Recent Homework Questions About Trigonometry
A = 1/2r^2 θ A = 1/2(6)^2(pi/2) A = 1/2(36)(pi/2) A = 9pi cm^2
Saturday, June 8, 2013 at 11:17pm
Find the area of a sector with the given central angle θ in a circle of radius r. θ = 90°, r = 6 cm
Saturday, June 8, 2013 at 11:03pm
Math Trig Find Quadrant I II III IV
In which quadrant is the terminal side of angle A? A = -5π/6 a. Quadrant III b. Quadrant I c. Quadrant II d. Quadrant IV
Saturday, June 8, 2013 at 10:49pm
on all these, they are the same thing. I am not certain how you see 4,5 as different. look here: http://www.sosmath.com/trig/Trig5/trig5/trig5.html Print that out. Notice the sum to product formulas. If you were my student, I would have you write each formula on a flash...
Monday, June 3, 2013 at 9:12pm
try doing it ur self
Monday, June 3, 2013 at 8:45pm
Then recall that tanx >0 in QI,QIII
Friday, May 31, 2013 at 11:06am
tanx - √3 = 0 tanx = √3 At this point it helps to have memorized the trig ratios for the few angles where at least one of them is rational. In this case, recall that sin60° = √3/2 cos60° = 1/2 tan60° = √3
Friday, May 31, 2013 at 11:06am
what are the values of the angle in the interval 0<the angle<360 that satisfy the equation tan beta- radical 3=o
Thursday, May 30, 2013 at 10:57pm
using x to avoid copy/paste of ø, m sinx + 2sinx + 2m cosx - cos x = 2m+1 (sinx + 2cosx)m + (2sinx - cosx) = 2m+1 If these are identical, then sinx + 2cosx = 2 2sinx - cosx = 1 sinx = 4/5 cosx = 3/5 tanx = 4/3
Wednesday, May 29, 2013 at 10:46am
If (m+2)sin ø + (2m-1)cos ø = 2m+1 then tan ø is equal to
Wednesday, May 29, 2013 at 2:54am
the velocity has two components: x: 36 cos70° = 12.31 y: 36 sin70° = 33.83 now recall that the x-speed is constant, and the height y = 33.8t - 16t^2 now solve for the various requirements
Tuesday, May 28, 2013 at 2:50pm
A ball is tossed up in the air at an angle of 70 degrees with the horizontal and with an initial velocity of 36 ft/sec. What is the position of the ball 1 second after it is released? When will the ball hit the ground? What is the maximum height the ball will reach? How far in...
Tuesday, May 28, 2013 at 2:47pm
My sketch is a triangle with sides 16, 24 and 28 , and I am looking for the angle Ø opposite the 28 by cosine law 28^2 = 16^2+24^2 - 2(16)(24)cosØ 768cosØ = 48 cosØ = 48/76 Ø = 50.8°
Monday, May 27, 2013 at 8:23am
A security camera needs to be set so that the angle of view includes the area from a doorway to the edge of a parking lot.The doorway is 16m from the camera. the edge of the parking lot is 24m for the camera. the doorway is 28m from the edge of the parking lot. what angle of ...
Monday, May 27, 2013 at 12:49am
in the diagram below.A,B and C are three points in the same horizontal plane and AD is a vertical tower.AC=AB=x and DC=DB.the angle of elevetion of D from C is alpha and DB^C=theta 1.express DC in terms of x trigonometry value of alpha 2.prove that BC=2xcostheta/cos alpha
Sunday, May 26, 2013 at 10:54am
please am stucked help me.in the diagram below.A,B and C are three points in the same horizontal plane and DC is a vertical tower.AC=AB=x and D^C=DB.the angle of elevation of D from C is alpha and DB^C=theta
Sunday, May 26, 2013 at 7:31am
How to get quick responses to your math questions
Math is a wide subject, ranging from K to 11, college and university. Then there is algebra, trigonometry, geometry, arithmetic, calculus, number theory, ... etc. Not all teachers answer all math questions (many do). If you would give a little more detail on which branch of ...
Saturday, May 25, 2013 at 9:45am
So on the Cartesian plane, it is in the fourth quadrant, with x-y as (900,-500). Atan(-500/900)= -29° approximately. So the bearing is S61°E.
Saturday, May 25, 2013 at 6:25am
A hiker walks 900m east and 500m south .Find the bearing of the finishing position from the staring point?
Saturday, May 25, 2013 at 3:44am
you are exactly right tan(4x) = 2tan2x/(1-tan^2(2x)) so, cot(4x) is the reciprocal, as needed.
Thursday, May 23, 2013 at 3:17pm
okay, thank you, would that still apply if it was cot4x=1-tan^2(2x)/2tan2x? because ive got the right side for this one but the cot4x is throwing me off, how would you solve that side?
Thursday, May 23, 2013 at 3:13pm
just apply the double-angle formula for tan(2x) and take the reciprocal
Thursday, May 23, 2013 at 3:02pm
TRIG Identities, Gr. 12: Prove: cot4x=1-tan^2x/2tan2x
Thursday, May 23, 2013 at 2:56pm
TRIG Help help help test tommarow
(h+1250)/1150 = tan 52°
Thursday, May 23, 2013 at 10:28am
TRIG Help help help test tommarow
A TV tower stands on top of the Empire State building. From a point (on the ground) 1150 feet from the base of the building, the angle of elevation to the top of the TV tower is 52 degrees. If the building is 1250 feet tall, what is the length of the TV tower?
Wednesday, May 22, 2013 at 6:48pm
what is 40Sin65? This is physics? Most folks would call this basic trig functions.
Monday, May 20, 2013 at 5:05pm
Mathematics Ms Sue help
for the building, h/18 = tan 88° for the boat, d/40 = sin 65° for stuff like this, it always helps to draw a diagram, then dig into your box of trig ratios
Monday, May 20, 2013 at 4:21pm
by test time you need to know the "standard" angles with easy-to-recall trig functions 0,π/6,π/4,π/3,π/2 If you know those angles and their trig ratios, you will recall that tan π/3 = √3 Now, recall the bit about principal values of ...
Saturday, May 18, 2013 at 11:47am
Can someone please give me a step by step answer on how to find the complex cube roots of 8(cos(4π/5)+isin(4π/5))? I need to know how to do this for my trig final next week.
Friday, May 17, 2013 at 5:01pm
I don't understand how to convert -3-4i to polar coordinates. I need to know how so I am ready for my trig final next year. Can someone please show me step by step how to solve this? Thanks
Friday, May 17, 2013 at 3:31pm
Can someone please show me step by step how to calculate the modulus and the argument for these complex numbers? I have a trig final next week and I am trying to finish this study guide so I am prepared. Thank you so much! If you can, please show my how you get the answer so I...
Friday, May 17, 2013 at 9:11am
Can you please help me with this question on my study guide for my trig final? Thanks! I'd also appreciate if you can check out my other postings and check my work for some other study guide questions. I want to make sure I'm ready for my final. :) 4. Transform each ...
Thursday, May 16, 2013 at 11:29am
Can you check my work, please? This is for a trig study guide for my final next week. I'd like to know if I'm doing this right. :) 2. The polar coordinates of a point are given. Find the rectangular coordinates of each point. a. (5,(π / 4)) b. (-2,(π / 6)) ...
Thursday, May 16, 2013 at 11:26am
Can you please help me with this question on my study guide for my trig final? Thanks! I'd also appreciate if you can check out my other postings and check my work for some other study guide questions. I want to make sure I'm ready for my final. :) 3. The rectangular ...
Thursday, May 16, 2013 at 11:13am
sinx cosy(cotx tany-1) sinx cosy cosx/sinx siny/cosy - sinx cosy cosx siny - sinx cosy sin(y-x)
Wednesday, May 15, 2013 at 2:50pm
Wednesday, May 15, 2013 at 12:16pm
Wednesday, May 15, 2013 at 12:15pm
There are 15,000 endive lettuce seeds in an ounce and 300 seeds in a packet. The seeds cost $1.50 per packet. What is the cost, in dollars, of one ounce of seeds?
Wednesday, May 15, 2013 at 10:04am
5cosA+3 = 0 means that cosA = -3/5 So, A is in QIII sinA = y/r = -4/5 sinA+cosA = -4/5 + -3/5 = -7/5 tanA*sinA = 4/3 * -4/5 = -16/15
Monday, May 13, 2013 at 12:08pm
if 5cos A plus 3=0 and 180<A<360..without using a calculator and with the aid of a diagram,determine the value of 1.1 sinA plus cosA 1.2 tanA *sinA
Monday, May 13, 2013 at 11:52am
4x+y = 84, so y = 84-4x v = x^2 y = x^2(84-4x) = 84x^2 - 4x^3 dv/dx = 168x - 12x^2 = 12x(14-x) dv/dx=0 when x=14 so the box is 14 x 14 x 28
Sunday, May 12, 2013 at 11:53pm
The postal service places a limit of 84 inches on the combined lenght and girth (distance around) of a package to be sen parcel post. What Dimensions of a rectangular box with square cross-section will contain the largest volume that can be mailed?
Sunday, May 12, 2013 at 11:32pm
term(n) = a + (n-1)d 428 = 4 + (n-1)(8) 424 = 8n - 8 432 = 8n n = 54 Draw your conclusion
Sunday, May 12, 2013 at 12:12am
Did you notice that there is a "common difference" of 4 ? so term (n) = .....
Sunday, May 12, 2013 at 12:10am
exactly what don't you understand about this question a = 2 d = 2 n = 100 Sum(100) = .... just use your formula
Sunday, May 12, 2013 at 12:08am
pop = 1.3(1.04)^8 = ..... million
Sunday, May 12, 2013 at 12:07am
term(6) = ar^5 = (-5)(2.5)^5 = -488.28125
Saturday, May 11, 2013 at 11:52pm
in an arithmetic sequence a1=4 and d=8 which term is 428 Show your work
Saturday, May 11, 2013 at 8:32pm
what is the explicit formula for the sequence 3,7,11,15
Saturday, May 11, 2013 at 8:30pm
determine the sum of the first 100 even integers SHOW YOUR WORK
Saturday, May 11, 2013 at 8:29pm
the population of a certain city is 1.3 million people. if the population is growing at the rate of 4% per year what will the population be in 8 years
Saturday, May 11, 2013 at 8:28pm
What is the 6th term of the geometric series with a1= -5 and r=2.5
Saturday, May 11, 2013 at 8:25pm
cos(a+b)/sin(a+b)= cosacosb+sinasinb/sinacosb-cosasinb multiplying and dividing by sinasins then it becomes cotacotb+1/cotb-cota
Saturday, May 11, 2013 at 12:02pm
since sin(n*180) = 0, 2x+60 = n*180 x = n*90 - 30
Friday, May 10, 2013 at 11:48pm
since sin2x+√3cos2x=2sin(2x+60) find the general solution for the equation sin2x+√3cosx=0 thank you
Friday, May 10, 2013 at 7:35pm
simplify sin(540-2x) this is to do with trig
Friday, May 10, 2013 at 10:13am
recall that (a-b)(a+b) = a^2-b^2 sec^2(x) - 1 = tan^2(x) put the fractions over a common denominator and watch the answer fall out.
Thursday, May 9, 2013 at 2:43pm
Verify the identity. (secx + tanx)/(secx - tanx) = (1 + 2sinx + sin(^2)x)/cos(^2)x
Thursday, May 9, 2013 at 2:16pm
Verify the identity. 1/(tanx-secx) + 1/(tanx+secx) = -2tanx
Thursday, May 9, 2013 at 1:54pm
I will do of these, for 135° : assume the axle is 20.5 above the ground height above axle: sin135 = h/20.5 h = 20.5sin135 = appr 14.5 m so height above the ground = 20.5 + 14.5 = 35 for 315° height from axle : sin 315 = h/20.5 h = 20.5sin135 = appr - 14.5 notice the ...
Thursday, May 9, 2013 at 12:33pm
sin45 = height/20.5 height = 20.5sin45 = 14.4 m above the axle
Thursday, May 9, 2013 at 12:20pm
If a ferris wheel with a 20.5 meter radius, how high would one car be from the loding dock at these given angles trveled by the rider?: 90 135 180 225 270 315 405 450 495 and 540?
Thursday, May 9, 2013 at 10:40am
If a ferris wheel has a radius of 20.5meters, how tall would a 45 degree angle be?
Thursday, May 9, 2013 at 10:28am
From the diagram that you made, let the speed of the wind be x, we get by the cosine law x^2= 350^2 + 400^2 - 2(350)(400)cos10° = 6753.829.. x = 82.18 mph by the sine law, the other acute angle Ø is .... sinØ/350 = sin10/82.18 sinØ = .7395.. Ø...
Wednesday, May 8, 2013 at 7:23pm
a plane is flying in the direction of 190 degrees with an air speed of 400 mph. Its course and ground speed are 200 degrees and 350 mph respectively. What is the speed and direction of the wind?
Wednesday, May 8, 2013 at 6:30pm
41/d = tan65°
Wednesday, May 8, 2013 at 2:45pm
The angle of depression as measured from the top of a 41 foot tower to a reference point on the ground is 65 degrees. How far away, to the nearest foot, is the reference point from the base of the tower?
Wednesday, May 8, 2013 at 2:41pm
oops that's (√3+1) / 2√2
Wednesday, May 8, 2013 at 12:03pm
15 = 45-30 cos15 = cos45cos30 + sin45sin30 = 1/√2 * √3/2 + 1/√2 * 1/2 = (√3-1) / 2√2
Wednesday, May 8, 2013 at 12:01pm
Cos(15)=cos(45-30)=cos45cos30-sin45sin30 you should have committed all those to memory.
Wednesday, May 8, 2013 at 12:01pm
Use sum and difference identitites to find the exact value of co 15 degrees
Wednesday, May 8, 2013 at 11:56am
cscx = 8/3 sinx = 3/8 cosx = sqrt [1 - sin^2x] = (sqrt55)/8 cos(2x) = 2 cos^2x -1 = 46/64 = 23/32
Wednesday, May 8, 2013 at 6:01am
Find the exact value of cos (2theta) given csc theta = 8/3 and 0 < theta < pi/2
Wednesday, May 8, 2013 at 1:02am
find the minimum and maximum value of sin100 degree plus cos100 degree
Tuesday, May 7, 2013 at 4:36pm
C = πd = 8π feet. So, the linear speed around the edge is 8π ft * 80/min = 640π ft/min
Tuesday, May 7, 2013 at 9:50am
If a flywheel 8 ft. in diameter rotates at 80 rpm., what is the linear velocity of a point on the outside edge, in feet per minute in terms of pi?
Tuesday, May 7, 2013 at 9:43am
let tan^-1 (3/4) = A and let cos^-1 (9/41) = B then cos[(tan^-1(3/4))+(cos^-1(9/41))] = cos(A + B) = cosA cosB - sinA sinB IF tan^-1 (3/4) = A then tanA = 3/4 ---> sinA = 3/5 and cosA = 4/5, recognize the 3-4-5 right angled triangle if cos^-1 (9/41) = B then cosB = 9/41...
Monday, May 6, 2013 at 10:42pm
Monday, May 6, 2013 at 10:10pm
in QIV, x>0 y<0 csc = -2 so sin = -1/2 cos = √3/2 ...
Monday, May 6, 2013 at 4:42pm
csc thea= -2, quadrant 4. what are the six trig functions?
Monday, May 6, 2013 at 4:17pm
I followed your description , got a right-angled triangle, used Pythagoras, and got x^2 + (2x-6)^2 = (2x-3)^2 x^2 + 4x^2 - 24x + 36 = 4x^2 - 12x + 9 x^2 - 12x + 27 = 0 (x-9)(x-3) = 0 x = 9 or x = 3 if x = 3, the sides would be 3, 0 and 3, which does not make a "slide"...
Sunday, May 5, 2013 at 9:51pm
Sunday, May 5, 2013 at 9:19pm
A slide is attached to the side of a tree house. The height of the tree house is 6 less than double the distance from the baswe of the tree to the base of the slide. The length of the slide is 3 more than the height of the tree house. Find the length of the slide.
Sunday, May 5, 2013 at 9:00pm
LS = cos^4 x + sin^4 x = (cos^2 x + sin^2 x)^2 - (2sin^2 x)(cos^2 x) = 1 - 2(sin^2 x)(cos^2 x) , now recall sin(2x) = 2sinxcosx = 1 - (2sinxcosx)(sinxcosx) = 1 - sin(2x) (1/2)sin(2x) = 1 - (1/2) sin^2 (x) = RS
Sunday, May 5, 2013 at 1:02pm
Sunday, May 5, 2013 at 12:56pm
Sunday, May 5, 2013 at 12:55pm
Prove the identity: cos^4 x + sin^4 x = 1 - (1/2)sin^2 (2x)
Sunday, May 5, 2013 at 11:16am
Saturday, May 4, 2013 at 7:57am
the first term is easy the derivative of 5e^x is 5e^x so the integral of 5e^x is 5e^x now look back at your derivatives of basic trig functions isn't derivative of secx = secxtanx ? We have that term so the integral of secxtanx would be secx thus the integral of -2secxtanx...
Friday, May 3, 2013 at 7:27am
Area = πr^2 d(area)/dt = 2πr dr/dt but dr/dt = 1 m/s d(area)/dt = 2π(30)(1) = 60π m^2/s
Monday, April 29, 2013 at 9:15pm
Suppose oil spills from a ruptured tanker and spreads in a circular pattern. If the radius of the oil spill increases at a constant rate of 1m/s, how fast is the area of the spill increasing when the radius is 30m?
Monday, April 29, 2013 at 8:02pm
Cos^-1 (3/5) = 53 degrees. (This is also close to one radian)
Monday, April 29, 2013 at 12:00pm
There are lots of possibilities here. The easiest is probably a simple parabola, with constant f" = -1 f' = -x + c since f'(2) = 2, 2 = -2 + c c=4 f' = -x+4 f = -1/2 x^2 + 4x + c since f(2) = 3, 3 = -2 + 8 + c c = -3 f(x) = -1/2 x^2 + 4x - 3 Or, you could try ...
Monday, April 29, 2013 at 11:03am
Trig need help
Indicate your specific subject in the "School Subject" box, so those with expertise in the area will respond to the question.
Sunday, April 28, 2013 at 12:20pm
if tanØ = 150/210 Ø = appr 35.5°
Sunday, April 28, 2013 at 12:13pm
at one point in the day, a tower that is 150 feet high casts a shadow that is 210 feet long. Find, to the nearest tenth of a degree, the angle of elevation of the sun at that point
Sunday, April 28, 2013 at 12:10pm
don't have a calculator? If you want to express it in terms of some particular angle, you gotta specify things a it more tightly.
Saturday, April 27, 2013 at 6:25pm
infinitely many x=1 x=2pi+1 x=4pi+1 ... sinx has period 2pi so adding 2pi to any solution gives another solution
Saturday, April 27, 2013 at 6:23pm
run do not walk to your calculator and figure arccos(3/5) = 53 degrees
Saturday, April 27, 2013 at 6:11pm
cos(t)=3/5 determine the exact value of t to the nearest degree
Saturday, April 27, 2013 at 3:39pm