Recent Homework Questions About Trigonometry
Given triangle ABC with a = 16, b = 14, and β = 54°, find the value of c.
Wednesday, July 3, 2013 at 11:09am
OR ... trig, math
Just noticed that Steve did the same question using components http://www.jiskha.com/display.cgi?id=1343845975 take your choice, both give 24° to the nearest degree.
Wednesday, July 3, 2013 at 11:06am
I get two. make a sketch Using the Sine Law, you will get sinC = 29sin40/24 = .776... so C = appr 51 degrees or 180-51 = 129 degrees (since the sine is positive in I or II) You will be able to draw a second triangle with B = 40, C = 129 and A = 11 degrees This is called the ...
Tuesday, July 2, 2013 at 11:45am
correct! (except that's theta, not tehta)
Tuesday, July 2, 2013 at 10:29am
period of cos kx = 2pi/k so, 2pi/k = 7 k = 2pi/7 period of tan,cot = pi, so (B)
Monday, July 1, 2013 at 1:34pm
you know that (1,1) = √2,π/4 so, now you have an angle in QIV, so it is 24,7π/4
Sunday, June 30, 2013 at 8:29pm
Hey, Tone, you've posted a bunch of these problems that are all just basically converting between rectangular and polar forms. I've done a few for you. What don't you get by now? We're willing to help, but hate to be used to do someone's whole assignment. ...
Friday, June 28, 2013 at 9:36pm
(6,-6) is in QIV Where are the given angles?
Friday, June 28, 2013 at 9:16pm
X ^5 - 11 = 0 X^5 = 11 (X^5)^(1/5) = (11)^(1/5) X = 1.615.
Friday, June 28, 2013 at 12:39pm
Find the indicated roots. Write the answer in trigonometric form. Fourth roots of 256(cos 220° + i sin 220°)
Friday, June 28, 2013 at 12:38pm
(2cis240°)^5 = 2^5 cis(5*240°) = 32 cis1200° = 32 cis120° = -16 + 16√3 i
Friday, June 28, 2013 at 12:08pm