# Posts by :(

Total # Posts: 12

**Physics**

:( physics:(

**Physics**

To ward off oceanic invaders, a cannon is placed 10 meters from the water's edge, pointing out at sea. The cannon is capable of firing a projectile at a maximum velocity of 100m/s. a) what is the maximum firing range of the cannon? b)If the cannon was placed on a cliff ...

**Calculus**

Let f(x)=1/x. Compute the difference quotient for f(x) at x=1 with h=0.3 I know that the formula for difference quotient is (f(x+h)-f(x))/h, but I am not sure how I am supposed to plug this in. I have tried a few ways but webworks says that the answer is wrong every time.

**Physics**

A ball with mass m = 0.210 kg and kinetic energy K1 = 2.97 J collides elastically with a second ball of the same mass that is initially at rest. After the collision, the first ball moves away at an angle of = 30.6° with respect to the hori- zontal, as shown in the figure. ...

**help me pls :(**

ms sue pls help me explain to me how you do it pls

**help me pls :(**

can u help me with 1-3 explainto me pls i don't get it

**help me pls :(**

1. m – 7 < 6 (1 point)m < –13 m < 1 m < –1 m < 13 2. n – 8 > 5 (1 point)n > 13 n > 3 n > –3 n > –13 3. p + 5 < 10 (1 point)p < –15 p < 5 p < 15 p < –5 4. The science class is taking a trip to ...

**7th grade science bobpursley or Ms. sue please**

i need help too DX

**chemistry**

Consider the following reaction: 2H2S (g) + 3O2 (g) --> 2SO2 (g) + 2H2O (g) If O2 was the excess reagent, 1.3 moles of H2S were consumed, and 18.7 g of wat were collected after the reaction has gone to completion, what is the percent yield of the equation?

**Physics**

A 570.0 g ball moves in a vertical circle on a 103.0 cm-long string. If the speed at the top is 4.30 m/s, then the speed at the bottom will be 10.65 m/s. (you'll learn how to show this Chapter 10.) What is the gravitational force (in N) acting on the ball? What is the ...

**math**

i mean: 3x-y=9 2x+y=6 x-2y=0 3x+y=0

**math**

-3x-y=9 2x+y=6 -x-2y=0 3x+y=0 tell me how to do one and i will try to do the other one..(use the substitutional method)

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