A = pi * (5x)^2 A = 3.14 (25x^2) A = 78.5 x^2

*February 8, 2011*

**pre cal**

If you sketch this out you will have a right triangle, I will call ABC. A is the vertex = angle of depression AC (side b) = base = 1400 feet BC (side a) = leg = 1100 feet AB (side c) = hypotenuse = distance to landing site To find angle A (angle of depression) tan A = a/b = ...

*February 8, 2011*

**Algebra 1**

Solution, x <= 10/3 and y < 5 - x/2 x > 10/3 and y < -2(x - 5) Google for an online graph calculator. You will be able to input the equations and the program will show you a graph.

*February 8, 2011*

**geometry**

The ratio of the sides of the 1st triangle is, 3 : 4 : 6 The second triangle is x : x : 15 6 : 15 = 3 : x 6/15 = 3/x cross multiply 6x = 45 x = 7.5

*February 8, 2011*

**math**

8/8 - 3/8 = 5/8 To find the percent, 5 divided by 8 = 0.625 * 100 = 62.5%

*February 8, 2011*

**Math**

Maybe if you would repost (again) and this time proofread for nonsense symbols that only you know what they mean. What is "x1,x2¡¦¡¦¡¦¡¦¡¦x11.(Thus,-2 is labeled x1,82 is labeled x2 and so on.) find ¢&...

*February 8, 2011*

**Jiskha**

Why would you need to do this? Were you looking for test answers? I don't mean to infer you were cheating, but I cannot think of any other reason you would need to remove questions asked.

*February 8, 2011*

**Chemistry**

Describe how to prepare 5.00 liters of a 5.00 % (w/w) NaCl solution, which has a density of 1.06 g/mL, from pure solid sodium chloride. I have no idea how to find the starting measurements please help!

*February 6, 2011*

**physics**

a framed picture of weight 15N is hung on a wall, using a piece of string. The ends of the string are tied to two points, 0.60 m apart on the same horizontal level, on the back of the picture.Find the tension in the string if the string is 1.0m long

*February 6, 2011*

**trigonometry**

can you correct the rest for me please? Express each as a function of theta: a. sin (270deg + theta)= cos theta b. cos (pi + theta)= -cos theta c. tan (810 + theta)= ????? d. sin (theta - 180)= -sin theta

*February 5, 2011*

**trigonometry**

Express as a function : c.tan (810degrees + theta ) I'm confused between two answers . 1. that it would be tan 90 deg (which is undefined) 2. it would be cot theta ?? can you tell me what i should do to get the right answer.

*February 5, 2011*

**Physics**

BUMP!

*February 5, 2011*

**math**

Well, 'biscet' is not a word and FGH could be just about anything. Your question is not clear.

*February 2, 2011*

**math**

Buy him a drink?

*February 2, 2011*

**Calculus**

f(x)= x^2 + bx + 1 on [-1,1] First, integrate | = integration symbol |x^2 + bx + 1 = 1/3 x^3 + 1/2 bx^2 + x + C Evaluate from -1 to 1 1/3 x^3 + 1/2 bx^2 + x + C 1/3 (1)^3 + 1/2 b(1)^2 + 1 - (1/3 (-1)^3 + 1/2 b(-1)^2 - 1 1/3 + 1/2 b + 1 - (-1/3 + 1/2 b - 1) 1/2 b + 4/3 - (1/2 b...

*February 1, 2011*

**algabra**

D = RT (Distance = Rate x Time) T = D/R T = 960/70 T = ? T = 960/75 T = ?

*February 1, 2011*

**Math**

4x^4 - 6x^2 + 2 2(2x^4 - 3x^2 + 1) 2(2x^2 - 1)(x^2 - 1) 2(2x^2 - 1)(x - 1)(x + 1)

*February 1, 2011*

**Spanish-7th grade**

What are you doing Monday at 10 o'clock? I Study. I write. I listen to the teacher. I watch television.

*February 1, 2011*

**Finance**

If simple interest, I = PRT I = 25000(0.07)(4) I = ? 25000 + ? (interest) = value in 4 yrs

*February 1, 2011*

**Algebra**

(4x^6)(-3x^9)(6x^7) 4 x -3 x 6 = -72 x^6 * x^9 * x^7 = x^22 (add the exponents) (4x^6)(-3x^9)(6x^7) = -72x^22

*February 1, 2011*

**english- to kill a mocking bird**

in the book to kill a mocking bird by harper lee, what did Atticus learn, i have been searching everywhere and cannot find the answer, PLEASE HELP:(

*January 30, 2011*

**English**

YOU'RE A LIAR!!!! THOSE ARE NOT "88.2" ANSWERS!!!!! THAT WAS A 29.3 ANSWERS!!!!!! U SUCK

*January 28, 2011*

**trigonometry plz explain.**

Which way is done correctly and why ?? Express the following in degrees,minutes, and seconds: (1)4 --> (180/pi)*4 = 229.18312 229.18312 = 229 + (0.18312*60) = 229 degrees + 10.9872' = 229 deg 10' + (0.9872*60)" = 229 deg 10' + 59.2" or (2)4*180/pi = ...

*January 26, 2011*

**trigonometry??**

Did I do this right???? Express the following in degrees,minutes, and seconds: a.4 --> (180/pi)*4 = 229.18312 b.0.23 --> (180/pi)*0.23 = 13.17803 c.pi(3.14159)/6 --> (180/pi)*(pi*3.14156/6) = 94.24778 d.3*pi/2 --> (180/pi)*(3pi/2) = 270 e.-1.4 --> (180/pi)*-1.4...

*January 26, 2011*

**Trigonometry **

Express the following in radians: f.1025degrees. --> (pi/180)*1025 = -185pi/36 Is that correct or theirs another way to do it ??

*January 24, 2011*

**PHYSICS**

A harmonic wave on a string moves along the x-axis according to: î(x,t) = 5.0 (cm) sin[ (2.5m-1) x - (63s-1) t ] At x = 1.0 m when t = 2.2 s the speed of the oscillations on the string is closest to ... 25.2 m/s 4.55 m/s 3.15 m/s 2.27 m/s 1.67 m/s

*January 23, 2011*

**physics**

At a distance of 30 m the noise from the engine of an jet has an intensity level of 130 dB. At this level, you will be in pain and your ears will hurt. That's why this intensity is know as the "pain threshold". How far do you have to be from a jet (total distance...

*January 23, 2011*

**Trigonometry **

Express the following in radians: f.1025degrees. --> (pi/180)*1025 = -185pi/36 Is that correct or theirs another way to do it ??

*January 23, 2011*

**physical**

A harmonic wave on a string moves along the x-axis according to: î(x,t) = 5.0 (cm) sin[ (2.5m-1) x - (63s-1) t ] At x = 1.0 m when t = 2.2 s the speed of the oscillations on the string is closest to ... 25.2 m/s 4.55 m/s 3.15 m/s 2.27 m/s 1.67 m/s

*January 23, 2011*

**physical**

At a distance of 30 m the noise from the engine of an jet has an intensity level of 130 dB. At this level, you will be in pain and your ears will hurt. That's why this intensity is know as the "pain threshold". How far do you have to be from a jet (total distance...

*January 23, 2011*

**Trigonometry **

showed me below where ??

*January 23, 2011*

**Trigonometry **

Express the following in radians: a.135degrees. --> (pi/180)*135 = how can i end up with a fraction answer?? b.-15degrees. --> (pi/180)* -15 = same here what are the steps to do next to get a fraction answer.

*January 23, 2011*

**ALGEBRA**

What exactly is "help properly"? He/she explained how to do this problem. Do you expect the problem to be done for you? "You need to attempt these questions yourself if you expect to learn anything." This is a true statement.

*January 23, 2011*

**MATH**

Do you mean, x^4 - x^2 - 6 This was answered the first time you posted it. I pasted the answer here for you. (x^2 - 3)(x^2 + 2)

*January 23, 2011*

**geometry**

una piramide cuadrangular?

*January 23, 2011*

**beginning algebra**

I got 1 +or- the sqrt 90/2

*January 22, 2011*

**beginning algebra**

Solve the equation (u-1)^2=2u^2-3u-29 for u .

*January 22, 2011*

**College Algebra**

Just not good at division

*January 22, 2011*

**College Algebra**

Divide. (9x^3-10+19+6x^4)/(-2x^2+3x-3) Write your answer in the form Q(x)+ R(x)/ -2x^2+3x-3, where Q(x) is the quotient and R(x) is the remainder.

*January 22, 2011*

**beginning algebra**

Solve the equation (u-1)^2=2u^2-3u-29 for u .

*January 22, 2011*

**beginning algebra**

Find the least common multiple of the two expressions 15v^4w^8 and 9vw^5x^4

*January 22, 2011*

**beginning algebra**

Solve for y. Write answer in simpliest form. 2+7/y=3/5

*January 22, 2011*

**math**

P = 2L + 2W W = 25 L = 50 P = 2(50) + 2(25) P = ? solve

*January 20, 2011*