Recent Homework Questions About Trigonometry
A 16 - foot ladder leaning against the side of a house reaches 12 feet up the side of the house. What angle does the ladder make with the ground
Sunday, September 23, 2012 at 5:02pm
a) one rotation = 2π radians so 4400 rpm = 2π(4400) radians/min = 8800π rad/min = appr 27646 rad/min b) one rotation = 2π(8.5) inches = 17π inches so 4400 rotations would be 17π(4400) inches = 74800π so the linear speed of a tooth = 74800...
Sunday, September 23, 2012 at 2:41pm
A circular power saw has an 8-1/2 inch diameter blade that rotates at 4400 revolutions per minute. a)Find the angular speed of the saw blade in radians per minute. b)Find the linear speed in feet per minute of one of the 24 cutting teeth as they contact the wood being cut. I...
Sunday, September 23, 2012 at 12:26pm
Write 8y = 300 in its equivalent logarithmic form
Friday, September 21, 2012 at 3:52pm
if the flagpole has height h, h/44 = tan 60.5° h = 77.77 now you want the angle x where 77.77/88 = tan x x = 41.5°
Tuesday, September 18, 2012 at 10:59am
What does the ladder have to do with the flagpole?
Monday, September 17, 2012 at 11:35pm
A flagpole casts a shadow 44 ft with the sun angle of elevation is 60.5 degrees. Find the height of the flagpole and at what angle is the shadow twice as long?
Monday, September 17, 2012 at 11:18pm
A 16 ft ladder casts a shadow 44 ft with the sun angle of elevation is 60.5 degrees. Find the height of the flagpole and at what angle is the shadow twice as long?
Monday, September 17, 2012 at 11:16pm
I think you mean find all angles theta between 0 and 2pi.
Sunday, September 16, 2012 at 12:26pm
The way to get their answer is to complete the square and then use trig substitution. If you go to wolframalpha.com and type in ∫ (5x + 3) / (x^2 + 4x + 7) dx then click the "Show Steps" button you can see how they did it. If you want the final numeric answer, ...
Saturday, September 15, 2012 at 11:18pm
construct your right-angled triangle by drawing a perpendicular to the x-axis from (1,-4) then r^2 = x^2 + y^2 = 1 + 16 r = √17 b) sinA = -4/√17 cscA = -√17/4 cosA = 1/√17 secA = √17 tanA = -4/1 = -4 cotA = -1/4
Saturday, September 15, 2012 at 7:49pm
-20000/360 = -55.555555.. = -55 - 200/360 so we have 55 clockwise rotations and then another clockwise rotation of 160° OR 360-200 = 160° in the counterclockwise of positive rotation direction 160° is in the second quadrant, where the sine is positve and we are 20&...
Saturday, September 15, 2012 at 7:43pm
(a) sketch an angle A in standard position whose terminal ray passses through the point (1,-4) (b) Find the exact value of the six trigonometric functions of A, (c) Let B be the reference angle of A. Find a point on the terminal rsy of B in standard position and add B to your ...
Saturday, September 15, 2012 at 4:47pm
find the reference angle of -20000 and express the six trigonometric functions of -20000 in terms of the six trigonometric functions of its reference angle.
Saturday, September 15, 2012 at 4:40pm
my question is find all angles of theta and 2pi whose reference angle is alpha = pi/12. Give exact answers. i cannot for the live of me find this
Saturday, September 15, 2012 at 4:30pm
first of all, to make things easier to type, let's say h = delta x so your question becomes lim [ sin(π/6 + h) - sin π/6 ]/h , as h ---> 0 This looks like you want the derivative of sin x, when x = π/6 if f(x) = sinx f'(x) = cosx f'(π/6) = ...
Thursday, September 13, 2012 at 10:12am
One of the fundamental limits with trig expressions is Lim tanx/x = 1 , as x---> 0 so notice that you have exactly that pattern, so lim tan(4Ø)/(4Ø) =1 , assuming 4Ø ---> 0
Wednesday, September 12, 2012 at 2:42pm
Actually it probably has something to do with trig identities...
Tuesday, September 11, 2012 at 11:09pm
A 5'6" person is standing near a light post that is 18' above the ground. How long is the man's shadow when he is 5' from the base of the light post?
Tuesday, September 11, 2012 at 8:47pm
53. the longest side is 55 cm. find the length of the shortest side
Tuesday, September 11, 2012 at 7:59pm
Picture a right angled triangle with one side AB being 25 x 125 metres long to the west; the other side BC being 19 x 66 metres long to the south. The displacement is the length of the hypotenuse AC; the direction being between 180 degrees and west. Sketch it out, then do the ...
Tuesday, September 11, 2012 at 8:39am
Math - Trig
find in degrees and radians the angle between the hour hand and the minute hand of a clock at half past three
Sunday, September 9, 2012 at 8:44am
You're ok to this point: 10 sin^-1 (5x)(x) + 2√(1-25x^2) + C |1/5, 1/10 By this time you should realize that radians are the measure of choice for trig stuff. sin^-1(1/2) = pi/6 sin^-1(1) = pi/2 so you end up with [10(1/5 * pi/2) + 2√(1-1)] - [10(1/10 * pi/6...
Friday, September 7, 2012 at 10:07am
think back, back, back to your days in trig. d^2 = 350^2 + 400^2 - 2*350*400*cos 50 d = 320.19
Monday, September 3, 2012 at 12:42pm
think back, back, back to your days in trig. If the tower has height h, tan 67 = h/50 h = 117.8 m
Monday, September 3, 2012 at 12:36pm
unless you can measure the angle, you have to use similar triangles. If you can measure the angle sighting from the tip of the stick's shadow to the top of the stick, then tanθ = opposite/adjacent The same angle is made from the pole's shadow to the top of the ...
Friday, August 31, 2012 at 6:08pm
I think i have to use soh cah toa instead of similar triangles
Friday, August 31, 2012 at 4:46pm
stick a stick vertically in the ground. measure the height and shadow of the stick. measure the shadow of the tree, and use the same ratio to calculate its height. extra credit: why does this work?
Friday, August 31, 2012 at 4:17pm
lets say you have a tree or a flagpole. Describe how you would measure this object using right angled triganometry
Friday, August 31, 2012 at 11:35am
My calculator says sin(70°)=0.93969262
Friday, August 31, 2012 at 8:06am
what is the value of sin 70
Friday, August 31, 2012 at 1:51am
Sin (180 - A) = sin A. (angle in degrees) sin 120 = sin (180 - 60) = sin 60 Cos (180 - A) = - cos A cos 150 = cos (180 - 30) = - cos 30 tan (360 - A) = - tan A, tan 280 = tan (360 - 80) = - tan 80
Friday, August 31, 2012 at 12:20am
how to prove ; tan 10 degrees + tan 70 degrees - tan 50 degrees = sqrt 3
Friday, August 31, 2012 at 12:08am
velocity is v = dh/dt = -sin(2t) average v over an interval is ∫[1,3] dv/dt / (3-1) = 1/2 ∫[1,3] -sin(2t) dt = 1/2 (1/2 cos 2t) [1,3] = 1/4 (cos6-cos1) = 1/4 (.4198) = 0.105 Note that this is just the total displacement / total time h(pi)-h(0) = .5(1) - .5(1) = 0 ...
Wednesday, August 29, 2012 at 2:19pm
pick any real number x > 0. x/2 < x so there is always a smaller positive real same for rational numbers pick any y such that x < y The difference is (y-x) x < x + (y-x)/2 < y
Tuesday, August 28, 2012 at 3:09pm
prove that there exists no smallest possitive real number dose there exist a smallest positive rational number given a real number x, does there exist a smallest real y>x?
Tuesday, August 28, 2012 at 2:40pm
Now Sabrina, We did the previous problem for you. It is very similar to this problem. Please try it. It is really just trig.
Monday, August 27, 2012 at 8:11am
nevermind, I figured it out, it is approximately 4.1 x10^13 km from the star
Thursday, August 23, 2012 at 10:29pm
some stars are so far away that their position appear fixed as earth orbits the sun. other stars, however, appear over time to shift their positions relative to the background of "fixed" stars. suppose that the star shown below appears to shift through an arc of ...
Thursday, August 23, 2012 at 9:52pm
Monday, August 20, 2012 at 11:37am
The Tangent Function: tanA = Y/X = 8/6.
Wednesday, August 15, 2012 at 7:05pm
Imagine that you are sitting 6 feet away from a television that is hung on a wall. The top of the TV is 8 feet off the ground. Which function correctly represents the angle that you make with the top of your television?
Wednesday, August 15, 2012 at 2:34pm
how would I measure a distance or object using right angled trig?
Tuesday, August 14, 2012 at 10:43pm
If Ø is your angle, and since r=√(a^2 + b^2) sinØ = b/r cscØ = r/b cosØ = a/r secØ = r/a tanØ = b/a cotØ = a/b These definitions should be in your textbook and are probably defined in terms of x, y and r. You should ...
Monday, August 13, 2012 at 9:02pm
Let be an angle in standard position and the point (a, b) be the point of intersection of the terminal side of with the unit circle. State the unit circle definitions of the six trigonometric functions. cos = sec = sin = csc = tan = cot =
Monday, August 13, 2012 at 8:53pm
sin -1 as principal values in [-π/2,π/2] sin -1-.5 = -π/6
Monday, August 13, 2012 at 5:24pm
find the exact value of the expression , sin-1(-0.5)
Monday, August 13, 2012 at 3:58pm
sin(x) has amplitude 1, period 2pi, no phase shift sin(x-pi/3) is shifted pi/3 to the right sin(2(x-pi/3)) has period pi, shifted right by pi/3 2sin(2(x-pi/3)) meets the requirements. Do the others in lime wise. Recall that tan(x) has period pi, not 2pi.
Monday, August 13, 2012 at 12:15am
Sunday, August 12, 2012 at 8:46pm
Construct the equations of the following trigonometric functions: A)A sine function with amplitude 2, period , phase shift /3 right B)A tangent function with a reflection in the y-axis, period ¾, translation up 5 units C)A cosine function with period 270°, ...
Sunday, August 12, 2012 at 7:07pm
you know that sin(x) has maximum value at x = pi/2. So, x - pi/3 = pi/2, or x = 5pi/6. However, that is not in the interval [0,2]. So, try x - pi/3 = -3pi/2. x = -7pi/6. So, y does not achieve its maximum possible value over x in [0,2]. So, the max achieved in [0,2] occurs ...
Sunday, August 12, 2012 at 1:58pm
For the function -2sin(x-(pi/3)) between x = 0 and x = 2 : (6 marks) For what value(s) of x does y have its maximum value? For what value(s) of x does y have its minimum value? For what value(s) of x does y=1?
Sunday, August 12, 2012 at 1:44pm
Determine the period, amplitude and phase shift for each given function: A)y = -4 cos 3x + 5 B)y = 2/3 sin (30x-90degrees)-10 c)y = -0.38 tan (x/3+pi/3) d)y = pi cos(2x)+ pi
Sunday, August 12, 2012 at 1:33pm
start-> programs-> Accessories-> Calculator-> View-> Scintific 17 sin
Thursday, August 9, 2012 at 11:40pm
Please help to find the value of: Sin 17 degree.
Thursday, August 9, 2012 at 10:33pm
One of the first things I usually do is test if the identity is true by picking any value of x. Since it is an identity it should work for all value of x let x=10 LS = (1/cos80 -1)/(1/cos40-1) = appr 15.58 RS = tan80/tan40 = appr 6.758 so , not true, no point trying to prove it.
Thursday, August 9, 2012 at 12:39pm
(sec 8 x - 1)/(sec 4x -1) = tan 8x/tan 4x Prove it!
Thursday, August 9, 2012 at 11:57am
1. Which numbers are NOT perfect squares? 2. √48-5√27+2√75 = √16√3 - 5√9√3 + 2√25√3 = 4√3 - 15√3 + 10√3 = -√3 3. I will assume you meant √(x+2) - 3 = 0 then √(x+2) = 3 square both sides x...
Tuesday, August 7, 2012 at 10:46am
1. let y = x^3 + 5 inverse is x = y^3 + 5 y^3 = x-5 y = (x-5)^(1/3) yes , it is a function 2. (f∙ g)(2) = f(g(2)) = f(3) = 10 3. Come on, you can do this!
Tuesday, August 7, 2012 at 10:39am
1. which number below is irrational? a)√4/9 b) √20 c)√121 Why is the number you chose irrational? 2. express in simplest form: √48-5√27+2√75 3. solve for x: (√x+2)-3=0
Tuesday, August 7, 2012 at 9:59am
1. f(x)=x^3+5 does f(x) have an inverse? if so, find the inverse and decide if it is a function. 2. if f(x)= 3x+1 and g(x)= x^2-1, find (f∙ g)(2) 3. if f(x)= (2x)^2, find f(-4) thank you :)
Tuesday, August 7, 2012 at 9:51am
Given y = 3cos2x you know it has amplitude of 3, so its minimum value is y = -3, since there is no y-translation. Unless you are specifically doing calculus, I'd surely use my knowledge of trig to answer this one. Good analysis, though, Bosnian!
Saturday, August 4, 2012 at 12:11pm
Calculus 1 Integration Trig Inverse
see answer in prior post
Tuesday, July 31, 2012 at 11:03am
Caculus:Integration Inverse Trig
for integrating 1/√(x^2-1) use x = secθ Then x√(x^2-1) = secθtanθ dx = secθtanθ dθ The integral of the first term then becomes ∫4 dθ = 4θ = 4 arcsec(x) for integrating 1/(1+x^2) use x = tanθ dx = sec^2θ dθ...
Tuesday, July 31, 2012 at 11:02am
Calculus 1 Integration Trig Inverse
integral of (4/(x times the square root of (x^2-1)) + (1+x+x^3)/(1+x^2)dx
Monday, July 30, 2012 at 10:42pm
Caculus:Integration Inverse Trig
integral of (4/(x times the square root of( x^2-1)) + (1+x+x^3)/(1+x^2)dx
Monday, July 30, 2012 at 10:40pm
You can just use basic Trig a few times. First, find x1 and y1 (Im defining these as the x and y components of the first triangle, the one where a is the hypotenuse. I drew them in green in the diagram above). x1 = 175*cos(30) y1 = 175*sin(30) You can do the same thing ...
Sunday, July 29, 2012 at 1:50am
Radicals and Trig.
Thank you! Next question. What if instead they gave me the hypotenuse? 2/(sqrt2? Still tan 30.
Friday, July 27, 2012 at 10:50am
For the second, draw you triangle in quadrant II hypotenuse = 3 , opposite = 1 x^2 + 1 = 9 x = ±√8 or ±2√2 , but we are in II, so use x - -2√2 cosØ = -1/3 tanØ = - 1/2√2 ---> cotØ = -2√2 I don't know how ...
Friday, July 27, 2012 at 8:53am
so cos would be root 15/ 4 and cot would be 1/ root 15? one more question, how do you know it is in the second quadrant?
Friday, July 27, 2012 at 12:43am
given cosØ = 2/3 and cotØ > 0 so Ø must be in quadrant I make a sketch of a right -angled triangle with hypotenuse 3 and adjacent 2 then y^2 + 2^2 = 3^2 y = √5 and sin Ø - √5/3 tanØ = √5/2 do the second the same way (&...
Thursday, July 26, 2012 at 11:48pm
find sin theta and tan theta if cos theta = 2/3 and cot theta is >0 and find cos theta and cot theta if sin theta = 1/3 and tan theta is <0 thanks! :)
Thursday, July 26, 2012 at 11:23pm
cosine, sine, vary between 1, -1? So they cannot be in the correct answer.
Thursday, July 26, 2012 at 5:11pm
Which of the following lists contains only functions with vertical asymptotes in their graphs? A. Cosine, sine, tangent, cotangent B. Tangent, secant, cosecant, cotangent C. Sine, tangent, secant, cosecant D. Cosine, sine, secant, cosecant
Thursday, July 26, 2012 at 4:23pm
Radicals and Trig.
Because that is the value of tan 30 . The short side length is half the hypotenuse for a 30-60-90 triangle. If the hypotenuse length is 1, the Second longest side length must be sqrt[3/4] That makes the tangent of 30 degrees 1/(sqrt3)
Wednesday, July 25, 2012 at 10:08pm
Radicals and Trig.
I am catching up over summer on math units that I have to rewrite. In my textbook it asks me to find the base of two triangles and add them together. the smallest angle of the larger triangle is 30 degrees. The opposite side to the angle is 40cm. it gives me Tan 30 = 40/x 1/...
Wednesday, July 25, 2012 at 3:32pm
LS = (1+ tanØ)^2 = 1 + 2tanØ + tan^2 Ø = 1 + 2tanØ + sec^2 Ø - 1 = 2sinØ/cosØ + 1/cos^2 Ø = (2sinØcosØ + 1)/cos^2 Ø = (sin^2 Ø + cos^2 Ø + 2sinØcosØ)/cos^2 Ø = (sin&...
Tuesday, July 24, 2012 at 11:40am
Claim: For all theta such that -pie/2<theta<pie/2 the following holds true: (1+tan(theta))^2=1/cos(theta)
Tuesday, July 24, 2012 at 11:02am
Trig Help Please!!!
I didn't know this, and I feel like I was cheated by my geomtery teacher.I feel like I should have known this I am a math professor with a Ph.D. but I'm comforted to hear that a lot of other people didn't know about it, either.
Tuesday, July 24, 2012 at 1:41am
One of the basic trig identities says: cos 2A = cos^2 A - sin^2 A
Monday, July 23, 2012 at 1:08pm
Is the answer y = 21.15sin(pi/6 t + 3)+66.25?
Saturday, July 21, 2012 at 2:26pm
Did you make a sketch? if so , you will see that tan 1° = 12000/x , where x is the distance along the ground x = 12000/tan 1° = ..... "How far on the ground is the plane ? " sounds like a very strange question.
Friday, July 20, 2012 at 6:43pm
There is an airplane at an altitude of 12000 ft. The angle of depression is 1 degree. How far on the ground is the plane.
Friday, July 20, 2012 at 2:36pm
tan(25+5)= tan25+5/1-tan25tan5 tan(30)= tan25+5/1-tan25tan5 1/root(3)= tan25+5/1-tan25tan5 ur answer is 1/root(3)
Friday, July 20, 2012 at 6:27am
Thursday, July 19, 2012 at 10:52pm
looks like we have some "homework dumping" going on here. I will do one more, and let you looks at my methods. Then you tell me where you are having problems Again, you must mean (tanx + cotx)/cscx = secx LS = (sinx/cosx + cosx/sinx)(sinx) = (sin^2 x + cos^2 x)/(...
Thursday, July 19, 2012 at 2:18pm
You must mean (1-cosx)/sinx = sinx/(1+cosx) LS = (1-cosx)/sinx * (1+cosx)/(1+cosx) = 1 - cos^2 x)/(sinx(1+cosx) ) = sin^2 x/(sinx(1+cosx) ) = sinx/(1+cosx) = RS
Thursday, July 19, 2012 at 2:15pm
verify the following identity: 2sinxcos^3x+2sin^3cosx=sin(2x)
Thursday, July 19, 2012 at 12:50pm
verify the following identity: tanx+cotx/cscx=secx
Thursday, July 19, 2012 at 12:49pm
verify the following identity: cos(A-B)/cosAsinB=tanA+cotB
Thursday, July 19, 2012 at 12:48pm
verify the following identity: sin(x+y)*sin(x-y)=sin^2x-sin^2y
Thursday, July 19, 2012 at 12:47pm
Verify the following identity: 1-cosx/sinx=sinx/1+cosx
Thursday, July 19, 2012 at 12:45pm
Hi, thank you so much. Everything I tried hit all around the borders, but just was not working out correctly. I really appreciate your help.
Thursday, July 19, 2012 at 3:50am
total displacement north = 5 sin 30 + 10 cos20 = 2.5 + 9.397 = 11.897 miles total displacement east = 5 cos30 - 10 sin20 = 4.33 - 3.42 = 0.91 miles (a) sqrt[(11.897)^2 + (0.91)^2] = 11.93 miles (b) direction = tan^-1 0.91/11.897 E of N = 4.37 deg E of N
Thursday, July 19, 2012 at 1:18am
Hi, sorry it was 30 degrees North of East.
Wednesday, July 18, 2012 at 11:38pm
You left out an important number that is needed to compute the answer. It should follow the first word "direction". How many degrees is the first direction North of East?
Wednesday, July 18, 2012 at 11:14pm
Joe walks 5 miles in the direction degrees North of East, and then 10 miles in the direction 20 degrees West of North. (a) How far is Joe from his starting position? (b) In what direction is Joe from his starting position?
Wednesday, July 18, 2012 at 10:01pm
Simplify the expression using trig identities: 1. (sin4x - cos4x)/(sin2x -cos2x) 2. (sinx(cotx)+cosx)/(2cotx)
Sunday, July 15, 2012 at 6:29pm
13. amplitude 3: 3cos(...) period p: 3cos(2pi(...)/p) ... translate by (-1,1): 3cos(2pi(x+1)/p) + 1 So, it appears to be (D), if by p you mean pi. 16: (0,4): (C) 20: (A) Your use of transition point appears unusual. In #13 the only possible interpretation, given the answer ...
Saturday, July 14, 2012 at 12:05pm
13. What is the equation of a cosine function with amplitude 3, transition point (−1, 1), and period p? A. y = p cos [3(x − 1)] − 1 B. y = 3 cos [2(x − 1)] + 1 C. y = 3 cos [p (x + 1)] − 1 D. y = 3 cos [2(x + 1)] + 1 16. What is the transition ...
Saturday, July 14, 2012 at 6:34am