Im also doing this problem wrong... 2^3V4(2^3V54-^3Vx) is equal to 16, then x is equal to... I simplified the 2^3V4 and got 64, and just got stuck.
A square is inscribed in a circle. If the area of the circle is 144(pi)cm*squared* --sorry the square root thing isnt showing up. Then the exact perimeter of the square is... I really dont get how to solve this, but the answer is supposed to somehow be 48V2 cm
Ok, so I missed out the 4, and ended up writing 7V2. That missing out the 4 messed up everything, and yup you are right, thanks a bunch =D
Dont know if the radicals will show up.. 2ã3(ã243-2)-ã2(5+7ã2) Can be expanded and simplified to the form p + qã2 + rã3. the value of p + q + r is_____ First I simplified the V243 and I got 9V3 2V3(9...
Oh Ok, so yeah the book is wrong, I checked again, and yeah that negative sign is an error in the book. That would have totally messed me up.
Thanks, so that - does not matter, cause Im supposed to add all of them, and the answer I got was 37 which is the exact same answer in my textbook.
Reiny could you please check my Calculus post below, it says Calculus--Reiny.
But all a,b,c and d are supposed to be positive integers, and I looked over this again, and its supposed to simplify into aVb-cVd, so that means that the negative sign is supposed to be there, but the integer C is not negative.
V = Radical The expression: V2(V5-12V3)-V3(V8-2V30) can be written in simplest form aVb-cVd, where a, b, c ,d are all positive integers. The value of a + b + c + d is ________. So after solving all this out, I arrived at 7V10 - 14V6. That - is beside the 14, and Im only suppos...
About rationalizing denominator, is it true that you can't always multiply by the same square root denominator to get a perfect square?
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