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April 17, 2014

Homework Help: Math: Trigonometry

Recent Homework Questions About Trigonometry

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Trig
I get two. make a sketch Using the Sine Law, you will get sinC = 29sin40/24 = .776... so C = appr 51 degrees or 180-51 = 129 degrees (since the sine is positive in I or II) You will be able to draw a second triangle with B = 40, C = 129 and A = 11 degrees This is called the ...
Tuesday, July 2, 2013 at 12:02pm

Trig
Determine the number of triangles with the given parts. b=24 c=29 B=40deg I got 1
Tuesday, July 2, 2013 at 11:45am

trig
correct! (except that's theta, not tehta)
Tuesday, July 2, 2013 at 10:43am

trig
Find all solutions of the equation. Leave answers in trigonometric form. x^5-1024=0 I got 4(cos tehta + i sin tehta), tehta = 0, 2pi/5, 4pi/5, 6pi/5, 8pi/5 is this right
Tuesday, July 2, 2013 at 10:29am

trig, math
period of cos kx = 2pi/k so, 2pi/k = 7 k = 2pi/7 period of tan,cot = pi, so (B)
Monday, July 1, 2013 at 3:04pm

trig, math
Which of these functions has period 7? A)y= cot 7/pi x B)y= tan pi/7 x C)y= sin 7/pi x D)y= cos pi/7 x
Monday, July 1, 2013 at 1:34pm

Trig
you know that (1,1) = √2,π/4 so, now you have an angle in QIV, so it is 24,7π/4
Monday, July 1, 2013 at 12:21am

Jolly
Find the magnitude and direction angle for the given vector. 12√(2), -12√(2)
Sunday, June 30, 2013 at 8:29pm

trig
X ^5 - 11 = 0 X^5 = 11 (X^5)^(1/5) = (11)^(1/5) X = 1.615.
Sunday, June 30, 2013 at 4:38pm

trig
(6,-6) is in QIV Where are the given angles?
Saturday, June 29, 2013 at 12:33am

trig
Hey, Tone, you've posted a bunch of these problems that are all just basically converting between rectangular and polar forms. I've done a few for you. What don't you get by now? We're willing to help, but hate to be used to do someone's whole assignment. ...
Saturday, June 29, 2013 at 12:30am

trig
Write the complex number in trigonometric form, using degree measure for the argument. -12 - 16i
Friday, June 28, 2013 at 9:36pm

trig
Convert the rectangular coordinates to polar coordinates, using radian measure for the angle. (6, -6) 6√(2),7π/4 OR -6√(2),5π/4
Friday, June 28, 2013 at 9:16pm

trig
Solve the equation. Express your answer in trigonometric form. x^5 - 11 = 0
Friday, June 28, 2013 at 12:39pm

trig
Find the indicated roots. Write the answer in trigonometric form. Fourth roots of 256(cos 220° + i sin 220°)
Friday, June 28, 2013 at 12:38pm

trig
(2cis240°)^5 = 2^5 cis(5*240°) = 32 cis1200° = 32 cis120° = -16 + 16√3 i
Friday, June 28, 2013 at 12:34pm

trig
z = 2(cos 240° + i sin 240°) = 2 exp(4/3 pi i) z^5 = 2^5 exp(20/3 pi i) = 32 exp(2/3 pi i) = -16 + 16 sqrt(3) i
Friday, June 28, 2013 at 12:33pm

trig
Use De Moivre's theorem to simplify the expression. Write the answer in a + bi form. [2(cos 240° + i sin 240°)]^5
Friday, June 28, 2013 at 12:08pm

trig
Find the dot product a*b. a= (5,-9), b=(4,-3)
Friday, June 28, 2013 at 11:36am

trig
x = v cosθ y = v sinθ
Friday, June 28, 2013 at 11:31am

trig
3u+v = 3(-9,1) + (-5,9) = (-27,3)+(-5,9) = (-32,12)
Friday, June 28, 2013 at 11:30am

trig
estimate the components of the vector. Round to one decimal place. [v] = 33.9, θ = 65.9° Find the horizontal and vertical components of v, and write in component form.
Friday, June 28, 2013 at 11:30am

trig
find the indicated vector. let u = (-9,1), v=(-5,9). Find 3u+v
Friday, June 28, 2013 at 11:28am

trig, math
sinβ = b/c
Thursday, June 27, 2013 at 3:28pm

trig, math
In a right triangle with g the right angle, b = 86.5 and c = 125.8. What is β ?
Thursday, June 27, 2013 at 12:26pm

trig, math
20/d = tan 60°
Thursday, June 27, 2013 at 11:43am

trig, math
A stairway must be built to a deck that is 20 feet above ground level. To the nearest half foot, how far from the base of the deck, on ground level, should the beginning of the stairway be placed so that the stairway forms a 60° angle from the ground?
Thursday, June 27, 2013 at 11:41am

trig
z1/z2 = (4+9i)/(-5-5i) Multiply top and bottom by the denominator's conjugate: (4+9i)(-5+5i) / (-5-5i)(-5+5i) (-65-25i) / (5^2+5^2) -65/50 - 25/50 i -13/10 - 1/2 i
Thursday, June 27, 2013 at 11:29am

math
If you are trying to find the area of the triangle you could use trig to find the height of the triangle and then use the formula 1/2 base x height. So draw the Isoceles triangle with each leg 3cm and the base 4cm Draw a centre line forming two right angled triangles find the ...
Thursday, June 27, 2013 at 9:04am

trig
Find z1z2 and z1/z2 for the pair of complex numbers using trigonometric form. z1=4+9i, z2=-5-5i I got z1z2 = 25-65i But cannot find the z1/z2.
Wednesday, June 26, 2013 at 10:12pm

differential calculus
surely your text has a table of derivatives of trig functions. This is such a basic question, you could have looked up the answer in less time than typing in the question. d/dx (sin x) = cos x Is there more to this than first appears?
Wednesday, June 26, 2013 at 11:44am

trig
A + B = 90o A + 31 = 90 A = 59o. c*sin 59 = 3. c = 3/sin59 = 3.50 tan 59 = 3/b b = 3/tan 59 = 1.80
Saturday, June 22, 2013 at 8:49pm

trig
work with it as a polynomial is sinx: 2sin^2x + sinx - 1 = 0 (2sinx-1)(sinx+1) = 0 sinx = 1/2 or -1
Friday, June 21, 2013 at 2:36pm

trig
use your half-angle formulas: sin^2(θ/2) = √(1-cosθ)/2
Friday, June 21, 2013 at 2:34pm

trig
i got it now. thanks
Friday, June 21, 2013 at 1:57pm

trig
slove the equation exactly over the interval [0, 2pi) sinx=1-2sin^2x
Friday, June 21, 2013 at 1:13pm

trig
use an identity to write the expression as a single trignometric function. squ root 1-cos48°/2
Friday, June 21, 2013 at 1:07pm

trig
How am I going to help you if you don't read what I wrote?
Friday, June 21, 2013 at 12:56pm

trig
cos8x
Friday, June 21, 2013 at 12:55pm

maths-trignometry(urgent)
got me. can't think of a trick that will reduce that number (degrees or radians!) without using a calculator. I can tell you right off that no trig function of a rational number of radians will come out to an easy value. As for degrees, well -38888 is equivalent to -8, but...
Friday, June 21, 2013 at 12:54pm

trig
choose the expression that is equivalent to the given expression. 2 cos^2 4x-1
Friday, June 21, 2013 at 12:53pm

trig
so the answer is 330
Friday, June 21, 2013 at 12:51pm

trig
Nope. cos/sin = cot csc * sin = 1 so you have cot^2 + 1 = csc^2
Friday, June 21, 2013 at 12:49pm

trig
√3 tan(θ/2) = -1 tan θ/2 = -1/√3 θ/2 = 150 or 330 θ = 300 or 660 θ=660 is equivalent to θ=300, since 660=300+360 tan 120 = -√3, not -1/√3
Friday, June 21, 2013 at 12:46pm

trig
Use the fundamental identities to simplify the expression. cos^2θ/sin^2θ+cscθsin_​2; I got tan^2theta
Friday, June 21, 2013 at 12:46pm

trig
fidn all values of tehta in [0, 360) that satisfy the equation. √(3)tan(θ/2)=-1 I have four choices 300, 330, 150 , 120 and i got 120
Friday, June 21, 2013 at 12:40pm

trig
since sin^2 + cos^2 = 1, you have 1 - 2 cosx sinx = 1-sin2x
Friday, June 21, 2013 at 12:37pm

trig
looks good to me.
Friday, June 21, 2013 at 12:36pm

trig
Multiply and simplify. (cos x - sin x)^2
Friday, June 21, 2013 at 12:36pm

trig
Choose the expression that is equivalent to the given expression. sin 6x tan 3x I got 2 sin^2 3x
Friday, June 21, 2013 at 12:33pm

trig
that would be tan 4π/3 = √3
Friday, June 21, 2013 at 12:29pm

trig
Write the expression as the sine, cosine, or tangent of a double angle. Then find the exact value of the expression. 2tan 2pi/3 / 1-tan^2 2pu/3
Friday, June 21, 2013 at 12:26pm

trig
Solve the right triangle with the given sides and angles. a = 3.0, B = 31.0°
Friday, June 21, 2013 at 11:46am

Physics (trig)
If the angle is x, tan x = 12.3333/19.2 Better review your trig ratios...
Thursday, June 20, 2013 at 4:29am

Physics (trig)
The height of an outdoor basketball backboard is 12 1/3 feet and the backboard casts a shadow 19 1/5 feet. Find the angle of elevation of the sun (answer in units of degrees). Can someone help me with the formula? Thank you!
Wednesday, June 19, 2013 at 9:10pm

Physics (algebra)
Thanks Steve, taking a physics course for credit this summer, but I am going in to 9th grade and have not had trig yet. Thanks for the formula!
Tuesday, June 18, 2013 at 6:16pm

Physics (algebra)
depends on what you want to find. The depth of the sub is d/4601 = sin32° Looks like you need to review your trig ratios
Tuesday, June 18, 2013 at 4:04pm

trig
2x = 45,315,... Follow for 2 periods to get values for x up to 360.
Monday, June 17, 2013 at 10:13am

trig
2sin2θ = √3 sin2θ = √3/2 sin(x) is positive in QI,QII 2θ = 60°,120°,... we need to go for two periods because we're dealing with 2θ. That gives us θ = 30°,60°,210°,240°
Monday, June 17, 2013 at 10:12am

trig
Find all values of ¸ in [0°, 360°) that satisfy the equation. 2 sin 2θ - √(3) = 0
Monday, June 17, 2013 at 9:47am

trig
Find all real numbers in [0, 2π) that satisfy the equation. cos 2x = √(2)/2
Monday, June 17, 2013 at 9:46am

trig
arctan(1.85) = 61.6° tan(x) < 0 in QII, QIV, so x = (180-61.6) = 118.4° x = (360-61.6) = 298.4°
Monday, June 17, 2013 at 4:34am

trig
tan(x+y) = (tanx + tany)/(1-tanx tany) so, what you have is tan(25°+5°) = tan 30° = 1/√3
Monday, June 17, 2013 at 4:31am

trig
what's all this work? A is in QI, so sinA = √8/3 B is in QIV so cosB = √3/2 and then as done in the final paragraph
Monday, June 17, 2013 at 4:30am

trig
Find all angles in degrees that satisfy the equation. Round approximate answers to the nearest tenth of a degree. tan α = -1.85
Monday, June 17, 2013 at 12:58am

trig
cos A = 1 / 3 sin A = + OR - sqrt ( 1 - cos A ^ 2 ) sin A = + OR - sqrt ( 1 - ( 1 / 3 ) ^ 2 ) sin A = + OR - sqrt ( 1 - 1 / 9 ) sin A = + OR - sqrt ( 9 / 9 - 1 / 9 ) sin A = + OR - sqrt ( 8 / 9 ) sin A = + OR - sqrt ( 4 * 2 / 9 ) sin A = + OR - sqrt ( 4 ) * sqrt ( 2 ) / sqrt...
Monday, June 17, 2013 at 12:42am

trig
Use a sum or difference identity to find the exact value. tan 25deg + tan 5deg / 1-tan 25deg tan 5deg
Monday, June 17, 2013 at 12:40am

trig
Find cos(A+B). cos A=1/3 and sin B=-1/2, with A in quadrant I and B in quadrant IV.
Sunday, June 16, 2013 at 11:20pm

trig
Since (5,12,13) is a Pythagorean triplet, tan(θ)=5/12. Mathematically, we solve it by: Divide by the right hand side: (5/13)sin(θ)+(12/13)cos(θ)=1​ Since (5/13)²+(12/13)²=1, we can put 5/13=sin(φ) 12/13=cos(φ) so sin(φ)sin(&theta...
Saturday, June 15, 2013 at 11:03am

trig
if 5sin theta + 12cos theta is equal to 13 find the value of tan theta
Saturday, June 15, 2013 at 8:41am

trig
Sin < 0-----> quadrant 3 and 4 Sec > 0 ---- quadrant 1 and 4 sec = 1/cos Answer is quadrant 4
Friday, June 14, 2013 at 6:30pm

Algebra 3 and trig
distance is √(177^2 + 265^2) bearing is (90-θ) where tanθ = -265/177
Thursday, June 13, 2013 at 5:28am

Algebra 3 and trig
An ocean liner is 177 miles due west of lighthouse A. Lighthouse B is 265 miles due south of lighthouse A. Find the distance from lighthouse B to the liner and the bearing of the ocean liner from lighthouse B.
Wednesday, June 12, 2013 at 6:22pm

trig
sin negative, cosine positive? sin is negative III, IV cosine positive I, III
Wednesday, June 12, 2013 at 3:27pm

trig
quadrant 1
Wednesday, June 12, 2013 at 3:19pm

trig
for the given angle, name the quadrant in whihc the terminal side lies. -350deg
Wednesday, June 12, 2013 at 2:25pm

trig
identify the quadrant in which 0 lies. sin < 0 and sec > 0
Wednesday, June 12, 2013 at 2:02pm

trig
determine the period of the function. y = cot 4t
Wednesday, June 12, 2013 at 1:26pm

trig
for (-3,4) x = -3, y = 4 cotØ = x/y = - 3/4
Tuesday, June 11, 2013 at 8:12pm

trig
cosØ = x/r = 2/7 so x=2 , r = 7 2^2 + y^2 = 7^2 y^2 = 45 = ± 3√5 but we are in IV , so y = -3√5 sinØ = -3√5/7
Tuesday, June 11, 2013 at 8:11pm

trig
sin positive, quad I and II Tan negative, Quad II, IV Quad II
Tuesday, June 11, 2013 at 8:04pm

trig
Identify the quadrant in which θ lies. sin > 0 and tan < 0
Tuesday, June 11, 2013 at 7:59pm

trig
Find the trigonometric function value of angle θ. Cos θ = 2/7 and θ is in quadrant IV. Find sin θ.
Tuesday, June 11, 2013 at 7:30pm

trig
The point (-3, 4) is on the terminal side of angle θ in standard position. Find cot θ.
Tuesday, June 11, 2013 at 7:24pm

trig
angular velocity: 1st wheel : 2π rad/30 sec = π/15 rad/sec 2nd wheel : 2π radians/15 sec = 2π/15 rad/sec linear velocity 1st wheel: circumference = 2π(20) = 40π ft linear velocity = 40π/30 ft/sec = 4π/3 ft/se 2nd wheel: circumf = 20π...
Tuesday, June 11, 2013 at 6:42pm

trig
construct your triangle in the third quadrant, using Pythagoras, you know r^2 = (-2)^2 + (-3)^2 = 13 r = √13 then cosØ = x/r = -2/√13 , then sec Ø = -√13/2
Tuesday, June 11, 2013 at 6:37pm

trig
Given that θ is an angle in standard position whose terminal side contains the given point, provide the exact value of the indicated function. (-2, -3) Find sec θ.
Tuesday, June 11, 2013 at 4:31pm

trig
ferris wheel one has a 40ft diameter, revolves once every 30 seconds and is 5ft above ground. Ferris wheel two has a diameter of 20feet, revolves once every 15seconds and is 2 feet above the ground. each angular velocity?? each linear velocity??
Tuesday, June 11, 2013 at 3:26pm

math - trig
You know that sinØ = y/r cosØ = x/r tanØ = y/x cscØ = r/y etc so in any point the first coordinate is the x, the 2nd is the y 1. for (-12, -5) you would be in quadrant III x = -12, y = -5 use Pythagoras, x^2 + y^2 = r^2 ( where we keep r always ...
Tuesday, June 11, 2013 at 8:52am

math - trig
1. Find csc A, cos A and tan A of an angle A whose terminal side contains (– 12, – 5). 2. Find sin X, sec X and cot X of an angle X whose terminal side contains (– 3, 5).
Tuesday, June 11, 2013 at 4:11am

Trig
I get 252.717 or 253
Monday, June 10, 2013 at 11:36pm

Trig
I got 263.
Monday, June 10, 2013 at 8:55pm

Trig
did you make a sketch? I have , top of tower -- P , bottom of tower Q closer point A farther point B In triangle PBA angle B = 29°5' angle BAP = 142°55' angle BPA = 8° AB = 120 by sine law: PA/sin 29°5' = 120/sin 8° PA = 419.1165 now triangle ...
Monday, June 10, 2013 at 8:29pm

Trig
The angle of elevation from a point on the ground to the top of a tower is 37deg5'. The angle of elevation from a point 120 feet farther back from the tower is 29deg5'. Find the height of the tower (to the nearest foot).
Monday, June 10, 2013 at 7:06pm

Math Help
Permutation and combinations (Trig/alg2 class) In how many ways can all the letters in SEYCHELLES be arranged?
Sunday, June 9, 2013 at 11:51pm

Trig
Oops. 11pi/9 > pi, so subtract pi to get 2pi/9 play around adding and subtracting 2pi or pi till you get an angle in QI.
Sunday, June 9, 2013 at 5:17pm

Trig
-7pi/9 + 2pi = 11pi/9 This is in QII, so we need to subtract it from pi: pi - 11pi/9 = 7pi/9 You can also subtract 2pi if the angle is large and positive.
Sunday, June 9, 2013 at 5:15pm

MATH -
Permutation and combinations (Trig/alg2 class) In how many ways can all the letters in SEYCHELLES be arranged?
Sunday, June 9, 2013 at 2:52pm

Trig
Find the reference angle θ'. θ= -7pi/9
Saturday, June 8, 2013 at 11:55pm

Math Trig Find Quadrant I II III IV
Think of degrees if radians give you trouble π radians = 180° so (-5/6)π radians = -(5/6)(180)° = -150° so going clockwise 150° would put you into quadrant III
Saturday, June 8, 2013 at 11:18pm

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