Recent Homework Questions About Trigonometry
Math - Trig
Still don't get it, so yes need more help.
Thursday, October 10, 2013 at 12:46am
we know we want y = a sin(bx+c) + d diameter is 2, so radius=1, and we have y = a sin(bx+c) + 1 Starting at t=0, the bead starts going downward, so y = -sin(bx+c)+1 If we make it so the axle is at (0,1) at t=0, we need to shift the graph to the right by 1, since the bead is on...
Monday, October 7, 2013 at 4:11am
Thursday, October 3, 2013 at 4:22pm
H(x) = sin2x cos2x = 1/2 sin4x That help? Using the product rule, it's a bit more work, but you can get the same answer: dH/dx = 2cos2x cos2x - 2sin2x sin2x = 2(cos^2 2x - sin^2 2x) = 2cos4x Don't forget your trig just because you're taking calculus! #2 df/dx = (u...
Thursday, October 3, 2013 at 3:52am
Go with Bosnian - Trig
sorry Kiki don't know how I missed that 2 in front of 2x^2 Go with Bosnian's solution or, how about this... 2x^2 + 2x > 4 x^2 + x - 2 > 0 (x+2)(x-1) > 0 (x+2>0 and x-1<0) OR ( x+2 < 0 and x-1 > 0 ) ( x>-2 and x<1) OR x< -2 and x> 1 -2 &...
Sunday, September 29, 2013 at 2:17pm
math - trig
sinA = a/c = cosB cosA = b/c = sinB tanA = a/b = cotB plug and chug.
Wednesday, September 25, 2013 at 4:09am
(x+1)(x-4) >= (x-2)^2 x^2-3x-4 >= x^2-4x+4 x >= 8 for the graphs, go to wolframalpha.com and enter plot y=(x+1)(x-4) , y=(x-2)^2, x=6..10 or, enter (x+1)(x-4)-(x-2)^2 and see where it's positive
Monday, September 23, 2013 at 2:57pm
SAme solution, but you should have the two solutions. it should be 45+45-37.5 degrees (if you think on the trig equations you get, you see why).
Wednesday, September 18, 2013 at 4:17pm
looks like "homework dumping" to me I have two of them for you. Please indicate where you are having difficulties with these standard type of trig questions.
Tuesday, September 17, 2013 at 11:24pm
make quick sketches of right-angled triangles for each of the two cases, and use Pythagoras to find the missing sides. first triangle: since sinA = 12/13 , y = 12 and r = 13 x^2 + y^2 = r^2 x^2 + 144 = 169 x^2 = 25 x = ±5, but we are in quad II, so x = -5 then tanA = - ...
Tuesday, September 17, 2013 at 11:22pm