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April 17, 2014

April 17, 2014

**Recent Homework Questions About Trigonometry**

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**Trig**

I get two. make a sketch Using the Sine Law, you will get sinC = 29sin40/24 = .776... so C = appr 51 degrees or 180-51 = 129 degrees (since the sine is positive in I or II) You will be able to draw a second triangle with B = 40, C = 129 and A = 11 degrees This is called the ...
*Tuesday, July 2, 2013 at 12:02pm*

**Trig**

Determine the number of triangles with the given parts. b=24 c=29 B=40deg I got 1
*Tuesday, July 2, 2013 at 11:45am*

**trig**

correct! (except that's theta, not tehta)
*Tuesday, July 2, 2013 at 10:43am*

**trig**

Find all solutions of the equation. Leave answers in trigonometric form. x^5-1024=0 I got 4(cos tehta + i sin tehta), tehta = 0, 2pi/5, 4pi/5, 6pi/5, 8pi/5 is this right
*Tuesday, July 2, 2013 at 10:29am*

**trig, math**

period of cos kx = 2pi/k so, 2pi/k = 7 k = 2pi/7 period of tan,cot = pi, so (B)
*Monday, July 1, 2013 at 3:04pm*

**trig, math**

Which of these functions has period 7? A)y= cot 7/pi x B)y= tan pi/7 x C)y= sin 7/pi x D)y= cos pi/7 x
*Monday, July 1, 2013 at 1:34pm*

**Trig**

you know that (1,1) = √2,π/4 so, now you have an angle in QIV, so it is 24,7π/4
*Monday, July 1, 2013 at 12:21am*

**Jolly**

Find the magnitude and direction angle for the given vector. 12√(2), -12√(2)
*Sunday, June 30, 2013 at 8:29pm*

**trig**

X ^5 - 11 = 0 X^5 = 11 (X^5)^(1/5) = (11)^(1/5) X = 1.615.
*Sunday, June 30, 2013 at 4:38pm*

**trig**

(6,-6) is in QIV Where are the given angles?
*Saturday, June 29, 2013 at 12:33am*

**trig**

Hey, Tone, you've posted a bunch of these problems that are all just basically converting between rectangular and polar forms. I've done a few for you. What don't you get by now? We're willing to help, but hate to be used to do someone's whole assignment. ...
*Saturday, June 29, 2013 at 12:30am*

**trig**

Write the complex number in trigonometric form, using degree measure for the argument. -12 - 16i
*Friday, June 28, 2013 at 9:36pm*

**trig**

Convert the rectangular coordinates to polar coordinates, using radian measure for the angle. (6, -6) 6√(2),7π/4 OR -6√(2),5π/4
*Friday, June 28, 2013 at 9:16pm*

**trig**

Solve the equation. Express your answer in trigonometric form. x^5 - 11 = 0
*Friday, June 28, 2013 at 12:39pm*

**trig**

Find the indicated roots. Write the answer in trigonometric form. Fourth roots of 256(cos 220° + i sin 220°)
*Friday, June 28, 2013 at 12:38pm*

**trig**

(2cis240°)^5 = 2^5 cis(5*240°) = 32 cis1200° = 32 cis120° = -16 + 16√3 i
*Friday, June 28, 2013 at 12:34pm*

**trig**

z = 2(cos 240° + i sin 240°) = 2 exp(4/3 pi i) z^5 = 2^5 exp(20/3 pi i) = 32 exp(2/3 pi i) = -16 + 16 sqrt(3) i
*Friday, June 28, 2013 at 12:33pm*

**trig**

Use De Moivre's theorem to simplify the expression. Write the answer in a + bi form. [2(cos 240° + i sin 240°)]^5
*Friday, June 28, 2013 at 12:08pm*

**trig**

Find the dot product a*b. a= (5,-9), b=(4,-3)
*Friday, June 28, 2013 at 11:36am*

**trig**

x = v cosθ y = v sinθ
*Friday, June 28, 2013 at 11:31am*

**trig**

3u+v = 3(-9,1) + (-5,9) = (-27,3)+(-5,9) = (-32,12)
*Friday, June 28, 2013 at 11:30am*

**trig**

estimate the components of the vector. Round to one decimal place. [v] = 33.9, θ = 65.9° Find the horizontal and vertical components of v, and write in component form.
*Friday, June 28, 2013 at 11:30am*

**trig**

find the indicated vector. let u = (-9,1), v=(-5,9). Find 3u+v
*Friday, June 28, 2013 at 11:28am*

**trig, math**

sinβ = b/c
*Thursday, June 27, 2013 at 3:28pm*

**trig, math**

In a right triangle with g the right angle, b = 86.5 and c = 125.8. What is β ?
*Thursday, June 27, 2013 at 12:26pm*

**trig, math**

20/d = tan 60°
*Thursday, June 27, 2013 at 11:43am*

**trig, math**

A stairway must be built to a deck that is 20 feet above ground level. To the nearest half foot, how far from the base of the deck, on ground level, should the beginning of the stairway be placed so that the stairway forms a 60° angle from the ground?
*Thursday, June 27, 2013 at 11:41am*

**trig**

z1/z2 = (4+9i)/(-5-5i) Multiply top and bottom by the denominator's conjugate: (4+9i)(-5+5i) / (-5-5i)(-5+5i) (-65-25i) / (5^2+5^2) -65/50 - 25/50 i -13/10 - 1/2 i
*Thursday, June 27, 2013 at 11:29am*

**math**

If you are trying to find the area of the triangle you could use trig to find the height of the triangle and then use the formula 1/2 base x height. So draw the Isoceles triangle with each leg 3cm and the base 4cm Draw a centre line forming two right angled triangles find the ...
*Thursday, June 27, 2013 at 9:04am*

**trig**

Find z1z2 and z1/z2 for the pair of complex numbers using trigonometric form. z1=4+9i, z2=-5-5i I got z1z2 = 25-65i But cannot find the z1/z2.
*Wednesday, June 26, 2013 at 10:12pm*

**differential calculus**

surely your text has a table of derivatives of trig functions. This is such a basic question, you could have looked up the answer in less time than typing in the question. d/dx (sin x) = cos x Is there more to this than first appears?
*Wednesday, June 26, 2013 at 11:44am*

**trig**

A + B = 90o A + 31 = 90 A = 59o. c*sin 59 = 3. c = 3/sin59 = 3.50 tan 59 = 3/b b = 3/tan 59 = 1.80
*Saturday, June 22, 2013 at 8:49pm*

**trig**

work with it as a polynomial is sinx: 2sin^2x + sinx - 1 = 0 (2sinx-1)(sinx+1) = 0 sinx = 1/2 or -1
*Friday, June 21, 2013 at 2:36pm*

**trig**

use your half-angle formulas: sin^2(θ/2) = √(1-cosθ)/2
*Friday, June 21, 2013 at 2:34pm*

**trig**

i got it now. thanks
*Friday, June 21, 2013 at 1:57pm*

**trig**

slove the equation exactly over the interval [0, 2pi) sinx=1-2sin^2x
*Friday, June 21, 2013 at 1:13pm*

**trig**

use an identity to write the expression as a single trignometric function. squ root 1-cos48°/2
*Friday, June 21, 2013 at 1:07pm*

**trig**

How am I going to help you if you don't read what I wrote?
*Friday, June 21, 2013 at 12:56pm*

**trig**

cos8x
*Friday, June 21, 2013 at 12:55pm*

**maths-trignometry(urgent)**

got me. can't think of a trick that will reduce that number (degrees or radians!) without using a calculator. I can tell you right off that no trig function of a rational number of radians will come out to an easy value. As for degrees, well -38888 is equivalent to -8, but...
*Friday, June 21, 2013 at 12:54pm*

**trig**

choose the expression that is equivalent to the given expression. 2 cos^2 4x-1
*Friday, June 21, 2013 at 12:53pm*

**trig**

so the answer is 330
*Friday, June 21, 2013 at 12:51pm*

**trig**

Nope. cos/sin = cot csc * sin = 1 so you have cot^2 + 1 = csc^2
*Friday, June 21, 2013 at 12:49pm*

**trig**

√3 tan(θ/2) = -1 tan θ/2 = -1/√3 θ/2 = 150 or 330 θ = 300 or 660 θ=660 is equivalent to θ=300, since 660=300+360 tan 120 = -√3, not -1/√3
*Friday, June 21, 2013 at 12:46pm*

**trig**

Use the fundamental identities to simplify the expression. cos^2θ/sin^2θ+cscθsin_2; I got tan^2theta
*Friday, June 21, 2013 at 12:46pm*

**trig**

fidn all values of tehta in [0, 360) that satisfy the equation. √(3)tan(θ/2)=-1 I have four choices 300, 330, 150 , 120 and i got 120
*Friday, June 21, 2013 at 12:40pm*

**trig**

since sin^2 + cos^2 = 1, you have 1 - 2 cosx sinx = 1-sin2x
*Friday, June 21, 2013 at 12:37pm*

**trig**

looks good to me.
*Friday, June 21, 2013 at 12:36pm*

**trig**

Multiply and simplify. (cos x - sin x)^2
*Friday, June 21, 2013 at 12:36pm*

**trig**

Choose the expression that is equivalent to the given expression. sin 6x tan 3x I got 2 sin^2 3x
*Friday, June 21, 2013 at 12:33pm*

**trig**

that would be tan 4π/3 = √3
*Friday, June 21, 2013 at 12:29pm*

**trig**

Write the expression as the sine, cosine, or tangent of a double angle. Then find the exact value of the expression. 2tan 2pi/3 / 1-tan^2 2pu/3
*Friday, June 21, 2013 at 12:26pm*

**trig**

Solve the right triangle with the given sides and angles. a = 3.0, B = 31.0°
*Friday, June 21, 2013 at 11:46am*

**Physics (trig)**

If the angle is x, tan x = 12.3333/19.2 Better review your trig ratios...
*Thursday, June 20, 2013 at 4:29am*

**Physics (trig)**

The height of an outdoor basketball backboard is 12 1/3 feet and the backboard casts a shadow 19 1/5 feet. Find the angle of elevation of the sun (answer in units of degrees). Can someone help me with the formula? Thank you!
*Wednesday, June 19, 2013 at 9:10pm*

**Physics (algebra)**

Thanks Steve, taking a physics course for credit this summer, but I am going in to 9th grade and have not had trig yet. Thanks for the formula!
*Tuesday, June 18, 2013 at 6:16pm*

**Physics (algebra)**

depends on what you want to find. The depth of the sub is d/4601 = sin32° Looks like you need to review your trig ratios
*Tuesday, June 18, 2013 at 4:04pm*

**trig**

2x = 45,315,... Follow for 2 periods to get values for x up to 360.
*Monday, June 17, 2013 at 10:13am*

**trig**

2sin2θ = √3 sin2θ = √3/2 sin(x) is positive in QI,QII 2θ = 60°,120°,... we need to go for two periods because we're dealing with 2θ. That gives us θ = 30°,60°,210°,240°
*Monday, June 17, 2013 at 10:12am*

**trig**

Find all values of ¸ in [0°, 360°) that satisfy the equation. 2 sin 2θ - √(3) = 0
*Monday, June 17, 2013 at 9:47am*

**trig**

Find all real numbers in [0, 2π) that satisfy the equation. cos 2x = √(2)/2
*Monday, June 17, 2013 at 9:46am*

**trig**

arctan(1.85) = 61.6° tan(x) < 0 in QII, QIV, so x = (180-61.6) = 118.4° x = (360-61.6) = 298.4°
*Monday, June 17, 2013 at 4:34am*

**trig**

tan(x+y) = (tanx + tany)/(1-tanx tany) so, what you have is tan(25°+5°) = tan 30° = 1/√3
*Monday, June 17, 2013 at 4:31am*

**trig**

what's all this work? A is in QI, so sinA = √8/3 B is in QIV so cosB = √3/2 and then as done in the final paragraph
*Monday, June 17, 2013 at 4:30am*

**trig**

Find all angles in degrees that satisfy the equation. Round approximate answers to the nearest tenth of a degree. tan α = -1.85
*Monday, June 17, 2013 at 12:58am*

**trig**

cos A = 1 / 3 sin A = + OR - sqrt ( 1 - cos A ^ 2 ) sin A = + OR - sqrt ( 1 - ( 1 / 3 ) ^ 2 ) sin A = + OR - sqrt ( 1 - 1 / 9 ) sin A = + OR - sqrt ( 9 / 9 - 1 / 9 ) sin A = + OR - sqrt ( 8 / 9 ) sin A = + OR - sqrt ( 4 * 2 / 9 ) sin A = + OR - sqrt ( 4 ) * sqrt ( 2 ) / sqrt...
*Monday, June 17, 2013 at 12:42am*

**trig**

Use a sum or difference identity to find the exact value. tan 25deg + tan 5deg / 1-tan 25deg tan 5deg
*Monday, June 17, 2013 at 12:40am*

**trig**

Find cos(A+B). cos A=1/3 and sin B=-1/2, with A in quadrant I and B in quadrant IV.
*Sunday, June 16, 2013 at 11:20pm*

**trig**

Since (5,12,13) is a Pythagorean triplet, tan(θ)=5/12. Mathematically, we solve it by: Divide by the right hand side: (5/13)sin(θ)+(12/13)cos(θ)=1 Since (5/13)²+(12/13)²=1, we can put 5/13=sin(φ) 12/13=cos(φ) so sin(φ)sin(&theta...
*Saturday, June 15, 2013 at 11:03am*

**trig**

if 5sin theta + 12cos theta is equal to 13 find the value of tan theta
*Saturday, June 15, 2013 at 8:41am*

**trig**

Sin < 0-----> quadrant 3 and 4 Sec > 0 ---- quadrant 1 and 4 sec = 1/cos Answer is quadrant 4
*Friday, June 14, 2013 at 6:30pm*

**Algebra 3 and trig**

distance is √(177^2 + 265^2) bearing is (90-θ) where tanθ = -265/177
*Thursday, June 13, 2013 at 5:28am*

**Algebra 3 and trig**

An ocean liner is 177 miles due west of lighthouse A. Lighthouse B is 265 miles due south of lighthouse A. Find the distance from lighthouse B to the liner and the bearing of the ocean liner from lighthouse B.
*Wednesday, June 12, 2013 at 6:22pm*

**trig**

sin negative, cosine positive? sin is negative III, IV cosine positive I, III
*Wednesday, June 12, 2013 at 3:27pm*

**trig**

quadrant 1
*Wednesday, June 12, 2013 at 3:19pm*

**trig**

for the given angle, name the quadrant in whihc the terminal side lies. -350deg
*Wednesday, June 12, 2013 at 2:25pm*

**trig**

identify the quadrant in which 0 lies. sin < 0 and sec > 0
*Wednesday, June 12, 2013 at 2:02pm*

**trig**

determine the period of the function. y = cot 4t
*Wednesday, June 12, 2013 at 1:26pm*

**trig**

for (-3,4) x = -3, y = 4 cotØ = x/y = - 3/4
*Tuesday, June 11, 2013 at 8:12pm*

**trig**

cosØ = x/r = 2/7 so x=2 , r = 7 2^2 + y^2 = 7^2 y^2 = 45 = ± 3√5 but we are in IV , so y = -3√5 sinØ = -3√5/7
*Tuesday, June 11, 2013 at 8:11pm*

**trig**

sin positive, quad I and II Tan negative, Quad II, IV Quad II
*Tuesday, June 11, 2013 at 8:04pm*

**trig**

Identify the quadrant in which θ lies. sin > 0 and tan < 0
*Tuesday, June 11, 2013 at 7:59pm*

**trig**

Find the trigonometric function value of angle θ. Cos θ = 2/7 and θ is in quadrant IV. Find sin θ.
*Tuesday, June 11, 2013 at 7:30pm*

**trig**

The point (-3, 4) is on the terminal side of angle θ in standard position. Find cot θ.
*Tuesday, June 11, 2013 at 7:24pm*

**trig**

angular velocity: 1st wheel : 2π rad/30 sec = π/15 rad/sec 2nd wheel : 2π radians/15 sec = 2π/15 rad/sec linear velocity 1st wheel: circumference = 2π(20) = 40π ft linear velocity = 40π/30 ft/sec = 4π/3 ft/se 2nd wheel: circumf = 20π...
*Tuesday, June 11, 2013 at 6:42pm*

**trig**

construct your triangle in the third quadrant, using Pythagoras, you know r^2 = (-2)^2 + (-3)^2 = 13 r = √13 then cosØ = x/r = -2/√13 , then sec Ø = -√13/2
*Tuesday, June 11, 2013 at 6:37pm*

**trig**

Given that θ is an angle in standard position whose terminal side contains the given point, provide the exact value of the indicated function. (-2, -3) Find sec θ.
*Tuesday, June 11, 2013 at 4:31pm*

**trig**

ferris wheel one has a 40ft diameter, revolves once every 30 seconds and is 5ft above ground. Ferris wheel two has a diameter of 20feet, revolves once every 15seconds and is 2 feet above the ground. each angular velocity?? each linear velocity??
*Tuesday, June 11, 2013 at 3:26pm*

**math - trig**

You know that sinØ = y/r cosØ = x/r tanØ = y/x cscØ = r/y etc so in any point the first coordinate is the x, the 2nd is the y 1. for (-12, -5) you would be in quadrant III x = -12, y = -5 use Pythagoras, x^2 + y^2 = r^2 ( where we keep r always ...
*Tuesday, June 11, 2013 at 8:52am*

**math - trig**

1. Find csc A, cos A and tan A of an angle A whose terminal side contains (– 12, – 5). 2. Find sin X, sec X and cot X of an angle X whose terminal side contains (– 3, 5).
*Tuesday, June 11, 2013 at 4:11am*

**Trig**

I get 252.717 or 253
*Monday, June 10, 2013 at 11:36pm*

**Trig**

I got 263.
*Monday, June 10, 2013 at 8:55pm*

**Trig**

did you make a sketch? I have , top of tower -- P , bottom of tower Q closer point A farther point B In triangle PBA angle B = 29°5' angle BAP = 142°55' angle BPA = 8° AB = 120 by sine law: PA/sin 29°5' = 120/sin 8° PA = 419.1165 now triangle ...
*Monday, June 10, 2013 at 8:29pm*

**Trig**

The angle of elevation from a point on the ground to the top of a tower is 37deg5'. The angle of elevation from a point 120 feet farther back from the tower is 29deg5'. Find the height of the tower (to the nearest foot).
*Monday, June 10, 2013 at 7:06pm*

**Math Help**

Permutation and combinations (Trig/alg2 class) In how many ways can all the letters in SEYCHELLES be arranged?
*Sunday, June 9, 2013 at 11:51pm*

**Trig**

Oops. 11pi/9 > pi, so subtract pi to get 2pi/9 play around adding and subtracting 2pi or pi till you get an angle in QI.
*Sunday, June 9, 2013 at 5:17pm*

**Trig**

-7pi/9 + 2pi = 11pi/9 This is in QII, so we need to subtract it from pi: pi - 11pi/9 = 7pi/9 You can also subtract 2pi if the angle is large and positive.
*Sunday, June 9, 2013 at 5:15pm*

**MATH - **

Permutation and combinations (Trig/alg2 class) In how many ways can all the letters in SEYCHELLES be arranged?
*Sunday, June 9, 2013 at 2:52pm*

**Trig**

Find the reference angle θ'. θ= -7pi/9
*Saturday, June 8, 2013 at 11:55pm*

**Math Trig Find Quadrant I II III IV**

Think of degrees if radians give you trouble π radians = 180° so (-5/6)π radians = -(5/6)(180)° = -150° so going clockwise 150° would put you into quadrant III
*Saturday, June 8, 2013 at 11:18pm*

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