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April 19, 2014

April 19, 2014

**Recent Homework Questions About Trigonometry**

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**trig**

Use the sine law sinA/18 = sin125°/42 sinA = .351065.. A =appr 20.55°
*Wednesday, May 16, 2012 at 10:46pm*

**trig**

(csc^2 Ø - 1)/csc^2 Ø = 1 - 1/csc^2 Ø = 1 - sin^2 Ø = cos^2 Ø
*Wednesday, May 16, 2012 at 10:43pm*

**trig**

the period of tan kØ is π/k (which is also true for cotangent) so period of -2cot (x/5) is π/(1/5) = 5π
*Wednesday, May 16, 2012 at 10:39pm*

**trig**

inverse cos 4/5 = cos^-1 (4/5) = .6435.. then tan^-1 x = .6435... x = tan .6435... = .75 or, make a diagram with sides 3-4-5 then, if tan^-1 x = cos^-1 (4/5) then x = tan (cos^-1(4/5) ) = 3/4 or .75
*Wednesday, May 16, 2012 at 10:36pm*

**trig**

1 rotation = 2π radians so the angular velocity at 100 revs/sec = 100(2π) radians/sec = ....
*Wednesday, May 16, 2012 at 10:28pm*

**trig**

Cos^2(x) - Sin^2(x) = Cos(2 x) So, you can write the expression as cos(8 theta)
*Wednesday, May 16, 2012 at 10:15pm*

**trig**

inverse tan x = inverse cos 4/5
*Wednesday, May 16, 2012 at 9:35pm*

**trig**

A wheel rotates at 100 revolutions per second. find the angle velocity in radians per second.
*Wednesday, May 16, 2012 at 9:32pm*

**trig**

find the single term of cos^2 4theta - sin^2 4theta
*Wednesday, May 16, 2012 at 9:23pm*

**trig**

find the period of f(x)=-2cot x/5
*Wednesday, May 16, 2012 at 9:21pm*

**trig**

what is the single term of csc^2 theta-1 over csc^2 theta
*Wednesday, May 16, 2012 at 9:15pm*

**trig**

what is the angle of A? C = 125 degrees, a = 18, and c = 42
*Wednesday, May 16, 2012 at 9:11pm*

**trig**

84*PI/180
*Wednesday, May 16, 2012 at 8:56pm*

**trig**

SA= PI-PI/8= 7PI/8
*Wednesday, May 16, 2012 at 8:56pm*

**trig**

find the supplimentary angle of pie over 8
*Wednesday, May 16, 2012 at 8:45pm*

**trig**

find the exact radian of 84 degrees
*Wednesday, May 16, 2012 at 8:44pm*

**trig**

What is 1/3 ?
*Wednesday, May 16, 2012 at 8:44pm*

**trig**

Find the amplitude of f(t)=1/3sin8t
*Wednesday, May 16, 2012 at 8:43pm*

**Trig **

Find the eccentricity of the ellipse. x^2+7y^2=35
*Wednesday, May 16, 2012 at 7:26pm*

**trig and combine function**

Suppose f(x)=cos x - sin x and g(x)=cos x + sin x. Explain why the graph of (fxg)(x) is equivalent to the graph of h(x)=cos x after it has been horizontally compressed by a factor of 1/2. Thanks so much...
*Wednesday, May 16, 2012 at 6:13pm*

**trig - correction**

bzzt, but thanks for playing 3e^2x=18 e^2x = 6 2x = ln6 x = 1/2 ln6
*Wednesday, May 16, 2012 at 4:04pm*

**trig**

thank you
*Wednesday, May 16, 2012 at 2:40pm*

**trig**

x=6/e^2
*Wednesday, May 16, 2012 at 2:30pm*

**trig**

3e^2x=18
*Wednesday, May 16, 2012 at 2:24pm*

**trig**

Here is a standard way to solve these kind of problems, I will do the first one sinx = -.35 , 180 < x <270 1. Find the acute angle, sometimes called the "angle in standard position" by using the positive decimal if sinx = .35, x = 20.5° but x is supposed to...
*Tuesday, May 15, 2012 at 9:27pm*

**trig**

solve for the equation x sin x= -.35 180<x<270 sin x= .2 90<x<180 cos x = -.72 180< x<270 please explain, thanks :)
*Tuesday, May 15, 2012 at 8:40pm*

**Trig**

1/cos + sin/cos = 1 1 + sin = cos 1 + 2sin + sin^2 = cos^2 = 1 - sin^2 2sin^2 + 2sin = 0 2sin(sin+1) = 0 sin=0 or sin = -1 x = 0, π, 3π/2 but, sec and tan are not defined at 3π/2, and π does not satisfy the original equation, so the solution is 0. so, x = ...
*Tuesday, May 15, 2012 at 5:41pm*

**Trig**

Ok i understand how to do these I'm just stuck on this one: secx + tanx = 1
*Tuesday, May 15, 2012 at 4:20pm*

**Pre-Calculus-Trig**

2044
*Monday, May 14, 2012 at 8:01pm*

**trig**

Here is the page of identities: http://www.trans4mind.com/personal_development/mathematics/trigonometry/sumProductCosSin.htm#Products I can not possibly help you on here typing all this. Plan on getting a yellow legal pad and be careful.
*Sunday, May 13, 2012 at 9:12pm*

**trig**

2sin(4x)[(cos(3/2)x)(cos(5x/2)-sin((15/4)x)]+x can someone simplify this using trig identities?
*Sunday, May 13, 2012 at 9:08pm*

**trig! please help!**

to bobpursely: i need to simplify the expression using trig identities. and no i meant for there to only be x
*Sunday, May 13, 2012 at 9:07pm*

**trig! please help!**

What is the question? Is there an equal sign in the above? Are there two variables, t and x?
*Sunday, May 13, 2012 at 9:02pm*

**trig! please help!**

2sin(4t)[(cos(3/2)x)(cos(5x/2)-sin((15/4)x)]+x
*Sunday, May 13, 2012 at 8:59pm*

**trig pre calc**

cosx secx=1 cos^2 *csc^2= ctn^2 x 1+ctn^2=csc^2 multipy left by sin^2/sin^2 1/sin^2 (sin^2+cos^2)= csc^2 = csc^2
*Sunday, May 13, 2012 at 8:44pm*

**trig pre calc**

cos x (sec x +cos x csc2x)=csc2x
*Sunday, May 13, 2012 at 8:16pm*

**trig**

Hmmmm. Wondering if you are taking calculus. Calculus y=sinxcosx y'=0=cos^2x-sin^2x cos^2x=sin^2x tan^2 x=1 tanx= +-1 which occurs at increments of 45 degrees x= +-PI/4, PI+-Pi/4 check that
*Sunday, May 13, 2012 at 12:46pm*

**trig**

find the values of x between 0 and 2 pi where the tangent line to the graph of y = sinxcosx is horizontal
*Sunday, May 13, 2012 at 10:40am*

**geom/trig**

The base of a right rectanglar prism is 12 cm by 8 cm. The height is 5 cm. Find its surface area.
*Friday, May 11, 2012 at 3:39pm*

**trig**

cos ( pi - x )= - cos x
*Friday, May 11, 2012 at 2:02pm*

**trig**

cos(π-x)=
*Friday, May 11, 2012 at 1:18pm*

**trig**

isn't this a difference of two squares? I assume it all is equal to zero... (1-sqrt2*sin2x)(1+sqrt2*sin2x)=0 solve for 2x, then x.
*Thursday, May 10, 2012 at 6:56pm*

**trig**

1-2sin^2(2x)
*Thursday, May 10, 2012 at 6:52pm*

**trig**

two dice are rolled, find p(2,then 3)
*Thursday, May 10, 2012 at 1:16pm*

**Trig**

(1-2Sin^2 X)^2 + 4sin^2 X Cos^2 X (sin^2 x + cos^2 x - 2sin^2 x)^2 + (2sinxcosx)^2 = (cos^2x - sin^2x)^2 + (sin 2x)^2 = (cos 2x)^2 + (sin 2x)^2 = 1
*Monday, May 7, 2012 at 8:19pm*

**Trig**

simplify the expression to a single term: (1-2Sin^2 X)^2 + 4sin^2 X Cos^2 X I'm not sure how to start this or which identities to use. Any suggestions?
*Monday, May 7, 2012 at 8:01pm*

**Trig**

I believer picture cards are the K, Q, and J so there are 12 of them prob(3 picture cards of 3 drawn) = (12/52)(11/51)(10/50) = 11/1105
*Monday, May 7, 2012 at 7:34pm*

**Trig**

If you are dealt 3 cards from a shuffled deck of 52 cards, find the probability that all 3 cards are picture cards.
*Monday, May 7, 2012 at 7:22pm*

**math algebra trig**

For all these problems, we only have to complete the squares and transform the equations to the form y=a(x-h)²+k then (h,k) is the vertex. If a>0, the vertex is a minimum, and if a<0, then the vertex is a maximum. a) y=-x²+4x-7 =-1(x-2)²-3 So (h,k)=(2,-3) ...
*Sunday, May 6, 2012 at 8:10am*

**algebra-trig help asap**

Write an equation I'm not sure how to do this though. The sine of x with an amplitude of 4, period of 3(pie) and phase shift to the right of pie/4
*Saturday, May 5, 2012 at 7:53pm*

**math algebra trig**

For the graph of each function, find an equation of the line of symmetry and the coordinates of the vertex. Tell whether the value of the function at the vertex if a maximum or a minimum: a) y = -x^2 + 4x - 7; b) y = 2x^2 + 4x; c) y = -3x^2 - 18x + 5.
*Saturday, May 5, 2012 at 7:42pm*

**algebra-trig help asap**

An isosceles triangle has a base 36 cm long and a base of 65 degrees. Find its perimeter. I'm not sure if this is right but my answer is 1250.4 in^2
*Saturday, May 5, 2012 at 6:48pm*

**PreCalculus (PLEASE HELP, IM BEGGING!)**

Can anyone please explain these problems to me?? I really need help!I need to simplify these trig expressions but I don't understand how my teacher is doing it at all and I have a quiz on this tomorrow! I've really been trying but I just don't get it! 1)Mulitply: [...
*Saturday, May 5, 2012 at 2:09am*

**trig**

from 5tanx - 12 = 0 tanx = 12/5 make a sketch of a right-angled triangle, in quad I where x is the angle at the origin, the other acute angle is y the hypotenuse would be 13 , from the 5-12-13 right-angled triangle then 2sin^2 x + cosy = 2(12^2 / 13^2) + 12/13 = 288/169 + 12/...
*Thursday, May 3, 2012 at 11:22am*

**trig - nope**

sorry, no diagrams here
*Thursday, May 3, 2012 at 10:08am*

**trig**

If x and y are complementary angles and 5 tan x-12=0,calculate by using a diagram the value of 2sin(squared)x+cos y.
*Thursday, May 3, 2012 at 3:04am*

**Trig**

T=1/F
*Wednesday, May 2, 2012 at 4:45pm*

**trig**

Not sure if you are better thinking in terms of degrees or radians, most people are more familiar with degrees 11π/8 radians = 247.5° so cos(11π/8) = cos(247.5°) (in quad III) = -cos 67.5 let that sit. 67.5 = 90-22.5 cos 67.5 = cos(90-22.5) = sin 22.5 (...
*Monday, April 30, 2012 at 10:24pm*

**trig**

I don't understand how to fnd it though Reiny :( perhaps you could help?
*Monday, April 30, 2012 at 10:12pm*

**trig**

(x,y) = (20.6cos102.5° , 20.6sin 102.5°)
*Monday, April 30, 2012 at 10:02pm*

**trig**

Oh I'm sorry. It's cosine (11pi/8) :)
*Monday, April 30, 2012 at 9:59pm*

**trig**

yea what reiny said
*Monday, April 30, 2012 at 9:59pm*

**trig**

11π/8 is an exact value. where does the trig part of your question come in? Was is something like sin (11π/8) ?
*Monday, April 30, 2012 at 9:58pm*

**trig**

What is the exact value of 11pi/8? (with steps please) :)
*Monday, April 30, 2012 at 9:55pm*

**trig**

to be perpendicular, the dot product must be zero to be parallel, one must a scalar multiple of the other. The question is very easy.
*Monday, April 30, 2012 at 9:30pm*

**trig**

Determine whether the vectors are parallel, perpendicular or neither. 1) v = (4,1), w = (1,-4) 2) v = (2,3), w = (4,6) 3) v = (2,3), w = (3,-3) Please and thanks!
*Monday, April 30, 2012 at 9:15pm*

**trig**

Find the component form for vector v with the given amplitude and direction angle theta. |v|=20.6, theta=102.5deg
*Monday, April 30, 2012 at 8:51pm*

**trig**

tan = -10 sqrt2/ -10 sqrt 2 becomes tan=1 which is 45degree
*Monday, April 30, 2012 at 8:20pm*

**trig**

(-10√2, -10√2), find te magnitude and direction angle of the vector, measure the direction angle in [0, 360). Please help!
*Monday, April 30, 2012 at 8:16pm*

**trig**

What is 3*11+7*(-5) ?
*Monday, April 30, 2012 at 6:53pm*

**trig**

Find the dot product of u and v u= 3i+7j v= 11i-5j
*Monday, April 30, 2012 at 6:42pm*

**trig problem**

F = 1c/min = 1rev/min. = Frquency. P = 1/F = 1min/rev. = The period. T = 13:12:40 - 13:0:0 = 12min,40s. = 12 2/3 min. = 38/3 min. 1rev/min * (38/3)min = 12 2/3 rev. (2/3)rev * 360Deg/rev = 240 Deg. Ar=240-180 = 60 Deg.=Reference angle. h = hmax*sinAr = 6*sin60 = 5.2 m.
*Monday, April 30, 2012 at 3:05pm*

**Application prob. for Trig.**

Hi, A fountain in a shopping centre has a single jet of water. The height of the jet of water varies according to a sinusoidal function. A student notes that, in exactly one minute, the jet goes from a minimum height of 2m to a maximum height of 6m and back to 2m. At 13:00, ...
*Monday, April 30, 2012 at 1:19pm*

**trig**

since it's a max at t=0, that indicates a cosine function The period is 1, so we are looking at cos(2pi*t) max is 120, min is 80, so amplitude is 20, and oscillates around h=100, and our function is f(t) = 100 + 20cos(2pi*t)
*Monday, April 30, 2012 at 11:54am*

**trig**

At rest, the human heart beats once every second. At the strongest part of the beat, a person's blood pressure peaks at 120mmHg. At the most relaxed part of the beat, a person's blood pressure drops to 80mmHg. Supposing that t = 0 corresponds to the peak of the beat, ...
*Monday, April 30, 2012 at 4:05am*

**Pre-Calc/Math**

1) rewrite cosx (cosx/sinx) + sinx = csc x 2) cosx^2/sinx + sinx = csc x 3) multiply sinx by (sinx/sinx) to get same denominator this gives you cosx^2/sinx + sinx^2/sinx = cscx 4) combine your fractions (cosx^2 + sinx^2)/sinx = cscx 5) rewrite numerator 1/sinx= csc x and there...
*Monday, April 30, 2012 at 1:00am*

**trig - incomplete**

"near" doesn't mean anything. If the man is 100 ft from the tree, a 4-ft shadow means the tree is enormous. If the man is 2 ft from the tree, the tree is short.
*Monday, April 30, 2012 at 12:18am*

**trig**

a 6 foot tall man is standing near a tree on level ground .if the man shadow 4 feet long .how many feet tall is the tree?
*Sunday, April 29, 2012 at 11:08pm*

**Trig. application**

C = pi * D = 3.14 * 2*25.5 = 160.14 cm. = 1.614 m = Circumference. V = 30km/h = 30,000m / 60min=500 m/min. d = 500m/min * 4min = 2000 m. 2000m / 1.614m/rev =1239.157373 revolutions. A = 90 + 0.157373*90 = 104.2 Deg. h = 25.5 + 25.5*sin104.2 = 50.2 cm.
*Sunday, April 29, 2012 at 10:29pm*

**Honors Trig.**

Here is an easy way to do these. 1) convert all angles to 000N,090E, 180S, 270W Example: 456@29deg S of E. = 456@119 then convert to N, E coordinates. V= 456(Cos119 N + Sin119 E) Now for your problem: V= 550(cos295 N +sin295 E)+28(cos109 N+ sin109) combine N, E vector ...
*Sunday, April 29, 2012 at 2:49pm*

**Honors Trig.**

A plane is flying at a speed and direction of 550 mph, 25 degrees north of west. There is a wind of 28 mph, at an angle of 19 degrees south of the east direction. How fast is the plane actually flying? What direction is the plane traveling?
*Sunday, April 29, 2012 at 2:38pm*

**Maths trig**

Whats the workings out to get to these answers ? Jw ta
*Sunday, April 29, 2012 at 12:29pm*

**Maths trig**

Thanks :)
*Sunday, April 29, 2012 at 12:27pm*

**Maths trig**

sin2t = 2 sint cost sin3t = sint cos2t + cost sin2t (cos2t = 1 - 2sin^2 t)
*Sunday, April 29, 2012 at 10:50am*

**Maths trig**

Use compound angle formulae to express Second harmonic i2= sin2t and the the third harmonic i3=sin3t in terms of the first harmonic sint
*Sunday, April 29, 2012 at 2:06am*

**algebra2/trig**

1) looks like you are dealing with the cubes so term(n) = n^3 2) did you notice that each term is one less than a perfect square? e.g. 3 = 2^2 - 1 --term(1) 8 = 3^2 -1 -- term(2) 15 = 4^2 -1 24 = 5^2 - 1 35 = 6^2 - 1 so term(n) = (n+1)^2 -1
*Saturday, April 28, 2012 at 10:43pm*

**algebra 2/trig**

1) a (n ) = n ^ 3 1 ^ 3 = 1 2 ^ 3 = 8 3 ^ 3 = 27 4 ^ 3 = 64 5 ^ 3 = 125 6 ^ 3 = 216 2 ) a (n ) = n ^ 2 + 2 n 1 ^ 2 + 2 * 1 = 1 + 2 = 3 2 ^ 2 + 2 * 2 = 4 + 4 = 8 3 ^ 2 + 2 * 3 = 9 + 6 = 15 4 ^ 2 + 2 * 4 = 16 + 8 = 24 5 ^ 2 + 2 * 5 = 25 + 10 = 35 6 ^ 2 + 2 * 6 = 36 + 12 = 48
*Saturday, April 28, 2012 at 10:31pm*

**TRIG**

one rotation is 5π ft so the hypotenuse has length 5π and sin 15 = height/(5π) height = 5π sin 15° = ......
*Saturday, April 28, 2012 at 10:12pm*

**algebra 2/trig**

Write the next term of sequence,and then write the rule for the nth term. 1)1,8,27,64,....125 the nth is 2) 3,8,15, 24,.....35 the nth is Can you help me and correct ? thank
*Saturday, April 28, 2012 at 9:16pm*

**TRIG**

5. A wheel 5.00 ft in diameter rolls up a 15.0° incline. How far above the base of the incline is the top of the wheel after the wheel has completed one revolution? A. 4.07 ft B. 13.1 ft C. 8.13 ft D. 9.07 ft
*Saturday, April 28, 2012 at 9:05pm*

**algebra2/trig**

Write the next term of sequence,and then write the rule for the nth term. 1)1,8,27,64,....125 the nth is n 2) 3,8,15, 24,.....35 the nth is Can you help me and correct ? thank you
*Saturday, April 28, 2012 at 7:55pm*

**trig question**

Sorry, the web address is spaced out so you need to put it together..again sorry, but I really need the help. Much appreciated!
*Saturday, April 28, 2012 at 6:05pm*

**trig question**

Hi, my question is attached to the web below (picture), because I can't draw the diagram on here. Sorry for any inconvenience. Please help and thanks. imageshack . us/photo/my-images / 845 / img0043gx . jpg/
*Saturday, April 28, 2012 at 6:02pm*

**trig question**

But the question ask to find the area of AE and EB together
*Saturday, April 28, 2012 at 5:55pm*

**trig-math**

4. A carpenter wants to be sure that the corner of a building is square and measures 6.0 ft and 8.0 ft along the sides. How long should the diagonal be? A. 12 ft B. 10 ft C. 11 ft D. 14 ft 5. A wheel 5.00 ft in diameter rolls up a 15.0° incline. How far above the base of ...
*Saturday, April 28, 2012 at 4:32pm*

**math-TRIG**

i thank you for the one u did i have 40 of these i got the ans to the rest these are the one i could figure out so plz any help i acan get i thNK U a lot
*Saturday, April 28, 2012 at 3:40pm*

**math-TRIG**

1. Which angle measure is consistent with all of the following criteria? (i) The reference angle is 40°. (ii) The angle is more than one revolution. (iii) The angle's terminal side is in Quadrant II. (iv) The angle isn't positive. A. –580° B. –500°...
*Saturday, April 28, 2012 at 3:33pm*

**trig question**

sorry 1 = EO, the side along the x axis
*Saturday, April 28, 2012 at 3:31pm*

**trig question**

a 30,60 , 90 triangle has sides 1 =AO, sqrt 3 = EA and hypotenuse 2 AB = 2 sqrt 3 your angle AOB is 2*60 = 120 OE the altitude is 1 Your area = (1/2)(1)(2 sqrt 3) = sqrt 3
*Saturday, April 28, 2012 at 3:30pm*

**trig question**

NEW DIAGRAM: On a unit circle, sin x = square root 3 over 2, with center O. Vertical line from top to center of circle is PO. Horizontal line from middle to right of circle is OE. Another vertical line of AB is parallel to PO. And radius of circle (line from O to A) is 1 unit...
*Saturday, April 28, 2012 at 2:57pm*

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