I think I already explained this to you down below.
1/a+1 + 1/a-1 I solved this out by multiplying the (a+1) by (a-1) and multiplying (a-1) with (a+1) To get (a+1)(a-1) as the denominator. Then I did the same with the numerators and got this: 1(a-1) + 1(a+1)/(a+1)(a-1) And I got 2a/(a+1)(a-1) But still sometimes this process co...
Multiplication of Rational Numbers: 1. Consider the factors of the numerator and of the denominator. 2. If there are factors common to the numerator and the denominator, reduce by dividing out the common factors. 3. Multiply all the numerators together and multiply all the den...
I'll give you a list steps to follow: 1. Determine the lowest common denominator (LCD) for the rational numbers. 2. Express each rational number as an equivalent rational number with the LCD as the denominator. 3. Combine the rational numbers by adding/subtracting numerato...
Thank you and yeah nonpermissible is another word for restrictions.
Thank you so much Damon :)
Simplify. State the nonpermissible values. (3t^2+3t-6/2t^2-2t-4)(4t^2+4t-24/3t^2+6t-9) This is the way I tried solving this: 3t(t-1)6(t-1)/2t(t-1)4(t-1)*4t(t-2)12(t-2)/3t(t+1)9(t-1) (3)(t)(t-1)(2)(3)(t-1)/(2)(t)(t-1)(2)(2)(t-1)*(2)(2)(t)(t-2)(2)(2)(3)(t-2)/(3)(t)(t-1)(3)(3)(t-...
Thanks Damon =)
Calculus - Reiny, Friday, December 23, 2011 at 6:59pm I read that as (4a^2-1)/(4a^2-16) * (2-a)/(2a-1) , my brackets are necessary = (2a+1)(2a-1)/( 4(a+2)(a-2) * (2-a)/(2a-1) the (2-a)/(a-2) are opposite, they will give you the -1 so.. = -(2a+1)/(4(a+2)) , again you have to us...
Thanks Reiny =) But I to get everything clear, the 2-a and the a-2 cancel right? After I cancel those I am left with (2a+1) as the numerator:S Sorry I am just confused. Also did you factor out the 2a+4 and 2a-4 to get 4(a+2)(a-2)? Could you please explain step by step?