Recent Homework Questions About Trigonometry
that would be tan 4π/3 = √3
Friday, June 21, 2013 at 12:26pm
Solve the right triangle with the given sides and angles. a = 3.0, B = 31.0°
Friday, June 21, 2013 at 11:46am
If the angle is x, tan x = 12.3333/19.2 Better review your trig ratios...
Wednesday, June 19, 2013 at 9:10pm
Thanks Steve, taking a physics course for credit this summer, but I am going in to 9th grade and have not had trig yet. Thanks for the formula!
Tuesday, June 18, 2013 at 3:34pm
2sin2θ = √3 sin2θ = √3/2 sin(x) is positive in QI,QII 2θ = 60°,120°,... we need to go for two periods because we're dealing with 2θ. That gives us θ = 30°,60°,210°,240°
Monday, June 17, 2013 at 9:47am
2x = 45,315,... Follow for 2 periods to get values for x up to 360.
Monday, June 17, 2013 at 9:46am
arctan(1.85) = 61.6° tan(x) < 0 in QII, QIV, so x = (180-61.6) = 118.4° x = (360-61.6) = 298.4°
Monday, June 17, 2013 at 12:58am
tan(x+y) = (tanx + tany)/(1-tanx tany) so, what you have is tan(25°+5°) = tan 30° = 1/√3
Monday, June 17, 2013 at 12:40am
what's all this work? A is in QI, so sinA = √8/3 B is in QIV so cosB = √3/2 and then as done in the final paragraph
Sunday, June 16, 2013 at 11:20pm
Since (5,12,13) is a Pythagorean triplet, tan(θ)=5/12. Mathematically, we solve it by: Divide by the right hand side: (5/13)sin(θ)+(12/13)cos(θ)=1 Since (5/13)²+(12/13)²=1, we can put 5/13=sin(φ) 12/13=cos(φ) so sin(φ)sin(&theta...
Saturday, June 15, 2013 at 8:41am