Saturday
March 8, 2014

# Homework Help: Math: Trigonometry

Trig
verify the following identity: cos(A-B)/cosAsinB=tanA+cotB
Thursday, July 19, 2012 at 12:48pm

Trig
verify the following identity: sin(x+y)*sin(x-y)=sin^2x-sin^2y
Thursday, July 19, 2012 at 12:47pm

Trig
Verify the following identity: 1-cosx/sinx=sinx/1+cosx
Thursday, July 19, 2012 at 12:45pm

Trig/Physics
Hi, thank you so much. Everything I tried hit all around the borders, but just was not working out correctly. I really appreciate your help.
Thursday, July 19, 2012 at 3:50am

Trig/Physics
total displacement north = 5 sin 30 + 10 cos20 = 2.5 + 9.397 = 11.897 miles total displacement east = 5 cos30 - 10 sin20 = 4.33 - 3.42 = 0.91 miles (a) sqrt[(11.897)^2 + (0.91)^2] = 11.93 miles (b) direction = tan^-1 0.91/11.897 E of N = 4.37 deg E of N
Thursday, July 19, 2012 at 1:18am

Trig/Physics
Hi, sorry it was 30 degrees North of East.
Wednesday, July 18, 2012 at 11:38pm

Trig/Physics
You left out an important number that is needed to compute the answer. It should follow the first word "direction". How many degrees is the first direction North of East?
Wednesday, July 18, 2012 at 11:14pm

Trig/Physics
Joe walks 5 miles in the direction degrees North of East, and then 10 miles in the direction 20 degrees West of North. (a) How far is Joe from his starting position? (b) In what direction is Joe from his starting position?
Wednesday, July 18, 2012 at 10:01pm

Trigonometry
Simplify the expression using trig identities: 1. (sin4x - cos4x)/(sin2x -cos2x) 2. (sinx(cotx)+cosx)/(2cotx)
Sunday, July 15, 2012 at 6:29pm

Math Trig
13. amplitude 3: 3cos(...) period p: 3cos(2pi(...)/p) ... translate by (-1,1): 3cos(2pi(x+1)/p) + 1 So, it appears to be (D), if by p you mean pi. 16: (0,4): (C) 20: (A) Your use of transition point appears unusual. In #13 the only possible interpretation, given the answer ...
Saturday, July 14, 2012 at 12:05pm

Math Trig
13. What is the equation of a cosine function with amplitude 3, transition point (−1, 1), and period p? A. y = p cos [3(x − 1)] − 1 B. y = 3 cos [2(x − 1)] + 1 C. y = 3 cos [p (x + 1)] − 1 D. y = 3 cos [2(x + 1)] + 1 16. What is the transition ...
Saturday, July 14, 2012 at 6:34am

trig
5 csc^2 Ø - 3cot^2 Ø = 2csc^2 Ø + 3 LS = 5/sin^2 Ø - 3cos^2 Ø/sin^2 Ø = (5 - 3cos^2 Ø)/sin^2 Ø = (5 - 3(1 - sin^2 Ø) )/sin^2 Ø = ( 2 + 3sin^2 Ø)/sin^2 Ø = 2/sin^2 Ø + 3sin^2 Ø/sin...
Friday, July 13, 2012 at 11:30pm

trig
establish identity 5csc^2theta-3cot^2theta=2csc^2theta+3
Friday, July 13, 2012 at 10:00pm

trig
cos^2t+2cos(t)+1=0 (cost + 1)^2 = 0 cost + 1 = 0 cost = -1 t = 270°
Thursday, July 12, 2012 at 1:05pm

trig
sin 4t = √3/2 you know sin 60° = √3/2, so 4t=60° or 120° t=15° or t=30° Now, to get all solutions in [0,360), add multiples of 2pi/4 = 90°: t = 15° + 90n° = 15,105,195,285 t = 30° + 90n° = 30,120,210,300
Thursday, July 12, 2012 at 11:45am

trig
Solve the equation on the interval [0,360) cos^2t+2cos(t)+1=0
Thursday, July 12, 2012 at 10:51am

trig
Find all solutions in the interval [0,360) sin(4t)=ã3/2
Thursday, July 12, 2012 at 10:49am

TRIG
And it is not even impish
Wednesday, July 11, 2012 at 12:29pm

algebra, not trig
CAPS LUK ST00PID, as do the contractions and typos. Assuming his present salary is the base salary, 24 * 1.10^2 = 29.04 Where can I get a job with an annual 10% raise?
Wednesday, July 11, 2012 at 11:04am

TRIG
cos theta = + OR - 1 / sqrt ( 1 + tan ^ 2 theta ) In Quadrant II, cosine are negative so : cos theta = - 1 / sqrt ( 1 + tan ^ 2 theta ) cos theta = - 1 / sqrt [ 1 + ( 3 / 4 ) ^ 2 theta ] cos theta = - 1 / sqrt ( 1 + 9 / 16 ) cos theta = - 1 / sqrt ( 16 / 16 + 9 / 16 ) cos ...
Wednesday, July 11, 2012 at 10:48am

Airplane trig question
the speed is irrelevant, since it does not change. So the relative times are the same as the relative distances. 90 min at 131° moves the plane 90(cos41°,-sin41°) = (67.92,-59.04) 30 min at 41° moves it an additional 30(cos41°,sin41°) = (22.64,19.68) So...
Wednesday, July 11, 2012 at 10:46am

TRIG
That was a good atempt bob but the options i have here is -2/35, 30.78, -24/35, AND 18
Wednesday, July 11, 2012 at 10:34am

TRIG
A WORKER PRESENT SALARY IS 24 PER ANNUM HIS ANUAL INCREMENT IS 10% OF HIS BASIC SALARY WAT WUD BE HIS ANNUAL SALARY AT THE BEGINNIN OF THE THIRD YEAR
Wednesday, July 11, 2012 at 10:27am

TRIG
see other post.
Wednesday, July 11, 2012 at 10:22am

TRIG
if tan is 3/4, then the right triangle is 3,4,5 so sin is 3/5, second quadrant.
Wednesday, July 11, 2012 at 10:22am

TRIG
Given that tan¤=3/4 and ¤ is in the second quadrant find sin2¤ (¤=theta)
Wednesday, July 11, 2012 at 10:17am

TRIG
Given that tan¤=3/4 and ¤ is in the second quadrant find sin2¤ (¤=theta)
Wednesday, July 11, 2012 at 10:17am

trig
rewrite it in the most general form y = -2 cos π(x - 3/π) amplitude = 2 period = 2π/π = 2 phase shift = 3/π units to the right
Wednesday, July 11, 2012 at 7:14am

Trig
sqrt ( 3 ) * csc ( 2 theta ) = - 2 Divide both sides by sqrt ( 3 ) csc ( 2 theta ) = - 2 / sqrt ( 3 ) Take the inverse cosecant of both sides. 2 theta = - pi / 3 and 2 theta = 4 pi / 3 [ Becouse csc ( pi / 3 ) = 2 / sqrt ( 3 ) , and csc ( 4 pi / 3 = 2 / sqrt ( 3 ) ] Divide ...
Wednesday, July 11, 2012 at 2:09am

trig
determine the amplitude,period and phase shift of y=-2cos(pix-3)
Wednesday, July 11, 2012 at 12:19am

Airplane trig question
An airplane, flying at a speed of 420 miles per hour, flies from point A in the direction 131 degrees for 90 min. and then flies in the direction 41 degrees for 30 min. in what direction does the plane need to fly in order to get back to point A?
Tuesday, July 10, 2012 at 7:34pm

Trig
find all solutions to the equation √3 csc(2theta)=-2 Would the answer be π/6 + 2πn, 5π/6 +2πn or π/6 + πn, 5π/6 +πn? or neither?
Tuesday, July 10, 2012 at 7:30pm

trig
sin t /(1-cos t) - (1+cos t)/sin t sin t (1+cos t)/((1-cos t)(1+cos t)) - (1+cos t)/sin t sin t (1+cos t)/(1-cos^2 t) - (1+cos t)/sin t sin t (1+cos t)/sin^2 t - sin t (1+cos t)/sin^2 t 0
Tuesday, July 10, 2012 at 5:35pm

trig
sin t /1-cos t - 1+ cos t/sin t= 0
Tuesday, July 10, 2012 at 5:24pm

trig
Prove sin 1 cos  1 cos sin  0 1. Show each step of your proof. 2. Provide written justification for each step of your proof. C. If you use sources, include all in-text citations and references in
Tuesday, July 10, 2012 at 5:22pm

Trig
Given y=2-4cos(3x-pi/4), find each of the following, giving the general representation of the location of all minimums. Also provide the graph of two full cycles, labeling everything. Domain = Range = Amplitude = Period = Ph. Shft. = Interval for one Complete cycle = ...
Monday, July 9, 2012 at 4:24pm

Trig/Precal
add the vectors. flying: 90sin310 E + 90 cos310 N windblowing: 40sin(332-180)E+40cos(332-180)N now add them result: East(90sin310+40sin152)+North(90cos310+4​0cos152) figure those, and you are near the end. Post your questions if you get lost from here.
Friday, July 6, 2012 at 8:41pm

Trig/Precal
An airplane flies on a compass heading of 90° at 310 mph. The wind affecting the plane is blowing from 332° at 40 mph. What is the true course and ground speed of the airplane?
Friday, July 6, 2012 at 7:37pm

Alg/Trig
(x-2)^2 + (y-3)^2 = 4.5^2
Friday, July 6, 2012 at 1:17pm

Alg/Trig
Write an equation of a circle with center (2, 3) and radius 4.5.
Friday, July 6, 2012 at 1:13pm

trig HELP
at each end, you have a triangle with base 15, and a height 15tan40°=12.58 so, each end has an area of 1/2 * 15 * 12.58 = 94.35 each half of the roof is 60 x 15sec40° = 60x19.58 = 1174.87
Thursday, July 5, 2012 at 3:43pm

trig HELP
A barn is 30ft. wide by 60ft long; the rafters make an angle of 40degrees with the horizontal. Find the area of each of the two gable ends and the area of the roof. Please Include Solution And If Possible An Illustration. Thank You In Advance :)
Thursday, July 5, 2012 at 9:51am

Algebra & Trig
Was there a picture given? I don't know if I can answer the question without a picture.
Thursday, July 5, 2012 at 2:05am

Algebra & Trig
under the influence of gravity? consider the maximum height, velocity vertical is zero. Vf=vi+gt 0=12sinTheta-9.8t t=12sinTheta/9.8 time in the air is twice that time. no, horizontal distance 13=12cosTheta*t=12cosTheta*2*12sinTheta/​9.8 13=12^2/9.8 *2 cosTheta*sinTheta ...
Wednesday, July 4, 2012 at 7:45pm

Algebra & Trig
at a throwing speed pf 12.2 meters per seconds,what is the angle that produce a distance of 13 meters
Wednesday, July 4, 2012 at 6:24pm

Algebra & Trig
calculate the velocity of 10 meters per second with an angle of 30 degrees
Wednesday, July 4, 2012 at 6:20pm

trig
in general the period of y = tan (kØ) is π/k so for y = tan (2x) the period is π/2
Wednesday, July 4, 2012 at 11:52am

trig
determine the period of y = tan 2x
Wednesday, July 4, 2012 at 10:47am

TRIG
Hey, I ca help you with the first one as this is the only one I understand so far. Since you have pi*x in the tan, you have to take the pi and divide by the k of the function, which in this case is pi. This gets you a perio of one, meaning that there is a point at every single...
Tuesday, July 3, 2012 at 1:38pm

trig
Connecting the center of the circle with the 2 ends of the chord makes an isc.. triangle. Half of that is a right triangle. The angle at the center of the circle is 39.1Âº and 1/2 the chord is 59.2 cm. 59.2 = r*sin(12/2) solve for r.
Tuesday, July 3, 2012 at 9:59am

trig
Find the radius of a circle which a 59-foot chord subtends an angle of 12degrees at the center. I Just Want To See The Illustration. I Can Handle The Rest. Thank You In Advance =)
Tuesday, July 3, 2012 at 9:51am

trig
57/X = sin 24deg, so you are correct.
Saturday, June 30, 2012 at 5:49am

trig
using a right triangle with one angle 24 degrees and the opposite side being 57 feet, write an expression to fine the hypotenuse, X? X=57/sin(24) is this correct?
Friday, June 29, 2012 at 11:47pm

trig
8/cos40=10.44 inches check that
Friday, June 29, 2012 at 8:37pm

trig
a circular chimney pipe with an 8-inch diameter passes vertically from a heater through a metal plate in the roof. the plate has an elliptical hole that measures 8 inches along one axis. if the roof is slanted at an angel of 40 degrees with the horizontal, what is the length ...
Friday, June 29, 2012 at 6:22pm

trig
tanA = 2 in QIII means sinA = -2/√5 cosA = -1/√5 cosA/(sin^3A + cos^3A) = -1/√5 / (-8/5√5 - 1/5√5) = -1/√5 / (-9/5√5) = -1/√5 * -5√5/9 = 5/9 that's PI, not PIE!
Friday, June 29, 2012 at 4:31pm

trig
If tan A = 2 and A belongs to [pie,3pie/2] then the expression cos A divided by sin cubed A +cos cubed A is equal to what?
Friday, June 29, 2012 at 12:41pm

trig
yes, you should get an angle of 30.1°
Friday, June 29, 2012 at 10:24am

trig
the horizontal speed of an airplane is 173 miles per hour. the magnitude of the planes velocity is 200 miles per hour. what angle is the plane climbing? My answer is Cos-1 173/200. is this correct
Friday, June 29, 2012 at 9:38am

trig
looks like height = .5n + 800 , where n is the number of weeks
Thursday, June 28, 2012 at 10:27am

trig
A certain species of tree grows an average of 0.5 cm per week. Write an equation for the sequence that represents the weekly height of this tree in centimeters if the measurements begin when the tree is 800 centimeters tall?
Thursday, June 28, 2012 at 8:10am

trig
to prove (sec8A-1)/(sec4A-1) = tan8A/tan2A Not sure how to do this with sec and tan only, but using sin and cos, we have sec8A-1 = (1-cos8A)/cos8A = (1-(2cos^2(4A)-1))/cos8A = 2(1-cos^2(4A))/cos8A sec4A-1 = (1-cos4A)/cos4A so, the LS is 2cos4A(1-cos^2(4A))/(2cos^2(4A)-1)*(1-co...
Wednesday, June 27, 2012 at 2:20pm

trig
sec8A-1/sec4A-1=tan8A/tan2A
Wednesday, June 27, 2012 at 12:53pm

Trig
If the height is h, and P is x m from the base, h/x = tan 27°10' = .5132 h/(x-23) = tan 51°30' = 1.2572 rearranging things a bit, h = .5132x = 1.2572(x-23) x = 38.8651 so, h = 19.9456, or 19.9m
Tuesday, June 26, 2012 at 11:32pm

Trig
From a point P on level ground, the angle of elevation of the top of a tower is 27°10'. From a point 23.0 meters closer to the tower and on the same line with P and the base of the tower, the angle of elevation of the top is 51°30'. Approximate the height of ...
Tuesday, June 26, 2012 at 11:14pm

trig
I will try to guess what you mean .... If π/3 is a rotation angle on a unit circle (60°) then 14π/3 = 4 + 2π/3 or 4 rotations + 2π/3 this would put you into quadrant II (120°) a point with angle π/3 and a point with angle 2π/3 has the same...
Sunday, June 24, 2012 at 8:21am

trig
explain how you will find the coordinate of P(14pi/3) if you knew the coordinate of P(pi/3)
Sunday, June 24, 2012 at 3:09am

trig
given cot-A square root of 5, find cot-B at the 4th quadrant.
Saturday, June 23, 2012 at 9:10pm

Trig
Sketch the graph through at least one complete cycle. Label the axes on the coordinate plane. Use your graph to predict the height of point P above the surface of the water when the stopwatch shows 7 seconds. Round to the nearest tenth of a foot. (Enter only the number.)
Thursday, June 21, 2012 at 6:11pm

Trig
P was at its maximum after 5 seconds. Use this information to write the value of the last constant, h. (If the value is a fraction, use a slash to separate the numerator from the denominator without spaces, such as 3/4.)
Thursday, June 21, 2012 at 6:09pm

Trig
6 + sin k x 6 feet
Thursday, June 21, 2012 at 5:17pm

Trig
Since the center is 6 feet above the water, the horizontal line of symmetry of the sine curve will be 6 units above the x-axis. This information helps you find the value of vertical shift. Write its value.
Thursday, June 21, 2012 at 5:15pm

Trig
sin theta = 4.7/25 so theta = sin^-1 (4.7/25) 10.8 degrees
Thursday, June 21, 2012 at 5:12pm

Trig
Jessica attains a height of 4.7 feet above the launch and landing ramps after 1 second. Her initial velocity is 25 feet per second. To find the angle of her launch, which equation can you use with the given information to solve for θ? (Answer: 1 or 2). Use the equation ...
Thursday, June 21, 2012 at 5:02pm

trig
We form a rt triangle: Y = 150 Ft. = Ver. side. X = Hor. side = Dist. from bottom of tower to point where wire attaches to gnd, Z = hyp. = Length of wire. Z = Y/sin40 = 150 / sin40 = 233.4 Ft. X = Z*cos40 = 233.4*cos40178.8 Ft.
Wednesday, June 20, 2012 at 9:01pm

trig
A guy wire runs from the ground to a cell tower. The wire is attached to the cell tower 150 feet above the ground. The angle formed between the wire and the ground is 40° (see figure). (Round your answers to one decimal place.)
Wednesday, June 20, 2012 at 3:46pm

trig
After you make your sketch you should see that tanØ = 5/14 Ø = 19.65°
Wednesday, June 20, 2012 at 2:00pm

trig
Two forces of 5 lb. and 14 lb. act on a body at right angles to each other. Find the angle their resultant force makes with the force of 14 lb
Wednesday, June 20, 2012 at 1:50pm

geometry
looks like a straight-forward right-angled triangle trig question. tan75° = x/145 x = 145tan75 = 541.15
Wednesday, June 20, 2012 at 1:28pm

trig
tan = rise/run = 55/2640 = 1/48
Tuesday, June 19, 2012 at 2:42pm

trig
A roadway rises 55ft in horizontal distance of 1/2 mile (1mile=5280ft) Find the tangent of the angle that it makes with the horizontal.
Tuesday, June 19, 2012 at 12:26pm

math
Looks like "homework or assignment dumping" to me Exactly what problems do you have with this list of trig questions? I will do this one.... show me some attempts at the others LS = cosx(2tan^2 x + 5tanx + 2) = 2cosx sin^2 x/cos^2 x + 5cosxsinx/cosx + 2cosx = 2sin^2 ...
Monday, June 18, 2012 at 9:45am

Algebra
Using similar triangles and ratios, we can find the height of the tower. h/60 = 3/2 h = 90 then by Pythagoras: let the length of the wire be x x^2 = 60^2+90^2 x = √11700 = appr 108.2 ft or using trig, let the angle formed by Ø tanØ = 3/2 Ø = 56.31&...
Friday, June 15, 2012 at 11:45pm

trig
Use the laws of scalar multiplication of vectors: A=(x,y) aA=(ax,ay) u=(10,5) -u=(-10,-5) -3u=(-30,-15)
Friday, June 15, 2012 at 2:26pm

trig
Give the component form of the resultant vector in the following. NOTE: Answer must be typed in using the following format -- including the parentheses: (#,#). u =(10, 5) -3u=
Friday, June 15, 2012 at 11:15am

trig
s = rθ = 18(44*pi/180) = 13.82ft in one arc It makes 10 (5 back and forth) swings every minute. Total travel: 138 ft
Thursday, June 14, 2012 at 1:06pm

trig
A pendulum is 18 feet long. Its central angle is 44º. The pendulum makes one back and forth swing every 12 seconds. Each minute, the pendulum swings _____ feet. (Answer to the nearest foot.)
Thursday, June 14, 2012 at 12:59pm

trig
the angle is appr 15 degrees You don't state where the sides A and H are, but once you have the angle I am sure you can find the other side.
Wednesday, June 13, 2012 at 5:01pm

trig
Use a table of trigonometric values to find the angle è in the right triangle in the following problem. Round to the nearest degree, if necessary. cos è =0.9659 A=? H=20
Wednesday, June 13, 2012 at 4:44pm

Trig
If csc Ø = 13/12, the sinØ = 12/13 so we are dealing with the 12-5-13 right-angled triangle in II then cosØ = -5/13 sin 2Ø = 2sinØcosØ = 2(12/13)(-5/13) = -120/169 cos 2Ø = cos^2 Ø - sin^2 Ø = 25/169 - 144/169 = -...
Wednesday, June 13, 2012 at 7:58am

Trig
Find sin2theta, cos2theta if csctheta=13/12 and lies in quadrant II. Thank you!
Wednesday, June 13, 2012 at 2:06am

trig
hjk.hjk.hkl;
Tuesday, June 12, 2012 at 9:06am

Trig
base of triangle --- x inches side of triangle ---- 4x inches 4x + 4x + x = 16 9x = 16 x = 16/9 the base is 16/9 inches long base = 16/9 each side = 64/9 check: 16/9+64/9+64/9 = 144/9 = 16
Monday, June 11, 2012 at 8:28pm

Trig
The length of the base of an isosceles triangle is one fourth the length of one of its legs. If the perimeter of the triangle is 16 inches, what is the length of the base?
Monday, June 11, 2012 at 6:15pm

trig/math
Determine the period, amplitude and phase shift for each given function: A)y = -4 cos 3x + 5 B)y = 2/3 sin (30x-90)-10 c)y = -0.38 tan (x/3+pi/3) d)y = pi cos(2x)+ pi
Monday, June 11, 2012 at 5:17pm

Math/Trig
sin(-θ) = -sinθ sin(θ±2kπ) = sinθ so, sin(-13π/6) = sin(-π/6) = -1/2 tan(θ±kπ) = tanθ -- same for cot cot(11π/6) = cot(-π/6) = -cot(π/6) = -√3 cot(-14π/4) = cot(2π/4) = cot(π/2...
Monday, June 11, 2012 at 11:29am

Math/Trig
How would I evaluate these trig functions without using a calculator? U: sin(-13π/6) cot 11π/6 cot(-14π/4) sec 23π/6 Thanks in advance ^^; and if you'd tell me step by step on how to do problems like these I'd be grateful :D
Monday, June 11, 2012 at 5:03am

Calculus
integral of cscx^(2/3)(cot^3)x i know that cot^2x is csc^2(x)-1, but i just don't understand how to solve the cscx^(2/3), any help? i also know that its trig integrals/substitution...
Sunday, June 10, 2012 at 12:05pm

trig