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April 18, 2014

Homework Help: Math: Trigonometry

Recent Homework Questions About Trigonometry

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Precalculus with Trig
Rewrite the following expression as an algebraic expression in x: cos(arcsin(x))
Sunday, April 7, 2013 at 1:38pm

11th grade math
If you have trig as a resource, then the altitude h from F to DE is h = 10 sin 50° = 7.66 Then, the area a = 14*h
Sunday, April 7, 2013 at 1:07pm

trig
evidently 195 = P-45
Saturday, April 6, 2013 at 4:00pm

trig
If it is given that tan(A-B)=tanA-tanB/1+tanAtanB and tanP-1/1+tanP=tan195 find p
Saturday, April 6, 2013 at 3:44pm

trig
Indoor steps generally are steeper and have smaller landings. A staircase has a 9 inch vertical rise per step to get to the second floor of a house. If the angle of elevation is 36.8 degrees and there are 16 feet of horizontal space total for each of the landings combined, ...
Wednesday, April 3, 2013 at 1:34pm

Trig
csc^2 = 1+cot^2, so you have sin^2 b csc^2 b = 1
Wednesday, April 3, 2013 at 11:04am

Trig
Sin^2 b(1 +cot^2 b) =1
Wednesday, April 3, 2013 at 10:14am

calculus
converting your directions to standard trig notation (x-axis is zero, counterclockwise) S 30° W ----> 240° S 20° E ----> 290° 300 km/h in S30W ---> vector(400cos240,400sin240) 50 km/h in S20E --> vector (50cos290 , 50sin 290) resultant = (400cos240...
Tuesday, April 2, 2013 at 4:28pm

trig
I have a triangle with sides 60 and 400 and the contained angle is 70° let the resultant be R R^2= 60^2 + 400^2 - 2(60)(400) cos70° = 147183.0331 R = 383.64 mi/h finding the angle opposite the 70° sinØ/60 = sin70/R sinØ = .14696.. Ø = 8.45°...
Monday, April 1, 2013 at 9:53pm

trig
An airplane pilot wishes to maintain a true course in the direction 250° with a ground speed of 400 mi/hr when the wind is blowing directly north at 60 mi/hr. Approximate the required airspeed and compass heading
Monday, April 1, 2013 at 9:33pm

Trig
I will assume you mean 1/(1-sinx) + 1/(1+sinx) = 2 sec^2 x LS = (1 + sinx + 1 - sinx)/((1-sinx)(1+sinx)) = 2/(1-sin^2 x) = 2/cos^2 x = 2sec^2 x = RS
Sunday, March 31, 2013 at 9:41pm

Trig
Verify that each trigometric equation is an identity. 1/1-sinx + 1/1+sinx = 2 sec^2x
Sunday, March 31, 2013 at 9:16pm

math
sketch a right-angled triangle in quadrant I , labeling the two acute angles A and B then A+B = 90° or π/2 and B = (90°-A) or (π/2 - A) label the horizontal x and the vertical side y sinA = y/r cosB = y/r so sinA = cosB = cos(π/2 - A) or in the ...
Sunday, March 31, 2013 at 8:44pm

Math: Solving Trig Equation
there's no equation the expression is equivalent to (9tan^2-9sec^2)/tan and since sec^2-tan^2=1, that's just -9/tan
Sunday, March 31, 2013 at 5:04am

Math: Solving Trig Equation
9tan (x) - 9 sec^2 (x)/ tan (x)
Sunday, March 31, 2013 at 1:16am

math
1. sin (π/6) csc (π/6) = sin (π/6) * 1/sin (π/6) = 1 2. sec(π/3)cos(π/3) + tan(π/3)cot(π/3) I think for both questions, they want you to realize that if you multiply a trig function by its reciprocal function you get 1 = 1 + 1 = 2
Saturday, March 30, 2013 at 2:26pm

Trig
Thank you very much!
Thursday, March 28, 2013 at 5:20pm

Trig
note that the problem was sin^2(67.5)-cos^2(67.5) = -cos(135) my hint was not intended to make you forget what was originally asked. :-) And, I know lots of folks hate roots in the denominator, but I see no reason why √2/2 is better than 1/√2. Just mt preference
Thursday, March 28, 2013 at 3:20pm

Trig
How exactly do you get there though? I tried to follow a similar homework problem and got: = (cos^2)*(67.5deg) - (sin^2)*(67.5deg) = cos(2*67.5deg) = cos135deg = -√2/2
Thursday, March 28, 2013 at 3:13pm

Trig
well, cos 2x = cos^2 x - sin^2 x, so what do you think? If you end up with 1/√2 you are correct.
Thursday, March 28, 2013 at 1:49pm

Trig
Simplify (sin^2)*(67.5deg) - (cos^2)*(67.5deg) and then evaluate exactly.
Thursday, March 28, 2013 at 1:46pm

Trig
Since sin = -12/13 in QIV, cos = 5/13 sec x/2 = 1/cos(x/2) = √(2/(1+cosx)) = √(1/(1+5/13)) = √(2/(18/13)) = √(26/18) = √13/3
Thursday, March 28, 2013 at 1:29pm

Trig
Use a half-angle identity to find the exact value for sec(x/2) if sinx = -12/13 ; 3pi/2 < x < 2pi
Thursday, March 28, 2013 at 12:27pm

trig
swagger.
Wednesday, March 27, 2013 at 9:13pm

Katlyn Krystien - Math
Please stick to one name, don't switch names from one post to another. this question is similar to the one you posted as Katlyn since the radius is 7 m, a = 7 remember : period = 2π/k , where k is the coefficient of your trig function ... sin (kt) so 2π/k = 16 ...
Monday, March 25, 2013 at 7:05pm

Trig
draw the circle and the line at the given angle. The intersection will give you a point (x,y). in this case, the line is at an angle of 45 degrees, in QIII, where y=x. tan (-3pi/4) = (-1√2)/(-1/√2) = 1
Monday, March 25, 2013 at 5:09pm

Trig
How do I use the unit circle to evaluate tan(-3pi/4)
Monday, March 25, 2013 at 5:03pm

trig
Find the first two terms a_1 =5 and an=3a _n-1+2
Sunday, March 24, 2013 at 9:50pm

Trig
tanA = sinA/cosA so tanA / sinA = (sinA/cosA)/sinA = 1/cosA = secA
Sunday, March 24, 2013 at 8:17pm

Trig
prove that tanA divided by the sinA equals the secA
Sunday, March 24, 2013 at 8:02pm

Trig needs help
Indicate your specific subject in the "School Subject" box, so those with expertise in the area will respond to the question.
Saturday, March 23, 2013 at 1:14pm

Trig needs help
Indicate your specific subject in the "School Subject" box, so those with expertise in the area will respond to the question.
Thursday, March 21, 2013 at 1:25pm

mathematics
I assume you want "exact" answers for these, the usual kind of request for these types of questions. All your given angles are combinations of the standard angles of 30, 45, 60 etc e.g. 75 = 45+30 15 = 45-30 105 = 60+45 You should also have memorized or have quick ...
Thursday, March 21, 2013 at 9:49am

trig
make a sketch labeling the height of the mountain as PQ, with P as the top of the mountain. Label the 2 points of observation as A and B, with B the closer point, In triang ABP, angle A = 35°15' angle ABP = 180 - 50°25' = 129°35' then angle APB = 15°...
Wednesday, March 20, 2013 at 3:29pm

trig
Sandra wants to find the height of a moutain. From her first location on the ground, she finds the angle of elevation to the top of the mountain to be 35 degrees 15 minutes. After moving 1000 meters closer to the moutain on level ground, she finds the elevation to be 50 ...
Wednesday, March 20, 2013 at 1:28pm

Trig
A is in QIII, so cosA = -2/3 tan(A/2) = (1-cosA)/sinA = (5/3)/(-√5/3) = -√5
Wednesday, March 20, 2013 at 11:32am

Trig
If 180<A<270 and sinA= -radical(5)/3, find tan(1/2)A.
Tuesday, March 19, 2013 at 11:36pm

trig
I keep trying to find the power reducing formula for sin^4(x), but I can't seem to get all the fractional parts correct. The answer I should be getting is: sin^4(x)=(1/8)cos4x-(1/2)cos2x+(3/8) I can only get this far knowing feeling confident. When I go further I start ...
Tuesday, March 19, 2013 at 9:57pm

Math
What is the inverse trig function cotangent of square root of 3/3? What is the value?
Tuesday, March 19, 2013 at 5:19pm

Trig
True or False: For a trignometric function, y = f(x), then x = f^-1(y). Explain your answer. Thanks.
Tuesday, March 19, 2013 at 4:51pm

Trig
True or False: For a one-to-one function, y = f(x),then x = F^-1(y). Explain your answer. Please help.
Tuesday, March 19, 2013 at 4:46pm

Trig
draw the triangles and you will see that tan(s) = 12/5 tan(t) = 4/3 Now just plug in your sum formula: tan(s+t) = (tan s + tan t)/(1 - tan s * tan t)
Tuesday, March 19, 2013 at 3:28pm

Trig
What is the exact value of tan(s+t) if sin(s+t)=56/65. And cos(s)=5/13 and sin(t)=4/5. Everything is in the first quadrant
Tuesday, March 19, 2013 at 3:22pm

Trig
A pulley with a diameter of 24 inches is driven by a belt which is moving 1045 ft/min. How many revolutions per minute are made by the pulley?
Tuesday, March 19, 2013 at 3:16pm

Trig
13sinx+5=0 sinx = -5/13 sinx is negative in QIII,QIV, but we want the QIII value. so, cosx = -12/13 sin2x = 2sinx cosx = 2(-5/13)(-12/13) = 120/169
Monday, March 18, 2013 at 3:53pm

trig
sin π/6 = 1/2 cos π/6 = √3/2 so, cos π/12 = √(1+√3/2) / 2 sin π/24 = √(1-cos π/12) / 2 = 1/2 √(1 - (√(1+√3/2) / 2)) = 1/2√2 √(2 - √(1+√3/2)) = 1/4 √(2√2 - √(1+√3...
Monday, March 18, 2013 at 9:50am

Trig
How do I find the exact value of sin (pi/24)?I am crying
Sunday, March 17, 2013 at 6:03pm

trig
Do I subtract ?
Sunday, March 17, 2013 at 5:51pm

trig
I really need help . I find this hard Steve .
Sunday, March 17, 2013 at 5:43pm

trig
I applied the half angle formula for sin and I got the square root of 2 minus the square root of 3 divided by 2 . and for cos I got thesqurof 2 plus thesqr of3divided by 2 .
Sunday, March 17, 2013 at 5:40pm

trig
I am not under standing could you show me ? to tell me ?
Sunday, March 17, 2013 at 5:36pm

trig
sin π/6 = 1/2 cos π/6 = √3/2 sin(x/2) = √(1-cosx) / 2 cos(x/2) = √(1+cosx) / 2 apply the half-angle formula twice to get sin π/24 = 1/2 √(2-√(2+√3))
Sunday, March 17, 2013 at 5:24pm

trig
How do I find the exact value of sin (pi/24)?
Sunday, March 17, 2013 at 5:11pm

Trigonometry
Hi, I really need help in understanding how to solve trig equations. How do you solve this equation? Solve the equation on the interval 0 < or equal to x < or equal to 2pi. sinx = (square root of 3)/2 I appreciate your help. Thank you!
Sunday, March 17, 2013 at 2:18pm

trig
h/100 = sin 40°
Friday, March 15, 2013 at 10:30am

trig
A pole is braced with a wire from the top of a pole to the ground. The wire is 100 feet long and makes an angle of 40° with the ground. Find the height of the pole.
Friday, March 15, 2013 at 10:03am

trig
Draw a diagram. If the nearer point is a distance x from the base of the mountain, then the height h can be figured from h/x = tan 43° h/(x+235) = tan 30° x = h/tan 43° x = h/tan 30° - 235 h/tan 43° = h/tan 30° - 235 h = 235/(cot30° - cot43°) h...
Thursday, March 14, 2013 at 12:42pm

trig
A road runs from the base of a mountain. From two points 235 meters apart on the road, the angles of elevation to the top of the mountain are 43 and 30. how high above the road is the mountaintop?
Wednesday, March 13, 2013 at 10:45pm

trig
A road runs from the base of a mountain. From two points 235 meters apart on the road, the angles of elevation to the top of the mountain are 43 and 30. how high above the road is the mountaintop?
Wednesday, March 13, 2013 at 10:29pm

trig
A road runs from the base of a mountain. From two points 235 meters apart on the road, the angles of elevation to the top of the mountain are 43 and 30. how high above the road is the mountaintop?
Wednesday, March 13, 2013 at 10:29pm

trig
2 csc 2θ cos 2θ = 2cot 2θ = 2/tan 2θ = 2(1-tan^2 θ)/(2tanθ) = 1/tanθ - tan^2θ/tanθ = cotθ - tanθ
Wednesday, March 13, 2013 at 5:19pm

Trig
tan34 = Y/X = Y/37. Y = 37*tan34 = 25 Ft. Ht. = Y + 5.3 = 25 + 5.3 = 30.3 Ft.
Wednesday, March 13, 2013 at 4:39pm

trig
no figure. Go figure.
Wednesday, March 13, 2013 at 4:23pm

trig
cos è = 0.9659 A = ? H = 20
Wednesday, March 13, 2013 at 4:19pm

trig
A math tutor told me to FOIL it. This is just a hint, or starting point because I don't know for sure.
Tuesday, March 12, 2013 at 7:01pm

Trig
so, what's the problem? Divide the equation in two and make new equations.
Tuesday, March 12, 2013 at 3:43am

Trig
a. Form a pair of simultaneous equations by letting y1 equal the left side and y2 equal the right side of sqrt 5-x=1. b.Repeat part (a) with the equivalent equation sqrt 5=x+1 c. Repeat part (a) with the equivalent equation sqrt 5-x-1=0
Tuesday, March 12, 2013 at 1:56am

math
My sketch looked like this: Side view, A vertical wall, T is the top and V is the bottom of the TV, Q is the point along a horizontal line level with her eyes, which I called P (we want that distance PQ) so we have TV = 30, and VQ = 6 Let PQ = x let angle TPV = A ---. that'...
Tuesday, March 12, 2013 at 12:08am

Maths
right-angled triangle trig . tan 28° = 76/x x = 76/tan28 = appr 142.9 m
Monday, March 11, 2013 at 10:13am

Trig
two sin x < 0 in QIII, QIV
Monday, March 11, 2013 at 2:39am

Trig
Whats the height of a flagpole if a student stand 37feet from it and determines the angle of elevation to be 34degrees and her eyes are 5.3 feet from the ground(round to the nearest whole number)
Monday, March 11, 2013 at 2:06am

Trig
the number of solutions of sin x= -sqrt3/2 for x between 0 and 2pi
Monday, March 11, 2013 at 2:02am

Trig
assuming the angle is to the top of the pole, the height h = 5.3 + 37 tan 34°
Monday, March 11, 2013 at 1:16am

Trig
the height of a flagpole if a student stands 37 feet from it and determines the angle of elevation to be 34 degrees and her eyes are 5.3 feet from the ground.
Monday, March 11, 2013 at 12:46am

Trigonometry
g(3) = 5(3)+1= 16 h(g(3)) = h(16) = 2(16-7) = 18 why do you call this trig ?
Sunday, March 10, 2013 at 5:27pm

trig
An airplane flying at 550 mph has a bearing of N 58 E. After flying for 1.5 hours, how far north and how far east has the plane traveled from its point of departure?
Wednesday, March 6, 2013 at 7:54pm

trig
182 * pi/180
Wednesday, March 6, 2013 at 3:58pm

trig
The radian measure of an angle of 182 degrees is ?
Wednesday, March 6, 2013 at 3:43pm

trig
cos(2x) = cos(x+x) = cosx cosx - sinx sinx = cos^2(x) - sin^2(x) = cos^2(x) - (1-cos^2(x)) = 2cos^2(x) - 1
Monday, March 4, 2013 at 3:29pm

trig
use an angel sum identity to verify cos2theta = -2cos^@-1
Monday, March 4, 2013 at 3:11pm

Trig
help please!: (sinx + sin2x +sin3x) / (cosx + cos2x + cos3x) = tan2x
Sunday, March 3, 2013 at 9:05pm

trig
cos(2x+4h)-cos(2x+2h)=?
Sunday, March 3, 2013 at 8:23pm

trig
cos(2x+4h)-cos(2x+2h)=?
Sunday, March 3, 2013 at 8:23pm

trig
cos(2x+4h)-cos(2x+2h)
Sunday, March 3, 2013 at 8:22pm

Algebra and Trigonometry
Trig - Damon, Sunday, March 3, 2013 at 6:24pm East speed = 100 + 200 sin 45 = 241 North speed = 200 cos 45 = 141 speed = sqrt( 141^2 + 241^2) = 279 mph tan east of north = 241/141 so angle east of north = 60 degrees
Sunday, March 3, 2013 at 6:28pm

Trig
East speed = 100 + 200 sin 45 = 241 North speed = 200 cos 45 = 141 speed = sqrt( 141^2 + 241^2) = 279 mph tan east of north = 241/141 so angle east of north = 60 degrees
Sunday, March 3, 2013 at 6:24pm

Trig
A plane if flying at 200 mph with a heading of 45 degrees and encounters a wind of 100 mph from the west. What is the resulting velocity and heading?
Sunday, March 3, 2013 at 6:13pm

trig
10sinB=sinB True if sinB=0 so, where does that happen?
Friday, March 1, 2013 at 4:17pm

Trig needs help
Indicate your specific subject in the "School Subject" box, so those with expertise in the area will respond to the question.
Friday, March 1, 2013 at 1:05pm

trig
10sinB+5 = sinB+5
Friday, March 1, 2013 at 12:51pm

trig
make a sketch of your triangle since sinØ = opposite /hypotenuse = 5/13 opposite = 5 and hypotenuse = 13 by Pythagoras: x^2 + 5^2 = 13^2 x^2 +25 = 169 x^2 = 144 x = ± 12 , but in quadrant II, x = - 12 sinØ = 5/13 , cscØ = 13/5 cosØ = -12/13...
Thursday, February 28, 2013 at 11:10pm

trig
If sin theta is equal to 5/13 and theta is an angle in quadrant II find the value of cos theta, sec theta, tan theta, csc theta, cot theta.
Thursday, February 28, 2013 at 10:44pm

Trig
N32.47E
Thursday, February 28, 2013 at 8:05pm

trig
Incomplete.
Thursday, February 28, 2013 at 3:40pm

trig
well, what's arctan(-28/45?) -31.9 degrees. So, That's 2x You didn't specify quadrant, but tan x is negative in QII and QIV
Thursday, February 28, 2013 at 10:16am

trig
solve tan2x = -28/45 Thank you
Thursday, February 28, 2013 at 10:11am

trig
A population of wolves in a country is represented by the equation p(t)=80(0.98)^t, where t is the number of years since 1998. Predict the number of wolves in the population in the year 2008. how many years will it take for the population of wolves to reach 500?
Tuesday, February 26, 2013 at 8:15pm

trig
A population of wolves in a country is represented by the equation p(t)=80(0.98)^t, where t is the number of years since 1998. Predict the number of wolves in the population in the year 2008. how many years will it take for the population of wolves to reach 500?
Tuesday, February 26, 2013 at 8:14pm

Trig
You have two wires of length 50 and two wires of length 10√13 add them up
Tuesday, February 26, 2013 at 10:42am

Trig
Four wires support a 40-meter radio tower. Two wires are attached to the top and two are attached to the center of the tower. The wires are anchored to the ground 30-meters from the base of the tower. What is the total length of wire needed?
Tuesday, February 26, 2013 at 10:36am

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