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April 23, 2014

April 23, 2014

**Recent Homework Questions About Trigonometry**

Post a New Question | Current Questions

**trig**

Find all angles in degrees that satisfy the equation. Round approximate answers to the nearest tenth of a degree. tan α = -1.85
*Monday, June 17, 2013 at 12:58am*

**trig**

cos A = 1 / 3 sin A = + OR - sqrt ( 1 - cos A ^ 2 ) sin A = + OR - sqrt ( 1 - ( 1 / 3 ) ^ 2 ) sin A = + OR - sqrt ( 1 - 1 / 9 ) sin A = + OR - sqrt ( 9 / 9 - 1 / 9 ) sin A = + OR - sqrt ( 8 / 9 ) sin A = + OR - sqrt ( 4 * 2 / 9 ) sin A = + OR - sqrt ( 4 ) * sqrt ( 2 ) / sqrt...
*Monday, June 17, 2013 at 12:42am*

**trig**

Use a sum or difference identity to find the exact value. tan 25deg + tan 5deg / 1-tan 25deg tan 5deg
*Monday, June 17, 2013 at 12:40am*

**trig**

Find cos(A+B). cos A=1/3 and sin B=-1/2, with A in quadrant I and B in quadrant IV.
*Sunday, June 16, 2013 at 11:20pm*

**trig**

Since (5,12,13) is a Pythagorean triplet, tan(θ)=5/12. Mathematically, we solve it by: Divide by the right hand side: (5/13)sin(θ)+(12/13)cos(θ)=1 Since (5/13)²+(12/13)²=1, we can put 5/13=sin(φ) 12/13=cos(φ) so sin(φ)sin(&theta...
*Saturday, June 15, 2013 at 11:03am*

**trig**

if 5sin theta + 12cos theta is equal to 13 find the value of tan theta
*Saturday, June 15, 2013 at 8:41am*

**trig**

Sin < 0-----> quadrant 3 and 4 Sec > 0 ---- quadrant 1 and 4 sec = 1/cos Answer is quadrant 4
*Friday, June 14, 2013 at 6:30pm*

**Algebra 3 and trig**

distance is √(177^2 + 265^2) bearing is (90-θ) where tanθ = -265/177
*Thursday, June 13, 2013 at 5:28am*

**Algebra 3 and trig**

An ocean liner is 177 miles due west of lighthouse A. Lighthouse B is 265 miles due south of lighthouse A. Find the distance from lighthouse B to the liner and the bearing of the ocean liner from lighthouse B.
*Wednesday, June 12, 2013 at 6:22pm*

**trig**

sin negative, cosine positive? sin is negative III, IV cosine positive I, III
*Wednesday, June 12, 2013 at 3:27pm*

**trig**

quadrant 1
*Wednesday, June 12, 2013 at 3:19pm*

**trig**

for the given angle, name the quadrant in whihc the terminal side lies. -350deg
*Wednesday, June 12, 2013 at 2:25pm*

**trig**

identify the quadrant in which 0 lies. sin < 0 and sec > 0
*Wednesday, June 12, 2013 at 2:02pm*

**trig**

determine the period of the function. y = cot 4t
*Wednesday, June 12, 2013 at 1:26pm*

**trig**

for (-3,4) x = -3, y = 4 cotØ = x/y = - 3/4
*Tuesday, June 11, 2013 at 8:12pm*

**trig**

cosØ = x/r = 2/7 so x=2 , r = 7 2^2 + y^2 = 7^2 y^2 = 45 = ± 3√5 but we are in IV , so y = -3√5 sinØ = -3√5/7
*Tuesday, June 11, 2013 at 8:11pm*

**trig**

sin positive, quad I and II Tan negative, Quad II, IV Quad II
*Tuesday, June 11, 2013 at 8:04pm*

**trig**

Identify the quadrant in which θ lies. sin > 0 and tan < 0
*Tuesday, June 11, 2013 at 7:59pm*

**trig**

Find the trigonometric function value of angle θ. Cos θ = 2/7 and θ is in quadrant IV. Find sin θ.
*Tuesday, June 11, 2013 at 7:30pm*

**trig**

The point (-3, 4) is on the terminal side of angle θ in standard position. Find cot θ.
*Tuesday, June 11, 2013 at 7:24pm*

**trig**

angular velocity: 1st wheel : 2π rad/30 sec = π/15 rad/sec 2nd wheel : 2π radians/15 sec = 2π/15 rad/sec linear velocity 1st wheel: circumference = 2π(20) = 40π ft linear velocity = 40π/30 ft/sec = 4π/3 ft/se 2nd wheel: circumf = 20π...
*Tuesday, June 11, 2013 at 6:42pm*

**trig**

construct your triangle in the third quadrant, using Pythagoras, you know r^2 = (-2)^2 + (-3)^2 = 13 r = √13 then cosØ = x/r = -2/√13 , then sec Ø = -√13/2
*Tuesday, June 11, 2013 at 6:37pm*

**trig**

Given that θ is an angle in standard position whose terminal side contains the given point, provide the exact value of the indicated function. (-2, -3) Find sec θ.
*Tuesday, June 11, 2013 at 4:31pm*

**trig**

ferris wheel one has a 40ft diameter, revolves once every 30 seconds and is 5ft above ground. Ferris wheel two has a diameter of 20feet, revolves once every 15seconds and is 2 feet above the ground. each angular velocity?? each linear velocity??
*Tuesday, June 11, 2013 at 3:26pm*

**math - trig**

You know that sinØ = y/r cosØ = x/r tanØ = y/x cscØ = r/y etc so in any point the first coordinate is the x, the 2nd is the y 1. for (-12, -5) you would be in quadrant III x = -12, y = -5 use Pythagoras, x^2 + y^2 = r^2 ( where we keep r always ...
*Tuesday, June 11, 2013 at 8:52am*

**math - trig**

1. Find csc A, cos A and tan A of an angle A whose terminal side contains (– 12, – 5). 2. Find sin X, sec X and cot X of an angle X whose terminal side contains (– 3, 5).
*Tuesday, June 11, 2013 at 4:11am*

**Trig**

I get 252.717 or 253
*Monday, June 10, 2013 at 11:36pm*

**Trig**

I got 263.
*Monday, June 10, 2013 at 8:55pm*

**Trig**

did you make a sketch? I have , top of tower -- P , bottom of tower Q closer point A farther point B In triangle PBA angle B = 29°5' angle BAP = 142°55' angle BPA = 8° AB = 120 by sine law: PA/sin 29°5' = 120/sin 8° PA = 419.1165 now triangle ...
*Monday, June 10, 2013 at 8:29pm*

**Trig**

The angle of elevation from a point on the ground to the top of a tower is 37deg5'. The angle of elevation from a point 120 feet farther back from the tower is 29deg5'. Find the height of the tower (to the nearest foot).
*Monday, June 10, 2013 at 7:06pm*

**Math Help**

Permutation and combinations (Trig/alg2 class) In how many ways can all the letters in SEYCHELLES be arranged?
*Sunday, June 9, 2013 at 11:51pm*

**Trig**

Oops. 11pi/9 > pi, so subtract pi to get 2pi/9 play around adding and subtracting 2pi or pi till you get an angle in QI.
*Sunday, June 9, 2013 at 5:17pm*

**Trig**

-7pi/9 + 2pi = 11pi/9 This is in QII, so we need to subtract it from pi: pi - 11pi/9 = 7pi/9 You can also subtract 2pi if the angle is large and positive.
*Sunday, June 9, 2013 at 5:15pm*

**MATH - **

Permutation and combinations (Trig/alg2 class) In how many ways can all the letters in SEYCHELLES be arranged?
*Sunday, June 9, 2013 at 2:52pm*

**Trig**

Find the reference angle θ'. θ= -7pi/9
*Saturday, June 8, 2013 at 11:55pm*

**Math Trig Find Quadrant I II III IV**

Think of degrees if radians give you trouble π radians = 180° so (-5/6)π radians = -(5/6)(180)° = -150° so going clockwise 150° would put you into quadrant III
*Saturday, June 8, 2013 at 11:18pm*

**Trig**

A = 1/2r^2 θ A = 1/2(6)^2(pi/2) A = 1/2(36)(pi/2) A = 9pi cm^2
*Saturday, June 8, 2013 at 11:17pm*

**Trig**

Find the area of a sector with the given central angle θ in a circle of radius r. θ = 90°, r = 6 cm
*Saturday, June 8, 2013 at 11:03pm*

**Math Trig Find Quadrant I II III IV**

In which quadrant is the terminal side of angle A? A = -5π/6 a. Quadrant III b. Quadrant I c. Quadrant II d. Quadrant IV
*Saturday, June 8, 2013 at 10:49pm*

**Math**

on all these, they are the same thing. I am not certain how you see 4,5 as different. look here: http://www.sosmath.com/trig/Trig5/trig5/trig5.html Print that out. Notice the sum to product formulas. If you were my student, I would have you write each formula on a flash...
*Monday, June 3, 2013 at 9:12pm*

**Trig**

try doing it ur self
*Monday, June 3, 2013 at 8:45pm*

**trig**

Then recall that tanx >0 in QI,QIII
*Friday, May 31, 2013 at 11:06am*

**trig**

tanx - √3 = 0 tanx = √3 At this point it helps to have memorized the trig ratios for the few angles where at least one of them is rational. In this case, recall that sin60° = √3/2 cos60° = 1/2 tan60° = √3
*Friday, May 31, 2013 at 11:06am*

**trig**

what are the values of the angle in the interval 0<the angle<360 that satisfy the equation tan beta- radical 3=o
*Thursday, May 30, 2013 at 10:57pm*

**trig**

using x to avoid copy/paste of ø, m sinx + 2sinx + 2m cosx - cos x = 2m+1 (sinx + 2cosx)m + (2sinx - cosx) = 2m+1 If these are identical, then sinx + 2cosx = 2 2sinx - cosx = 1 sinx = 4/5 cosx = 3/5 tanx = 4/3
*Wednesday, May 29, 2013 at 10:46am*

**trig**

If (m+2)sin ø + (2m-1)cos ø = 2m+1 then tan ø is equal to
*Wednesday, May 29, 2013 at 2:54am*

**Math-Trig**

the velocity has two components: x: 36 cos70° = 12.31 y: 36 sin70° = 33.83 now recall that the x-speed is constant, and the height y = 33.8t - 16t^2 now solve for the various requirements
*Tuesday, May 28, 2013 at 2:50pm*

**Math-Trig**

A ball is tossed up in the air at an angle of 70 degrees with the horizontal and with an initial velocity of 36 ft/sec. What is the position of the ball 1 second after it is released? When will the ball hit the ground? What is the maximum height the ball will reach? How far in...
*Tuesday, May 28, 2013 at 2:47pm*

**trig**

My sketch is a triangle with sides 16, 24 and 28 , and I am looking for the angle Ø opposite the 28 by cosine law 28^2 = 16^2+24^2 - 2(16)(24)cosØ 768cosØ = 48 cosØ = 48/76 Ø = 50.8°
*Monday, May 27, 2013 at 8:23am*

**trig**

A security camera needs to be set so that the angle of view includes the area from a doorway to the edge of a parking lot.The doorway is 16m from the camera. the edge of the parking lot is 24m for the camera. the doorway is 28m from the edge of the parking lot. what angle of ...
*Monday, May 27, 2013 at 12:49am*

**trig**

in the diagram below.A,B and C are three points in the same horizontal plane and AD is a vertical tower.AC=AB=x and DC=DB.the angle of elevetion of D from C is alpha and DB^C=theta 1.express DC in terms of x trigonometry value of alpha 2.prove that BC=2xcostheta/cos alpha
*Sunday, May 26, 2013 at 10:54am*

**trig**

please am stucked help me.in the diagram below.A,B and C are three points in the same horizontal plane and DC is a vertical tower.AC=AB=x and D^C=DB.the angle of elevation of D from C is alpha and DB^C=theta
*Sunday, May 26, 2013 at 7:31am*

**How to get quick responses to your math questions**

Math is a wide subject, ranging from K to 11, college and university. Then there is algebra, trigonometry, geometry, arithmetic, calculus, number theory, ... etc. Not all teachers answer all math questions (many do). If you would give a little more detail on which branch of ...
*Saturday, May 25, 2013 at 9:45am*

**trig**

So on the Cartesian plane, it is in the fourth quadrant, with x-y as (900,-500). Atan(-500/900)= -29° approximately. So the bearing is S61°E.
*Saturday, May 25, 2013 at 6:25am*

**trig**

A hiker walks 900m east and 500m south .Find the bearing of the finishing position from the staring point?
*Saturday, May 25, 2013 at 3:44am*

**trig**

you are exactly right tan(4x) = 2tan2x/(1-tan^2(2x)) so, cot(4x) is the reciprocal, as needed.
*Thursday, May 23, 2013 at 3:17pm*

**trig**

okay, thank you, would that still apply if it was cot4x=1-tan^2(2x)/2tan2x? because ive got the right side for this one but the cot4x is throwing me off, how would you solve that side?
*Thursday, May 23, 2013 at 3:13pm*

**trig**

just apply the double-angle formula for tan(2x) and take the reciprocal
*Thursday, May 23, 2013 at 3:02pm*

**trig**

TRIG Identities, Gr. 12: Prove: cot4x=1-tan^2x/2tan2x
*Thursday, May 23, 2013 at 2:56pm*

**TRIG Help help help test tommarow**

(h+1250)/1150 = tan 52°
*Thursday, May 23, 2013 at 10:28am*

**TRIG Help help help test tommarow**

A TV tower stands on top of the Empire State building. From a point (on the ground) 1150 feet from the base of the building, the angle of elevation to the top of the TV tower is 52 degrees. If the building is 1250 feet tall, what is the length of the TV tower?
*Wednesday, May 22, 2013 at 6:48pm*

**Applied Physics**

what is 40Sin65? This is physics? Most folks would call this basic trig functions.
*Monday, May 20, 2013 at 5:05pm*

**Mathematics Ms Sue help**

for the building, h/18 = tan 88° for the boat, d/40 = sin 65° for stuff like this, it always helps to draw a diagram, then dig into your box of trig ratios
*Monday, May 20, 2013 at 4:21pm*

**TRIGONOMETRY**

by test time you need to know the "standard" angles with easy-to-recall trig functions 0,π/6,π/4,π/3,π/2 If you know those angles and their trig ratios, you will recall that tan π/3 = √3 Now, recall the bit about principal values of ...
*Saturday, May 18, 2013 at 11:47am*

**TRIGONOMETRY**

Can someone please give me a step by step answer on how to find the complex cube roots of 8(cos(4π/5)+isin(4π/5))? I need to know how to do this for my trig final next week.
*Friday, May 17, 2013 at 5:01pm*

**TRIGONOMETRY**

I don't understand how to convert -3-4i to polar coordinates. I need to know how so I am ready for my trig final next year. Can someone please show me step by step how to solve this? Thanks
*Friday, May 17, 2013 at 3:31pm*

**TRIGONOMETRY**

Can someone please show me step by step how to calculate the modulus and the argument for these complex numbers? I have a trig final next week and I am trying to finish this study guide so I am prepared. Thank you so much! If you can, please show my how you get the answer so I...
*Friday, May 17, 2013 at 9:11am*

**TRIGONOMETRY**

Can you please help me with this question on my study guide for my trig final? Thanks! I'd also appreciate if you can check out my other postings and check my work for some other study guide questions. I want to make sure I'm ready for my final. :) 4. Transform each ...
*Thursday, May 16, 2013 at 11:29am*

**TRIGONOMETRY**

Can you check my work, please? This is for a trig study guide for my final next week. I'd like to know if I'm doing this right. :) 2. The polar coordinates of a point are given. Find the rectangular coordinates of each point. a. (5,(π / 4)) b. (-2,(π / 6)) ...
*Thursday, May 16, 2013 at 11:26am*

**TRIGONOMETRY**

Can you please help me with this question on my study guide for my trig final? Thanks! I'd also appreciate if you can check out my other postings and check my work for some other study guide questions. I want to make sure I'm ready for my final. :) 3. The rectangular ...
*Thursday, May 16, 2013 at 11:13am*

**trig**

sinx cosy(cotx tany-1) sinx cosy cosx/sinx siny/cosy - sinx cosy cosx siny - sinx cosy sin(y-x)
*Wednesday, May 15, 2013 at 2:50pm*

**trig**

Sinxcosy(cotxtany-1)
*Wednesday, May 15, 2013 at 12:16pm*

**trig**

Sinxcosy(cotxtany-1)
*Wednesday, May 15, 2013 at 12:15pm*

**trig**

There are 15,000 endive lettuce seeds in an ounce and 300 seeds in a packet. The seeds cost $1.50 per packet. What is the cost, in dollars, of one ounce of seeds?
*Wednesday, May 15, 2013 at 10:04am*

**trig**

5cosA+3 = 0 means that cosA = -3/5 So, A is in QIII sinA = y/r = -4/5 sinA+cosA = -4/5 + -3/5 = -7/5 tanA*sinA = 4/3 * -4/5 = -16/15
*Monday, May 13, 2013 at 12:08pm*

**trig**

if 5cos A plus 3=0 and 180<A<360..without using a calculator and with the aid of a diagram,determine the value of 1.1 sinA plus cosA 1.2 tanA *sinA
*Monday, May 13, 2013 at 11:52am*

**Trig**

4x+y = 84, so y = 84-4x v = x^2 y = x^2(84-4x) = 84x^2 - 4x^3 dv/dx = 168x - 12x^2 = 12x(14-x) dv/dx=0 when x=14 so the box is 14 x 14 x 28
*Sunday, May 12, 2013 at 11:53pm*

**Trig**

The postal service places a limit of 84 inches on the combined lenght and girth (distance around) of a package to be sen parcel post. What Dimensions of a rectangular box with square cross-section will contain the largest volume that can be mailed?
*Sunday, May 12, 2013 at 11:32pm*

**TRIG**

term(n) = a + (n-1)d 428 = 4 + (n-1)(8) 424 = 8n - 8 432 = 8n n = 54 Draw your conclusion
*Sunday, May 12, 2013 at 12:12am*

**TRIG**

Did you notice that there is a "common difference" of 4 ? so term (n) = .....
*Sunday, May 12, 2013 at 12:10am*

**TRIG**

exactly what don't you understand about this question a = 2 d = 2 n = 100 Sum(100) = .... just use your formula
*Sunday, May 12, 2013 at 12:08am*

**TRIG**

pop = 1.3(1.04)^8 = ..... million
*Sunday, May 12, 2013 at 12:07am*

**TRIG**

term(6) = ar^5 = (-5)(2.5)^5 = -488.28125
*Saturday, May 11, 2013 at 11:52pm*

**TRIG**

in an arithmetic sequence a1=4 and d=8 which term is 428 Show your work
*Saturday, May 11, 2013 at 8:32pm*

**TRIG**

what is the explicit formula for the sequence 3,7,11,15
*Saturday, May 11, 2013 at 8:30pm*

**TRIG**

determine the sum of the first 100 even integers SHOW YOUR WORK
*Saturday, May 11, 2013 at 8:29pm*

**TRIG**

the population of a certain city is 1.3 million people. if the population is growing at the rate of 4% per year what will the population be in 8 years
*Saturday, May 11, 2013 at 8:28pm*

**TRIG**

What is the 6th term of the geometric series with a1= -5 and r=2.5
*Saturday, May 11, 2013 at 8:25pm*

**trig**

cos(a+b)/sin(a+b)= cosacosb+sinasinb/sinacosb-cosasinb multiplying and dividing by sinasins then it becomes cotacotb+1/cotb-cota
*Saturday, May 11, 2013 at 12:02pm*

**trig identites**

since sin(n*180) = 0, 2x+60 = n*180 x = n*90 - 30
*Friday, May 10, 2013 at 11:48pm*

**trig identites**

since sin2x+√3cos2x=2sin(2x+60) find the general solution for the equation sin2x+√3cosx=0 thank you
*Friday, May 10, 2013 at 7:35pm*

**math**

simplify sin(540-2x) this is to do with trig
*Friday, May 10, 2013 at 10:13am*

**Trig**

recall that (a-b)(a+b) = a^2-b^2 sec^2(x) - 1 = tan^2(x) put the fractions over a common denominator and watch the answer fall out.
*Thursday, May 9, 2013 at 2:43pm*

**Trig**

Verify the identity. (secx + tanx)/(secx - tanx) = (1 + 2sinx + sin(^2)x)/cos(^2)x
*Thursday, May 9, 2013 at 2:16pm*

**Trig**

Verify the identity. 1/(tanx-secx) + 1/(tanx+secx) = -2tanx
*Thursday, May 9, 2013 at 1:54pm*

**math trig**

I will do of these, for 135° : assume the axle is 20.5 above the ground height above axle: sin135 = h/20.5 h = 20.5sin135 = appr 14.5 m so height above the ground = 20.5 + 14.5 = 35 for 315° height from axle : sin 315 = h/20.5 h = 20.5sin135 = appr - 14.5 notice the ...
*Thursday, May 9, 2013 at 12:33pm*

**math trig**

sin45 = height/20.5 height = 20.5sin45 = 14.4 m above the axle
*Thursday, May 9, 2013 at 12:20pm*

**math trig**

If a ferris wheel with a 20.5 meter radius, how high would one car be from the loding dock at these given angles trveled by the rider?: 90 135 180 225 270 315 405 450 495 and 540?
*Thursday, May 9, 2013 at 10:40am*

**math trig**

If a ferris wheel has a radius of 20.5meters, how tall would a 45 degree angle be?
*Thursday, May 9, 2013 at 10:28am*

**Honors Trig**

From the diagram that you made, let the speed of the wind be x, we get by the cosine law x^2= 350^2 + 400^2 - 2(350)(400)cos10° = 6753.829.. x = 82.18 mph by the sine law, the other acute angle Ø is .... sinØ/350 = sin10/82.18 sinØ = .7395.. Ø...
*Wednesday, May 8, 2013 at 7:23pm*

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